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RESOMOST
SAMPLE TEST PAPER
TARGET : AIPMT 2015
FOR CLASS XII (APPEARED) & XII PASSED STUDENTS
Duration : 3 Hours
Max. Marks : 800
INSTRUCTIONS
v uq
ns'k
A. General :
A. lkekU; :
1.
1.
This Question Paper contains 200 (50 Chemistry, 50
Physics & 100 Biology) questions.
2.
The question paper CODE is printed on the right hand
50 Physics & 100 Biology)
2.
top corner on this sheet of this booklet.
3.
Rough work is to be done on the space provided for
Blank paper, clipboard, log tables, slide rules,
3.
The answer sheet, a machine-gradable Objective
iz'u i=k d k d ksM CODE izLrqr i`"B d sÅ ij nk,¡d ksusesa
jQ d k;Zijh{kkiq
fLrd kes
ad soy fu/kkZ
fjr t xg ij ghd hft ,A
;g t xg iz
R;s
d i`
"B ij uhpsd h vks
j gS
A
4.
calculators, cellular phones, pagers and electronic
gadgets in any form are not allowed.
5.
iz'u gSaA
Nik gSA
this purpose in the Test Booklet only. This space is
given at the bottom of each page.
4.
;g iqfLrd kvkid kiz'u i=kgSA ft lesa200 (50 Chemistry,
ijh{kk Hkou d svUnj d ksjsd kxt ] fDyi cksMZ] ykWx Vscy]
LykbM : y]d Sy d qy sVj]lsy qy j Q ksu]ist j vkSj bysDVªkfud
mid j.k fd lh Hkh : i esafuf"k) gSaA
5.
Response Sheet (ORS), is provided separately.
mRrj i=k],d ;a
=kJs
.khd j.k;kXs; i=kObjective Response
Sheet (ORS) gSt ksfd
vyx lsfn;st k;s
xs
a
A
a
6.
Do not Tamper / mutilate the ORS or this booklet.
6.
iq
fLrd k vFkok ORS es
au rksgs
j Qs
j d js
au gh mlsfod r` d js
Aa
7.
Do not break the seals of the question-paper booklet
7.
t c rd ifjos"kd funsZ'k ughansarc rd iz'u i=k d h lhy
before instructed to do so by the invigilators.
d ksugha[kksay sA
B. Question paper format and Marking scheme :
B. iz
'ui=k xzUFkkd kj
8.
The question paper consists of 3 Parts (Part-A
(Chemistry), PART-B (Physics) & PART-C (Biology)).
8.
For each question, you will be awarded 4 marks if
you darken the bubble corresponding to the correct
9.
9.
answer and zero marks if no bubble is darkened. In
case of bubbling of incorrect answer, minus one (–1)
mark will be awarded.
v kSj v ad u v k;kst u :
iz'ui=k3 Hkkxksad kgS(Hkkx-A (Chemistry), Hkkx-B (Physics)
rFkk Hkkx-C (Biology) gSA
[k.M –I d s izR;sd iz'u d s fy,] ;fn vkius flQ Z mfpr
mRrjokyscqYysd ksgh d kyk fd ;k gSrksvkid ks4 v ad fn;s
t k,axsA ;fn fd lh Hkh cqYysd ksd kyk ughafd ;k gSrks'kwU;
v ad fn;k t k,xkA xyr mRrj d scqYysd ksd kyk d jusij
_ .kkRed ,d (–1) v ad fn;k t k,xkA
PART-A
Atomic masses : [H = 1, D = 2, Li = 7, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24, Al = 27,
Si = 28, P = 31, S = 32, Cl = 35.5, K = 39, Ca = 40, Cr = 52, Mn = 55, Fe = 56, Cu = 63.5, Zn = 65,
As = 75, Br = 80, Ag = 108, I = 127, Ba = 137, Hg = 200, Pb = 207]
Straight Objective Type
This section contains 50 multiple choice
questions. Each question has 4 choices (1), (2),
(3) and (4) for its answer, out of which ONLY
ONE is correct.
1. Incorrect statement about interhalogen
compound is :
(1) These compound can be used as non
aqueous solvent.
(2) Interhalogen compound are very useful
fluorinating agents.
l h/ksoLrqfu"B izd kj
bl [k.M es
a50 cgq& fod Yihiz
'u gS
A iz
a
R;sd iz
'u d s
4 fod Yi (1), (2), (3) rFkk (4) gS
a]ft uesalsfl Q Z,d
l gh gSA
1. vUrjgS
y kst u ;kSfxd d sfy , vlR; d Fku gS:
(1) bu ;kS
fxd ksad ksvt y h;&foy k;d d s: i esaiz;qDr
fd ;k t krk gSA
(2) vUrjgS
y kts u ;kfSxd cgq
r mi;kxsh¶ykjshuhd r` ;kfSxd
gksrsgSA
(3) These all are covalent & dimagnetic in
nature.
(3) ;g lHkh iz
d `fr esalgla;kst hrFkkizfrpqEcd h; gksrs
(4) Generally interhalogen compound are less
reactive then halogens.
(4) lkekU;r% vUrjgS
y kst u] gSy kst u d h vis{kk d e
2. Choose the incorrect statement :
(1) Size of 4d & 5d series elements is almost
same.
(2) Generally negative value of standard
reduction potential (M2+/M) of 3d-series
element decreases across the period.
gSA
fØ ;k'khy gksrsgSaA
2. vlR; d Fku d kspq
fu;s:
(1) 4d o 5d Js
.khd srRoks
ad kvkd kj y xHkx leku gks
rk
gSA
(2) lkekU;r%3d-Js
.khrRoksad svkorZesaekud vip;u
foHko d s_ .kkRed eku (M2+/M) esad eh vkrh gSA
(3) Cr2O72– has one type Cr–O bond length.
(3) Cr2O72– es
a,d izd kj d h Cr–O cU/k y EckbZgSA
(4) Generally actinide and lanthanide shows +3
oxidation state.
(4) lkekU;r% ,fDVukbM o y S
UFksukWbM +3 vkWDlhd j.k
3. Correct fact about tyndall effect is :
voLFkk n'kkZrk gSA
3. fVa
My izHkko d sckjsesalR; d Fku fuEu gS:
(1) The diameter of dispersed particles is much
smaller than the wave length of light used.
(1) ifjf{kIr d .k d k O;kl] iz
;qDr d h xbZizd k'k d h
(2) Refractive indices of the dispersed phase
and the dispersion medium differ greatly in
magnitude.
(2) ifjf{kIr iz
koLFkk o ifj{ksi.k ek/;e d k viorZukad
(3) It is shown by true solution.
(3) blsokLrfod foy ;u }kjk n'kkZ
;k t krk gSA
(4) All are correct
(4) lHkh lgh gS
A
RESONANCE
rjaxnS/;Zd h vis{kk d e gksrk gSA
ifjek.k esavf/kd fHkUu gksrsgSA
XIII ResoMost_STP – 1
4. Gold (atomic radius = 0.144 nm) crystallises in
face - centred unit cell. What is the length of a
side of the cell?
(1) 0.407nm
(3) 0.332 nm
(2) 0.288nm
(4) 0.432nm
5. What is the order of freezing point of aqueous
solution if same mole of acetic acid,
trichloroacetic acid and tri fluoroacetic acid are
added in given amount of water
(1) Acetic acid < Trichloroacetic acid
Tri fluoroacetic acid
<
(2) Tri fluoroacetic acid >
Trichloroacetic acid
>
Acetic acid
4. Q yd &d f
sUnz
r bd kbZd ks
f"Bd kes
axks
YM ¼ijek.oh; f=kT;k
= 0.144 nm) fØ LVy hd `
r fd ;k t krk gSA d ksf"Bd k d s
fd ukjsd h y EckbZD;k gS?
(1) 0.407nm
(2) 0.288nm
(3) 0.332 nm
(4) 0.432nm
5. t y h; foy ;uks
ad sfgekad d k Ø e D;k gksxkA ;fn fn;s
x;st y esa,flfVd vEy ]VªkbDy ksjks,flfVd vEy rFkk
Vªkb¶y ksjks,flfVd vEy d sleku eksy fey k;st krsgks
(1) ,flfVd vEy
< Vª
kbDy ksjks,fl fVd v Ey <
Vªkb¶y ksjks,flfVd vEy
(2) Vª
kb¶y ksjks,flfVd vEy
> ,flfVd vEy >
VªkbDy ksjks,flfVd vEy
(3) Trichloroacetic acid > Tri fluoroacetic acid
> Acetic acid
(3) Vª
kbDy ksjks,flfVd vEy > Vªkb¶y ksjks,flfVd vEy
(4) Acetic acid > Trichloroacetic acid
Tri fluoroacetic acid
(4) ,flfVd vEy
>
6. Determine the amount of CaCl2 dissolve in 2.5
lit of water such that its osmatic pressure is 0.75
atm. at 27ºC. If degree of dissociation of CaCl2
is 75%.
(1) 3.38gm
(2) 5.27gm
(3) 4.25 gm
(4) 52.7gm
7. The conversion of molecule X to Y follow second
order kinetics. If concentration of X is increased
to three times. How will it effect the rate of
formation of Y
(1) Rate increase by 8 times
(2) Rate increase by 9 times
(3) Rate increase by 6 times
(4) Rate decrease by 8 times
8. What will be the correct order for wave length of
absorption in the visible region for the following
complex :
(a) [Ni(NO2)6]4– (b) [Ni(NH3)6]2+ (c) [Ni(H2O)6]2+
(1) a < b < c
(3) a > c > b
RESONANCE
(2) a > b > c
(4) a < c < b
> ,flfVd vEy
> Vª
kbDy ksjks,flfVd vEy >
Vªkb¶y ksjks,flfVd vEy
6. 2.5 y hVj t y es
afoy ; CaCl2 d h ek=kk Kkr d hft ,
;fn 27ºC ij bl foy ;u d k ijklj.k nkc 0.75
ok;qe.My h; gSrFkk CaCl2 d sfo;kst u d h ek=kk 75%
gSA
(1) 3.38gm
(2) 5.27gm
(3) 4.25 gm
(4) 52.7gm
7. v.kqX d kY es
aifjorZ
u f}rh; d ks
fV cyxfrd hd kikyu
d jrkgS
A ;fn X d hlkUnz
rkd ksrhu xq
ukc<+
kfn;kt krk
gS]rksY d sfuekZ.k d h nj ij D;k izHkko iM+sxk
(1) nj 8 xq
uk c<+t k;sxh
(2) nj 9 xq
uk c<+t k;sxh
(3) nj 6 xq
uk c<+t k;sxh
(4) nj 8 xq
uk d e gkst k;sxh
8. fuEu la
d qy ksad sfy , n`'; {ks
=kesavo'kksf"kr rjaxnS
/;Zd k
lgh Ø e D;k gksxk :
(a) [Ni(NO2)6]4– (b) [Ni(NH3)6]2+ (c) [Ni(H2O)6]2+
(1) a < b < c
(2) a > b > c
(3) a > c > b
(4) a < c < b
XIII ResoMost_STP – 2
9. Hybridization and magnetic behaviour of
complex K4[Mn(CN)6] is :
9. la
dq
y K4[Mn(CN)6] d sfy, la
d j.ko pq
Ecd h; O;ogkj
fuEu gS:
(1) d2sp3, diamagnetic
(1) d2sp3, iz
frpqEcd h;
(2) d2sp3, paramagnetic
(2) d2sp3, vuq
p qEcd h;
(3) sp3d2, diamagnetic
(3) sp3d2, iz
frpqEcd h;
(4) sp3d2, paramagnetic
(4) sp3d2 ] vuq
p qEcd h;
10. A solution of CuSO4 is electrolysed for 10
minutes with a current of 1.5 amp what is the
mass of copper deposite at cathode (atomic
weight of copper = 63) :
10. CuSO4 d s,d foy ;u d k 1.5 ,fEi;j /kkjk d slkFk
10 fefuV d sfy , oS
| qr vi?kVu fd ;kt krkgSA d SFkksM+
ij fu{ksfir d kWij d k nzO;eku D;k gS\ (d kWij d k
ijek.oh; nzO;eku = 63) :
(1) 0.29gm
(2) 0.35gm
(1) 0.29gm
(2) 0.35gm
(3) 0.0048gm
(4) 0.7gm
(3) 0.0048gm
(4) 0.7gm
11. 14 moles of A and 20 moles of B , 8 moles of C
is formed in the following reaction 3A + 4B 
2C then.
(1) 8 mole of B react
11. A d s14 eks
y , B d s20 ekys lsC d s8 ekys fuEu vfHkfØ ;k
(3A + 4B  2C) es
acursgSarc %
(1) B d s8 eks
y fØ ;k d jrsgSa
(2) A d s10 eks
y fØ ;k d jrsgSa
(2) 10 mole of A react
(3) B d s4 eks
y cps
(3) 4 mole of B left
(4) A d s8 eks
y cps
(4) 8 mole of A left
12. In which of the following ‘N’ atom is not sp2
hybridised
(1) HNO4
(2) FNO3
(3)
(4) B3N3H6
13. The first three successive ionisation energies
of an element Z are 900, 1757 and 14850 kJ
12. fuEu ea
slsfd l esa‘N’ ijek.kqsp2 lad fjr ughagSA
(1) HNO4
(2) FNO3
(3)
(4) B3N3H6
13. ,d rRo Z d h iz
Fke rhu Ø ekxr vk;uu Å t k;ZsØ e'k%
900, 1757 rFkk14850 kJ mol–1 gS
A rRo Z lEcfU/kr gS
&
mol–1 respectively. The element Z belongs to
(1) oxZ
-1 ls
(2) oxZ
-2 ls
(1) group-1
(3) group-15
(3) oxZ
-15 ls
(4) oxZ
-17 ls
(2) group-2
(4) group-17
14. Moles fraction of benzene in vapour phase which
is in equilibrium with solution of toluene (P° = 80
mm) and benzene (P° = 120 mm) having one
mole of each
(1) 0.80
(2) 0.20
(3) 0.40
(4) 0.60
RESONANCE
14. ok"i voLFkkes
acsUt hu d heksy fHkUu D;kgS]t ksVkWy wbu
(P° = 80 mm) rFkkcs
at hu (P° = 120 mm) d sfoy ;u
d slkFk lkE;koLFkk esagSrFkk ;g foy ;u izR;sd ?kVd
d s,d eksy j[krk gSA
(1) 0.80
(2) 0.20
(3) 0.40
(4) 0.60
XIII ResoMost_STP – 3
15. If 40 ml of 0.2 M CH3COOH is titrated with 0.2 M
NaOH. How many ml of base must be added to
form a buffer solution with greatest buffering
capacity
(1) 10 ml
15. ;fn 0.2 M CH3COOH d s40 ml d ks0.2 M NaOH d s
lkFkvuqekfir fd ;kt krkgSA rc lokZf/kd cQ j {kerk]
oky scQ j foy ;u d kscukusd sfy , {kkj d sfd rusmL
fey kuspkfg;s\
(1) 10 ml
(2) 20 ml
(3) 30 ml
(4) 40 ml
(2) 20 ml
(3) 30 ml
(4) 40 ml
16. Suppose that a hypothetical atom gives a red,
green, blue and violet line spectrum . Which
jump according to figure would give off the red
spectral line.
(1) 3  1
(2) 2  1
(3) 4  1
(4) 3  2
17. Calculate the potential of hydrogen electrode in
contact with a solution of 5 × 10–3M of Ba(OH)2
at 1 atm pressure and 298K temperature.
(1) –0.059V
16. ekukfd ,d d kYifud ijek.kq,d yky]gjk]uhykrFkk
cSaxuh js[kh; LisDVªe nsrk gSA fp=k d svuql kj d kSulk
laØ e.ky ky LisDVªy js[kknsxkA
(1) 3  1
(2) 2  1
(3) 4  1
(4) 3  2
17. 1 atm nkc o 298K rki ij 5 × 10–3M Ba(OH)2 d slkFk
lEid Zes
agkbMª
kts u byS
DVª
kMW d kfoHko ifjd fyr d hft ,A
(1) –0.059V
(2) 0.059V
(2) 0.059V
(3) 0.59V
(3) 0.59V
(4) – 0.59V
(4) – 0.59V
18. Which of the following statement is incorrect ?
(1) Among O 2+ , O 2 and O 2 - the stability
decreases as O2+ > O2 > O2(2) He2 molecule does not exit as the bonding
and anti-bonding influence cancel each other.
(3) C2 ,O22 - and Li2 are diamagnetic
(4) In F2 molecule, the energy of 2 Pz is more
than  2px and  2 Py
18. fuEu es
alsd kSulk d Fku xy r gS?
(1) O2+, O2 rFkkO2- es
aLFkkf;Ro O2+ > O2 > O2- d s
Ø e esa?kVrk gSA
(2) He2 v.kqughacurk D;ks
afd cU/kh vkSj vcU/kh izHkko
,d nwl jsd ksfujLr d j nsrsgSA
(3) C2 ,O22 - rFkkLi2 iz
frpqEcd h; gSA
(4) F2 v.kqes
a2 Pz d hÅ t kZ] 2px rFkk  2 Py lsT;knk
gksrh gSA
RESONANCE
XIII ResoMost_STP – 4
19. H and S for a reaction are +30.558 kJ mol–1
and 0.666 kJ mol–1 at 1 atm pressure. The temperature at which free energy is equal to zero
and the nature of reaction below this temperature are
(1) 483 K, spontaneous
(2) 443 K, non-spontaneous
(3) 443 K, spontaneous
(4) 463 K, non-spontaneous
19. 1 ok;q
e.My h; nkc ij ,d vfHkfØ ;k d sfy , H rFkk
S
Ø e'k% +30.558 kJ mol–1 rFkk 0.666 kJ mol–1
gSA og rki ft l ij eqDr Å t kZ'kwU; d scjkcj gkst krh
gSrFkk bl rki d suhpsvfHkfØ ;k d h izd `fr fuEu gS&
(1) 483 K, Lor%iz
Øe
(2) 443 K, vLor%iz
Øe
(3) 443 K, Lor%iz
Øe
(4) 463 K, vLor%iz
Øe
20. Consider the modes of transformation of a gas
from state ‘A’ to state ‘B’ as shown in following
P–V diagram. Which one of the following is true
20. voLFkk‘A’ lsvoLFkk‘B’ es
axS
l d sLFkkukraj.kes
arjhd @siz
Øe
d ksnsf[k;s]t Sl kd hP–V vkjs[kesan'kkZ;kx;kgSA fuEu
esad kSulk ,d d Fku lR; gSA
(1) H = q along A  C
(1) A  C d sfy , H = q
(2) S is same along both A  B and A  C  B
(2) A  B rFkkA  C  B nks
uks
ad sfy, S leku gS
A
(3) W is same along A  B and A  C  B
(4) W > 0 along both A  B and A  C
(3) A  B rFkk A  C  B d sfy , W leku gS
A
(4) A  B rFkk A  C nks
uksad sfy , W > 0 gSA
21. Dinitrogen can be purified from the impurities of
NO and NH3 by passing through :
(1) concentrated HCl.
.
(2) alkaline solution of pyrogallol.
(3) an acidified solution of potassium dichromate.
(4) an aqueous solution of KOH.
21. MkbZ
ukbVªkst u esalsNO rFkkNH3 d hv'kqf) d ksfd lesa
izokfgr d j 'kq) fd ;k t krk gSA
(1) lkUnzHCl.
(2) ikbjks
xSy ksy d k {kkjh; foy ;uA
(3) iks
VSf'k;e MkbZØ ksesV d svEy hd `r foy ;u lsA
(4) KOH d st y h; foy ;u ls
A
22. White phosphorus when boiled with strong
solution of caustic soda produces :
22. d kf
WLVd lkMss+d siz
cy foy;u d slkFkt c 'os
r Q kLQ kjsl
d ksxeZfd ;k t krk gSt ksmRiUu gksxk&
(1) sodium phosphide
(1) lks
fM;e Q kLQ kbM
(2) sodium phosphate
(2) lks
fM;e Q kLQ sV
(3) sodium hypophosphite
(4) red phosphourus
RESONANCE
(3) lks
fM;e gkbiksQ kLQ kbZV
(4) y ky Q kLQ ks
jl
XIII ResoMost_STP – 5
23. Which of the following statements is true ?
23. fuEu es
alsd kSulk d Fku lR; gS\
(1) Cl2 can not be dried over H2SO4.
(1) Cl2 d ksH2SO4 ij 'kq
"d ughafd ;k t k ld rk gSaA
(2) Available chlorine is obtained from caustic
soda by treating with HCl.
(2) HCl d slkFkd kfLVd lkM
skd ksmipkfjr d j Dyks
jhu
(3) Conc. HCl + conc. HNO3 is Marshall's acid.
(4) All neutral interhalogen molecules are
diamagnetic in nature.
24. The catalyst used in Decons process is :
izkIr d h t k ld rh gSA
(3) lkUnzHCl + lkUnzHNO3 ek'kZ
y vEy gSA
(4) lHkhmnklhu vUrjkgS
y kts u v.kqiz
d f`r es
aiz
frpq
Ecd h;
gksrsgSaA
24. Ms
d u iz
Ø e (Decons process) es
aiz
;Dqr mRiz
jsd fuEu gS%
(1) CuCl2
(2) Cu
(1) CuCl2
(2) Cu
(3) CuSO4
(4) CuS
(3) CuSO4
(4) CuS
25. Which of the following is not the characteristic
of interhalogen compounds ?
25. fuEu es
alsd kSulk vUrjgSy kst u ;kSfxd ksad k vfHky {k.k
(1) They are more reactive than halogens.
(1) ;g gS
y kst u d h vis{kk vf/kd fØ ;k'khy gksrsgSaA
(2) They are quite unstable but none of them is
explosive.
(2) ;g iw
.kZr;k vLFkk;h gksrsgSay sfd u foLQ ksVd ugha
(3) They are covalent in nature.
(4) They have low boiling points and are highly
volatile.
ughagS\
gksrsgSA
(3) ;g lgla
;kst d izd `fr d sgSA
(4) ;g U;w
u DoFkukad fcUnqj[krsgSarFkkmPp ok"i'khy
gksrsgSA
26. In the clathrates of xenon with water, the nature
of bonding between xenon and water molecule
is :
(1) covalent
26. t y d slkFkt huks
u d sDy sFkjsV esat huks
u rFkkt y v.kq
d schp cU/ku d h izd `fr fuEu gS%
(1) lgla
;kst h
(2) gkbMª
kst u cU/ku
(2) hydrogen bonding
(3) mi&lgla
;kst h
(3) co-ordinate
(4) dipole-induced dipole interaction
27. Producer gas is a mixture of :
(4) f}/kq
zo&izsfjr f}/kqzo vUr%fØ ;k
27. mRiknd xS
l (Producer gas) feJ.k gS%
(1) CO + H2
(2) CO + N2
(1) CO + H2
(2) CO + N2
(3) H2 + N2
(4) CO + CO2
(3) H2 + N2
(4) CO + CO2
28. Which one of the following is the correct
statement ?
(1) Beryllium exhibits coordination number of six
(2) Chlorides of both beryllium and aluminium have
bridged chloride structures in solid phase
(3) B2H6.2NH3 is known as 'inorganic benzene'
(4) Boric acid is a protonic acid
RESONANCE
28. fuEu es
alsd kSulk d Fku lR; gS?
(1) cs
fjfy;e milgla
;ks
t u la[;kN%iz
nf'kZr d jrkgS
A
(2) cs
fjfy ;e rFkk ,sy qfefu;e nksuksad sDy ksjkbMksad h
Bksl voLFkk esalsrqDy ksjkbM lajpuk,¡gksrh gSaA
(3) B2H6.2NH3 d ksvd kcZ
fud csUt +hu’ d grsgSaA
(4) cks
fjd vEy ,d izksVkWfud vEy gSA
XIII ResoMost_STP – 6
29. Calculate value of 'n Keq' for the reaction at
250 K.
N2O4 (g)
Given :
29. 250K rki ij fuEu vfHkfØ ;k d sfy ,] 'n Keq' d k
eku Kkr d hft ;sA
2NO2 (g)
Hºƒ (NO2)g = + 40.407 kJ / mol
N2O4 (g)
fn;k gS:
Hºƒ (N2O4)g = + 70 kJ / mol
Sºr = 10
2NO2 (g)
Hºƒ (NO2)g = + 40.407 kJ / mol
Hºƒ (N2O4)g = + 70 kJ / mol
JK–1
Sºr = 10 JK–1
(1) 4
(2) – 4
(1) 4
(2) – 4
(3) 1.2
(4) – 1.2
(3) 1.2
(4) – 1.2
30. The INCORRECT statement is :
(1) In metallurgy, flux is a substance used to
convert infusible impurities to fusible mass.
(2) Cryolite is Na 3AlF 6 and is used in the
electrolysis of alumina for lowering the
melting point of alumina.
(3) Extraction of iron metal from iron oxide ore
is carried out by heating with coke and lime
stone.
(4) Haematite, Cassiterite and argentite are oxide
ores.
31. Identify correct structure for the following IUPAC
name.
3-Methyl -4, 5-dioxopentanoicacid.
(1)
(2)
(3)
30. v l R; d Fku gS%
(1) /kkrq
d eZesa] xky d og inkFkZgSft ld k mi;ksx
vxyuh; v'kq
f) ;ks
ad ks]xyuh; nz
O;eku esaifjofrZ
r
d jusd sfy ,]fd ;k t krk gSA
(2) Na3AlF6, Ø k;ks
y kbV gSbld kmi;ksx],Y;q
qfeukd s
oS
|q
r vi?kVu esa
],Y;q
feukd sxyuka
d d ksd e d jus
d sfy , fd ;k t krk gSA
(3) vk;ju vkW
DlkbM lsvk;ju /kkrqd kfu"d "kZ.kd ksd
o y kbeLVksu d slkFk xeZd jd sfd ;k t krk gSA
(4) gs
eVskbV]d fslfVjkbV rFkkvt UZsVkbV vkDWlkbM v;Ld
gSA
31. fn;sx;sIUPAC uke d h lgh la
jpuk igpkuksA
3-es
fFky -4, 5-MkbZ
v kWDlksisUVsuksbd vEy
(1)
(2)
(3)
(4)
(4)
RESONANCE
XIII ResoMost_STP – 7
32. How many positional isomers of Bromochloro
benzene are possible :
(1) 3
(3) 5
32. cz
kseksDy ksjkscsUt hu d sfd rusfLFkfr leko;ohlEHko gSa\
(2) 4
(4) 6
33. Write down total number of geometrical isomer
for the following compound :
(1) 4
(3) 8
(2) 4
(3) 5
(4) 6
33. fn;sx;s;kS
fxd d sT;kferh; leko;oh d h d qy la[;k
gksxh%
(2) 2
(4) 3
34. Which of the following option is enantiomer of
given compound ?
(1) 3
(1) 4
(2) 2
(3) 8
(4) 3
34. fn;sx;s;kf
Sxd d k iz
frfcEc : ihleko;ohd kuSlsfod Yi
es
agS\
(1)
(2)
(3)
(4)
H / Ni
35.
2 
 A
(1)
(2)
(3)
(4)
H / Ni
2 
 A
35.
H / Pt
2 
 B
H / Pt
2 
 B
A & B are
(1) Chain isomer
(3) Identical
RESONANCE
(2) Position isomer
(4) Geometrical isomer
A vkS
j B gS\
(1) J`
a[ky k leko;oh
(2) fLFkfrleko;oh
(3) le: i
(4) T;kferh; leko;oh
XIII ResoMost_STP – 8
36. Two compounds react with tollen's reagent
which give white and black ppt respectively,
these are ?
36. nks;kS
fxd VkWy su vfHkd kjd lsvfHkfØ ;k d jd sØ e'k%
'osr o d ky k vo{ksi nsrsgSA osfuEu gSA
(1)
(1)
(2)
(2)
(3)
(3)
(4)
(4)
37. Which does not have conjugate system ?
(1) CH2 = CHCl
(2) CH2 = CHCHO
(3) CH3CH = CH2 (4)
38. Which of the following statement is CORRECT
regarding the inductive effect ?
(1) Electron-donating inductive effect(+I effect)
is generally more powerful than electronwithdrawing inductive effect(-I effect)
(2) It implies the shifting of  electrons density
from more electronegative atom to the lesser
electronegative atom in a molecule
(3) It implies the shifting of  electrons density
from less electronegative atom to the more
electronegative atom in a molecule
(4) It increases with increase in distance.
39. The structure of the major product formed in the
following reaction is
37. d kS
ul k l a;qfXer ra=k ughaj[krk gS\
(1) CH2 = CHCl
(2) CH2 = CHCHO
(3) CH3CH = CH2
(4)
38. iz
sjf.kd izHkko lslEcfU/kr d kSulk d Fku lR; gS\
(1) by s
DVªksu nsusoky k izsjf.kd izHkko (+ I) lkekU;r;k%
vf/kd izHkkohgksrkgSA by s
DVªksu [khpusoky sizjsf.kd
izHkko (–I) ls
(2) bl ?kVukes
av.kqes
avf/kd fo|q
r_ .khijek.kqlsd e
fo|q
r_ .khijek.kqd hvks
j  bysDVª
kW
u d kfoLFkkiu
gksrk gSA
(3) bl ?kVukes
av.kqes
ad e fo|q
r_ .khijek.kqlsvf/kd
fo|q
r_ .khijek.kqd hvks
j  bys
DVª
kW
u d kfoLFkkiu
gks
rk gS
A
(4) ;g nw
jh c<+usd slkFk c<+rk gSA
39. fuEufy f[kr vfHkfØ ;kes
aeq[; mRikn d hlajpukgksxh%
H O / Acetone
H O / Acetone
2   
2   
(1)
(2)
(1)
(2)
(3)
(4)
(3)
(4)
RESONANCE
XIII ResoMost_STP – 9
40. Which alcohol cannot be prepared on reaction
of carbonyl compound with grignard reagent.
(1) CH3OH
(2) CH3CH2OH
(3)
(4)
41. When benzene reacts with HNO3/H2SO4 structure of intermediate formed is :
(1)
(2)
(3)
(4)
42. Friedel craft reaction can be possible for
40. fuEu es
alsfd l ,Yd kgsy d ksfxz
U;kj vfHkd eZ
d d hd kckfZsuy
;kS
fxd d h vfHkfØ ;k lsugh cuk;k t k ld rk gS
A
(1) CH3OH
(2) CH3CH2OH
(3)
(4)
41. t c cs
Ut hu d h fØ ;k HNO3/H2SO4 d slkFkd h t krh
gSrc e/;orhZD;k gksxk &
(1)
(2)
(3)
(4)
42. fuEu es
afd lesafÝ M~y Ø k¶V vfHkfØ ;k lEHko gSA
(1)
(2)
(1)
(2)
(3)
(4)
(3)
(4)
43. In the reaction, the product (C) is :
NaNO2  HCl
CuCN
 
