One Page Thermodynamics Alex Yanjun Hao At thermodynamic equilibrium π! π! = 0 Perfect gas ! π = π ββ + π πππ(π) π is chemical potential for the pure gas (denoted by *), at unit pressure P=1 atm (denoted by °), (itβs written as π β in the textbook); π ββ is a function of T, π ββ = π(π). Perfect gas mixture π! = π!ββ + π πππ(π! ) π!ββ pure i, unit P; f(T). Imperfect gas π = π ββ + π πππ(π) π ββ pure, unit P; f(T); fugacity coefficient π = π/π β 1 ππ π β 0 . Imperfect gas mixture π! = π!ββ + π πππ(π! ) π!ββ pure i, unit P; f(T); π! /π! β 1 ππ π β 0 Ideal solution (gas, liquid, solid) π! = π!β + π πππ(π! ) π!β pure i, arbitrary P; f(T,P). Non-βideal solution (gas, liquid, solid) π! = π!β + π πππ(π! ) π!β pure i, arbitrary P; f(T,P); activity π! = πΎ! π! Aqueous solution (electrolyte) π! = π!β + π πππ(π! ) β π! chemical potential of hypothetical ideal solution of unit molality, arbitrary P; f(T,P); activity π! = πΎ! π! ; activity coefficient of j: log!! πΎ! = βπΌπ!! πΌ ; ionic strength πΌ = ββ ! β π! π!! (sum of all ions); equilibrium ! constant πΎ!" = π! !! . Explain: π! = π!ββ + π πππ(π! π) = π!ββ + π πππ(π) + π πππ(π! ) = π!β + π πππ(π! ) For standard state, π!β = π!ββ , pure i, unit P. For other state, π!β (π) need to be converted to unit pressure value, π!ββ , via π β = π ββ + π πππ(π) for gas (or use f for imperfect gas); or π β = π ββ + π! (π β 1) for liquid and solid, if V is assumed constant. If V is not constant, use compressibility 1 ππ π = β π ππ ! !" ! (which gives π = π! π !!(!!!) in relation !" = π) when deriving the P-βV relation. !" ! Now π β = π ββ β π! !!(!!!) π β 1 π All the π ββ (pure, unit pressure) are functions of T, to get the chemical potential at reference temperature π! , use π π ° ° ° βπΊ!"# (π) = βπΊ!"# (π! ) + βπ»!"# (π! ) 1 β π! π! ° where βπ»!"# (π! ) is assumed to be constant in ° ° range [π! , π]: βπ»!"# (π! ) = βπ»!"# (π) Derive: πΊ π π = β π» ππ π! ! ! πΊ 1 π = βπ» ππ π !! !! π πΊ(π) πΊ(π! ) 1 1 β =π» β π π! π π! π π πΊ(π) = πΊ(π! ) + π» 1 β π! π!
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