24- capacitors: capacitance, combination (equivalent capacity), dielectric materials, Tomorrow – Quiz 2: Thursday/Friday

24- capacitors:
capacitance, combination (equivalent
capacity), dielectric materials,
Tomorrow – Quiz 2: Thursday/Friday
(Oct 9 & 10) – Gauss, electric
potential, Capacitors
More-or-less parallel capacitor
• The membrane of the axon of a nerve cell is a
thin cylindrical shell of radius r = 10-5 m,
length L = 0.48 m, and thickness d = 10-8 m.
The membrane has a positive charge on one
side and a negative charge on the other, and
acts as a parallel-plate capacitor of area A =
2πrL and separation d. Its dielectric constant is
about κ = 5.
Cylindrical capacitor
• Gauss’s surface: cylinder of radius, r, and length L.
•
𝐸 ∙ 𝑑𝑎 =
cylinder above
𝑄inc
𝜀0
• →2𝜋𝑟𝐿𝐸 = 𝜆𝐿/𝜀0 →𝐸 = 𝜆/2𝜋𝑟𝜀0
• Field is inversely prop to r, not r2.
• Now elec. potential difference between r = a and b!
• Δ𝑉 = −
𝑎
𝐸
𝑏
∙ 𝑑𝑟 =
𝑏 𝑑𝑟
𝜆
2𝜋𝜀0 𝑎 𝑟
=
𝜆
𝑏
ln .
2𝜋𝜀0
𝑎
• If the capacitor is thin (𝑏 = 𝑎 + 𝛿)
𝐴𝜀0
?
𝛿
𝜆
𝑎+𝛿
𝜆
ln
=
ln
2𝜋𝜀0
𝑎
2𝜋𝜀0
• Can we show that 𝐶 =
•
𝜆
𝑏
ln
2𝜋𝜀0
𝑎
• 𝐶=
𝑄
Δ𝑉
=
=
2𝜋𝜀0 𝐿𝑎
𝛿
=
𝐴𝜀0
!
𝛿
1+
𝛿
𝑎
~
𝜆 𝛿
2𝜋𝜀0 𝑎
=
𝑄/𝐿 𝛿
.
2𝜋𝜀0 𝑎
More or less parallel capacitor
• The membrane of the axon of a nerve cell is a
thin cylindrical shell of radius r = 10-5 m,
length L = 0.48 m, and thickness d = 10-8 m.
The membrane has a positive charge on one
side and a negative charge on the other, and
acts as a parallel-plate capacitor of area A =
2πrL and separation d. Its dielectric constant is
about κ = 5.
A parallel plate capacitor is hooked up across a
battery’s terminals, charging it up to a given
potential. While the capacitor remains
connected to the battery, the distance between
the capacitor’s plates is doubled. What is the
change of the energy stored in this new
capacitor as compared with the original
capacitor?
A. Decrease by factor of 4
B. Decrease by factor of 2
C. Stays the same
D. Increases by factor of 2
E. Increase by factor of 4
How about this?
C1
C4
C3
C2
C5
How about this?
C1
C4
C3
C2
C5
•
•
•
•
•
•
𝑉1 + 𝑉4 = 𝑉
𝑉2 + 𝑉5 = 𝑉
𝑉1 − 𝑉2 = 𝑉3
𝑄1 + 𝑄3 − 𝑄4 = 0
𝑄2 − 𝑄3 − 𝑄5 = 0
5 unknowns, 5
equations?
Geiger tube
• E-field?
• Equipotential
surfaces?
• Where is 500 V?
• Argon ion speed as it hits the cathode?
Dielectric materials
+Q
+
+
+
+
+
+
+
+
+
+
+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–Q
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–+
–
–
–
–
–
–
–
–
–
–
–
+Q
=
+
+
+
+
+
+
+
+
+
+
+
• Δ𝑉 = 𝐸𝑑 = 𝐸𝑄 + 𝐸𝑄′ 𝑑 =
𝑄−𝑄′ 𝑑
𝐴𝜀
=
𝑄−𝑄𝛼 𝑑
𝐴𝜀
→𝐶=
–Q’ +Q’
–
–
–
–
–
–
–
–
–
–
–
+
+
+
+
+
+
+
+
+
+
+
𝜎𝑄 +𝜎𝑄′ 𝑑
𝐴𝜀0
𝑑 1−𝛼
𝜀0
=
=
𝜅𝐴𝜀0
𝑑
–
–
–
–
–
–
–
–
–
–
–
–Q