 (A) 

 (B)
C6H5NH2 
0 – 5 ºC
KCN
43. fuEu vfHkfØ ;k es
amRikn (C) gS%

H / H2 O

 (C)
(1) C6H5CH2NH2
(2) C6H5COOH
(3) C6H5OH
(4) none of these
44. An aldol condensation reaction is possible in
(1) H – C C – CHO
(2) CCl3CHO
(3) CD3CHO
(4) C6H5CHO
RESONANCE
NaNO2  HCl
CuCN
 
 (A) 

 (B)
C6H5NH2 
0 – 5 ºC
KCN
H / H O
 2 (C)
(1) C6H5CH2NH2
(2) C6H5COOH
(3) C6H5OH
(4) bues
alsd ksbZugha
44. ,YMks
y la?kuu vfHkfØ ;k fd lesalEHko gS
(1) H – C C – CHO
(2) CCl3CHO
(3) CD3CHO
(4) C6H5CHO
XIII ResoMost_STP – 10
45. Denaturation of protein :
45. iz
ksVhu d k fod `frd j.k :
(1) Destroyed the primary or secondary or
tertiary structure of protein
(1) iz
ksVhu d hizkFkfed ;k f}rh;d ;k r`rh;d lajpuk
(2) Destroyed the secondary and tertiary
structure only
(2) iz
ksVhu d hf}rh;d rFkkr`rh;d lja
p ukd ksrksM+ukA
d ksrksM+
ukA
(3) iz
ksVhu d h izkFkfed ]f}rh;d rFkk r`
rh;d ;gkard
(3) Destroyed the primary, secondary and
tertiary and even the quaternary structure
of protein
d hprq"d lja
p ukd ksrksM+
ukA
(4) okLrfod t S
fod fØ ;k'khyrkij d ksbZiz
Hkko ughagSA
(4) Will not affect the original biological activity
46. Green Chemistry means such reaction which :
46. gjh jlk;u d k rkRi;Z:
(1) uq
d lkunk;d jlk;uksad kmi;ksx rFkkmRIkknu d e
(1) Reduce the use and production of hazardous
chemicals
d juk fufgr gSA
(2) Are related to the depletion of ozone Layer
(2) vks
t ksu ije d k vo{k; fufgr gSA
(3) Study the reaction in plants
(3) ikS
/kks
aes
avfHkfØ ;kvksad k v/;;u gSA
(4) Produce colour during reactions
(4) vfHkfØ ;kvks
aesajax d k fuekZ
.k fufgr gSA
47.
X is ?
X gks
xk \
47.
(1)
(1)
(2)
(2)
(3)
(3)
(4)
(4)
RESONANCE
XIII ResoMost_STP – 11
48. Ph – CH – CH  CH2
|
CH3
dil. H SO
4
 2 

 X(major product),
ruqH SO
2
4
48. Ph – CH – CH  CH2   
[; mRikn).


