EE 2260 Lecture 18 Fourier Transform Reading: 17.1 – 17.3 HW #18 AP: 17.1, 17.2, 17.3 §17.1 The Derivation of the Fourier Transform For a periodic function f(t) we have a Fourier series: or in the exponential form: If the function f(t) is not periodic, we may think that the period T . In this situation, 1 d jt dt , n0 , C n T f (t )e T 2 We define the Fourier transform of f(t) as F ( ) f (t )e jt dt The Fourier expansion becomes the Inverse Fourier transform: 1 f ( t ) jn0t 1 f ( t ) (C n T ) e 2 T n F ( )e j t d Example1: Example2: f (t ) e at u(t ) , a > 0. F ( ) PLOTS 0 at jt ( a j ) t dt e u(t )e dt e e ( a j ) t 1 |0 ( a j ) a j . . §17.2 The Convergence of the Fourier Integral We consider some useful but not integrable functions. Example: Find the Fourier transform of a constant f(t) = 1: 1 e jt dt e jt e jt dt | ? j Let’s consider a different function: f (t ) e a |t | , a > 0. F ( ) a|t| jt e e dt 0 0 at jt at jt e e dt e e dt 1 1 2a 2 a j a j a 2 2a 0 a 2 2a If 0 , let a 0 , 2 a If 0 , let a 0 , 2 Notice that the area under the curve (not shown) 2a x 2a is d 2 tan 1 | 2 2 2 2 2 a a a Therefore, F ( ) 2 ( ) when f(t) = 1. §17.3 Using Laplace Transforms to Find Fourier Transforms Case #1: f(t) = 0 for t < 0 and let s =j. Example: f (t ) e at cos(0 t )u(t ) , Case #2: f(t) = 0 for t > 0 and let s = -j. F ( ) f (t )e jt dt 0 f (t )e jt dt Change f(t) to f(-t), and let s = -j. jt f ( t )e dt 0 Example: f ( t ) e at cos( 0 t )[ 1 u ( t )] , f ( t ) e at cos(0 t )[1 u( t )] e at cos(0 t )u(t ) Case #3: For a general f (t ) f (t ) f (t ) , where f (t ) f (t )u(t ) , f (t ) f (t )[1 u(t )] Example: f (t ) e a|t| e at u(t ) e at [1 u(t )] , f (t ) e at u(t ) , f ( t ) e at u(t )
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