1. No category

Allahabad, U.P.
Sample Questions
for
One year Integrated/Academic Course
(FOR XI TO XII MOVING STUDENTS)
2014
SCHOLARSHIP & TALENT SEARCH
PROGRAMME- 2014
for
MKC Foundation
MAJOR KALSHI CLASSES PVT. LTD.
9/10 A, Church Lane, Nr. Anand Bhawan, Allahabad - 211 006
Contact : 09696330033, 09935145976, 09005308749
Visit us www.majorkalshiclasses.com
Email : [email protected]
MKC FOUNDATION (SAMPLE PAPER)
NOTE : For each question, you will be awarded
1 marks if you darken the bubble corresponding
to the correct answer Only and Zero Marks if no
bubbles are darkened. In all other cases, Minus
(0.33) mark will be awarded in this paper.
Out of the four options in each question only
one option is correct.
1. If (x + 9), (x – 6), 4 are in G.P., then the value of
x is
Class - 12th
uksV % izR;sd iz”u esa dsoy lgh mRrj okys cqycqys
(BUBBLE) dks dkyk djus ij 1 vad vkSj dksbZ Hkh
cqycqyk (BUBBLE) dkyk ugha djus ij “kwU; ¼0½ vad
iznku fd, tk;saxsA vU; lHkh fLFkfr;ksa esa _.kkRed
¼0-33½ vad iznku fd;k tk,xkA
izR;sd iz”u esa fn;s x;s pkj fodYiksa esa ls dsoy ,d gh
lgh fodYi gSA
1. ;fn (x + 9), (x – 6), 4 xq.kksRrj Js.kh esa gS rks x dk
eku gS %
(a) 1
(b) 2
(a) 1
(b) 2
(c) –3
(d) 0
(c) –3
(d) 0
2. If A, G, H are respectively the Arithmetic,
Geometric and Harmonic means between two
positive real numbers a and b, then A, G, H are in
2. ;fn A, G, H Øe”k% a o b ds chp lekUrj ek/;]
xq.kksRrj ek/; rFkk gjkRed ek/; gS rks A, G, H
gksaxs %
(a) A.P.
(b) G.P.
(a) A.P.
(b) G.P.
(c) H.P.
(d) None
(c) H.P.
(d) None
3. Given log 2 = 0.3010, how many digits are there
in 225 ?
3. fn;k gS log 2 = 0.3010, rks 225 esa fdruh la[;k,¡
gksaxh\
(a) 26
(b) 13
(a) 26
(b) 13
(c) 7
(d) 8
(c) 7
(d) 8
4. If x is real, then maximum value of (7  10x  5x 2 )
is
(a) 20
(b) 23
(c) 12
(d) 7
5. Sin 75o = ?
4. ;fn x ,d okLrfod la[;k gS] rks (7  10x  5x 2 )
dk vf/kdre eku gS %
(a) 20
(b) 23
(c) 12
(d) 7
5. Sin 75o = ?
(a)
1
( 3  2)
4
(b)
1
( 6  2)
4
(a)
1
( 3  2)
4
(b)
1
( 6  2)
4
(c)
1
( 3  1)
2
(d)
1
( 6  3)
4
(c)
1
( 3  1)
2
(d)
1
( 6  3)
4
(b)
3
2
6. (cos245o –sin215o) = ?
(a)
3
4
(c) 2 3
6. (cos245o –sin215o) = ?
(b)
(d)
3
2
3
2
MAJOR KALSHI CLASSES PVT. LTD.
(a)
3
4
(c) 2 3
(d)
3
2
Beware of Negative Marking
1
MKC FOUNDATION (SAMPLE PAPER)
Class - 12th
7. From the top of a cliff 150 m high, the angles of
7. 150 ehVj Å¡ph ,d igkM+h ds Åij ls ,d Vkoj ds
depression of the top and bottom of a tower are
“kh’kZ rFkk ikn ds voueu dks.k Øe”k% 300 o 600 gSa
o
o
observed to be 30 and 60 respectively. The
rc Vkoj dh Å¡pkbZ gksxh %
height of the tower is
(a) 100 m
(a) 100 m
(b) 50 3 m
1
(c) 133 m
3
1
3
(c) 133 m
(d) 100( 3 1)m