 X(eq
|
CH3
mRikn 'X' d ksigpkfu,A
Identify product 'X' is :
(1) Ph – CH – CH2 – CH2
(1) Ph – CH – CH2 – CH2
|
CH3
|
CH3
|
OH
|
OH
(2) Ph – CH – CH – CH3
(2) Ph – CH – CH – CH3
|
|
CH3 OH
|
|
CH3 OH
OH
|
(3) Ph – C – CH2 – CH3
|
CH3
OH
|
(3) Ph – C – CH2 – CH3
|
CH3
(4) Ph – CH – CH – CH3
|
|
OH CH3
(4) Ph – CH – CH – CH3
|
|
OH CH3
49. The anomeric carbon atom in glucose and fructose is
49. Xy w
d ksl o Q zDVksl esa,uksesfjd d kcZu ijek.kqgSA
(1) C1
(1) C1
(2) C2
(2) C2
(3) C5
(3) C5
(4) Xy w
d ksl esaC1 rFkk Q zDVksl esaC2
(4) C1 in glucose and C2 in fructose
50. The amino acid
pH exist as
(1)
(2)
(3)
at high
50. vehuksvEy
vf/kd pH ij
fd l izd kj d h fLFkfr esagksxk %
(1)
(2)
(3)
(4)
(4)
RESONANCE
XIII ResoMost_STP – 12
PART–B
PART–B
Straight Objective Type
l h/ksoLrqfu"B izd kj
This section contains 50 multiple choice
questions. Each question has 4 choices (1),
(2), (3) and (4) for its answer, out of which
ONLY ONE is correct.
bl [k.M es
a50 cgq& fod Yihiz'u gSaA iz
R;s
d iz'u d s4
fod Yi (1), (2), (3) rFkk (4) gSa] ft uesalsfl Q Z,d
l gh gSA
51. Two masses of 9 g and 6 g are tied to a string
51. 9 xz
ke o 6 xzke d snksnzO;eku ,d fpd uh f?kjuh ls
which passes over a smooth pulley. Then
xqt j jgh ,d Mksjh lsca/ksgSA rksmHk;fu"B Roj.k
common acceleration will be :
gksxkA
(1) 1.96 cm/s2
(2) 48 cm/s2
(1) 1.96 cm/s2
(2) 48 cm/s2
2
(3) 98 cm/s
(3) 98 cm/s2
2
(4) 196 cm/s
(4) 196 cm/s2
52. A block of mass 5 kg and surface area 2 m2
52. 5 kg nz
O;eku o 2 m2 i`"Bh; {ks=kQ y okykxq
Vd k30º
just begins to slide down on an inclined plane
>qd ko oky sur ry ij fQ ly uk izkjEHk d j nsrk gSA
when the angle of inclination is 30º. Keeping
mass same, the surface area of the block is
doubled. The angle at which this starts
;fn nzO;eku leku j[krsgq, i`"Bh; {ks=kQ y nqxukd j
nsarksfQ ly u izkjEHk gksusd sfy , d ks.k gksxk :
sliding down is :
(1) 30º
(1) 30º
(2) 60º
(2) 60º
(3) 15º
(3) 15º
(4) d ks
bZugha
(4) none
53. A position dependent force F = 7 – 2x + 3x2
53. fLFkfr ij fuHkZ
j cy F = 7 – 2x + 3x2 U;wVu , 2 kg
newton acts on a small body of mass 2 kg
nzO;eku d h ,d NksVh oLrqij d k;Zd jrk gS,oabls
and displaces it from x = 0 to x = 5m. The
x = 0 lsx = 5m rd foLFkkfir d jrk gS
A fd ;k x;k
work done in joules is
d k;Zt wy esagS&
(1) 70
(1) 70
(2) 270
(2) 270
(3) 35
(3) 35
(4) 135
(4) 135
RESONANCE
XIII ResoMost_STP – 13
54. A body of mass m is kept on a rough fixed
54. m nz
O;eku d k ,d Cy kW
d  d ks
.k oky sfLFkj [kqjnjs
inclined plane of angle of inclination . It
urry ij j[kk t krk gSA ;g fLFkj voLFkk es
agSrks
remains stationary. Then magnitude of force
acting on the body by the inclined plane is
equal to:
(1) mg
(2) mg sin 
Cy kWd ij urry d s}kjk y xk;sx;scy d k ifj.kke
gks
xkA
(1) mg
(2) mg sin 
(3) mg cos 
(3) mg cos 
(4) none
(4) d ks
bZugha
55. Two mirrors are inclined at an angle  as shown
55. nkslery niZ
.kksad ksfp=kkuql kj d ks.k ij >qd kd j
in the figure. Light ray is incident parallel to one
j[kk t krk gSA fd lh ,d niZ.k d slekukUrj vkifrr
of the mirrors. Light will start retracing its path
after third reflection if :
iz
d k'kfd j.krhljsijkorZu d sckn viusiqjkusiFkd k
vuql j.k (retrace) d jsxh ;fn&
(1)  = 45°
(2)  = 30°
(1)  = 45°
(3)  = 60°
(2)  = 30°
(4) all three
(3)  = 60°
(4) rhuks
ad sfy ,
RESONANCE
XIII ResoMost_STP – 14
56. Velocities of blocks A, B and pulley p2 are
shown in figure. Velocity of block C is :
(1) 2.5 m/s
(2) 1.5 m/s
(3) 1 m/s
(4) 2 m/s
57. A plane mirror is moving with velocity
56. fp=k es
aiqy hp2 rFkkCy kWd A, B d sosx çnf'kZr gSrks
Cy kWd C d k osx K kr d jks\
(1) 2.5 m/s
(2) 1.5 m/s
(3) 1 m/s
(4) 2 m/s
57. ,d l ery niZ
.k 4 ˆi  5 ˆj  8 kˆ d sosx l sxfreku
4 ˆi  5 ˆj  8 kˆ . A point object in front of the
gSA n iZ.k d s l keu s ,d fcUn qor oLr q
mirror moves with a velocity 3 ˆi  4 ˆj  5 kˆ .
x l sxfreku gSA ;gk¡ kˆ l ery
3 ˆi  4 ˆj  5 kˆ os
Here kˆ is along the normal to the plane mirror
and facing towards the object. The velocity
of the image is :
(1)  3 ˆi  4 ˆj  5 kˆ
(2) 3 ˆi  4 ˆj  11 kˆ
(3)  3 ˆi  4 ˆj  11 kˆ
niZ.k d svfHky Ecor rFkk oLrqd h vksj gSA izfrfcEc
d k osx gksxk &
(1)  3 ˆi  4 ˆj  5 kˆ
(2) 3 ˆi  4 ˆj  11 kˆ
(3)  3 ˆi  4 ˆj  11 kˆ
(4) 7 ˆi  9 ˆj  11kˆ
(4) 7 ˆi  9 ˆj  11kˆ
RESONANCE
XIII ResoMost_STP – 15
58. If the mass of earth is 80 times of that of a
planet and diameter is double that of planet &
g on earth is 9.8 m/s2, then the value of g on
that planet is
58. i`
Fohd knzO;eku ,d xz
g d snz
O;eku d k80 xq
ukgS,oa
O;kl xzg d sO;kl d k nksxquk gSA ;fn i`Foh ry ij
xq: Roh; Roj.kg d keku 9.8 eh/lSd .M+2 gSrksxzg ij
(1) 4.9 m/s2
g d k eku gks
xk
(2) 0.98 m/s2
(1) 4.9 m/s2
(3) 0.49m/s2
(2) 0.98 m/s2
(4) 49 m/s2
(3) 0.49m/s2
(4) 49 m/s2
59. A particle mass m and charge q is placed at
59. ,d d .kft ld knz
O;eku m rFkkvkos
'kq gSfd lh,d
rest in a unifrom elecrtic field E and then
leku fo|qr {ks=kE esafLFkj gSfQ j blseqDr d j fn;k
released.The kinetic energy attained by the
t k;srksy nwjhpy usd si'pkr bld s}kjkizkIr xfrt
particle after moving a distance y is
(1) qEy2
(2) qE2y
(3) qEy
(4) q2Ey
Å t kZgksxh
(1) qEy2
(2) qE2y
(3) qEy
(4) q2Ey
60. Two infinetly long parallel conducting plates
60. nksvuUr yEckbZd hlekukUrj pkyd ifV~
Vd k;s
a(Iys
Vl~ )
having surface charge densities + and –
ft ud slrgh vkos'k ?kuRo Ø e'k%+ vkSj – gS, ,d
respectively , are separated by a small
FkksMh nwjh d svarjky ij j[kh gSaA bu ifV~Vd kvksd s
distance. The medium between the plates is
vaccum. If 0 is the dielectric permittivity of
chp d k ek/;e fuokZr gSA vxj fuokZr d k ijkoS| qrkad
vaccum, then the electric field in the region
0 gS
, rksifV~
Vd kvksad se/;
between the plates is
(1) 0 oks
YV/ehVj
fo|qr {ks=k d k eku gS
(1) 0 volts/meter


(2) 2 oks
YV/ehVj
0
(2) 2 volts/meter
0

(3)  volts/meter
0
2
(4)  volts/meter
0
RESONANCE

(3)  oks
YV/ehVj
0
2
(4)  oks
YV/ehVj
0
XIII ResoMost_STP – 16
61. The resistance of a wire is R. If the length of
the wire is doubled by stretching, then the
resistance will be
61. fd lh rkj d k iz
frjks/k R gSA ;fn rkj d h y EckbZ
[khap d j nksxquh d j nh t k;sarksizfrjks/k gksxk
(1) 2R
(1) 2R
(2) 4R
(2) 4R
(3) R
(3) R
(4) R/4
(4) R/4
62. As we go from the equator to the poles , the
value of g
62. Hkw
e/; js[kk l s/kzqoksad h vksj t kusij g d k eku
(1) l eku jgrk gS
(1) Remains the same
(2) Decreases
(2) ?kVrk gS
(3) c<rk gS
(3) Increases
(4) Decreases upto a latitude of 45°
63. The radii of two planets are respectively R1
and R2 and their densities are respectively
1 and 2. The ratio of the accelerations due
(4) 45°vk{kka
'k rd ?kVrk gS
63. nksxz
gksad h f=kT;k;saØ e'k%R1 rFkkR2 gSarFkk mud s
?kuRo Ø e'k%1 rFkk2gSaA mud hl rgksaij xq: Roh;
Roj.kksad k vuqikr gksxk &
to gravity at their surfaces is
1
2
(1) g 1 : g 2 = R 2 : R 2
1
2
(2) g 1 : g 2 = R1R2: 1 2
(3) g 1 : g 2 = R12 : R2 1
(4) g 1 : g 2 = R1 1 : R2 2
64. A parallel plate capacitor is charged to a
potential difference of 100 V and disconnected
from the source of emf. A slab of dielectric is


1
2
(1) g 1 : g 2 = R 2 : R 2
1
2
(2) g 1 : g 2 = R1R2: 1 2
(3) g 1 : g 2 = R12 : R2 1
(4) g 1 : g 2 = R1 1 : R2 2
64. ,d lekUrj Iy s
V la/kkfj=k d ks100 V foHkokUrj ij
vkosf'kr d jd semf fo-ok- cy d slzksr lsvy x d j
then inserted between the plates. Which of the
fn;k x;k gSA vc Iy sVksad se/; ijkoS| qr iêh Mky h
following three quantities change?
t krh gSA fuEu rhuksesalsfd lesaifjorZu gksxk ?
(i) The potential difference
(i) foHkokUrj
(ii) /kkfjrk
(iii) Iy s
Vksaij vkos'k
(ii) The capacitance
(iii) The charge on the plates
(1) d s
oy (i) vkSj (ii)
(1) only (i) and (ii)
(2) d s
oy (i) vkSj (iii)
(2) only (i) and (iii)
oy (ii) vkSj (iii)
(3) d s
(3) only (ii) and (iii)
(4) All (i), (ii) and (iii)
RESONANCE
(4) lHkh (i), (ii) vkS
j (iii)
XIII ResoMost_STP – 17
65. One plate of a parallel plate capacitor(5 F)
65. lekUrj Iy s
V la/kkfj=k(5 F) d h,d Iy sV ij 10 C
has a fixed charge 10 C. The charge q(in
d kvkos'kfLFkj gSA vU; IysV ij vkos'kq(C es
a) le;
C)on the other plate is varied with time t(in
seconds) as q = 2t. The potential difference
(in volts) between the plates will vary as
t(lS
d .M esa) d slkFkq = 2t d svuql kj ifjofrZr gksrk
gSA Iy sVksad se/; foHkokUrj (oksYV esa) fd l çd kj
ifjofrZr gksxkA
(1) 1 0.2 t
(1) 1 0.2 t
(2) 1 0.2 t
(2) 1 0.2 t
(3) 0.5t
(4) 0.2t
(3) 0.5t
(4) 0.2t
66. A 1 µF capacitor is connected in the circuit
66. 1 µF d k la
/kkfj=k ifjiFk esafp=kkuql kj t qM+k gSA lSy
shown below. The e.m.f. of the cell is 3 volts
d k fo0 ok0 cy rFkk vkarfjd izfrjks/k Ø e'k%3 oksYV
and internal resistance is 0.5 ohms. The
resistors R1 and R2 have values 4 ohms and
1 ohm respectively. The charge on the
rFkk 0.5 vkse gSA R1 rFkk R2 izfrjks/kksad seku Ø e'k%
4 vks
e rFkk 1 vkse gSaA LFkk;h voLFkk esala/kkfj=k ij
capacitor in steady state must be :
vkos'k gksuk pkfg,A
(1) 2  C
(1) 2  C
(2) 1  C
(2) 1  C
(3) 1.33  C
(3) 1.33  C
(4) zero
(4) 'kw
U;
RESONANCE
XIII ResoMost_STP – 18
67. In which of the following states is the potential
energy of an electric dipole maximum-
67. fuEu es
ad kSulhfLFkfr esaoS| qr f}/kqz
o d hfLFkfrt Å t kZ
vf/kd re gks
xh&
+q
+q
+q
-q
+q
E
(1)
(2)
E
(1)
(2)
-q
E
-q
+q
+q
-q
+q
-q
E
(3)
-q
E
(4)
+q
E
E
-q
(3)
(4)
E
-q
68. For which of the following colour, the
magnifying power of a microscope will be
maximum :
(1) White colour
(2) Red colour
(3) Violet colour
(4) Yellow colour
68. fd l o.kZd sfy ;s,d lw
+{en'khZd h vko/kZu {kerk
69. A particle of mass 11 × 10–12 kg is moving with
a velocity 6 × 10 –7 m/s. Its de–Broglie
wavelength is nearly :
69. ,d 11 × 10–12 kg nz
O;eku d k d .k 6 × 10–7 m/s
(1) 10–20 m
(2) 10–16 m
(3) 10–12 m
(4) 10–8 m
70. The decreasing order of wavelength of
infrared, microwave, ultraviolet and gamma
rays is:
vf/kd jgrh gSA
(1) 'os
r o.kZ
(2) y ky o.kZ
(3) cS
axuh o.kZ
(4) ihy k o.kZ
d sosx l spy jgk gSA bl d h Mh&czksxy h rjaxnS/;Z
y xHkx gS:
(1) 10–20 m
(2) 10–16 m
(3) 10–12 m
(4) 10–8 m
70. vojDr fd j.kks
a] l w{e rjaxksa] ijkcSaxuh rjaxksavkSj
xkek fd j.kksad h rjaxnS/;Z?kVrsØ e esagS:
(1) microwave, infrared, ultraviolet, gamma
rays
(1) l w
{erjaxsa]vojDr]ijkcSaxuh] xkek fd j.ksa
(2) gamma rays, ultraviolet, infrared,
microwaves
(3) l w
{e rjaxsa] xkek fd j.ksa] vojDr] ijkcSaxuh
(3) microwaves, gamma rays, infrared,
ultraviolet
(2) xkek fd j.ks
a] ijkcSaxuh]vojDr]l w{e rjaxsa
(4) vojDr] l w
{erjaxsa]ijkcSaxuh] xkek fd j.ksa
(4) infrared, microwave, ultraviolet, gamma
rays
RESONANCE
XIII ResoMost_STP – 19
71. The specific activity (per gm) of radium is nearly
71. js
fM;e d h fof'k"V lfØ ;rk gksrh gS]y xHkx &
(1) 1 Bq
(1) 1 Bq
(2) 1 Ci
(2) 1 Ci
(3) 3.7 × 1010 Ci
(3) 3.7 × 1010 Ci
(4) 1 mCi
(4) 1 mCi
72. The output of an OR gate is connected to both
the inputs of a NAND gate. The combination
will serve as a :
72. OR xs
V d sfuxZr d ksNAND xsV d snksauksfuos'kksals
t ksM+k t krk gSA la;kst u bl Hkkafr d k;Zd jsxk :
(1) NOT xs
V
(1) NOT gate
(2) NOR xs
V
(2) NOR gate
(3) AND gate
(3) AND xs
V
(4) OR gate
(4) OR xs
V
73. In the following, which one of the diodes is
73. fuEu es
alsd kSulk Mk;ksM mRØ e vfHkurh esagSA
reverse biased?
R
(1)
R
(1)
10 V
(1)
10 V
(1)
5 V
5 V
R
R
(2)
(2)
10 V
10 V
(3)
(3)
R
5 V
R
5 V
(4)
(4)
12 V
R
12 V
R
5 V
5 V
RESONANCE
XIII ResoMost_STP – 20
74. Choose the correct option for the forward
biased characteristics of a p–n junction.
I
74. p–n la
f/k d h vxzvfHkurh d sfy, lgh y k{kf.kd oØ
d sfy ,A
I
(1)
I
(2)
(1)
V
(2)
V
I
V
I
(3)
I
I
(4)
V
V
I
(3)
(4)
V
75. The thickness of a plate which will produce a
change in optical path equal to one fourth of
the wavelength  of the light passing through it
normally. The refractive index of the plate is µ.
V
V
75. Iys
V d heks
VkbZD;kgks
xhft l ij rja
xnS
/;Zd kiz
d k'k
yEcor~fxjusij t ksçd k'kh; iFkkUrj rja
xnS
/;Zd k,d
pkS
FkkbZnsrh gS
A Iy s
V d k viorZuka
d µ gS
aA


(1) 2(  1)
(1) 2(  1)

(2) 4(  1)
(2) 4(  1)

(3) (  1)
(3) (  1)

(4) 6(  1)
(4) 6(  1)



RESONANCE
XIII ResoMost_STP – 21
76. Which of the following four alternatives is not
correct?
76. fuEufy f[kr fod Yiks
aesalsd kSulk lgh ughagS\
We need modulation:
gesaekMq
y s'ku d h v ko' ; d r k gksr h gs%
(1) to reduce the time lag between
transmission and reception of the information
signal
(1) lw
p ukflXuy d h lap j.kvkSj çkfIr d schp le;
(2) to reduce the size of antenna
(2) ,UVhuk d k vkd kj ?kVkusd sfy ,A
(3) to reduce the e fractional band width, that
(3) vka
f'kd cS.M pkSM+kbZvFkkZr~flXuy cS.M pkSM+kbZd k
is the ratio of the signal band width to the centre
frequency
(4) to increase the selectivity.
77. The current i in a coil varies with time as shown
vUrjky d ks?kVkusd sfy ,A
d sUnzh; vko`fÙk lsvuqikr ?kVkusd sfy ,A
(4) oj.k {kerk es
ao`f) d sfy ,A
77. fd lhd q
.My hesafo|q
r/kkjki d keku vkjs
[kkuq
l kj le;
time would be:
d slkFkifjofrZ
r gksrkgS
]rksçsfjr fo|qr okgd cy d k
eku le; d slkFk ifjofrZr gksxk :
(1)
(1)
(2)
(2)
(3)
(3)
(4)
(4)
in the figure. The variation of induced emf with
RESONANCE
XIII ResoMost_STP – 22
78. In a step-up transformer the voltage in the
78. mPpk;h Vª
kal Q keZj d h çkFkfed d q.My h esa foHko
primary is 220 V and the current is 5A. The
rFkk /kkjk d sifjek.k Ø e'k% 220 V rFkk 5A gSA
secondary voltage is found to be 22000 V. The
current in the secondary (neglect losses) is
(1) 5 A
(2) 50 A
(3) 500 A
(4) 0.05 A
f}rh;d d q.My h esafoHko 22000 V çkIr gksrkgSrks
f}rh;d esa/kkjk gksxhA (gkfu;ksad ksux.; ekuksa)
(1) 5 A
(2) 50 A
(3) 500 A
(4) 0.05 A
79. The magnetic materials having negative
magnetic susceptibility are:
(1) Non magnetic
(2) Para magnetic
(3) Diamagnetic
(4) Ferromagnetic
79. fd l pq
Ecd h; inkFkZd h pqEcd h; ços';rk _ .kkRed
gS&
(1) vpq
Ecd h;
(2) vuq
p qEcd h;
(3) çfrpq
Ecd h;
(4) y kS
gpqEcd h;
80. If n drops of potential V merge, find new
potential on the big drop :
(1) n2/3 V
(2) n1/3 V
(3) nV
n/3
(4) V
80. ;fn V foHko d h n cw
anslfEefy r gks] rkscM+h cwan d k
u;k foHko Kkr d hft ;sA
(1) n2/3 V
(2) n1/3 V
(3) nV
(4) Vn/3
81. The wavelength of most energetic X-rays
81. fd lh /kkrqy{; ij 40 keV d sby s
DVªkWuksad h ceckjh
emitted when a metal target is bombarded by
d jusij mRlft Zr vf/kd re Å t kZokyh X-fd j.k d h
40 keV electrons is approximately
(1) 300Å
(2) 10 Å
(3) 4 Å
(4) 0.31 Å
RESONANCE
rja
xnZ/;ZyxHkx gS
&
(1) 300Å
(2) 10 Å
(3) 4 Å
(4) 0.31 Å
XIII ResoMost_STP – 23
82. The ratio of kinetic energy to total energy, for
th
n shell of an atom will be -
82. fd lhijek.kqd snos
ad ks
'kd sfy, xfrt Å t kZrFkkd q
y
Å t kZd k vuqikr D;k gksxk&
(1) 1
(1) 1
(2) –1
(2) –1
(3) n2
(3) n2
(4) 1/n2
(4) 1/n2


