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Chapter_10_Review_Stations.notebook
May 07, 2015
Label as major minor or semi
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Chapter_10_Review_Stations.notebook
May 07, 2015
16) 70o because those are vertical angles so they are congruent
17) 110o NR is a diameter so it cuts the circle in half. 180­70 =110
18) 290o
We want the whole circle except for QR which is 70
19) 30o
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Chapter_10_Review_Stations.notebook
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May 07, 2015
2)
o
237
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Chapter_10_Review_Stations.notebook
360 ­ 237 = 123
May 07, 2015
If they intersect INSIDE, then you ADD the arcs and divide by 2
If they intersect outside you SUBTRACT the arcs and divide by 2
So 33+131 = 164 so so 237­123 = 114
Angle 1 = 82
X = 72
Angle 2 = 98
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Chapter_10_Review_Stations.notebook
May 07, 2015
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Chapter_10_Review_Stations.notebook
May 07, 2015
(6x + 28) is the inscribed angle so we double the angle to get the arc which becomes
2(6x+28) = 16x
12x + 56 = 16x
56 = 4x
x = 14
Then plug in to find out all the missing info
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Chapter_10_Review_Stations.notebook
May 07, 2015
Find Arcs 1 and 2 and Angle 3
3
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Chapter_10_Review_Stations.notebook
May 07, 2015
ARCS
(1) = 234 (double 117)
(2) = 126 ANGLE
(3) = 63
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Chapter_10_Review_Stations.notebook
May 07, 2015
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Chapter_10_Review_Stations.notebook
May 07, 2015
Find the circumference and area of the big circle
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Chapter_10_Review_Stations.notebook
May 07, 2015
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Chapter_10_Review_Stations.notebook
May 07, 2015
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Chapter_10_Review_Stations.notebook
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