Liquids, Solids, and Phase Changes Chapter 10 1 Gases, Liquids and Solids • Gases have little or no interactions. • Liquids and solids have significant interactions. 2 Gases, Liquids and Solids • Liquids and solids have well-defined volume. • Liquid molecules “flow,” while solids are held “rigid.” 3 Intermolecular Forces Intermolecular forces are attractive forces between molecules. Intramolecular forces hold atoms together in a molecule. Intermolecular vs Intramolecular • 41 kJ to vaporize 1 mole of water (inter) • 930 kJ to break all O-H bonds in 1 mole of water (intra) “Measure” of intermolecular force Generally, intermolecular forces are much weaker than intramolecular forces. boiling point melting point 4 Intermolecular Forces Dipole Moments 01 • Polar covalent bonds form between atoms of different electronegativity. This is described as a bond dipole. 5 Dipole Moments 02 • Dipole Moment (µ): The measure of net molecular polarity or charge separation. µ=Qr r = distance between charges + = Q, – = –Q 6 Dipole Moments: µ = Q r • Q = Charge of electron: Q = 1.60 x 10-19 C, • r = bond length, m • μ , dipole moments are expressed in debyes (D) where 1 D = 3.336 x 10–30 C·m What is the dipole moment if one proton separated from one electron by a distance of 100 PM μ = Q x r = (1.60 x 10-19 C) (100 x 10-12 m) (1D/3.336 x 10-30 C . m) = 4.80 D 7 Dipole Moments 03 • Polarity can be illustrated with an electrostatic potential map. These show electron-rich groups as red and electron-poor groups as blue-green. 8 Dipole Moments 04 9 Intermolecular Forces 01 • Attractive forces between molecules and ions. • Several types of forces: –Dipole–dipole –Instantaneous induced dipole (dispersion forces) –Ion–dipole –Hydrogen “bonds.” 11 Intermolecular Forces Dipole-Dipole Forces Attractive forces between polar molecules Orientation of Polar Molecules in a Solid 12 Intermolecular Forces Ion-Dipole Forces Attractive forces between an ion and a polar molecule Ion-Dipole Interaction 13 Intermolecular Forces 04 • London Dispersion Forces: Attraction is due to instantaneous, temporary dipoles formed due to electron motions. 14 Intermolecular Forces Dispersion Forces Continued Polarizability is the ease with which the electron distribution in the atom or molecule can be distorted. Polarizability increases with: • greater number of electrons • more diffuse electron cloud Dispersion forces usually increase with molar mass. XXXXX 2 XXXX 15 What type(s) of intermolecular forces exist between each of the following molecules? HBr HBr is a polar molecule: dipole-dipole forces. There are also dispersion forces between HBr molecules. CH4 CH4 is nonpolar: dispersion forces. S SO2 SO2 is a polar molecule: dipole-dipole forces. There are also dispersion forces between SO2 molecules. 16 Hydrogen Bond • Hydrogen Bond: Molecules containing N– H, O–H, or F–H groups, and an electronegative O, N, or F. 17 Why is the hydrogen bond considered a “special” dipole-dipole interaction? Decreasing molar mass Decreasing boiling point 18 Which of the following molecules can hydrogen bond with itself? • • • • • 1, 2 2, 3 3, 4 1, 2, 3 1, 2, 3, 4 O CH2F2 NH3 CH3-O-H H3C C CH3 1 2 3 4 19 Which of the following molecules can hydrogen bond with itself? • • • • • 1, 2 2, 3 3, 4 1, 2, 3 1, 2, 3, 4 O CH2F2 NH3 CH3-O-H H3C C CH3 1 2 3 4 20 Of the following substances, predict which has the lowest boiling point based on London dispersion forces. 1. 2. 3. 4. 5. He Ne Ar Kr Xe 21 Correct Answer: 1. 2. 3. 4. 5. He Ne Ar Kr Xe More massive species have more polarizability and stronger London dispersion forces; consequently, amongst the noble gases He has the lowest boiling point. 22 Of the following substances, predict which has the highest boiling point based upon intermolecular forces? 1. 2. 3. 4. 5. CH4 H2O H2S SiH4 H2Se NH ……. O=C 23 Correct Answer: 1. 2. 3. 4. 5. CH4 H2O H2S SiH4 H2Se Of these, only H2O has any hydrogen bonding. Hydrogen bonding substantially increases the intermolecular forces, and hence the boiling point. 24 © 2003 John Wiley and Sons Publishers Courtesy Ken Karp 25 With nerves as steady as a chemical bond. © 2003 John Wiley and Sons Publishers Figure 13.1: “Floating” a tack on water. 