83. If a = 3 ˆi + 4 ˆj & b = 7 ˆi + 24 ˆj then the vector


83. ;fn a = 3 ˆi + 4 ˆj & b = 7 ˆi + 24 ˆj gksrksog lfn'k

having the same magnitude as b and same


ft ld kifjek.k b d sleku rFkkfn'kk a d hfn'kkesa

direction as a is :
gks] gksxk&
(1) 15 ˆi + 20 ˆj
(1) 15 ˆi + 20 ˆj
(2) 10 ˆi + 20 ˆj
(2) 10 ˆi + 20 ˆj
(3) 20 ˆi + 15 ˆj
(3) 20 ˆi + 15 ˆj
(4) 15 ˆi + 10 ˆj
(4) 15 ˆi + 10 ˆj
84. A particle moves along a straight line such
that its displacement at any time t is given
by :
s = t3 – 6t2 + 3t + 4 metres
The velocity when the acceleration is zero
84. ljy js
[kkesaxfr d j jgs,d d .kd kfd lh{k.k t ij
foLFkkiu :
s = t3 – 6t2 + 3t + 4 ehVj
lsfn;k t krk gSA t c Roj.k 'kwU; gksrc d .k d k osx
is :
gksxk &
(1) 3 ms–1
(1) 3 ms–1
(2) – 12 ms–1
(2) – 12 ms–1
(3) 42 ms–1
(3) 42 ms–1
(4) – 9 ms–1
(4) – 9 ms–1
RESONANCE
XIII ResoMost_STP – 24
85. Rain is falling with a velocity (  4ˆi  8 ˆj  10kˆ ) . A
85. ckfj'k (  4ˆi  8 ˆj  10kˆ ) d sos
x l sfxj jgh gSA ,d
person is moving with a velocity of (6ˆi  8ˆj) on
vkneh (6ˆi  8ˆj) osx l st ehu ij py jgkgSA vkneh
the ground. Find the velocity of rain with
d sl kis{k ckfj'k d k osx K kr d jksrFkk og fn'kk Hkh
respect to man and the direction from which
K kr d jksft l l sckfj'k vkrh gqbZizrhr gksjgh gSA
the rain appears to be coming.
(1) ( 10 ˆi  10kˆ )
(1) ( 10 ˆi  10kˆ )
(2) ( 10 ˆi  10kˆ )
(2) ( 10 ˆi  10kˆ )
(3) (10 ˆi – 10kˆ )
(4) (–10 ˆi  10kˆ )
86. A particle of mass 5 kg is moving on rough
fixed inclined plane with constant velocity of
5 m/s as shown in the figure. Find the friction
force acting on a body by plane.
(1) 25 N
(2) 20 N
(3) 30 N
(3) (10 ˆi – 10kˆ )
(4) (–10 ˆi  10kˆ )
86. 5 kg nz
O;eku d k,d Cy kWd fLFkj rFkk[kqjnjsurry
ij 5 m/s d sfu;r osx lsfp=kkuql kj xfr d j jgk gS
rkslrg }kjk Cy kWd ij y xk;k x;k ?k"kZ.k cy gksxkA
(1) 25 N
(2) 20 N
(3) 30 N
(4) none of these
(4) bues
al sd ksbZugha
87. A force of 2 ˆi + 3 ˆj + 4 kˆ N acts on a body for
4 second, produces a displacement of
87. ,d cy 2 ˆi + 3 ˆj + 4 kˆ N }kjkfd lhoLrqea
s4 lSd .M
esamRiUu foLFkkiu (3 ˆi + 4 ˆj + 5 kˆ )m gSA ç;qDr
(3 ˆi + 4 ˆj + 5 kˆ )m. The power used is :
'kfDr gS&
(1) 9.5 W
(1) 9.5 W
(2) 7.5 W
(2) 7.5 W
(3) 6.5 W
(3) 6.5 W
(4) 4.5 W
(4) 4.5 W
RESONANCE
XIII ResoMost_STP – 25
88. A rigid body of mass m kg is taken slowly up
an inclined plane and then allowed to slide
down to the bottom again. The co-efficient of
friction between the body and the plane is .
88. m kg nz
O;eku d h ,d n`<+oLrqd ksur ry ij
/khjs& /khjsy st k;kt krkgSSvkSj fQ j uhpsfQ l y usd s
fy ;sN ksM +fn;k t krk gSA ur ry o oLrqd schp
sign of the work done by the gravitational force
?k"kZ.k xq.kkad
 gS
A
over the round trip is.
fd ;k x;k d k;Zd k fpUg gksxk&
µ = 0.15
µ = 0.15
0.3
kg
0.3
kg
Fixed
Fixed
(1) positive
(1) /kukRed
(2) Negative
(2) _ .kkRed
(3) zero
(4) upward journey positive, down word journey
negative
iw.kZpØ esaxq: Rok"kZ.k cy }kjk
(3) 'kw
U;
(4) mij d h vks
j t kusij /kukRed ] uhpsd h vksj
t kusij _ .kkRed
89. The dimension of Magnetic energy density
=
1 B2
(where 0 is permiabilty of free space
2 0
89. pq
Ecd h; Å t kZ?kuRo =
1 B2
2 0
d k fofe; lw=k gksxk
¼t gkW 0 fuokZr d h pqEcd 'khy rk rFkk B pqEcd h;
{ks=k gS½ %
and B is magnetic field) is :
(1)
M1L-1T –2
(2)
M1L-1T –3
(3) M1L-2T –2
(4)
(1) M1L-1T –2
(2) M1L-1T –3
(3) M1L-2T –2
(4) M1L1T–2
M1L1T–2
RESONANCE
XIII ResoMost_STP – 26
90. A smooth disc is rotating with uniform angular
90. ,d fpd uhfMLd ¼pd rh½,d leku d ks
.kh; pky  ls
speed  about a fixed vertical axis passing
,d fLFkj t M+Ro m/okZ/kj v{kd slkis{k?kw.kZu d j jgh
through its centre and normal to its plane as
shown. A small block of mass m is gently
gSrFkk ;g m/okZ/kj v{k] fMLd d sd sUnzlsxqt jrh gS
placed at the periphery of the disc. Then
rFkk ;g fMLd d sry d sy Ecor~fp=kkuql kj gSA ,d
(pickup the correct alternative or alternatives)
NksVsCy kWd ft ld knzO;eku m gSd ks/khjslssfMLd d h
ifj/khij j[kfn;kt krkgS
A rc ¼lghfod Yi@fod Yiks
a
d kspqfu,½
(1) In comparision to the angular speed of
the disc now increases.
(2) In comparision to the angular speed of
the disc now decreases.
(1) d ks
.kh; pky d h rqy uk esavc fMLd d h d ks.kh;
pky c<+sxh
(2) d ks
.kh; pky d hrqy ukesa]vc fMLd d hd ks.kh;
(3) In comparision to the angular speed of
pky ?kVsxh
the disc now remains same.
(3) d ks
.kh; pky d hrqy ukesafMLd d hd ks.kh; pky
(4) The block will move tangentially and fall off
vc ogh leku jgsxh
the disc.
(4) Cy kW
d Li'kZjs[kh; xfr d jsxk rFkk fMLd lsfxj
t k;sxk
91. What is the effect on the time period of a simple
pendulum if the mass of the bob is doubled :
(1) Halved
91. ;fn fd lh y ks
y d d snksy d (bob)d knzO;eku nksxquk
d j fn;k t k;sarksmld svkorZd ky ij izHkko gksxk
(1) vk/kk
(2) nks
xq
uk
(3) vkB xq
uk
(4) d ks
bZifjorZu ughagksxk
(2) Doubled
(3) Becomes eight times
(4) No effect
92. Latent heat of 1 gm of steam is 536 cal/gm ,
92. 1 xz
ke Hkki d h xqIr Å "ek 536 cal/gm gSrksmld k
then its value in joule/kg is:
eku J/kg esagksxk:
(1) 2.25 × 106
(2) 2.25 × 103
(1) 2.25 × 106
(2) 2.25 × 103
(3) 2.25
(4) none of these
(3) 2.25
(4) d ks
bZugha
RESONANCE
XIII ResoMost_STP – 27
93. When a wave pulse travelling in a string is
reflected from a rigid wall to which string is
tied as shown in figure. For this situation two
statements are given below.
93. t c ,d rja
x LiUn (pulse) jLl h d svuqfn'k xeu
d j jgh gSrFkk ;g n`<+nhokj l sijkofrZr gksjgh
gSA jLl hnhokj l sfp=kkuql kj ca/kh gSA bl fLFkfr d s
fy , nksd Fku fn, x, gSA
v
v
(i) The reflected pulse will be in same
orientation of incident pulse due to a phase
(i) ijkofrZ
r LiUn d kfoU;kl vkifrr LiUn d sleku
change of  radians
gks
rkgSrFkkmld kd y kes
aifjorZ
u  jsfM;u gksrkgSA
(ii) During reflection the wall exert a force on
(ii) ijkorZ
u d snkSjku nhokj jLl hij Å ij d hfn'kk
string in upward direction
For the above given two statements choose
the correct option given below.
(1) Only (i) is true
(2) Only (ii) is true
(3) Both are true (4) Both are wrong
esacy y xkrh gSA
bu fn;sx;sd Fkuksaesal R; gSA
(1) d s
oy (i) l R; gS
(2) d s
oy (ii) l R; gS
(3) nks
uksal R; gS
(4) nks
uksxy r gS
94. On a new scale of temperature (which is linear)
94. rki d h ,d ubZLd s
y ]t ksjs[kh; gS]mlsW Ld sy d k
and called the W scale, the freezing and boiling
uke fn;k x;k gSA bl Ld sy ij t y d k fgekad vkSj
points of water
DoFkukad Ø ekuql kj 39°W vkSj 239°W gSA t c
are 39°W and 239°W
respectively. What will be the temperature on
the new scale, corresponding to a temperature
of 39°C on the Celsius scale ?
lsfYl;l Ld sy ij rki 39°C gksxk]rksubZLd sy ij
rki d k eku gksxk:
(1) 78°C
(1) 78°C
(2) 117°W
(2) 117°W
(3) 200°W
(3) 200°W
(4) 139°W
(4) 139°W
RESONANCE
XIII ResoMost_STP – 28
95. A catapult's string made of rubber having
cross section area 25 mm2 and length 10
cm. To throw a 5 gm pabble it is stretched
up to 5 cm and released. Velocity of
95. jcj d h Mks
jhl scuh ,d xqy sy d hMksjhd svuqizLFk
d kV d k {ks=kQ y 25 feeh2 gS,oajcj d h Mksjh d h
y EckbZ10 l seh gSA 5 xzke d s,d d ad M+d ksQ sad us
projected pabble is (Young coefficient of
d sfy , bl s5 l seh rd [khap k t krk gS] fQ j N ksM +
elasticity of rubber is 5 × 108 N/m2) :
fn;kt krkgSA iz{ksfir d ad M+d kosx gS¼jcj d k ;ax
(1) 20 m/s
izR;kLFkrk xq.kkad = 5 × 108 U;wVu@eh2½
(2) 100 m/s
(1) 20 eh@l s
(3) 250 m/s
(2) 100 eh@l s
(4) 200 m/s
(3) 250 eh@l s
(4) 200 eh@l s
96. A tunnel is dug along a diameter of a planet
and a small body is dropped into it at the
surface. The motion of the body is :
96. ,d lq
jax ,d xzg d sO;kl d svuqfn'k [kksnh t krh gS
rFkk ,d NksVh oLrqbld h lrg lsfxjk;h t krh gSA
oLrqd hxfr gksxh&
(1) uniform motion
(2) periodic motion
(1) ,d leku xfr
(3) S.H.M.
(2) vkorhZxfr
(4) None of these
(3) ljy vkorZxfr
(4) bues
alsd ksbZugha
97. If the relation between displacement (x) and
97. ;fn SHM d jrk gq
v k d .k d k x2 o v2 d k xzkQ
velocity v is shown in x2 Vs v2 graph of a particle
foLFkkiu (x) o os
x v es
alEcU/kcrkrkgS
A rc vkorZ
d ky
executing S.H.M. is given below. Find the time
Kkr d jksA
period :
(1) 4 sec.
(1) 4sec.
(2) sec.
(3) 2sec.
(2)  sec.
(3) 2 sec.
(4) 6 sec.
(4) 6sec.
RESONANCE
XIII ResoMost_STP – 29
98. A solid cylinder S is placed over a plank P on
98. ,d Bks
l csy u S, Iy kad P ij y q<+d rk gSA csy u rFkk
which it rolls. There is no slipping between
Iy kad d se/; fQ ly u ughagS
A v,  rFkku d se/; lgh
cylinder and plank. The correct relation between
v,  and u is :
lEcU/kgksxk:
(1) v = u + R
(1) v = u + R
(2) u = v + R
(2) u = v + R
(3) v + u – R = 0
(3) v + u – R = 0
(4) u – R + v = 0
(4) u – R + v = 0
99. The speed of projectile at its maximum height
99. ,d ç{ks
I; d kvf/kd re Å ¡
pkbZij os
x bld sç{ksi.kos
x
is half of velocity of projection. Then ratio of
4H
is (where H is maximum height and R is
R
d k vk/kk gSrc vuqikr
4H
R
gksxk (t gk¡H vf/kd re
Å ¡p kbZrFkk R ijkl gS)
range)
1
(1)
2
(2)
1
(3)
4
3
(4)
2
(1)
1
2
(2)
3
(3)
1
4
(4)
3
2
3
100.The displacement of an object attached to a
100. ,d fLiz
x lst q
a
M+
hrFkkljy vkorZxfr d jusokyh,d
spring and executing simple harmonic motion