8. The principal value of sin1  sin

2π 
 is
3 
(b) 50 3 m

8. sin1  sin

2π 

3 
(d) 100( 3 1)m
dk ewy eku gS %
(a)
2π
3
(b)
π
3
(a)
2π
3
(b)
(c)
5π
3
(d) None
(c)
5π
3
(d) None
9. The system of equations
x + y + z = 0. 2x + y – z = 0, 3x + 2y = 0 has
(a) a unique solution
(b) exactly two solutions
(c) no solution
(d) infinitely many solutions
x 3  3x 2  5 x  4
?
10. lim 3
x   2x  4 x 2  3x  2
(a)
1
2
(c) 
5
3
y
11. If x  e
(d) 
xy
9. lehdj.k x + y + z = 0 . 2x + y – z = 0, 3x
+ 2y = 0 dh iz.kkyh gS %
(a) ,d gy gS
(b) nks gy gS
(c) dksbZ gy ugha gS
(d) vuUr gy gSa
10.
(b) – 2
3
4
dy
?
, then
dx
x 3  3x 2  5 x  4
?
x   2x 3  4 x 2  3x  2
lim
(a)
1
2
(c) 
(b) – 2
5
3
(d) 
11. ;fn x y  ex y , rc
1
1
(a) (1  log x)
x
(b) (1  log x)2
(a) (1  log x)
log x
(c) (1  log x)2
log x
(d) (1  log x)2
(c) (1  log x)2
t
12. If x  a cos t  log tan  and y = a sin t, then

2
dy
?
dx
π
3
log x
3
4
dy
?
dx
x
(b) (1  log x)2
log x
(d) (1  log x)2
t
12. ;fn x  a cos t  log tan  ,oa y = a sin t, rc

2
dy
?
dx
(a) tan t
(b) cot t
(a) tan t
(b) cot t
(c) sec t tan t
(d) 1
(c) sec t tan t
(d) 1
MAJOR KALSHI CLASSES PVT. LTD.
Beware of Negative Marking
2
MKC FOUNDATION (SAMPLE PAPER)
13. If x  acos3 t , y  a sin3 t , then
(a) –sec2t
sec 4 t cos ect
(c)
3a
d2 y
?
dx 2
cos x
(2y  1)
cos x
(c) (2y  1)
13. ;fn
2
(c) 2
2
(b) asec t cosect
(d) None of these
sec 4 t cos ect
(c)
3a
(d) buesa ls dksbZ ugha
(b)
dy
?
dx
(a)
cos x
(2y  1)
(b)
cos x
(d) None of these
dy
?
dx
2 cos x
(1  y)
(d) buesa ls dksbZ ugha
(c) (2y  1)
15. fcUnq ¼4] 2½ dh ijoy; y2 = 8x ls fuEure nwjh
gS %
(b) 2 2
(a)
(d) 3 2
(c) 2
16.
(b) 2 2
2
(d) 3 2
3 sinx  cosx
dk vf/kdre eku gksxk tc x cjkcj
gksxk %
(a)
π
2
(b)
π
4
(a)
π
2
(b)
π
4
(c)
π
3
(d)
π
6
(c)
π
3
(d)
π
6
(b)
x 1
 sin 2x  C
2 4
2
 cos
(a)

17.
xdx  ?
1
cos 3 x  C
3
(c)  sin2x  C
18.
14. ;fn y  sin x  sin x  sin x  ...... , rc
2 cos x
(1  y)
16. The value of 3 sinx  cosx is greatest when x is
equal to
17.
d2 y
?
dx 2
(a) –sec2t
15. The minimum distance from the point (4, 2) to
the parabola y2 = 8x is
(a)
3
x  acos3 t , y  a sin t , rc
2
(b) asec t cosect
14. If y  sin x  sin x  sin x  ...... , then
(a)
Class - 12th
(b)
x 1
 sin 2x  C
2 4
(a)
xdx  ?
1
cos 3 x  C
3
(c)  sin2x  C
(d) None of these
x
dx  ?
1x
2
 cos
18.

