Higher Relationships and Calculus NAB Revision Pack Assessment Standard 1.1 1. Prove that x 2 is a factor of x 3 x 2 10x 8 and hence find the other factors. 2. Prove that x 3 is a factor of x 3 x 2 9x 9 and hence fully factorise the expression. 3. Factorise fully : 4. Solve the equations : 5. (a) x 3 21x 20 (b) 4x 3 8x 2 x 3 (a) 3x 3 7x 2 4 0 (b) x 3 7x 6 (a) Find the value of k which results in the equation k x 2 2kx 1 0 having equal roots, given that k 0 ? (b) A quadratic equation is given as x 2 ( p 3) x ( 1 4 3p) 0 . For what values of p will the above equation have i) equal roots ii) no real roots? Assessment Standard 1.2 6. Solve each of the following equations : (a) 2 sin 2x 1 0 , for 0 x 360 (b) 2 cos 2x 3sin x 1 0 for 0 x 360 (c) cos x 7. 1 2 for 0 x 360 sin 2x (a) Express 2 sin x 2 cos x in the form k cos ( x ) where k > 0 and 0 < < 90. (b) Hence solve the equation 2 sin x 2 cos x 2 81 for x where x > 40 . Assessment Standard 1.3 8. Differentiate each of the following functions with respect to the relevant variable : (a) f (x) x3 (x x2 ) (d) f (t ) t 2 (t 2 t 2 ) (e) (g) x5 2x 2 g(x) x4 1 (b) 3 (h) g ( x ) 3x 2 g ( p) 1 x3 1 13 2 (p p 3) p 5v 2 f (v ) v 1 1 x 3x 2 (c) h (x) (f) h (u) u (i) 1 t2 t 2 h (t ) t t 1 2 u 3 9. 10. 11. The amount of pressure P (pounds per square inch) within a cylinder varies with time t (milliseconds) according to the formula P (t ) 400t 50t 2 . (a) Calculate the rate of change of P when t 2 . (b) Calculate how fast P is changing when t 4 . (c) How is the rate of P changing when t 5 ? Comment ( x 1) dx x2 (a) Find the equation of the tangent to the curve with equation y 3x 2 2 x at the point where x 1 . (b) Find the equation of the tangent to the curve y 1 x at the point where x x Differentiate the following functions with respect to x : (a) f(x) = 3sinx (b) f(x) = 9cosx (c) ( 3x x 2 ) 2 dx (c) f(x) = 2sinx – 5cosx Assessment Standard 1.4 12. Find : (a) 13. (b) 3cosx dx (b) Find : (a) 14. ( 9 x 2 6x ) dx ( x 1) dx x2 7sinx dx (c) Evaluate each of the following definite integrals : (a) 4 1 x2 2 x dx x (b) 1 1 1 1 3v3 v 3 dv v 2cosθ – sinθ dθ 1 2 .
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