oLrqd k foLFkkiu x = 2 × 10–2 cos  t  4  ehVj
is given by x = 2 × 10–2 cos  t  4  metres.
lsfn;k t krk gSA le; ft l ij igy h ckj vf/kd re
The time at which the maximum displacement
first occurs is :
(1) 0.5 s
(2) 0.75 s
(3) 0.125 s
(4) 0.25 s
RESONANCE
foLFkkiu izd V gksrk gS] gS
(1) 0.5 s
(2) 0.75 s
(3) 0.125 s
(4) 0.25 s
XIII ResoMost_STP – 30
PART-C
l h/ksoLrqfu"B izd kj
Straight Objective Type
This section contains 100 multiple choice
bl [k.M esa100 cgq-fod Yihiz'u gSA izR;sd iz'u d s4
questions. Each question has 4 choices (1), (2),
fod Yi (1), (2), (3) rFkk(4) gS, ft uesalsflQ Z,d lgh
(3) and (4) for its answer, out of which ONLY
gSaA
ONE is correct.
101. Which of the following is not a feature of Algae
101. fuEu es
alsd kSulk ,d y {k.k 'kSoky d k ughagS
(1) Vascular tissues are usually absent
(1) la
ogu Å rd lkekU;r%vuqifLFkr gksrsgSa
(2) Embryo stage is absent
(2) Hkz
w.kh; voLFkk vuqifLFkr gksrh gS
(3) Sex organs are jacketed
(4) Grana are absent in Chloroplast
102. Fluidity of plasma membrane is due to
(3) y S
fxd vax t Sd sV ;qDr gks
a
rsgSaA
(4) Dy ks
jks
Iy kLV esaxzsuk vuq
ifLFkr gksrh gSa
102. Iy kTek d y k d h rjy rk d k d kj.k gS
A
(1) Polar ends of lipid molecules
(1) fy fiM v.kq
v ksad s/kqzoh; fljs
(2) Protein molecules
(2) iz
ksVhu v.kq
(3) Non polar ends of fatty acids
(3) olh; vEy ks
ad sv/kqzoh; fljs
(4) Oligosaccharides
(4) vks
fy xksl sd jkbM~l
103. In pBR 322 rop is related with
(1) Coding of protein that take part in replication
of plasmid
103. pBR 322 es
arop fd llsla
caf/kr gS
(1) d ks
fMax izks
Vhu lst ksIy kfTeM d hiq
ujko`
fÙkesaHkkx
y srh gS
(2) Reverse of plasmid
(3) Decoding of genes that are related with
replication of plasmid
(4) Identification of foreign DNA
(2) Iy kfTeM d sO;q
RØ e ls
(3) t hUl d hMhd ks
fMa
x lst ksIykfTeM d hiqujko`
fÙkls
lacaf/kr gS
(4) cká DNA d h igpku ls
104. Which is Zero in Turgid cell
(1) OP
(2) TP
(3) DPD
(4) DP
RESONANCE
104. d kS
ulk LQ hr d ksf'kd k eas'kwU; gksrk gS
(1) OP
(2) TP
(3) DPD
(4) DP
XIII ResoMost_STP 31
105. The gene for starch synthesis in pea seeds
105. eVj d sikni es
aLVkpZla
'ys
"k.kd sfy, mRrjnk;ht hu
can produce more than one effect. The former
,d lsvf/kd çHkko mRié d jrkgS;g ....(a).... t hu
represents ....(a).... gene. It has two alleles B
d ksn'kkZrkgSA blesanks;qXe fod YihB rFkkb gksrsgSaA
and b. BB & Bb genotype produce rounded
BB ,oaBb t hu çk: i xks
y vkÑ fr d scht mRié
seeds while bb form wrinkled seeds In bb
d jrsgS
at cfd bb Lo: i >qjhZ
nkj cht mRié d jrsgS
aA
homozyotes, smaller starch grains are
produced while BB genotypes form large
bb gks
ekst kbxksV Nks
Vsvkd kj d sLVkpZd .kmRié d jrs
starch grains and Bb genotypes form .....(b)....
gSat cfd BB t hu çk: i cM+svkd kj d sLVkpZd .k
size of starch grain due to ....(c).... Here (a),
mRié d jrsgSarFkk Bb t hu çk: i .....(b).... vkd kj
(b) and (c) are
d sLVkpZd .k ....(c)..... d sd kj.k mRié d jrsgSa&
(1) (a) Multiple allelism (b) Large size (c)
(1) (a) cgq
;qXe fod fYirk (b) cM+kvkd kj (c) çHkkfork
Dominance
(2) (a) iks
y ht hu (b) e/;orhZvkd kj (c) lgçHkkfork
(2) (a) Polygene (b) Intermediate size (c)
(3) (a) fIy ;ks
Vªksfid t hu (b) e/;orhZ vkd kj (c)
Codominance
viw.kZçHkkfork
(3) (a) Pleiotropic gene (b) Intermediate size
(4) (a) vfrçHkkoh(b) NkV
skvkd kj (c) ek=kkRed oa
'kkxfr
(c) Incomplete dominance
(4) (a) Overdominant (b) small size (c)
Quanitative inheritance
106.
106.
mijks
Dr fp=kksad svk/kkj, xq.klw
=kks
ad hla
jpuko eki d k
On the basis of above diagrams, the study of
structure and size of chromosomes can be
performed by the
(1) a
(2) b
(3) c
(4) d
107. Complementary cells are associated with
(1) Lenticels
(2) Hydathodes
(3) Rhytidome
RESONANCE
(4) Bark
v/;;u fd ld s}kjk lEikfnr fd ;k t k ld rk gSA
(1) a
(2) b
(3) c
(4) d
107. iw
jd d ksf'kd k,¡ (complementary cells) fd l l s
lEcfU/kr gS
(1) okrjU/kz
(2) t y jU/kz
(3) jkbfVMks
e
(4) Nky
XIII ResoMost_STP 32
c
a
c
a
108.
108.
d
d
b
b
In the above diagram, Identify the labelling &
mijks
Dr fp=kes
aukeka
d u d ksigpkfu;srFkklghfod Yi
select the appropitate option
d kspqfu;s
(1) a - seed, b - Mesocarp, c - Thalamus, d -
(1) a - cht , b - fet ks
d kWiZ, c - iq
"iklu, d - ,.Mks
d kW
iZ
Endocarp
(2) a - Endocarp, b - Thalamus, c - Mesocarp,
d - seed
(3) a - seed, b - Endocarp, c - Mesocarp, d -
(2) a - ,.Mks
d kWiZ , b - iq"iklu, c - fet ksd kWiZ, d -
cht
(3) a - cht , b - ,.Mks
d kWiZ , c - fet ksd kWiZ, d -
iq"iklu
Thalamus
(4) a - Endocarp, b - Thalamus, c - seed, d Mesocarp
(4) a - ,.Mks
d kW
iZ, b - iq
"iklu, c - cht , d - fet ksd kW
iZ
109. Mk;Ve Ý LV~
;w
y fd ld k cuk gksrk gSA
(1) flfy d k
109. Diatom frustule is made of
(1) Silica
(2) d S
fYl;e d kcksZ
usV
(2) Calcium carbonate
(3) d S
fYl;e gkbMªkWDlkbM
(3) Calcium hydroxide
(4) 1 & 3 nks
uksa
(4) Both 1 and 3.
110. d kW
y e lqesfy r d hft , &
110. Match the column
Column-I
Column-II
(a) fVM~
Mh
(i) gkFk es
ajs[kkvksad k
Column-I
Column-II
(a) Grasshopper
(i) Palmer crease in
t ky (Palmer crease
hand
in hand)
(b) Turner's syndrome
(ii) Mental retardation
(b) Turner's syndrome
(ii) ekufld {kfr rFkk
& accumulation of
fQ uk;y ikb: fod vEy
phenylpyruvic acid
d k lap ;
(c) Phenyl ketonuria
(iii) Barr body absent
(c) Phenylketonuria
(iii) ckj d k; vuq
ifLFkr
(d) Sickle cell anaemia
(iv) XX
(d) Sickle cell anaemia
(iv) XX
(e) Down's syndrome
(v) Pleiotropic gene
(e) Down's syndrome
(v) Pleiotropic gene
– XO
Select the correct option
lgh fod Yi d kspqfu;s&
(1) a – iv, b – iii, c – ii, d – v, e – i
(1) a – iv, b – iii, c – ii, d – v, e – i
(2) a – iii, b – iv, c – ii, d – v, e – i
(2) a – iii, b – iv, c – ii, d – v, e – i
(3) a – iii, b – ii, c – v, d – i, e – iv
(3) a – iii, b – ii, c – v, d – i, e – iv
(4) a – iv, b – iii, c – ii, d – i, e – v
(4) a – iv, b – iii, c – ii, d – i, e – v
RESONANCE
– XO
XIII ResoMost_STP 33
111. The outer most limiting layer of mycoplasma
is made up of
(1) Cell wall
111. ekbd ks
Iy kTek d h lclsckgjh lhekLrj fd ld k cuk
gksrk gS
(2) Cell membrane
(3) Mucilaginous sheath (4) slime layer
112. Which one is not correctly matched
(1) d ks
f'kd k fHkfÙk
(2) d ks
f'kd k d y k
(3) 'y s
"ekijr
(4) Ly kbe Lrj
112. fuEu ea
slsd kSulk lgh lqesfy r ughagSA
(1) Cytokinin – cell division
(1) lkbVks
d kbfuu – d ksf'kd k foHkkt u
(2) IAA – cell wall elongation
(2) IAA – d ks
f'kd k fHkfÙk foo) Zu
(3) Abscisic acid – stomatal closure
(4) Gibberellic acid – Leaf fall
113. Given bellow the following terms.
(3) ,fClfld vEy – ja
/kzksad kscan d juk
(4) ft Ccjs
fy d vEy – i.kZ>M+u
113. uhpsd q
N 'kCnkofy ;kanh xbZgSa
(a) Pollen grains
(a) ijkxd .k
(b) Sporogenous tissue
(b) Liks
jkst hul Å rd
(c) Megaspore mother cell
(d) Synergid
(e) PEN
(f) Nucellus
(g) Aleuron layer
(c) es
xkLiksj ekr`d ksf'kd k
(d) lhujft M
(e) PEN
(f) cht k.Md k;
The correct ploidy level of above terms is given
(g) ,Y;w
jkWu ijr
in which option -
mijksDr 'kCnkofy ;ksad klghxq
f.krkLrj fd l fod Yi
(1) a - n, b - 2n, c - 2n, d - n, e -3n, f - 2n, g - 2n
esafn;k x;k gS-
(2) a - n, b - n, c - 2n, d - n, e -2n, f - 2n, g - 3n
(1) a - n, b - 2n, c - 2n, d - n, e -3n, f - 2n, g - 2n
(3) a - n, b - 2n, c - 2n, d - n, e -3n, f - 2n, g - 3n
(2) a - n, b - n, c - 2n, d - n, e -2n, f - 2n, g - 3n
(4) a - n, b - n, c - 2n, d - n, e -n, f - 2n, g - 3n
(3) a - n, b - 2n, c - 2n, d - n, e -3n, f - 2n, g - 3n
(4) a - n, b - n, c - 2n, d - n, e -n, f - 2n, g - 3n
114. Phenetic classification is based on
(1) dendrograms based on DNA characteristics
(2) sexual characteristics
114. Q hfufVd oxhZ
d j.k fd l ij vk/kkfjr gSA
(1) DNA vfHky {k.kks
aij vk/kkfjr MsUMªksxz
kWEl ij
(3) the ancestral lineage of existing organisms
(2) y S
fxd vfHkYk{k.k ij
a
(4) observable characteristics of existing
(3) orZ
eku t hoks
ad siwoZt oa
'kksij
organisms
RESONANCE
(4) orZ
eku t hoks
ad sizsf{kr fd ;sx;svfHky {k.kksaij
XIII ResoMost_STP 34
115. Increase in concentration of the toxicant like
115. mÙkjks
rj iks"k Lrjksaesafo"kkDr inkFkZt Sl sDDT d h
DDT at successive trophic levels refers to
lkUnzrk esac<+ksÙkjh fd l : i esat kuh t krh gS
(1) Bioremediation
(1) t S
o fuLrkj.k (Bioremediation)
(2) Biological oxidation
(2) t S
fod vkWDlhd j.k (Biological oxidation)
(3) Biomagnification
(3) t S
o vko/kZu (Biomagnification)
(4) Elusion
(4) 'kkj.k (Elusion)
116. The floral formula
is that of
iq"i lw=k fd ld k gSA
116.
(1) Tomato
(2) Tulip
(1) VekVj
(2) V~
;wfy i
(3) Soybean
(4) Sunnhemp
(3) lks
;kchu
(4) lugs
Ei
117.
117.
In the above pedigree chart, shows which trait
and what will the genotype of parents
mijksDr oa'kkoy h pkVZd kSu lsfo'ks"kd d ksn'kkZrk gS
(1) Autosomal recessive Aa + × Aa
rFkk t ud ksad k t hu çk: i D;k gksxk\
(2) Sex linked recessive Aa + × aa
(1) Autosomal recessive Aa + × Aa
(3) Autosomal dominant aa + × Aa
(4) Sex linked dominant Aa + × Aa
(2) Sex linked recessive Aa + × aa
(3) Autosomal dominant aa + × Aa
(4) Sex linked dominant Aa + × Aa
118. The technical term used from the androecium
in a flower of China rose (Hibiscus
rosasinensis) is
ikfjHkkf"kd 'kCn bLrseky fd ;k t krk gS
(1) Diadelphous
(2) Polyandrous
(3) Polyadelphous
(4) Monadelphous
119. An element playing important role in nitrogen
fixation is
(1) Copper
(2) Manganese
(3) Zinc
(4) Molybdenum
RESONANCE
118. xq
M+
gy (fgfcLd l jks
t kflus
fll ) es
a
aiq
exa d sfy, d kuSlk
(1) f}la
?kh
(2) cgq
iaqd sl jh
(3) cgq
l a?kh
(4) ,d la
?kh
119. ukbVª
kst u- fLFkjhd j.kesaegRoiw.kZHkwfed kfuHkkusoky k
,d rRo d kSulk gS
(1) d kW
ij ¼rkez½
(2) eS
xuht
a
(3) ft a
d
(4) eks
fy CMs
ue
XIII ResoMost_STP 35
120. Which of the following pair is incorrect –
(1) Clown fish & sea anemone – Mutualism
(2) Abingdon tortoise & Goat– Competition
(3) Orchid ophrys & species of bees
–
Co-evolution
120. fuEu es
alsd kSulk ;qXe lgh ughagS–
(1) Clown fish & sea anemone – lgks
id kfjrk
(Mutualism)
(2) Abingdon tortoise & Goat– izfrLi/kkZ
(Competition)
(4) Opuntia – Cochineal insect
(3) Orchid ophrys & species of bees–
lg&fod kl (Co-evolution)
(4) ukxQ uh– d ks
fd fu;y d hV (Cochineal insect)
121. Leghaemoglobin in root nodules of legumes
(1) Protects nitrogenase
121. f'kEcks
a(legumes) d h ewy xazfFkd kvksaesaik;k t kus
oky k y SxfgeksXy ksfcu D;k d jrk gSA
(2) Converts N2 to NH3
(1) ukbVª
ksft ust d h j{kk
(3) Oxidises NO2 to NO3
(4) helps in development of infection threads
(2) N2 d kNH3 es
aifjorZu
(3) NO2 d kNO3 es
avkWDlhd j.k
(4) la
Ø e.k rarqv ksad sfod kl esalgk;rk
122. Plasmodesmata take part in
(1) Cytoplasmic streaming
(2) Synchronous mitotic divisions
122. Iy kTeks
MsLesVkfd lesaHkkx y srsgSaA
(1) d ks
f'kd kæO;h izokg esa
(3) Movements of substance between plant cells
(2) fluØ ks
ul lw=kh foHkkt u esa
(4) Locomotion in unicellular organism
(3) ikni d ks
f'kd kvksad schp inkFkksZad sifjogu esa
(4) ,d d ks
f'kd h; t ho esaxeu esa
123. Pr state of phytochrome absorbs light wave
length of
123. Pr iz
d kj d sQ kbVks
Ø ks
e ) kjkiz
d k'kd hd kSulhrja
xnS
/
;Zvo'kksf"kr gksrh gSaA
(1) 660 nm
(2) 640 nm
(3) 620 nm
(4) 720 nm
124. The vascular cambial ring of a dicot stem is
(1) 660 nm
(2) 640 nm
(3) 620 nm
(4) 720 nm
124. ,d f}cht i=kh LrEHk d h la
oguh ,/kk oy ; gS
(1) Primary in origin
(1) mRifÙk es
aizkFkfed
(2) Secondary in origin
(2) mRifÙk es
af}rh;d
(3) Partly primary partly secondary in origin
(4) Embryonic in origin
RESONANCE
(3) vka
f'kd : i lsiz
kFkfed rFkkvkfa'kd : i lsf}rh;d
(4) mRifÙk es
aHkzw.kh;
XIII ResoMost_STP 36
125.
125.
Select the correct option having correct
ml lghfod Yi d kspq
fu;sft les
amijks
Dr fp=kd slgh
labelling in above diagram.
ukekad u d ksn'kkZ;k x;k gSA
(1) i – Denaturation, ii – Primers, iii – Annealing,
(1) i – fuf"Ø ; d j.k]ii – çkbelZ
]iii – rkikuq'khy u]iv
iv – DNA ligase, v – Extension
(2) i – Heating, ii – Anealing, iii, Primers, iv –
DNA Polymerase, v – Amplification
(3) i – Dinaturation, ii – Primers, iii – Annealing,
iv – Taq DNA Polymerase, v – Extension
(4) i – DNA, ii – Denaturation, iii – Primer, iv –
Annealing, v – Extension
– DNA y kbxs
t ]v – çlkj
(2) i – rki]ii – rkikuq
'khyu]iii, çkbelZ
]iv – DNA
ikyhejs
t v – vko/kZu
(3) i – fuf"Ø ;d j.k] ii – çkbelZ
]iii – rkikuq
'khyu]iv
– Vkd DNA ikyhejs
t ]v – çlkj
(4) i – DNA, ii – fuf"Ø ;d j.k] iii – çkbej] iv –
rkikuq
'khyu v – çlkj
126. Edible part in the fruit of Litchi is
126. y hph d sQ y es
a[kkus;ksX; Hkkx gSA
(1) Mesocarp
(2) Aril
(1) e/;Q y fHkfÙk
(2) ,fjy
(3) Fleshy thalamus
(4) Cotyledons.
(3) eka
l y iq"iklu
(4) cht i=k
127. Flowers are zygomorphic in
127. ,d O;kllefer iq
"i fd lesagksrsgSaA
(1) Mustard
(2) Radish
(1) ljlks
a
(2) ew
yh
(3) lily
(4) Candytuft
(3) fy y h
(4) d S
fUMV¶V
RESONANCE
XIII ResoMost_STP 37
128. Which of the following is incorrectly matched
128. cht k.MU;kl d sla
nHkZesafuEu esad kSu viusfp=k ls
with its diagram in respect to placentation
lgh lqesfy r ugh gS
