G.C.5 STUDENT NOTES WS #2 1 Radians and Arc Length The arc length of an arc is the physical distance along the circumference between the two points of the arc. We know that the full arc length of a circle is known as its circumference. So to calculate a portion of that circumference we calculate a percentage of the circumference. If the arc is measured in degrees we get the θ following relationship, arc length = s = 2π r (% of the circumference). Lowercase s is often used the 360° variable used to symbolize arc length. s 60° 5 cm θ 60° arc length = s = 2π r = 360° 360° 10π 5π 1 = ≈ 5.24 cm 2π (5) = (10π ) = 6 3 6 θ 90° arc length = s = 2π r = 360° 360° 32π 1 = 8π ≈ 25.13 cm 2π (16) = (32π ) = 4 4 s 90° 16 cm Now if the angle is measured in terms of radians instead of degrees a nice thing happens to the formula….. θ arc length = s = 2π r = θ r (% of the circumference). Look how simple the formula for arc length is now 2π when our angle is measured in radians, s = Ɵr. Arc Length, s = Ɵr, when the angle is measured in radians. π s π 5π arc length = s = θ r = 5 = ≈ 5.24 cm 3 3 3 5 cm s π 2 16 cm π arc length = s = θ r = 16 = 8π ≈ 25.13 cm 2 Example #1 What is the length of an arc if the circle has a radius of 4 cm and the central angle is 120°? 8 120 s= 2 π (4) = π cm ≈ 8.38 cm 3 360 Example #2 What the length of the an arc if the circle has a 4π radius of 10 cm and the central angle is ? 5 4π s = Ɵr = 10 = 8π cm ≈ 25.13 cm 5 G.C.5 WORKSHEET #2 Name: ________________________________ Period ______ 1 1. Determine the arc length. a) Central Angle of 30°°, radius of 3 cm b) Central Angle of 90°°, radius of 8 cm c) Central Angle of 72°°, radius of 10 cm s = ____________ (E) s = ____________ (E) s = ____________ (E) d) Central Angle of π 4 rad . , e) Central Angle of 2π rad . , 3 f) Central Angle of 4π rad . , 5 radius of 12 cm radius of 15 cm radius of 10 cm s = ____________ (E) s = ____________ (E) s = ____________ (E) 2. After class Angela says, “I didn’t understand how he got the formula for arc length, s = Ɵr. Did you understand it?” Explain to Angela where the formula comes from. 3. Determine the arc length of the following. a) b) 4π rad. 5 10 cm s = ____________ (E) c) 7π rad. 6 3 cm s = ____________ (E) d) π rad. 6 3π rad. 2 4 cm s = ____________ (E) 18 cm s = ____________ (E) 4. Circle G has a radius of 7 cm. After computing an arc on circle G Nancy finds the arc length to be 14 cm. She exclaims, “The central angle must be 2 radians.” How did she know this? G.C.5 WORKSHEET #2 2 5. Determine the missing information. π a) s = 4π cm, r = 8 cm b) Ɵ = 0.8 rad., s = 8 cm c) r = 4.5 cm, Ɵ = Ɵ = ____________ rad. r = ___________ cm s = ___________ cm e) s = 10π cm, r = 8 cm f) Ɵ = Ɵ = ____________ rad. r = ___________ cm 2π rad., s = 5π cm 5 g) r = 8 cm, Ɵ = π 2 3 rad., rad., s = ___________ cm d) Ɵ = 7π rad., s = 28π cm 4 r = ___________ cm h) Ɵ = 5π rad., s = 10π cm 6 r = ___________ cm 6. Find the radius of a circle in which a central angle of 5 radians intercepts an arc length of 62.5 feet? 7. Find the measure (in radians) of a central angle that intercepts an arc of length 16 cm in a circle of radius 8 cm. 8. Find the measure (in radians) of a central angle that intercepts an arc of length 24π π cm in a circle of radius 10 cm. Nome: f141y G.C.s WORKSHEET #2 period 1. Determine the arc length. a) Central Angle of 30o, radius of 3 cm y'= b) CentralAngle of 90", radius of 8 cm c) Central Angle of 72", radius of 10 cm 9r6-A-rGl) s= ?* bq('q) dc,^ = [*' fuo ,= {,q Jbo gy d) CentralAngle s= ol L rad., (E) radius of 15 cm radius of 12 cm zd : -7 t^* 2. After S= tU (E) it?" ,o4., f) CentratAngle o1? 0r) A, Cvlr\ lEl s= (E) "l didn't understand how Anc t"%r^ -tg a_ pzvcaa4aT.-. o+ (r<,) = e S. Ll ,o4., radius of 10 cm he got the formula for arc length, s = Explain to Angela where the formula comes from. class Angela says, understand (E) $r a- s= ol4 e) CentratAngle = Vt ctrx s ccTcD Or. Did you a(-"*-<-e'' 9r- 3. Determine the arc length of the following. b) a) d) c) s=er,'+5d ra{= 1 -_ 10 cm \ I t..' \ *,-/ - -/ 'ry b) s= (E) 4. Circle G has a radius of 7 r= *rc^^- (r) cm. After computing She exclaims, 'The central angle must be 2 s= 5{rc) - .-" (E) r= 3lf Cn\1s1 an arc on circle G Nancy finds the arc length to be 14 cm. radians." How did she know this? 6.C.5 WORKSHEET #2 5. Determine the missi,ng information. als=4ncm, r=8 cm 'b)O =0.8 rad., s =8 1T cm c) r=4.5cm,O=-*rad., 9=9r- 9=*r- tllt = eG) "r= 4Y =0 6 Q= v ,2r - f) lr- e=+rad.,s=5ncm g) gv5= "e = lfi=O ? 6. ! 1f ecr) s= 4T h)O= 9 'r^a. 5 a -'{ $=62,T{+ ,^ r= lengh of 62.5 feet? =9v- 6z'<:5t V;W Find the measure (in radians) of a central angle in a circle of radius 8 cm. 7. - that intercepts an arc of length 16 cm g. Find the measure (in radians) of a central angle that intercepts an arc of length24n cm in a circle of radius 10 cm. $ = 21'1( f= (o cvv..' 5- en ct,,.': 1on cm :47 Find the radius of a circle in which a central angle of 5 radians intercepts an arc L-/J, ,^a.,'r= (t)b) .L/( ,=' r= 4 cm r=8cm,O=-i-rad., 3 =&r [o7T= 7L ,^a.,s = 28n cm k'') 5= [') l( rad. rl e)s=10ncm,r=8cm (9) d) o = 7vY ry -= 'saa) e
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