1 Longitudinal Phase-Space: How to obtain a full Picture - by Markus Hüning The motion of the particles inside the bunches of accelerated beams can be described in their 6-dimensional phase-space. In common use the phase-space is divided into three 2-dimensional sub-spaces: 2 x transverse (offset - divergence) 1 x longitudinal (energy - time). Most measurement devices only can measure projections of the phasespace (transverse profile, energy profile, longitudinal profile). For the understanding of effects it is often desireable to measure the phase-space distribution rather than one single projection. That is when TOMOGRAPHY enters the game! Related Articles: • The Idea of Tomography • The ART of Reconstruction • How to cool down the Result • In Phase Space • The Bunches of TTF • Wakefields • Outlook http://www.desy.de/~mhuening Save Energy with every electron accelerated: Join TESLA! Markus Hüning, February 12, 2001 2 The Idea of Tomography The Idea of Tomography Given a distribution in 2 dimensions (particle density in phase-space, tissue in human body, ...) Take Projections with different angles (Radon Transform) 0˚ 45˚ 90˚ Algorithm to reconstruct original distribution from the projections 135˚ 180˚ http://www.desy.de/~mhuening Markus Hüning, February 12, 2001 3 The ART of Reconstruction The ART of Reconstruction There are many algorithms to perform the reconstruction: • Filtered backprojection -> see M. Geitz • Fourier reconstruction • Algebraic reconstruction technique (ART)-> discussed here • Maximum Entropy Method (MENT) -> coming soon • ... The first to methods take advantage of the similarity of Fourier-Transform and Radon-Transform, The third method performs an inversion of matrices, the fourth method additionally maximizes the distribution’s entropy. Next I will explain the ART-method http://www.desy.de/~mhuening Markus Hüning, February 12, 2001 4 The ART of Reconstruction The ART Algorithm Let the phase-space-distribution being given as a row-vector: 1.4 1.2 1.4 1.2 1 1 0.8 0.8 0.6 0.6 0.4 0.2 0.4 0 60 50 60 40 50 30 0.2 40 30 20 20 10 10 0 0 0 0 10 20 30 40 50 60 1 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 500 1000 1500 2000 2500 3000 3500 Also the projections may be merged into one single row-vector: 20 18 16 14 12 10 8 6 4 2 0 0 50 100 150 200 250 300 350 400 450 500 The projections then can be described as matrix-multiplication: g = A ⋅ F ⇒ Atells how projections are done http://www.desy.de/~mhuening Markus Hüning, February 12, 2001 5 The ART of Reconstruction Doing just a simple inversion of A doesn’t work for noisy data F = A –1 ⋅g Instead one uses Kaczmarz’s method T ω F j = F j – 1 + ----------- ( g j – a j F j – 1 )a j 2 aj j = 1…N with aj being the jth row of A, gj the jth value of g, Fj the full vector of F in jth (sub-)iteration One full turn of j=1...N is one iteration of the algorithm. equations The way of Kaczmarz’s method F1 http://www.desy.de/~mhuening F0 Markus Hüning, February 12, 2001 6 The ART of Reconstruction One example of that algorithm original reconstructed 10 10 20 20 30 30 40 40 50 50 60 60 10 20 30 40 50 60 10 20 30 40 50 60 1 0.8 0.8 0.6 0.6 0.4 0.4 0.2 0.2 0 60 60 40 20 10 20 30 40 50 60 40 20 10 20 30 40 50 60 Student Version of MATLAB http://www.desy.de/~mhuening Markus Hüning, February 12, 2001 7 The ART of Reconstruction But when you don’t take projections for 180˚ original reconstructed 10 10 20 20 30 30 40 40 50 50 60 60 10 20 30 40 50 60 10 1 0.8 0.8 0.6 0.6 0.4 0.4 0.2 0.2 20 30 40 50 60 0 60 60 40 20 10 20 30 40 50 60 40 20 10 20 30 40 50 60 Student Version of MATLAB http://www.desy.de/~mhuening Markus Hüning, February 12, 2001 8 The ART of Reconstruction What happens there? Compare the projections (original and reconstructed) 20 15 10 5 0 −5 0 50 100 150 200 250 300 350 400 450 500 What looks very small here has a big impact on the reconstructed distribution. -> It is not sufficient to only fit the projections http://www.desy.de/~mhuening Markus Hüning, February 12, 2001 9 How to cool down the Result How to cool down the Result From Thermodynamics you may know the Entropy S = log ∆Γ ∆Γ: # of states The Entropy is the bigger the bigger the disorder in the system. For S=0 the system is perfectly in order, meaning in one well defined state. Here we define something similar (and also call it entropy): η( f ) = – ∫ ∫ f (x,y) log ( f (x,y) ) dx dy f : distribution function This doesn’t look very similar by first impression, but η ∼ log ( F ) F = f dx dy ∫∫ This expression has to be maximized to obtain the solution with the least information content (there is a “-” missing somewhere) -> the simplest description (expected to be the best) The algorithm doing this maximization is called MENT. Another point is the representation of the phase-space: The MENT algorithm divides the phase-space into polygons as seen here. http://www.desy.de/~mhuening Markus Hüning, February 12, 2001 10 How to cool down the Result The same example as above: original reconstructed −5 −5 0 0 5 −5 0 5 −5 5 0 5 0.15 0.15 0.1 0.1 0.05 5 5 0 0 0.05 5 0 5 0 0 −5 −5 http://www.desy.de/~mhuening −5 −5 Markus Hüning, February 12, 2001 11 In Phase Space In Phase Space So far the the tomography, But how to achieve rotation of phase space? a) Transverse Phase Space Quadrupole OTR off Quadrupole OTR Quadrupole OTR Quadrupole OTR Quadrupole maximum current http://www.desy.de/~mhuening OTR Markus Hüning, February 12, 2001 12 In Phase Space b)Longitudinal rf module Phase Space 0˚ rf module 30˚ rf module -30˚ rf module -90˚ rf module 90˚ =>impossible to rotate 180˚! http://www.desy.de/~mhuening Markus Hüning, February 12, 2001 13 The Bunches of TTF The Bunches of TTF One result from longitudinal tomography in the TTF 5 4 4 3 3 2 2 1 1 0 0 −1 −1 ∆ E [MeV] 5 −2 −6 −4 −2 0 2 −2 0 4 50 100 Population [a.u.] comparison with interferometer 80 1 Charge Distribution (Current) [a.u.] Population [a.u.] 70 60 50 40 30 0.8 0.6 0.4 0.2 20 −6 −4 −2 0 Time [ps] http://www.desy.de/~mhuening 2 4 0 −10 −8 −6 time [ps] −4 −2 0 Markus Hüning, February 12, 2001 14 The Bunches of TTF ∆E [MeV] What could have been expected −6 6 −4 4 −2 2 0 0 2 −2 4 −4 6 −6 8 −8 10 −10 12 −3 −2 −1 0 1 −12 0 0.5 1 1 incoming beam σe = 100keV σt = 3ps 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 −3 −2 −1 Time [ps] http://www.desy.de/~mhuening 0 1 Markus Hüning, February 12, 2001 15 The Bunches of TTF ∆E [MeV] Or maybe this −6 6 −4 4 −2 2 0 0 2 −2 4 −4 6 −6 8 −8 10 −10 12 −3 −2 −1 0 1 −12 0.2 0.4 0.6 0.8 1 1 incoming beam σe = 180keV σt = 1ps 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 −3 −2 −1 Time [ps] http://www.desy.de/~mhuening 0 1 Markus Hüning, February 12, 2001 16 The Bunches of TTF ∆E [MeV] Assuming a non-gaussian bunch from Injector: −6 6 −4 4 −2 2 0 0 2 −2 4 −4 6 −6 8 −8 10 −10 12 −3 −2 −1 0 1 −12 0 0.5 1 1 0.9 1.8 0.8 1.6 0.7 1.4 0.6 1.2 0.5 1 0.4 0.8 0.3 0.6 0.2 0.4 0.1 0.2 −3 −2 −1 Time [ps] http://www.desy.de/~mhuening 0 1 0 σt=0.7ps lt=8ps σe=180keV −10 −5 Time [ps] 0 Markus Hüning, February 12, 2001 17 Wakefields Wakefields ∆E [MeV] The method of longitudinal tomography is especially interesting for studying longitudinal wakefields because it can directly probe the wake-potential - especially when I can switch on/off the wake −6 6 −4 4 −2 2 0 0 2 −2 4 −4 6 −6 8 −8 10 −10 12 −3 −2 −1 0 1 −12 0 0.5 1 1 0.9 1.8 0.8 1.6 0.7 1.4 0.6 1.2 0.5 1 0.4 0.8 0.3 0.6 0.2 0.4 0.1 0.2 −3 −2 −1 Time [ps] http://www.desy.de/~mhuening 0 1 0 −10 −5 Time [ps] 0 Markus Hüning, February 12, 2001 18 Wakefields sandblasted What has been seen so far estimate 4σ regular estimate 4σ 0 1 0.5 1 estimate 4σ 1.5 2 2.5 3 3.5 4 Particle 0 -1 Energy [MeV] -2 -3 Energy Deviation [MeV] 4.5 estimate based on gaussian bunch, σz=250 µm http://www.desy.de/~mhuening Markus Hüning, February 12, 2001 19 Outlook Outlook Phase-Space tomography is a powerfull means to study effects on the beam, especially longitudinal tomography offers the possibility for interesting insight into the beam dynamics: • Bunch Compressors • Coherent Synchrotron Radiation • Wakefields • Cross-Calibration However, there are some open questions • What’s the resolution? From energy resolution (7*10-5) I expect 1.3 fs*MeV, but there might be some additional effect from the reconstruction, phase errors and position jitter • Where do the spikes in the reconstruction come from (MENT)? • What about CSR in the spectrometer dipole? • What, if I combine longitudinal and transversal tomography? Is it possible to measure some slice emittance? • Is it possible to use longitudinal tomography in the Injector? http://www.desy.de/~mhuening Markus Hüning, February 12, 2001
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