(1) Primrose
(1) iz
kbejkst
(2) Marigold
(2) xs
ank
(3) Tomato
(3) VekVj
(4) Pea
(4) eVj
129. Match the column
Column-I
129. d kW
y e lqesfy r d hft ;s
Column-II
1. Fasciculated roots
a. Tinospora
2. Pneumatophores
b. Heritiera
3. Haustorial roots
d kWy e-I
d kWy e-II
1. iq
y fd r ewy sa
a. fVuks
Liksjk
c. Asparagus
2. U;w
esVkQ ks
lZ
b. gs
fjfV,jk
4. Stilt roots
d. Viscum
3. pw
"kd kaxhewy sa
c. ,Lis
jsxl
5. Assimilatory roots
e. Sugarcane
4. fLVYV ew
y sa
d. foLd e
(1) l-c, 2-b, 3-d, 4-e 5-a
5. Loka
xhd kjh ewy sa e. xUuk
(2) I-b, 2-c, 3-d, 4-e, 5-a
(1) l-c, 2-b, 3-d, 4-e 5-a
(3) l-c, 2-d, 3-e, 4-a, 5-b
(2) I-b, 2-c, 3-d, 4-e, 5-a
(4) l-c 2-a 3-b 4-e 5-d
(3) l-c, 2-d, 3-e, 4-a, 5-b
(4) l-c 2-a 3-b 4-e 5-d
RESONANCE
XIII ResoMost_STP 38
130. In leaves of C4 plants malic acid synthesis
130. C4 ikS
/kksad hifÙk;ksaesaCO2 LFkk;hd j.kd sle; eSfy d
during CO2 fixation occurs in -
vEy d k fuekZ.k d gk¡gksrk gS\
(1) Bundle sheath
(2) Mesophyll
(1) iw
y kPNn esa
(2) i.kZ
e/;ksrd esa
(3) Epidermis
(4) Guard cells
(3) ckg~
;RoPkk esa
(4) }kj d ks
f'kd kvksaesa
131. The chemiosmotic couling hypothesis of
oxidative phosphorylation proposes that
adenosine triphosphate (ATP) is formed
131. vkW
Dlhd kjhQ kWLQ ksfjyhd j.kd hjlksijklj.khd ify ax
ifjd Yiuk d svuql kj ,Mhuksflu VªkbQ kWLQ sV (ATP)
because
d k fuekZ.k gksrk gSD;ksafd
(1) A proton gradient forms across the inner
(1) vkUrfjd d y k d svkj ikj ,d iz
ksVksu izo.krk
fufeZr gksrh gS
membrane
(2) There is a change in the permeability of the
(2) ;gk¡ ,Mhuks
fl u MkbQ kWLQ sV (ADP) d h vksj
inner mitochondrial membrane towards
ekbVksd kWfUMª;k d h vkUrfjd d y k d h ikjxE;rk
adenosine diphosphate (ADP)
esaifjorZu gksrk gS
(3) High energy bonds are formed in
mitochondrial proteins
(4) ADP is pumped out of the matrix into
(3) ekbVkd
s kfWUMª
;y iz
kVshUl es
amPp mt kZ;q
Dr ca
/kgkrssgS
(4) eS
fVª
Dl d hADP vUrjdykvod k'kes
aiEi dht krhgS
intermembrane space.
132. d kW
y e lqesfy r d hft ;s
132. Match the Column
Column-I
Column-II
d kWy e-I
d kWy e-II
(i) Pollen Kitt
(a) Typha
(i) ikW
y u fd V
(a) VkbQ k
(ii) Sporopollenin
(b) Attracts pollen
(ii) Liks
jksiksy sfuu
(b) cht k.M d s
(iii) Filiform apparatus
tube towards
cht k.M}kj d h vksj
micropyla of ovule
ijkxuy h d ksvkd f"kZr
(c) Present in
d juk
fossilized pollen
grains
(iv) Pollinium
(iii) ra
rq: ihmid j.k
(c) t hok'eh; ijkxd .kks
a
esamifLFkr
(d) Protection from
(iv) ikW
y hfu;e
(d) UV fd j.kks
alslqj{kk
(v) Compound pollen grain (e) Calotropis
(v) la
;qDr ijkxd .k
(e) d s
y kVªkWfil
(1) i - e, ii - d, iii - b, iv - c, v - a
(1) i - e, ii - d, iii - b, iv - c, v - a
(2) i - c, ii - b, iii - d, iv - e, v - a
(2) i - c, ii - b, iii - d, iv - e, v - a
UV rays
(3) i - d, ii - c, iii - b, iv - e, v - a
(4) i - b, ii - c, iii - a, iv - e, v - d
RESONANCE
(3) i - d, ii - c, iii - b, iv - e, v - a
(4) i - b, ii - c, iii - a, iv - e, v - d
XIII ResoMost_STP 39
133. Crossing over occurs during
133. t hufofue; (Ø kfla
x vksoj) fd l nkSjku izd V gks
rkgSA
(1) Leptotene
(2) Pachytene
(1) y s
IVksVhu esa
(2) is
d hVhu es a
(3) Diplotene
(4) Diakinesis
(3) fMIy ks
Vhu esa
(4) Mk;d kbus
fll esa
134. Segregation of mendelian factors (Aa) occurs
134. es
.Ms
fy;u d kjd kas(Aa) d ki`
FkDd j.k fd l le; iz
dV
during
gkrsk gS
A
(1) Diplotene
(1) fMIy ks
Vhu esa
(2) Anaphase-I
(2) ,ukQ s
t -I esa
(3) Zygotene / Pachytene
(3) t kbxks
Vhu / isd hVhu esa
(4) Anaphase-II
(4) ,ukQ s
t -II es
a
135. Somatic cell hybrids are produced with the help
of
135. d kf;d d ks
f'kd klad j fd ld hlgk;rklsmRiUu gksrs
gSaA
(1) Polyhydroxy glycol
(2) Polyethylene glycol
(1) iky hgkbMª
kWDlh y kbd ksy
(3) Polyvinyl glycol
(2) iky h bFkkby hu Xy kbd kW
y
(4) Polyprolene glycol
(3) iky hfoukby Xy kbd kW
y
(4) iky hiz
ksfy u Xy kbd kWy
136. Infectious proteins are present in
(1) Prions
(2) Viroids
(3) Satellite viruses
(4) Gemini viruses
136. la
Ø ked izksVhusafd u esagksrh gSaA
(1) iz
kbvkWUl esa
(2) ok;jkW
M~l esa
(3) vuq
"kaxh ok;jlksaesa
(4) t s
feuhok;jlksaesa
137. Semidwarf varieties of wheat developed by
137. ukeZ
u cks
jykx }kjkxs
gw
¡d hv/kZckS
uhfd Lesfod flr d h
Norman borlaug as a result high yielding &
xbZbld sifj.kke Lo: i Hkkjr es
aHkhxs
gw¡mRiknd {ks
=kksa
disease resistance varieties of wheat
esaxsgw¡d h mPp mRiknd rFkk jksx izfrjks/kh fd Lesa
developed in wheat yielding areas in india.
fod flr d h xbZ;sFkhA
These were
(1) Pusa shubhra
(2) Pusa sadabahar
(1) iw
l k 'kqHkzk
(2) iw
l k lnkcgkj
(3) Sonalica & kalyan sona
(3) lks
ukfy d k & d Y;k.k lksuk
(4) Pusa komal
(4) iw
l k d ksey
RESONANCE
XIII ResoMost_STP 40
138. In Whittaker's classification which of the
138. fOgVS
d j d soxhZ
d j.kes
afuEu esalsd kSulk,d ekin.M
following is not mentioned as a criteria
d s: i es
a'kkfey ughagS-
(1) Thallus arganization & mode of nutrition
(1) FkS
y l laxBu rFkk iks"k.k d k iz
d kj
(2) Cell structure & Reproduction
(2) d ks
f'kd k lajpuk rFkk t uu
(3) Phylogenetic relationships
(3) t kfro`
Ùkh; laca/k
(4) Mode of locomotion
(4) xeu d k iz
d kj
(i)
(i)
(ii)
(ii)
139.
139.
Given below the following statements about
ukekad u (i) rFkk(ii) d sckjsesauhpsd Fku fn;sx;sgS
a-
labelling (i) and (ii)
(a) Labelling (ii) provides protection to plant
lscpkusd sfy , lqj{kk iz
nku d jrk gS
from dessication by water current
(b) Labelling (i) can fix atmospheric nitrogen
(c) Labelling (ii) is also found around pollen
grains of hydrophilous plants
(c) ukeka
d u (ii) t y ijkfxr ikniksad sijkxd .kksad s
pkjksavksj Hkh ik;k t krk gSA
(d) Labelling (i) is found is Nostoc & anabaena
(e) Labelling (i) & (ii) are features of
autotrophs
(b) ukeka
d u (i) O2 d h mifLFkfr esaHkh ok;qe.My h;
ukbVªkst u d ksfLFkj d j ld rk gS
even in the presence of O2
photosynthetic
(a) ukeka
d u (ii) ikni d kst y /kkjkvksa}kjkd VusQ Vus
&
chemosynthetic autotrophs.
(d) ukeka
d u (i) ukW
LVkWd rFkk,sukfcukesaik;kt krkgS
(e) ukeka
d u (i) & (ii) izd k'k la'y s
"kh vkWVksVªkWQ rFkk
jlk;u la'y s"kh vkWVks
VªkWQ d k y{k.k gS
In the above statements, pick up the incorrect
mijks
Dr d Fkuks
aes
alsukekad u (i) & (ii) d sckjses
avlR;
statements about labelling (i) & (ii)
d Fku Nk¡fV;sa
(1) b, c, e
(1) b, c, e
(2) a, b, d
(2) a, b, d
(3) b, e
(3) b, e
(4) b, d, e
(4) b, d, e
RESONANCE
XIII ResoMost_STP 41
140. Tall & Red (TTRR ) flowered Antirrhinum plant
140. y EcsrFkk y ky iq
"i/kkjh (TTRR ) ,UVhjhue d sikni
crossed with dwarf and white flowered (ttrr )
d ksckSusrFkk 'osr iq"i/kkjh (ttrr ) ,UVhjhue d sikni
Antirrhinum plant in F1 generation, all the plants
d slkFkØ kW
l d jk;kx;krksF1 ih<+
hes
alHkhikni y Ecs
were Tall & Pink flowered. F1 generation is
crossed with double recessive parent, what
will the phenotypic ratio obtained in F 2
rFkk xqy kch iq"i/kkjh FksA F1 ih<+h d ksnksgjsvçHkkoh
t ud d slkFkØ kW
l d jkrsgS
arksF2 ih<+hes
ay{k.kç: ih
generation and what will be possibility of
vuqikr D;k gksxk rFkk y ky o y Ecsiq"i/kkjh ikni
occurence of tall & Red flowered plants.
mRiUu gksusd h D;k laHkkouk gksxh
(1) 9 : 3 : 3 : 1, 25%
(2) 3 : 1 , 50%
(1) 9 : 3 : 3 : 1, 25%
(2) 3 : 1 , 50%
(3) 1 : 1, 0%
(4) 1 : 1 : 1 : 1, 0%
(3) 1 : 1, 0%
(4) 1 : 1 : 1 : 1, 0%
141. Pappus is modification of
141. iS
il fd ld k : IkkUrj.k gSA
(1) Bracts
(2) Bracteoles
(3) Corolla
(4) Calyx
142. Normal HB (A) gene
(1) lgi=kks
ad k
(2) lgif=kd kvks
ad k
(3) ny iq
at d k
(4) cká ny iq
at d k
......GAG....
.
.... CTC....
Diagram (1)
Sickel cell Hb(S) gene
142. Normal HB (A) gene
......GAG....
.
.... CTC....
Sickel cell Hb(S) gene
... GTG....
Diagram (1)
... GTG....
..(i)....
..(i)....
Diagram (2)
Diagram (2)
In the above diagram (2) (i), (ii) and (iii) are
mijksDr fp=k ¼2½esaØ e'k%(i), (ii) rFkk (iii) gSa&
respectively -
(1) (i) GUG (ii) GAG (iii) valine
(1) (i) GUG (ii) GAG (iii) valine
(2) (i) GUG (ii) CAC (iii) Glutamic acid
(2) (i) GUG (ii) CAC (iii) Glutamic acid
(3) (i) CAC (ii) GUG (iii) Valine
(3) (i) CAC (ii) GUG (iii) Valine
(4) (i) GTG (ii) CAC (iii) Glutamic acid
(4) (i) GTG (ii) CAC (iii) Glutamic acid
RESONANCE
XIII ResoMost_STP 42
143. How many meiosis and mitosis are required
143. ,d ekbØ kL
sikjs ekr`d kfs'kd klsuj xs
feVkQs kbV cukusd s
for the formation of a male gametophyte from
fy, fd rusfe;kfsll rFkkekbVkfsll vko';d gkrssgS
Aa
a pollen mother cell / microspore mother cell
(1) 2 fe;kfll rFkk 2 ekbVks
fll
(1) 2 meiosis and 2 mitosis
(2) 1 Meiosis & 1 Mitosis
(2) 1 fe;kfll rFkk1 ekbVks
fll
(3) 1 fe;kfll rFkk3 ekbVks
fll
(3) 1 Meiosis & 3 Mitosis
(4) 1 fe;kfll rFkk2 ekbVks
fll
(4) 1 Meiosis & 2 Mitosis
144. W hich of the following statements are
144. fuEufy f[kr es
alsd kSulsd Fku vlR; gS
a\
(a) js
LVªhD'ku ,.Mks
U;wfDy ,st st vkjcj] ukFkUl rFkk
incorrect
(a) Restriction endonucleases discovered by
Arber, Nathans and Smith
(b) Cry I Ab gene controls bollworm while cry
IAc and cry II Ab control the cotton
cornborer
(c) In Bam H I 'am' stand for species name
amyloliquifeciens
(d) Selectable marker helps in identifying and
fLeFk }kjk [kks
t sx;sA
(b) Cry I Ab t hu cky oeZd ksfu;a
f=kr d jrkgSat cfd
Cry I Ac rFkk cry II Ab d ikl] d kW
uZcksjj d ks
fu;af=kr d jrk gSaA
(c) Bam H I esa 'am' t kfr
d s uke
,ekby sfyfDoQ s
f'k;Ul d sfy , gSA
(d) lys
DVs
cy ekd jZ ¼oj.k;kXs; fpUá d ½Vª
ka
l Q ks
jeUV~
l
eliminating transformants and selectively
d ksigpkuuso gVkuses
algk;d gksrsgSarFkk
permitting the growth of the non-
p;ukRed : i lsukW
u&Vª
ka
l Q ks
jes
UV~
l d ho`
f) d ks
transformants
izs
fjr d jrk gSaA
(1) a & b
(2) b & c
(1) a & b
(2) b & c
(3) a & b
(4) b & d
(3) a & b
(4) b & d
145. Exploring molecular, genetic and species level
145.vkfFkZ
d egRo d smRiknksad sfy ;svk.kfod ]vkuqokaf'kd
diversity for products of economic importance
rFkk t kfr Lrj ij fofo/krk d k vUos"k.k d gy krk gS-
is called
(1) t S
o vko/kZu (Biomagnification)
(1) Biomagnification
(2) t S
o fuLrkj.k (Bioremediation)
(2) Bioremediation
(3) t S
o vUos"k.k (Bioprospecting)
(3) Bioprospecting
(4) t S
o fujh{k.k (Biomonitering)
(4) Biomonitering
146. Green leaf-like one internode long stem
branches/phylloclades are called
146. gjh i.kZ
-ln`
'; ,d ioZ;qDr y Ech LrEHk 'kk[kk,¡/
d gy krh@d gy krsgS
(1) Phylloclades
(2) Phyllodes
(1) i.kkZ
HkLrEHk
(2) i.kkZ
Hk o`Ur
(3) Bulbils
(4) Cladodes
(3) i=kiz
d fy d k
(4) i.kkZ
HkioZ
RESONANCE
XIII ResoMost_STP 43
147. Match the column
147. d kW
y e lqesfy r d hft ;s
Column-I
Column-II
d kW
y e-I
d kWy e-II
(a) Lungs of planet
(i) Ecosystem
(a) y a
Xl vkWQ Iy susV
(i) ikfjfLFkfrd ra
=kfofo/krk
(b) ukby ipZ
(ii) d a
xk:
(c)  - fofo/krk
(iii) t S
o fofo/krk cgqy
diversity
(b) Nile perch
(ii) Kangaroo
(c) - diversity
(iii) Biodiversity rich
{ks=k
areas
(d) Endemism
(d) LFkkfud rk (Endemism)(iv) fld fy M eNy h d k
(iv) Elimination of
foy ksiu
cichlid fish
(e) Hot spot
(v)Amazon rain
(e) rIr LFky (Hot spot)
(v) ves
t u o"kkZou
forest
(1) (a) - i (b) - v (c) - iii (d) - ii (e) iv
(1) (a) - i (b) - v (c) - iii (d) - ii (e) iv
(2) (a) - v (b) - iv (c) - iii (d) - i (e) ii
(2) (a) - v (b) - iv (c) - iii (d) - i (e) ii
(3) (a) - v (b) - iv (c) - i (d) - ii (e) iii
(3) (a) - v (b) - iv (c) - i (d) - ii (e) iii
(4) (a) - iii (b) - v (c) - i (d) - ii (e) iv
(4) (a) - iii (b) - v (c) - i (d) - ii (e) iv
148. Breeding of crops with high level of minerals,
148. [kfut ks
a, foVkfeUl rFkk izksVhUl d smPp Lrj ;qDr
Q ly ksad k izt uu d gy krk gSA
vitamins and proteins is called
(1) Biofortification
(1) t S
oiqf"Vd j.k (ck;ksQ kWVhZfQ d s'ku)
(2) Biomagnification
(2) t S
ovko/kZu (ck;kseSXuhfQ d s'ku)
(3) Micropropagation
(3) lw
{e izo/kZu (ekbØ ksizksisxs'ku)
(4) Somatic hybridisation
(4) d kf;d iz
o/kZu (lksesfVd gkbfczMkbt s'ku)
149.
149.
In the above diagrams, Identify the correct
labelling
mijksDr fp=kksaesalgh ukekad u d ksigpkfu;s
(1) a - Asparagus , b - Fucus , c - Dictyota ,
(1) a - ,LiS
jsxl , b - ¶;wd l , c - fMDV;ksVk, d -
d - Polysiphonia
(2) a - Chara , b - Fucus , c - Laminaria , d Polysiphonia
(3) a - Chara , b - Laminaria , c - Fucus , d Porphyra
(4) a - Asparagus , b - Dictyota , c - Laminaria
, d - Porphyra
RESONANCE
ikWy hl kbQ ksfu;k
(2) a - d kjk, b - ¶;w
d l , c - y sfeusfj;k, d -
ikWy hl kbQ ksfu;k
(3) a - d kjk, b - y s
feusfj;k, c - ¶;w
d l , d - ikWjQ k;jk
(4) a - ,LiS
js
xl , b - fMDV;ks
Vk, c - y sfeusfj;k, d -
ikWjQ k;jk
XIII ResoMost_STP 44
150. In gel electrophoresis which of the following
150. t S
y bys
DVª
ks
Q ks
js
fll es
afuEu es
alsd kS
ulk;kS
fxd DNA
compound is used in the staining of DNA
d svfHkjat u esaiz;qDr fd ;k t krk gS
(1) Methyl bromide
(1) feFkkby cz
ksekbM
(2) Ethyle ethane sulphonate
(3) Ethedium bromide
(2) bFkkby bFks
u lYQ ksusV
(3) bFkhfM;e cz
ksekbM
(4) Ethyl bromide
(4) bFkkby cz
ksekbM
151. Which is the following harmones has no control
over gluconeogenesis?
151. fuEu es
alsd kuS lsgkekuZs d kfu;U=k.kXyw
