Kerr MPM2D Applying Quadratic Models 5.1 Stretching/Reflecting Quadratic Relations Every quadratic relation begins as y = x2. This is your basic parabola. x y -2 4 -1 1 0 0 1 1 2 4 Today we are going to transform the parabola in two different ways by changing the shape and the direction of the opening. Reflection in the x-axis Examine the value of a in y = ax2. If a is positive, the parabola opens up. If a is negative, the parabola opens down because it been reflected in the x-axis. Example #1: Describe the transformation applied to the graph of y = x2. a) y = -x2 reflection in the x-axis Vertical Stretch Examine the value of a in y = ax2. If a < -1 (less than -1) or if a > +1 (more than +1), then the parabola undergoes a vertical stretch by a factor of a. A vertical stretch means the parabola becomes more narrow. Every y-coordinate on the parabola is multiplied by a. Kerr MPM2D Applying Quadratic Models Example #2: Describe the transformation applied to the graph of y = x2. a) y = 3x2 vertical stretch by a factor of 3 2 b) y = -5x vertical stretch by a factor of 5, reflection in the x-axis 7 2 x 2 41 y = - x2 5 c) 7 2 41 vertical stretch by a factor of , reflection in 5 y= d) vertical stretch by a factor of the x-axis Examine in more detail with a diagram. x y = x2 y -2 -1 0 y = (-2)2 y = (-1)2 y = (0)2 4 1 0 1 2 y = (1)2 y = (2)2 1 4 x y = 3x2 y 2 -2 -1 0 y = 3(-2) y = 3(-1)2 y = 3(0)2 12 3 0 1 2 y = 3(1)2 y = 3(2)2 3 12 Vertical Compression Examine the value of a in y = ax2. If -1 < a < +1 (between -1 and +1) then the parabola undergoes a vertical compression by a factor of a. A vertical compression means the parabola becomes more wide. Every y-coordinate on the parabola is multiplied by a. Kerr MPM2D Applying Quadratic Models Example #3: Describe the transformation applied to the graph of y = x2. a) y = -0.5x2 vertical compression by a factor of 0.5, reflection in the x-axis 1 2 x 4 b) y= vertical compression by a factor of c) y = 0.1x2 vertical compression by a factor of 0.1 d) 2 y = - x2 11 vertical compression by a factor of in the x-axis 1 4 2 , reflection 11 Examine in more detail with a diagram. x y = x2 y -2 -1 0 y = (-2)2 y = (-1)2 y = (0)2 4 1 0 1 2 y = (1)2 y = (2)2 1 4 x y = 0.5x2 y = 0.5(-2)2 y -2 -1 0 2 y = 0.5(-1) y = 0.5(0)2 2 0.5 0 1 2 y = 0.5(1)2 y = 0.5(2)2 0.5 2 More Examples: 4. The graph of y = x2 is transformed to y = ax2 (a ≠ 1). For each point on y = x2, determine the coordinates of the transformed point for the indicated value of a. a) (5, 7) when a = -2 (5, -14) The value of a only affects the ycoordinate of the vertex. The xcoordinate remains the same and the y-coordinate is multiplied by a. Kerr MPM2D Applying Quadratic Models b) (-2, -20) when a = 5. Describe the transformation(s) that were applied to the graph of y = x2. Write the equation of the transformed graph. 1 10 (-2, -2) Examine the y-coordinate of each graph when x = 1. (1, 1) (1, 2) The y-coordinate was multiplied by 2. vertical stretch by a factor of 2 y = 2x2 6. Identify the transformation(s) that must be applied to the graph of y = x2 to create a graph of each equation. Then state the coordinates of the image of the point (-3, 5). a) y = - x2 1 6 5 (-3, - ) 6 vertical compression by a factor of the x-axis 1 , reflection in 6 The x-coordinate of the point stays the same. We must multiply the y-coordinate by the vertical compression factor. (5 x - b) y = 2.5x2 (-3, 12.5) 1 ) 6 vertical stretch by a factor of 2.5 The x-coordinate of the point stays the same. We must multiply the y-coordinate by the vertical stretch factor. (5 x 2.5) Kerr MPM2D Applying Quadratic Models 7. Determine the equation for the parabola below and describe the transformation. Substitute this point (2.5, 5) into the equation y = ax2 to solve for a. y = ax2 5 = a(2.5)2 a = 0.8 y = 0.8x2 vertical compression by a factor by 0.8 Hints for the homework: Question #2 is just like example #4. Question #5 is just like example #5. Question #8 is just like example #6. Question #6 and 7 are just like example #7. Homework: Page 256 #1-8, 10, 11
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