Physics 285 Orange Coast College Arnold Guerra III Extra Examples – Chapter 17 1. A brass ring of diameter 10.00 cm at 20.00C is heated and slipped over an aluminum rod of diameter 10.01 cm at 20.00C. Assuming the average coefficients of thermal expansion are constant for brass and aluminum, (a) to what temperature must this combination be cooled to separate them? Is this attainable? (b) What if the aluminum rod is 10.02 cm in diameter? 2. Calculate the final equilibrium temperature when 150 grams of steam initially at 100oC is passed into 200 grams of liquid water and 25 grams of ice both initially at 0 oC in a calorimeter container. That is, the liquid water AND the ice are initially at 0 oC. Ignore any heat energy exchanges to the calorimeter and the surroundings. {For water: the latent heat of fusion is 3.33x105 J/kg, the heat of vaporization is 2.26x106 J/kg, and the specific heat capacity is 4186 J/kg oC}. If the final temperature of the system is 0 oC, what mass of ice remain, but if the final temperature of the system is 100 oC, what mass of steam remains? 3. Heat Conduction The heat (energy) flow down a temperature gradient through stationary matter is given by Fourier’s law of heat conduction as ! = −! ∇! where ! ≡ heat current density = heat flowing per unit time, per unit area ∇! ≡ temperature gradient ! ≡ thermal conductivity of the material We can think of −∇! as a thermal “driving force” which drives thermal energy. The total heat current I flowing across an area A is != ! ∙ !! where !! = ! !" and ! is a unit vector along the normal to the surface area. “Steady State” heat flow occurs when the heat flowing across an area is the same at all times, i.e., I = constant. Derive expressions for the steady state heat current I for the following geometries: (a) heat flow in one-dimension across an area A, with no heat source (b) radial heat flow in a cylinder, with no heat source (c) radial heat flow in a sphere, with no heat source (d) radial heat flow in a cylinder, with a heat source S = heat generated per unit time, per unit volume 4. Starting with Fourier’s law of heat conduction, ! = −! ∇! , and the fact that ∇ ∙ ! !" is the net outward heat current across the boundary of the volume element dV, show that the temperature satisties the equation !" ! = !∇! ! + ! !" ! !! ! where D = ! ! ! is the thermal diffusivity of the medium, and s is the heat source density (heat ! generated per unit volume per unit time). 5. Greenhouse Effect Earth absorbs solar energy and radiates infrared. The solar energy incident on earth is π R2 J where R is earth radius and J = 1350 W m-2 is the solar constant. Also, earth radiates from its entire surface area 4 π R2 . In the following questions, assume earth’s surface temperature to be uniform at Ts . (a) Find the steady state value of Ts assuming the earth absorbs ALL the incident solar energy, and that the earth is black (emissivity = 1) for infrared. (numerical answer required). (b) Find the steady state value of Ts taking into account that earth absorbs only 0.65 of the incident solar energy. (The remaining 35% is reflected from clouds and ice). You’ll discover that at this temperature earth would not support life. (c) Now find the steady state value of Ts taking into account the “greenhouse effect” of atmospheric infrared absorption and emission. The diagram below shows the ground at the surface temperature Ts and the atmosphere, represented as a thin black layer, at temperature Ta . The atmosphere absorbs 95% of the infrared radiation emitted by the earth, and can therefore be approximated as a single black layer. The diagram shows the infrared radiation emitted upward by the earth, and both upward and downward radiation emitted by the atmosphere. Assume that the ground absorbs 0.475 of the incident solar energy and the atmosphere absorbs 0.175 of the incident solar energy (for a total of 0.65). Write the heat energy balance (heat gained = heat lost) for the ground and for the atmospheric layer to obtain two equations for Ts and Ta . Solve for these temperatures and evaluate them numerically. Then look up on WolframAlpha the average surface temperature for the earth and compare this value with your answer obtained for the ground temperature using the above greenhouse effect model.
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