d kfsu;kfst us
fll
ij ughagksrk\
(1) glucagon
(2) insulin
(3) aldosteron
(4) adrenalin
152. A person passes much urine and drinks much
(1) Xy w
ds
xkWu
(2) bulw
fy u
(3) ,YMks
LVsjkWu
(4) ,Mª
uyhu
s
152. ,d O;fDr vf/kd ew
=k R;kx d jrk gSo vf/kd t y
water but his blood glucose level is normal.
ihrkgSrc Hkhmld k: f/kj Xywd ks
l Lrj lkekU; jgrk
This condition may be the result of
gSA ;g ifjfLFkfr fd ld k ifj.kke gS\
(1) a reduction in insulin secretion from
(1) vXuk'k; lsbUlw
fy u d sò ko esad eh vkukA
pancrease
(2) a reduction in vasopressin secretion from
posterior pituitary
(3) a fall in the glucose concentration in urine
(2) i'p ih;w
"k lsoklksçsflu d sò ko esad eh vkukA
(3) ew
=k esaXy wd ksl d h lkUnzrk esad eh vkukA
(4) Xy w
d kst u d sò ko.k esao`f) A
(4) an increase in secretion of glucogen.
153. The treatment of snake-bite by antivenine is
153. lk¡
i d sd kVusd k by kt çfrfo"k d s}kjk fd ;k t krk
an example of
gS] ;g mnkgj.k gS&
(1) Artificiallyacquired active immunity
(1) d `
f=ke mikft Zr lfØ ; çfrj{kk
(2) Artificiallyacquired passive immunity
(2) d `
f=ke mikft Zr fuf"Ø ; çfrj{kk
(3) Naturally acquired passive immunity
(3) çkd `
frd mikft Zr fuf"Ø ; çfrj{kk
(4) Specific natural immunity
154. Basement membrane is made up of
(4) fof'k"V çkd `
frd çfrj{kk
154. vk/kkjh; d y k fd ld h cuh gks
rh gS\
(1) only epidermal cell
(1) d s
oy bihMeZd ksf'kd kvksad k
(2) endodermal cell
(2) ,.Mks
MeZd ksf'kd kvksad k
(3) no cell product of epithelium
(3) mid y k lsmRiUu d ks
f'kd k,saugha
(4) both (1) and (2)
(4) (1) rFkk (2) nks
uksa
RESONANCE
XIII ResoMost_STP 45
155. Which part of the brain is affected first in a
155. ,d 'kjkcheuq
"; d sefLr"d d kd kS
u lkHkkx loZçFke
drunk person ?
çHkkfor gksrk gS\
(1) Cerebrum
(1) çefLr"d
(2) Olfactory lobe
(2) ?kz
k.k iky h
(3) Cerebellum
(3) ls
jhcsy e
(4) Medulla oblongata
(4) es
M~;wy kvkWCy ksaxsVk
156. Select incorrect matching
156. xy r es
y d kspqfu;s&
(1) Pivot joint - atlas and axis
(1) ikboV la
f/k - ,Vy l o v{k d se/;
(2) Saddle joint - carpels and metacarpal of thumb
(3) Pennatula - Sea pan
(4) tetany - low calcium level in blood
(2) lS
My la
f/k- va
xw
Bsd sd kiZ
y o es
Vkd kiZ
y d se/;
(3) fius
Vwy k - lh iku
(4) VhVs
uh - : f/kj esafuEu d SfYl;e Lrj
157. Which of the following is important for muscle
concentration
and
nerves
impulse
transmission?
157 fuEu es
alsd kSu lk rRo isf'k;ksad slad qp u o rfU=kd k
vkosx lap j.k gsrqegRoiw.kZgS&
(1) Ca2+ vk;u
2+
(1) Ca ions
(2) Ca++ ,oaMg++ vkW
;u
(2) Ca++ and Mg++ ions
(3) Mg++ vk;u
(3) Mg++ ions
(4) Fe2+ vk;u
(4) Fe2+ ions
158. Which of the following statement is / are true ?
(a) Urine is hypertonic in distal convoluted
(a) nw
jLFkd .qMfyr ufyd kes
aew
=kvfrijkljhgkrskgS
A
(b) t c ew
=kla
xkzgd ufyd klsxq
t jrkgSrc vYiijkljh
tubule
(b) When the urine passes into the collecting
tubule, it becomes hypotonic
(c) Urine is isotonic in proximal convoluted
tubule
(d) Urine becomes more and more hypotonic
as it passes through the henel’s loop
(1) a and d only
(2) a, b,and c only
(3) b and c only
(4) all incorrect
RESONANCE
158. fuEufyf[kr d Fkuka
ses
alsd kuSlk@d kuSlsd Fku lR; gS
\
gksrk gS
(c) lehiLFkd .
qMfyr ufyd kes
aew
=kleijkljhgkrskgS
A
(d) ew
=kvR;f/kd vYiijkljhgkst krkgSt c og gsuy s
y wi lsgksd j xqt jrk gSA
(1) d s
oy a vkSj d
(2) d s
oy a, b ,oac
(3) d s
oy b vkSj c
(4) lHkh xy r
XIII ResoMost_STP 46
159. Match the excretory functions of section-l with
159. oxZ
-I es
afn;sx;smRlt hZd k;ks±d ksoxZ-II esafn;sx;s
the part of the excretory system in section-ll.
mRlt hZrU=kksad sHkkxksad slkFk lqesfy r d hft , rFkk
Choose the correct combination from among
fn;sx;smRrj fod Yiks
aes
alslgh;q
Xe d kp;u d hft ,
the answers given.
Section l
Section-ll
&
oxZ-l
oxZ-ll
(ii) Concentration of urine (B) Ureter
(i) ijkfuL;Unu
(A) gs
uy sy wi
(iii) Transport of urine
(C) urinary bladder
(ii) ew
=klkUnzrk
(B) ew
=k okfguh
(iv) Storage of urine
(D) Malpighian
(iii) ew
=k d k lap j.k
(C) ew
=kk'k;
corpuscles
(iv) ew
=k laxzg
(D) eS
Yih?kh;u
(i) Ultra filtration
(A) Henle’s loop
(E) Proximal
d kWiZl Yl
convoluted tubule.
(E) lehiLFk d q
.Mfy r
ufyd k
(1) (i) - D, (ii) - A, (iii) - B, (iv) - C
(2) (i) - D, (ii) - C, (iii) - B, (iv) - A
(3) (i) - E, (ii) - D, (iii) - A, (iv) - C
(4) (i) - E, (ii) - D, (iii) - A, (iv) - B
(1) (i) - D, (ii) - A, (iii) - B, (iv) - C
(2) (i) - D, (ii) - C, (iii) - B, (iv) - A
(3) (i) - E, (ii) - D, (iii) - A, (iv) - C
(4) (i) - E, (ii) - D, (iii) - A, (iv) - B
160. Which of the following statements are wrong
(i) Leucocytes disintegrate in the spleen and
the liver.
(i) Y;w
d ksl kbV d ksf'kd k,¡Iy hgk o ;Ñ r esafo?kfVr
gksrh gSA
(ii) RBC, WBC and blood platelets are
produced by bone marrow
(iii) Neutrophils bring about destruction and
detoxification of toxin of protein origin
(iv) The important function of lymphocytes is
to produce antibodies
(1) (i) and (ii) only
(2) (i) and (iv) only
(3) (i) and (iii) only
(4) (ii) and (iv) only
RESONANCE
160. fuEu es
alsd kSu lk d Fku xy r gS\
(ii) RBC, WBC o : f/kj Iy s
Vy sV~l vfLFk eTt k esa
curh gSaA
(iii) U;w
VªksfQ Yl çksVhu lsmRié fo"kksad k fouk'k o
fofo"kkfDrd j.k d jrh gSA
(iv) fy EQ ks
l kbV~l d k eq[; d k;Z ,.VhckWMht d k
mRiknu d juk gksrk gSA
(1) d s
oy (i) vkSj (ii)
(2) d s
oy (i) vkSj (iv)
(3) d s
oy (i) vkSj (iii)
(4) d s
oy (ii) vSkj(iv)
XIII ResoMost_STP 47
161. If it was possible to genetically engineer
161. ;fn vkuq
okaf'kd h izkS| ksfxd h d svuql kj ;g laHko gksrk
humans to be able to run long distances faster
fd ekuo Å ¡p kbZij y Echnwjhd ksrhozxfr lsnkS
M+usesa
at high altitudesd, which of the following would
leFkZgksrk]rc fuEu esalsd kSu lgk;d ughagksxk\
not help ?
(1) Increasing the thickness of the cellular lining
of the alveoli
(2) Increasing the amount of haemoglobin in
each red blood cell
(3) Decreasing the average size of the alveoli
(1) ,fYo;ks
y kbZd sd ksf'kd h; Lrj d h eksVkbZesao`f)
(2) iz
R;sd y ky jDr d ksf'kd kesagheksXy ksfcu d hek=kk
esao`f)
(3) ,fYo;ks
y kbZd svkSl r vkd kj esad eh
(4) (1) rFkk (3) nks
uksa
(4) both (1) and (3)
162.d kcZ
fud ,ugkbMªst d sfy , d kSulk d Fku vlR; gS
162. False about carbonic anhydrase is
(1) Minute quantities of this is present plasma also
(2) RBC contain high concentration of this
enzyme
(3) This enzyme facilitate the formation/
dissociation of carbonic acid in only one
(1) bld h lw
{e ek=kk Iy kT+ek esaHkh ik;h t krh gS
(2) RBC es
abl ,Ut kbe d hmPp lkUnz
rkik;ht krhgS
(3) ;g ,Ut kbe d s
oy ,d gh fn'kk esad kcZfud vEy
d k fuekZ.k@fo?kVu d jrk gS
(4) lHkh lR; gS
a
direction
(4) all are correct.
163. How does carbon monoxide, a poisonious gas
163. Lopfy r ;a
=kksa }kjk mRl ft Zr fo"kSy h xSl d kcZu
emitted by automobiles, prevent transport of
eksuksv kWDlkbM 'kjhj mÙkd ksaesavkWDlht u d sifjogu
oxygen into the body tissues.?
d ksfd l çd kj vo: ) d jrh gS\
(1) By changing O2 into CO2
(1) O2 d sCO2 es
aifjorZu }kjk
(2) By destroying heamoglobin.
(3) By forming a stable compound with
heamoglobin
(4) By destructing the reaction of O2 with
heamoglobin.
RESONANCE
(2) gheks
Xy ksfcu d ksu"V d jd s
(3) gheks
Xy ksfcu d slkFk LFkkbZ;kSfxd d sfuekZ.k }kjk
(4) gheks
Xy ksfcu d slkFk vkWDlht u d h fouk'kd kjh
vfHkfØ ;k }kjk
XIII ResoMost_STP 48
164.
164.
Correct matching is
lgh ;qXe gSa
(1) 1- bryophyta 2- peridophytes
(1) 1- cz
k;ksQ kbVk 2- VsfjMksQ kbVk
(2) 1- sponges
2- bryophytes
(2) 1- LiUt
2- cz
k;ksQ kbVk
(3) 1- algae
2- euspongia
(3) 1- 'kS
oky
2- ;w
LiksfUt ;k
(4) 1- spongilla
2- euspongia
(4) 1- Liks
fUt y k
2- ;w
LiksfUt ;k
165. Typhlosole of earth worm is (1) Internal median fold of ventral wall of
intestine
165. d s
ap q, d svka=koy u gS(1) vka
=k d h v/kj fHkfÙk d svkUrfjd oy u
(2) vka
=k d h i`"B fHkfÙk d svkarfjd oy u
(2) Internal median fold of dorsal wall of
intestine
(3) vka
=k d h ik'oZfHkfÙk d svkUrfjd oy u
(4) mijks
Dr esalsd ksbZ,d
(3) Internal median fold of lateral wall of intestine
(4) Any of above
166. In which of the following , proteins are absent
166. fuEu es
alsfd lesaçksVhu vuqifLFkr gksrk gS\
(1) Pancreatic juice
(2) saliva
(1) vXuk'k;h jl
(2) y kj
(3) Bile
(4) Intestinal juice
(3) fiÙk
(4) vkU=kh; jl
167. Which is correctly matched for human body
167. ekuo 'kjhj d sfy , lgh lq
esfy r ;qXe gS
(a) Hydrogen : 3.3%
(b) Carbon : 65%
(a) gkbMª
kst u : 3.3%
(b) d kW
cZu : 65%
(c) Mg : 0.1%
(d) Calcium : 1.5%
(c) Mg : 0.1%
fYl;e : 1.5%
(d) d S
(1) a and b only
(2) b and c
(1) d s
oy a rFkk b
(2) d s
oy b rFkk c
(3) c and d only
(4) a and d only
(3) d s
oy c rFkk d
(4) d s
oy a rFkk d
RESONANCE
XIII ResoMost_STP 49
168. Which of the following is correct represtation
168. fuEufyf[kr es
alsd kS
ulk,Mhukbfyd vEy d ksiz
nf'kZ
r
of Adenylic acid -
d jrk gS
(1)
(1)
(2)
(2)
(3)
(3)
(4)
(4)
169.
169.
(A)
(B)
(A)
(B)
(C)
(C)
(D)
(D)
Select the correct labelling for parts in above
mijksDr fp=k esafn;sx;sHkkxksad slgh ukekad u d k
diagram -
p;u d hft ;s-
(1) A - Lacteal
(2) B - capillaries
(3) C - Villi
(4) D - crypts
(1) A - y S
DVh;y
(2) B - d s
f'kd k,sa
(3) C - va
d qj
(4) D - fØ IV~
l
RESONANCE
XIII ResoMost_STP 50
170. Carbon monoxide has greater infinity for
170.vkD
Wlht u d hrq
y ukes
ad kcZ
uekuskvskDWlkbM d hghekXsykfscu
heamoglobin as compared to oxygen by
d ksxz
g.k d jusd h{kerk fd rusxq
.kk gkrsh gS
\
(1) 1000 times
(2) 200 times
(1) 1000 xq
.kk
(2) 200 xq
.kk
(3) 20 times
(4) 2 times
(3) 20 xq
.kk
(4) 2 xq
.kk
171. Choose correct statement about cockroach (i) If the head of cockroach cut off, it will live
for as long as one week
(ii) mosaic vision has less sensitivity and more
171. d kW
d jksp d sfo"k; esalgh d Fku d k p;u d hft ;s\
(i) ;fn d kW
d jksp d sflj d ksd kV fn;kt krkgS]rksHkh
og ,d lIrkg rd t hfor jgrk gSA
(ii) eks
t +d n`f"V d e la
os
nhrFkkvf/kd foLr`r gks
rhgSA
resolution
(iii) anal style and anal cerci both present in
(iii) xq
nh; 'kwd o xqnh; y we nksuksagheknkd kWd jksp esa
ik;st krsgSaA
female cockroach
(iv) number of malphigian tubules are 100-150
(iv) eS
Yih?kh;u ufyd kvks
ad hla
[;k100-150 gks
rhgS
A
(v) 6 chitinous teeth are present in gizzard
(v) is
"k.kh esa6 d kbVhu ;qDr nk¡r ik;st krsgSa
(1) only (ii)
(2) only (iii)
(1) d s
oy (ii)
(2) d s
oy (iii)
(3) only (i), (iv) and (v)
(4) only (vi)
(3) d s
oy (i), (iv) rFkk (v)
(4) d s
oy (vi)
172. Which is the correct matching
Common
Name
Order
172. fuEu es
alslgh fey ku D;k gS\
Family
l kekU; uke
d yq
x.k
Diptera
(1) ?kjs
y weD[kh
eDlhMh
fMIVsjk
(1) Housefly
Muscidae
(2) Mango
Anacardiaceae Poales
(2)vke
,ukd fMZ,sl h
ikWYl
(3) Wheat
Poaceae
Sapindales
(3) xs
ag¡w
iks,l h
ls
fiuMs
Yl
(4) Man
Primata
Hominidae
(4) ekuo
çkbesV~l
gksehfuMh
173. Where collected plant specimens that are
dried, preserved and pressed on sheets are
stored in
(1) Herbarium
(2) Botanical Garden
(3) Museum
(4) Zoological park
174. The Keys are based on the contrasting
173. lw
[ks] lajf{kr rFkk 'khV~l esapiVso ,d f=kr ikniksa
uewuksad ksd gk¡laxzfgr fd ;k t krk gS&
(1) gcs
Zfj;e
(2) ouLifr m|ku
(3) la
xzgky ;
(4) fpfM+
;k?kj
174. d q
at hlkekU;r%fci;kZl hy {k.kksad st ksM+ksaij vk/kkfjr
characters generally in pairs called -
gksrh gSft UgsalkekU;r%D;k d gk t krk gS&
(1) Duplet
(2) Singlet
(1) f}iy d
(2) ,d y d
(3) Couplet
(4) Triplet
(3) ;q
Xe
(4) f=ky d
RESONANCE
XIII ResoMost_STP 51
175. Which of the following are family
175. fuEu es
alsd kSulk d qy gS&
(1) Felidae
(2) Canine
(1) Q s
fy Mh
(2) d s
ukbu
(3) Felis
(4) Diptera
(3) Q s
fy l
(4) fMIVs
jk
176. d ks
,uksl kbV~l vkLrfjr gksrh gS&
176. Choanocytes lines
(1) Spongocoel
(2) Canals
(1) LiUt ks
l hy
(2) d s
ukYl
(3) Both
(4) Coelentron
(3) nks
uks
(4) lhy s
UVªkW
u
177. Corals have skeleton composed of
(1) SiO2
(2) CaCO3
(3) Both
(4) None
178. Select Incorrect matching
177. d ks
jYl d k d ad ky fd ld k cuk gksrk gS&
(1) SiO2
(2) CaCO3
(3) nks
uks
(4) d ks
bZugha
178. v;q
fXer d k p;u d hft , &
(1) Sea fan - Gorgonia
(1) leq
nzh ia[kk & xkxksZfu;k
(2) Sea hare - Aplysia
(2) leq
nzh [kjxks'k & ,Iy kbfl;k
(3) Sea lily - antedon
(3) leq
nzhfy y h& ,UVsMkWu
(4) See fish – pristis
(4) leq
nzhehu & fçfLVl
179.
179.
Correct statement about above diagram
(1) In Male pelvic fin bears claspers
(2) Fertilization is external
mijksDr fp=kd slUnHkZesalghd Fku d kp;u d hft ,
(1) uj d sis
fYod fQ u ij Dy sLij ik;k t krk gSA
(3) Operculum present
(2) fu"ks
p u cká gksrk gS
(4) Clarias belongs to same class
(3) vkW
ijd qy e mifLFkr
(4) Dy s
fj,l leku oxZlslEcfU/kr gS
180. Select incorrect matching
(1) Petromyzon – Have sucking and circular
mouth without jaw
(2) Pterophyllum - Torpedo
(3) Pteropus – Angel fish
(4) Psittacula – They posses beak
180. xy r ;q
Xe d k p;u d hft , &
(1) is
Vªksekbt ksu & blesapw"kd o o`Ùkkd kj t cM+sjfgr
eq[k ik;k t krk gSA
(2) Vs
jksQ kby e & VkWjihMks
(3) Vs
jksil & ,saxy ehu
(4) lhVs
d wy k & buesapksap ikbZt krh gSA