(d) buesa ls dksbZ ugha
x
dx  ?
1x
(a) sin1 x  C
(a) sin1 x  C
(b) sin1 x(1  x)  C
(b) sin1 x(1  x)  C
(c) sin1 x  x(1  x)  C
(c) sin1 x  x(1  x)  C
(d) None of these
(d) buesa ls dksbZ ugha
MAJOR KALSHI CLASSES PVT. LTD.
Beware of Negative Marking
3
MKC FOUNDATION (SAMPLE PAPER)
19. The equation of the curve that passes through
the point (1, 2) and satisfies the differential equady  2xy
tion dx  (x2  1) is
Class - 12th
19. fcUnq ¼1] 2½ ls xqtjus okys rFkk vody lehdj.k
dy  2xy

dx (x 2  1)
dks larq’V djus okys ml oØ dk
lehdj.k gksxk %
(a) y(x 2  1)  4
(b) x(x2 1)  4
(a) y(x 2  1)  4
(b) x(x2 1)  4
(c) y  tan1 x  4
(d) None of these
(c) y  tan1 x  4
(d) buesa ls dksbZ ugha
20. The general solution of the differential equation
dy y 2  x 2

is
dx
2xy
20. vody lehdj.k
dy y 2  x 2

dx
2xy
dk lkekU; gy
gksxk %
(a) x 2 + y2 = C
(b) x2 + y2 + Cx
(a) x2 + y2 = C
(b) x2 + y2 + Cx
(c) x2 – y2 = Cx
(d) –x2 + y2 = Cx
(c) x2 – y2 = Cx
(d) –x2 + y2 = Cx
10
21. The term independent of x in the expansion of
10
 x2 3 
  2
3 x 


 x2 3 
21.   2 
3 x 
ds foLrkj es a x ls Lora = in
gS %
is
(a) 252
(b) –252
(a) 252
(b) –252
(c) 210
(d) –210
(c) 210
(d) –210
22. The value of p for which t he vecto rs
(2ˆj  ˆj  kˆ), (ˆi  2ˆj  3kˆ)
coplanar is
(a) 4
(c)
13
7
(3ˆj  pˆj  5kˆ)
and
are
(b) –4
(d)
18
7

23. The work done by a force F  (2ˆi  3ˆj  2kˆ) in
moving a particle from A (3, 4, 5) to B (1, 2, 3)
is
(a) 4
(b) 2
(c) 3/2
(d) –2
24. The direction coisnes of z axis are
22. lfn”k (2ˆj  ˆj  kˆ), (ˆi  2ˆj  3kˆ) rFkk (3ˆj  pˆj  5kˆ)
p ds fdl eku ds fy, lgleryh; gksx
a s%
(a) 4
(c)
13
7
(b) –4
(d)
18
7
23. fcUnq A (3, 4, 5) ls B (1, 2, 3) rd cy

F  (2ˆi  3ˆj  2kˆ)
}kjk ,d d.k dks xfreku djus
ds fy, fd;k x;k dk;Z gksxk %
(a) 4
(b) 2
(c) 3/2
(d) –2
24. z v{k dh T;k gkasxh %
(a) 1, 1, 0
(b) –1, 1, 0
(a) 1, 1, 0
(b) –1, 1, 0
(c) 0, 0, 1
(d) –1, –1, 0
(c) 0, 0, 1
(d) –1, –1, 0
25. The angle between the planes 2x  y  z  6 and x
+ y + 2z = 7, is
(a) 30o
(b) 45o
(c) 60o
(d) 90o
MAJOR KALSHI CLASSES PVT. LTD.
25. nks ry 2x  y  z  6 rFkk x + y + 2z = 7, ds chp
dks.k gksxk %
(a) 30o
(c) 60o
(b) 45o
(d) 90o
Beware of Negative Marking
4
MKC FOUNDATION (SAMPLE PAPER)
Class - 12th
26. If P(–1, 4, –3) is one end of a diameter PQ of the
26. ;fn P (–1, 4, –3) xksys x2 + y2 + z2 – 3x – 2y + 2z
sphere x2 + y2 + z2 – 3x – 2y + 2z – 15 = 0, then
– 15 = 0 ds O;kl PQ dk ,d Nksj gS] rc fcUnq Q
the co-ordinates of Q are
ds funsZ”kkad gksaxs %
(a) (–2, 4, 1)
(b) (–4, 2, 1)
(a) (–2, 4, 1)
(b) (–4, 2, 1)
(c) (4, 2, –1)
(d) (4, –2, 1)
(c) (4, 2, –1)
(d) (4, –2, 1)
27. The mean of 200 items was 50. Later on it was
detected that two items were misread as 92 and
8 instead of 192 and 88 respectively. The correct mean is
27. 50 oLrqvksa dk ek/; 200 Fkk] dqN le; i”pkr~ ;g
irk pyk fd 192 rFkk 88 ds LFkku ij xyrh ls 92
rFkk 8 i<+ fy;k x;k] rc lgh ek/; D;k gksxk\
(a) 50.2
(b) 51.4
(a) 50.2
(b) 51.4
(c) 50.9
(d) 51.6
(c) 50.9
(d) 51.6
28. If E and F are independent event s, then
28. ;fn E rFkk F Lora= ?kVuk,¡ gSa] rc P(E  F)  ?
P(E  F)  ?
(a) P(E)  P(F)
(b) 0
(a) P(E)  P(F)
(b) 0
(c) P(E).P(F)
(d) P(E)  P(F)
(c) P(E).P(F)
(d) P(E)  P(F)
29. If z is a complex variable, then
z3
2
z 3
29. ;fn z ,d lfeJ pj gS] rc
(a) a pair of straight lines
djrk gS %
(a) lh/kh js[kk dk ,d tksM+k
(b) a circle
(b) ,d o`Rr
(c) a parabola
(c) ,d ijoy;
(d) a hyperbola
(d) ,d nh?kZo`Rr
represents
30. The focus of the parabola 4y2 + 12x – 12y – 39
z3
2
z 3
;g iznf”kZr
30. ijoy; 4y2 + 12x – 12y – 39 = 0 dh ukfHk
gS %
= 0 is
3
4