26 © 2003 John Wiley and Sons Publishers Courtesy Ken Karp Figure 13.2: Place a tack on the surface of a glass of water. 27 Surface Tension Water strider walks on a pond without penetrating the surface 28 Surface Tension 29 Properties of Liquids Surface tension is the amount of energy required to stretch or increase the surface of a liquid by a unit area. Strong intermolecular forces High surface tension 30 Viscosity Viscosity is the measure of a liquid’s resistance to flow and is related to the ease with which molecules move around, and thus to the intermolecular forces. 31 Surface Tension Tensiometer 32 Intermolecular Forces 09 • Viscosity is the measure of a liquid’s resistance to flow and is related to the ease with which molecules move around, and thus to the intermolecular forces. Another unit of viscosity is kg/m.s 33 Phase Changes 01 34 Phase Changes Phase Change (State Change): A change in physical form but not the chemical identity of a substance. Fusion (melting): solid to liquid Freezing: liquid to solid Vaporization: liquid to gas Condensation: gas to liquid Sublimation: solid to gas Deposition: gas to solid Phase Changes 02 (∆Hfus) kJ/mol (∆Hvap ) 36 (∆Hfus) = 6.01 KJ/mol (∆Hvap ) = 40.67 KJ/mol Phase Changes • Vapor Pressure: The pressure exerted by gaseous molecules above a liquid. 37 Molar heat of vaporization (DHvap) is the energy required to vaporize 1 mole of a liquid. Clausius-Clapeyron Equation DHvap ln P = +C RT P = (equilibrium) vapor pressure T = temperature (K) R = gas constant (8.314 J/K•mol) 38 Vapor Pressure • The boiling point of a liquid is the temperature at which its vapor pressure equals atmospheric pressure. • The normal boiling point is the temperature at which its vapor pressure is 760 torr. 39 Evaporation, Vapor Pressure, and Boiling Point ln Pvap = y = DHvap 1 R T m x + b +C Evaporation, Vapor Pressure, and Boiling Point Vapor Pressure 42 Clausius-Clapeyron Equation ln P = - DHvap RT +C • By taking measurements at two temps, we get: P1 DHvap 1 1 ln P2 R T2 T1 43 The normal boiling point of benzene is 80.1 °C, and ΔHvap = 30.8 kJ/mol, what is boiling point of benzene on top of Mount Everest, where P = 260 mm Hg • P1 = 760 mm Hg; P2 = 260 mm Hg; t1 = 80.1oC, T2 = ? • ΔHvap = 30.8 kJ/mol P1 DHvap 1 1 • ln P2 R T2 T1 , R = 8.3145 J / K . mol • Solve for T2 (the boiling point for benzene at 260 mm Hg). T2 = 320 K ; t = 47oC (boiling point is lower at lower pressure) 44 • • • • • Boiling point ~120°C Boiling point ~95°C Boiling point ~75°C Melting point ~95°C Melting point ~75°C Vapor Pressure (mm Hg) Which statement is true? 800 600 400 200 0 0 25 50 75 100 Temperature (°C) 45 • • • • • Boiling point ~120°C Boiling point ~95°C Boiling point ~75°C Melting point ~95°C Melting point ~75°C Vapor Pressure (mm Hg) Which statement is true? 800 600 400 200 0 0 25 50 75 100 Temperature (°C) 46 Solids An amorphous solid does not possess a well-defined arrangement and long-range molecular order they do not have a fixed sharp melting point. . A glass is an optically transparent fusion product of inorganic materials that has cooled to a rigid state without crystallizing •Structure of a crystalline solid is based on the unit cell, a basic • repeating structural unit. Crystalline quartz (SiO2) Non-crystalline quartz glass 47 Kinds of Solids Amorphous Solids: Particles are randomly arranged and have no ordered long-range structure. Example - rubber. Crystalline Solids: Particles have an ordered arrangement extending over a long range. • ionic solids • molecular solids • covalent network solids • metallic solids Kinds of Solids Ionic Solids: Particles are ions ordered in a regular three-dimensional arrangement and held together by ionic bonds. Example - sodium chloride. lattice point At lattice points: Unit Cell Unit cells in 3 dimensions • Atoms • Molecules • Ions 50 Simple Cubic Packing Body-Centered Cubic Packing Crystal Structure Simple Cube Body-Centered Cube: 52 Crystal Structure 04 Face-Centered Cube: 53 Crystalline Solids We can determine the empirical formula of an ionic solid by determining how many ions of each element fall within the unit cell. 54 Hexagonal Closest Pack A-B-A-B- Space used 74% Cubic Closes Pack • Space used 74% • A-B-C-A-B-C 56 57 Unit Cells and the Packing of Spheres in Crystalline Solids Unit Cell: A small repeating unit that makes up a crystal. Types of Crystals What are the empirical formulas for these compounds? (a) Orange:chlorine; Gray:cesium (b) Blue:sulfur; Gray: zinc (c) Green:fluorine, Gray: calcium (a) (b) (c) 59 CsCl ZnS CaF2 Types of Crystal 04 • Carbon: 60 Carbon Allotropes Types of Crystals Covalent Crystals • Lattice points occupied by atoms • Held together by covalent bonds • Hard, high melting point lattice points: • Atoms • Molecules • Ions carbon atoms diamond graphite 62 Types of Crystals Molecular Crystals • Lattice points occupied by molecules • Held together by intermolecular forces • Soft, low melting point 63 11.6 Types of Crystals Metallic Crystals • Lattice points occupied by metal atoms • Held together by metallic bonds • Soft to hard, low to high melting point • Good conductors of heat and electricity Cross Section of a Metallic Crystal nucleus & inner shell emobile “sea” of e- 64 • • • • Ionic Crystals Covalent Crystals Molecular Crystals Metallic Crystals 65 Simple cubic cell Body-centered cubic 66 Face-centered cubic When silver crystallizes, it forms face-centered cubic cells. The unit cell edge length is 409 pm. Calculate the density of silver. d= m V V = a3 = (409 pm)3 = 6.83 x 10-23 cm3 4 atoms/unit cell in a face-centered cubic cell 1 mole Ag 107.9 g -22 g x m = 4 Ag atoms x = 7.17 x 10 mole Ag 6.022 x 1023 atoms 7.17 x 10-22 g m 3 = = 10.5 g/cm d= V 6.83 x 10-23 cm3 67 X-Ray Crystallography • Diffraction is the scattering of radiation by an object containing regularly spaced lines, with a spacing that is equivalent to the wavelength of radiation. • Diffraction is due to interference between two waves passing through the same region of space at the same time. 68 69 Extra distance = BC + CD = 2d sinq = nl (Bragg Equation) 70 X rays of wavelength 0.154 nm are diffracted from a crystal at an angle of 14.170. Assuming that n = 1, what is the distance (in pm) between layers in the crystal? nl = 2d sin q n=1 q = 14.170 l = 0.154 nm = 154 pm nl 1 x 154 pm = = 315 pm d= 2 x sin14.17 2sinq 71 1 mol 6.022 x 1023 atoms Titanium metal has a density of 4.54 g/cm3, and an atomic radius of 144.8 pm. What is the structure of cubic unit cell? • mass of one Ti atom = 7.951 x 10-23 g/atom (problem 10.78) • r = 144.8 pm = 144.8 x 10-12 m • r = 144.8 x 10-12 m = 1.448 x 10-8 cm • Calculate the volume and then the density for Ti assuming it is Simple (primitive) cubic, body-centered cubic, and face-centered cubic. Compare the calculated density with the actual density to identify the unit cell. • For primitive cubic: • a = 2r; volume = a3 = [2(1.448 x 10-8 cm)]3 = 2.429 x 10-23 cm3 • density = m/v = 3.273 g/cm3 72 • For face-centered cubic: • a = √8. r; volume = a3 = [2√2 . (1.448 x 10-8 cm)]3 = 6.870 x 10-23 cm3 • density = = 4.630 g/cm3 • For body-centered cubic: • a = 4r/√3; volume = a3 = 3.739 x 1023 cm3 • density = = 4.253 g/cm3 • The calculated density for a face-centered cube (4.630 g/cm3) is closest to the actual density of 4.54 g/cm3. Ti crystallizes in the face-centered cubic unit cell. 73 Phase Diagrams 01 74 Water Phase Diagrams Normal BP: Occurs at 1 atm. Critical Point: A combination of temperature and pressure beyond which a gas cannot be liquefied. • Critical Temperature: The temperature beyond which a gas cannot be liquefied regardless of the pressure. • Critical Pressure: The pressure beyond which a liquid cannot be vaporized regardless of the temperature. Supercritical Fluid: A state of matter beyond the critical point that is neither liquid nor gas. Triple Point: A point at which three phases coexist in equilibrium. Supercritical CO2 Caffeine extraction from green coffee with supercritical CO2 Application of Supercritical CO2 in dry cleaning 77 Phase Diagrams Carbon Dioxide Phase Diagrams 05 • Approximately, what is the normal boiling point and what is the normal melting point of the substance? • What is the physical state when: i. T = 150 K, P = 0.5 atm ii. T = 325 K, P = 0.9 atm iii. T = 450 K, P = 265 atm 79 The End 80 Coordination Numbers 81 82
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