RESONANCE
XIII ResoMost_STP 52
181. (i) Do not have external ear opening
181. (i) bles
acká d .kZfNnzughaik;st krs
(ii) Fertilisation is internal
(ii) vka
rfjd fu"ksp u
(iii) Some of them shade their skin as cast
(iii) bues
alsd qN viuh Ropk d ksmrkj nsrsgSa
Above features belongs to class
(1) Aves
(2) Reptilia
(3) Cyclostomata
(4) Amphibia
mijksDr y {k.k fd l oxZlslacaf/kr gS
182. Select correct one
(1) i{kh
(2) ljhl`
i
(3) lkbDy ks
LVkses
Vk
(4) mHk;pj
182. lgh d Fku d k p;u d hft ;s-
(i) ART - assisted reproductive technologies
(i) ART - iz
t uu rd uhd esalgk;d
(ii) IUT - intra uterine transfer
(ii) IUT - vUr%xHkkZ
'k;hLFkkukUrj.k
(iii) ZIFT - zygote intra fallopian transfer
(iii) ZIFT - ;q
Xeut vUr%Q y ksfi;u LFkkukUrj.k
(iv) GIFT - gamete intra fallopian transfer
(v) ICSI - intra cytoplasmic sperm injection
(iv) GIFT - ;q
Xeut vUr%Q sy ksfi;u LFkkukUrj.k
(vi) IUI - intra uterine insemination
(v) ICSI - vUr%d ks
f'kd knzO;h 'kqØ k.kqizos'k
(1) i,ii,iii,iv
(2) i,ii
(vi) IUI - vUr%xHkkZ
'k;hbuls
ehus'ku
(3) iv,v,vi
(4) all
(1) i,ii,iii,iv
(2) i,ii
(3) iv,v,vi
(4) lHkh
183. How many sperms are produced from one
183. ,d iz
kFkfed LiZes
Vksl kbV esafd rus'kqØ k.kqcursgSa&
primary spermatocyte ?
(1) 8
(2) 6
(3) 2
(4) 4
184. The process of sperm formation is
.........A...........that is completed in three basic
phases. The conversion of non-motile
spermatid in to motile and active spermatozoa
is called .........B.........After that spermotozoa
(1) 8
(2) 6
(3) 2
(4) 4
184. 'kq
Ø k.kqfuekZ.k d k izØ e .........A...........d gy krk gS]
t ksfd rhu vk/kkjhiz
koLFkkvkases
aiw
.kZgks
rkgS
A vxfr'khy
Lies
fVM d kxfr'khy o lfØ ; Lies
Z
VZkts ks
v kes
a: ikUrj.k
.........B.........d gykrkgS
A Lies
VZks
t ksvkd k'kØq ufyd k
released from seminiferous tubules in to
}kjkbihMhMkbel esaeq
Dr gksuk........C........... izØ e
epididymis through ........C........... process.
d gy krk gSA
(1)
A
=
Spermotogenesis,
B
=
Spermateliogensis, C = Semination
(2) A = Spermatogensis, B = Spermeogensis,
C = Spermiation
(3) A = Insemination, B = Spermiation, C =
Semination
(4) A = Spermatigetion, B = Spermatogensis,
(1) A = 'kq
Ø k.kqt uu, B = LiesZfVfy vksft usfll , C =
ls
feus
'ku
(2) A = 'kq
Ø k.kq t uu, B = LifeZ;ksft usfl l , C =
LifeZ,'ku
(3) A = buls
ehus'ku, B = LifeZ;s'ku, C = lsfeus'ku
(4) A = Lies
VZht 'sku, B = Lies
VZkfst us
fll , C = LifeZ
,'ku
C = Spermiation
RESONANCE
XIII ResoMost_STP 53
185. The function of hyaluronidase is-
185. gk;Y;w
jksfuMst d k d k;ZgSa&
(1) To form one of reception in egg
(1) v.Mses
aizos
'k }kj d k fuekZ.k d juk
(2) To puncture the vitelline membrane of egg
(2) v.Msd h ihrd f>Yyh d ksHks
nuk
(3) It is not produced in human sperm
(4) None of the above
(3) ;g ekuo 'kq
Ø k.kqv ksaesamRiUu ughafd ;k t krk gSa
(4) mijks
Dr esalsd ksbZugha
186. How many secondary spermatocytes are
186. 400 Lies
ZVkst ksv k d s fuekZ.k gsrq fd ruh f}rh;d
required to form 400 spermatozoa?
LiesZVksl kbV d h vko';d rk gksxh\
(1) 40
(2) 100
(1) 40
(2) 100
(3) 200
(4) 400
(3) 200
(4) 400
187. The product of the fitst maturation division of
germ cell in testis are known as
(1) Spermatids
(2) Oocytes
(3) Secondary spermatocytes
(4) Sperms
188. Antimularian hormone is secreted from-
187. o`
"k.kksaesaçFke ifjiDou foHkkt u d smRikn gksrsgSa&
(1) LieS
ZfVM~l (Spermatids)
(2) Å lkbV~
l (Oocytes)
(3) f}rh;d
LieSZVksl kbV~l (Secondary
spermatocytes)
(4) 'kq
Ø k.kq(Sperms)
188. ,UVhew
y sfj;u gkWeksZu fd ld s}kjklzkfor fd ;kt krkgS
(1) Ovaries of female
(1) eknk d h v.Mk'k;ks
a}kjk
(2) Testis of male
(2) uj d so`
"k.k }kjk
(3) Vagina of female
(3) eknk ;ks
uh }kjk
(4) None of the above
(4) fuEu es
alsd ksbZugha
189. Hymen can be broken by
(1) Sudden fall
(2) Cycling
(3) Insertion of a veginal tampon
(4) all
RESONANCE
189. gkbeu fd ld s}kjk Vw
V ld rh gS
(1) d w
nusls
(2) lkbfd y py kusls
(3) ;ks
uh VsEikWu d svUnj Mky usls
(4) lHkh
XIII ResoMost_STP 54
190. Choose the correct combination for labelling
190. 'kq
Ø okfgd kd sHkkx d slghukekad u d kp;u d hft ,
of part of seminiferous tubule
(1) a – lVky
Zs hd kfs'kd kb – lies
VZkxskfsu;e]c – Lies
fZVM]
(1) a – setoli cell, b – spermatogonium c –
spermatid, d – interstitial cell, e –
spermatozoa
(2) a – interstitial cell, b – spermatid, c –
spermatogonium d – spermatozoa, e –
sertoli cell
(3) a – interstitial cell, b – spermatogonium, c –
spermatid, d – spermatozoa, e – sertoli cell
(4) a – interstitial cell, b – spermatogonium, c –
spermatozoa, d – spermatid, e – sertoli cell
191. Uterus of female reproductive system is (1) Primary sex organ
(2) Secondary sex organ
(3) Accessory sex organ
(4) External sex character
192. Select the correct statement with respect to
d – vUrjky h d ks
f'kd k]e – LiesZVkst ksv k
(2) a – vUrjky h
d ksf'kd k] b – LiesZfVM] c –
l iesZVksxksfu;e] d – LiesZVkst ksv k] e – l VksZy h
d ksf'kd k
(3) a – vUrjky h d ks
f'kd k]b – liesZVksxksfu;e]c –
LiesZfVM]d – LiesZVkst ksv k]e – lVksZy h d ksf'kd k
(4) a – vUrjky h d ks
f'kd k]b – liesZVksxksfu;e]c –
LiesZVkst ksv k]d – LiesZfVM]e – lVksZy h d ksf'kd k,a
191. eknk çt uu rU=k es
axHkkZ'k; gS(1) çkFkfed y S
afxd vax
(2) f) rh;d y S
afxd vax
(3) vko';d y S
afxd vax
(4) cká y S
afxd vax
192. jks
xksarFkk jksx çfrj{kk d slanHkZesafuEufy f[kr esals
diseases and immunisation :
d kSu lk ,d d Fku lgh gS\
(1) If due to some reason B-and T-lymphocytes
(1) ;fn fd lh d kj.ko'k B-rFkk T-y lhd k.kq{kfrxz
Lr
are damaged, the body will not produce
antibodies against a pathogen
(2) Injection of dead / inactivated pathogens
causes passive immunity
(3) Certain protozoans have been used to
mass produce hepatitis B vaccine.
(4) Injection of snake antivenom against snake
bite is an example of active immunisation
gkst krsgS]rks'kjhj d sHkhrj fd lh jksxt ud d s
çfr ,aasVhckWMht +¼çfrfiaM½ ugh cu ik,axsA
(2) e`
r vFkokfuf"Ø ;d `r jksxt ud ksad sbat sD'ku fn;s
t kusij ijks{k çfrj{kk curh gSA
(3) d q
N çksVkst +ksv uksad kscM+siSekusij ghiSVkbfVl B
oSDlhu cukusesabLrseky fd ;k t krk jgk gSA
(4) lki
a }kjkd kVst kusd sçfr liZ
&,a
Vshohue d kba
t Ds'ku
fn;k t kuk lfØ ; çfrj{kk d k mnkgj.k gS
A
RESONANCE
XIII ResoMost_STP 55
193. Which one of the following is a matching pair
193. fuEu d kS
ulk ,d lqesfy r t ksM+k vkS"kf/k ,oamld soxZ
of a its category
d k gS
(1) Amphetamines - Stimulant
(1) ,EQ hVs
feu&mÙkst d
(2) Lysergic and Dimethyl amide - Narcotic
(3) Heroin - Psychotropic
(2) y kbls
ft Zd ,oaMkbZfeFkkby ,ekbM ukjd ksfVd
(3) gs
jksbu lkbd ksVªksfid
(4) Benzodiazepam - Pain killer
(4) cS
at ksMk;t hike nnZuk'kd
194. Cholera patient is administrated by 'saline drip'
194. gS
t k jksxh d kslsy kbu fMªi nh t krh gSD;ksafd &
because
(1) Na+ ions are essential for the transport of
(1) Na+ vk;u f>Yy hd svkj&ikj inkFkks
Zad sifjogu
d sfy , vko';d gksrsgSa
substances across the membrane
(2) Na+ ions are helpful to conserving water in
(2) Na+ vk;u 'kjhj es
aikuhd hek=kklqjf{kr j[kusesa
the body
enn d jrsgSa
(3) CI ions are helpful in the formation HCI for
–
(3) CI– vk;u ikpu d s fy , vko';d HCI for
digestion
digestion
(4) CI ions is significant component of blood
–
(4) CI– jDr Iy kTek d k egRoiw
.kZ?kVd gS
plasma
195. fuEufy f[kr lw
p h d ksi<+d j lgh mRrj ij fu'kku
195. Study the following lists
yxk;s
List-I
List-II
(1) Pasteurella pestis
(I) Angular leaf spot
lw
p h-I
lwp h-II
of cotton
(1) iLPpw
jsy k isLVhl
(I) d ikl es
a,a
X;w
y j yhQ
LikWV uked chekjh
(2) Treponema pallidum (II) Amphoterican
(C Mycobacterium bovis (III) Actinomycosis of
cattle
(2) Vª
siksuhek isy hfM;e
(II) ,EQ ks
Vs
fjd u
(C ek;ks
cSDVhfj;e
(III) i'kq
v ksaesa¼xk;ksaesa½
(D Streptomyces nodosus(IV) Syphilis
(V) Plague
,fDVuksek;d ksl hl
(D LVª
sIVksek;lhl uksMksl l
The correct match is
(V) Iys
x
A
B
C
D
(1)
IV
I
II
lII
(2)
II
III
IV
V
(3)
V
IV
lII
II
(4)
III
II
I
IV
RESONANCE
(IV) flfQ fy l
lghlqesafy r gS
A
B
C
D
(1)
IV
I
II
lII
(2)
II
III
IV
V
(3)
V
IV
lII
II
(4)
III
II
I
IV
XIII ResoMost_STP 56
196. Dilation of blood vessels, increase in fat
196. jDr okfgfu;ks
ad k Q wy uk]olk la'y s"k.k esao`f) ]fuEu
synthesis, low blood sugar and inflammation
jDr 'kd Zjk]vkek'k; esa'kksFk(inflammation) fd ld s
of stomach are due to the consumption of
mi;ksx d sd kj.k gksrk gS
(1) Tobacco
(1) rEckd w
(2) Drug addiction
(2) vkS
"kf/k O;lu
(3) Alcohol
(4) Tobacco and drug addiction
(3) ,Yd ks
gy
(4) rEckd w,oavkS
"kf/k O;lu
197. Column-I lists the components of body
defense and column-II lists the corresponding
descriptions. Match the two columns. Choose
the correct option from those given
Column-I
Column-II
(A) Active natural immunity (p) Injection of
gamma globulins
197. d kW
y e-I 'kkjhfjd j{kk lst qM+sd kjd rFkk d kWy e-II
mulslEcfU/kr d k;Zd ksn'kkZjgsgSanksuksd kWy eksad ks
lqesfy r d jsasvkSj lgh ;qXe pqus
Column-I
(A) lfØ ; çkd `
frd çfrj{kk (p) xkekXy ksC;qfy u d k
ba
ts
Dlu
(B) First line of defense (q) Complement
proteins and
(B) j{kk d h çFke js
[kk
(C) fuf"d `
; çkd `frd çfrj{kk(r) 'kjhj esa?kql sjksx
d kjd ksalslh/kk lEid Z
with the pathogens
that have entered
(q) d kE
WIyhes
UaV çkVshu vkjS
bUVjQ sjkWu
interferons
(C) Passive natural immunity (r) Direct contact
Column-II
(D) j{kk d h f}rh; js
[kk
(s) lrg jks
/kd
(t) Iy s
l sUVk d sikj x,
inside
(D) Second line of defense (s) Surface barriers
,.VhckWM h
(t) Antibodies
(1) A= s, B= r, C= t, D= q
transferred through
(2) A= r, B= s, C= q, D=t
the placenta
(3) A= r, B= s, C= t, D= q
(1) A= s, B= r, C= t, D= q
(4) A= t, B= r, C= q, D=p
(2) A= r, B= s, C= q, D=t
(3) A= r, B= s, C= t, D= q
(4) A= t, B= r, C= q, D=p
198. An insect bite may result in inflammation of that
spot. This is triggered by the alarm chemicals
198. ,d d ht d sd kVusij t xg ij lw
t u vkt krhgS;gk¡
ij d kSu lh vy keZjlk;u lzkfor gksrsgSa\
such as
(1) fgLVs
feu rFkk Mksikfeu
(1) Histamine and dopamine
(2) fgLVs
feu rFkk d k;fuu
(2) Histamine and kinins
(3) bUVjQ s
jkUl rFkk vkIlksfuZl
(3) Interferons and opsonin
(4) bUVj Q s
jkUl rFkk fgLVksUl
(4) Interferons and histones
RESONANCE
XIII ResoMost_STP 57
199. Match the names of disease listed under
199. d ky
W e I lsjks
xks
ad suke d ksd kW
y e II d svfHkçk; d slkFk
column-I with meanings given under column -
lqesfy r d jsa] LrEHk esafn;sx;so.kZØ e d slal xZd s
II, choose the answer which gives the correct
vuql kj lgh mRrj d kspqus
combination of the alphabets of the columns.
d kWy e I
d kWy e II
(jks
x d k uke)
(la
l xZ
)
p-Allergic
A - ihfy ;k
p - ukd d h ,y ft Z
d lwt d
inflammation of
B - LVhuks
fll
q - pky d fØ ;kvks
ad h gkfu
nose
C - jkfgukbfVl
r - ân;h d ikV es
anks"k
q - Loss of motor
D - is
jky kbfll
s - jDr es
afiRr o.kZd esao`f)
Column-I
Column-II
(Name of disease)
(Meanings)
A - Jaundice
B - Stenosis
functions
t - ân; es
aiV~Vh; nks"k
C - Rhinitis
r - Heart valve defect
D - Paralysis
s - Increase in bile
pigments in the
blood
(1) A = q ; B = t ; C = r ; D = p
(2) A = s ; B= p : C = q ; D = r
(3) A = s ; B = r ; C = p ; D = q
(4) A = s ; B = t ; C = p ; D = q
t - Septal defect of
200. fuEu fp=k es
alsd kSulk vehuksvEy FkkbjkWbM gkWeksZu
heart
(1) A = q; B = t; C = r; D = P
cukusd sd ke vkrk gS&
(2) A = s; B= p: C = q; D = r
(3) A = s; B = r; C = p; D = q
(4) A = s; B = t; C = p; D = q
200. In the given diagram which amino acid is used
to form thyroid hormone
(A)
(A)
(B)
(C)
(1) (A)
(2) (B)
(3) (C)
(4) (D)
RESONANCE
(B)
(C)
(1) (A)
(2) (B)
(3) (C)
(4) (D)
(D)
(D)
XIII ResoMost_STP 58
ANSWER KEY
Q.No.
1
2
3
4
5
6
7
8
9
10
Ans.
4
3
2
1
4
1
2
1
2
1
Q.No.
11
12
13
14
15
16
17
18
19
20
Ans.
3
3
2
4
2
4
4
4
4
2
Q.No.
21
22
23
24
25
26
27
28
29
30
Ans.
3
3
4
1
4
4
2
2
2
4
Q.No.
31
32
33
34
35
36
37
38
39
40
Ans.
1
1
1
1
3
3
3
3
3
1
Q.No.
41
42
43
44
45
46
47
48
49
50
Ans.
3
3
2
3
2
1
2
3
4
4
Q.No.
51
52
53
54
55
56
57
58
59
60
Ans.
4
1
4
1
2
1
2
3
3
3
Q.No.
61
62
63
64
65
66
67
68
69
70
Ans.
4
3
4
1
1
1
4
3
2
1
Q.No.
71
72
73
74
75
76
77
78
79
80
Ans.
2
2
2
3
2
1
4
4
3
1
Q.No.
81
82
83
84
85
86
87
88
89
90
Ans.
4
2
1
4
2
1
1
3
1
3
Q.No.
91
92
93
94
95
96
97
98
99
100
Ans.
4
1
4
2
3
3
1
1
2
2
Q.No.
101
102
103
104
105
106
107
108
109
110
Ans.
3
3
1
3
3
2
1
1
1
1
Q. No.
111
112
113
114
115
116
117
118
119
120
Ans.
2
4
3
4
3
1
3
4
4
1
Q. No.
121
122
123
124
125
126
127
128
129
130
Ans.
1
3
1
4
3
2
4
2
1
2
Q. No.
131
132
133
134
135
136
137
138
139
140
Ans.
1
3
2
2
2
1
3
4
3
4
Q. No.
141
142
143
144
145
146
147
148
149
150
Ans.
4
3
4
4
3
4
3
1
2
3
Q. No.
151
152
153
154
155
156
157
158
159
160
Ans.
3
2
2
3
3
3
1
4
1
4
Q. No.
161
162
163
164
165
166
167
168
169
170
Ans.
4
3
3
3
2
3
3
2
4
2
Q. No.
171
172
173
174
175
176
177
178
179
180
Ans.
3
1
1
3
1
3
2
4
4
2
Q. No.
181
182
183
184
185
186
187
188
189
190
Ans.
2
4
4
2
2
3
3
2
4
3
Q. No.
191
192
193
194
195
196
197
198
199
200
Ans.
2
1
1
2
3
3
3
2
3
3
RESONANCE
XIII ResoMost_STP 59