1
1


(a)  ,0 
(c)  2 , 2 


3
4

1
1


(b)   ,0 


(a)  ,0 
(d) (–3, 2)
(c)  2 , 2 


3
 4

31. The working of a Hydrolic lift is based on :
3
 4


(b)   ,0 
(d) (–3, 2)
31. gkbMªksfyd fy¶V ;a= dh dk;Z iz.kkyh vk/kkfjr gSa%
(a) Boyle’s Law
(a) ckW;y ds fu;e ij
(b) Charles’s Law
(b) pkYlZ ds fu;e ij
(c) Pascal’s Law
(c) ikLdy ds fu;e ij
(d) Archimedes’s Principle
(d) vkdhZfeMht fl)kUr ij
MAJOR KALSHI CLASSES PVT. LTD.

Beware of Negative Marking
5
MKC FOUNDATION (SAMPLE PAPER)
32. A uniformly tapering vessel completely filled with
water is shown in the figure given below. What
is the thrust on the base of the vessel due to
water?
2 A cm
Class - 12th
32. uhps fn, fp= esa ty ls iwjh rjg Hkjk ,d ckYVhuqek
crZu n”kkZ;k x;k gSA ikuh }kjk crZu ds isans ij
yxus okys cy dk eku gksxk\
2
h
2 A cm2
h
A cm2
(a) Ahg
(c) (3/2) Ahg
(b) 2 Ahg
(d) 3 Ahg
33. Why doesn’t Archimedes’ principle hold for a
vessel under a free fall?
(a) The effective value of g increases
(b) The effective value of g decreases
(c) The body immersed in the vessel will become weightless
(d) The density of air increases
34. A body moves with a constant speed along a
curved path. Its acceleration :
(a) is zero
(b) is parallel to its velocity
(c) can make any arbitrary angle with its velocity
(d) is perpendicular to its velocity
35. A bullet of mass 150g strikes a target at 600 m/s
velocity which is reduced to 150 m/s. The approximate loss of energy is :
(a) 13400 J
(b) 25300 J
(c) 8400 J
(d) 18400 J
(a) Ahg
(c) (3/2) Ahg
A cm2
(b) 2 Ahg
(d) 3 Ahg
33. fuokZ/k :i ls xq#Rokd’kZ.k cy ds izHkko ds vUrxZr
uhps fxjrs fdlh crZu ij vkdZehfMt dk fl)kar
D;ksa ykxw ugha gksrk\
(a) g dk izHkkoh eku c<+rk gSA
(b) g dk izHkkoh eku ?kVrk gSA
(c) mDr crZu esa Mwcs fi.M Hkkjghu gks tk,axsA
(d) ok;q dk ?kuRo c<+sxkA
34. ,d ?kqekonkj iFk ij ,d fi.M fLFkj osx ls xfreku
gSA mldk Roj.k gksxk %
(a) “kwU;
(b) osx ds lekukarj gksxkA
(c) vius osx ds lkis{k og dksbZ euekuk dks.k cuk
ldrk gSA
(d) vius osx dh fn”kk ds yEcor gksxkA
35. 150 xzke Hkkj okys cqysV dk osx vius y{; ls
Vdjkdj 600 m/s ls ?kVdj 150 m/s jg tkrk gSA
ÅtkZ dh vuqekfur {kfr gksxh yxHkx %
(a) 13400 J
(c) 8400 J
(b) 25300 J
(d) 18400 J
36. An astronaut of mass 60 kg is revolving around
the earth in a satellite. What will be his weight
inside the satellite assuming g = 10 m/s2?
(a) 1200 N
(b) 600 N
(c) Infinite
(d) Zero
36. ,d 60 fdxzk0 otu okyk varfj{k ;k=h ,d mixzg
37. A hydrogen balloon on being released rises up.
What will happen to the balloon ultimately at a
certain high altitude?
37. gkbMªkstu xSl ls Hkjs ,d xqCckjs dks NksM+us ij Åij
(a) It will start floating in the atmosphere.
(b) It will shrink and start moving down.
(c) It will continue to move up infinitely.
(d) It will burst.
MAJOR KALSHI CLASSES PVT. LTD.
esa cSBdj i`Foh ds pkjksa vksj ifjØek djrk gSA
mixzg ds Hkhrj mldk otu gksxk (g = 10 m/s2? )
(a) 1200 N
(c) Infinite
(b) 600 N
(d) “kwU;
dh vksj mBrk gSA ,d fuf”pr Å¡pkbZ ij xqCckjs dk
D;k&D;k gJ gksxk\
(a) og ok;qe.My esa rSjuk “kq: dj nsxkA
(b) og fldqM+dj uhps dh vksj fxjuk izkjaHk djsxkA
(c) og Åij dh fn”kk esa vuUr le; rd mM+rs
tk,xk
(d) og QV tk,xkA
Beware of Negative Marking
6
MKC FOUNDATION (SAMPLE PAPER)
Class - 12th
38. A car accelerates from rest with acceleration 1.2
m/s2. A bus moves with constant speed of 12m/s
in a parallel lane. How long does the car take
from its start to meet the bus?
(a) 17 s
(b) 8 s
(c) 20 s
(d) 12 s
38. ,d dkj fLFkj voLFkk ls 1.2 m/sec2 dh nj ls
Rofjr gksrk gSA ,d cl 12 m/s dh LFkk;h osx ls
39. Match List-I (Physical Quantities) with List-II
(Unit of measurement) and select the correct
answer using the codes given below the lists :
List-I
List-II
(Physical Quantities) (Unit of measurement)
39. lwph-I (HkkSfrd ek=k,¡) dks lwph-II (eki dh bdkbZ)
,d lekukarj xyh esa pyrh gSA ml dkj dks cl
,d igq¡pus esa fdruk le; yxsxk\
(a) 17 s
(c) 20 s
(b) 8 s
(d) 12 s
A. Heat
1. cal/0C
ls lqesfyr djsa rFkk uhps fn, x, dwVksa dk iz;ksx
djrs gq, lgh mRrj dk p;u djsaA
lwph-I
lwph-II
(HkkSfrd ek=k,¡ )
(eki dh bdkbZ)
A. rki
1. cal/0C
B. Specific Heat
2. cal
B. fo”kq) rki
2. cal
C. Latent Heat
3. cal/g
C. xqIr Å’ek
3. cal/g
D. Heat Capacity
4. cal/(g 0C)
D. rki {kerk
4. cal/(g 0C)
Codes :
A
(a) 1
(b) 2
(c) 4
(d) 4
dwV :
B
4
4
2
2
C
1
3
1
3
D
3
1
3
1
(a)
(b)
(c)
(d)
40. When water is heated from 00C to 200C, how
does its volume change?
A
1
2
4
4
B
4
4
2
2
C
1
3
1
3
D
3
1
3
1
40. tc ty dks 00C ls 200C rd xeZ fd;k tkrk gS rks
mldk vk;ru fdl izdkj cnyrk gS\
(a) It shall increase
(a) og c<+sxkA
(b) It shall decreases
(b) og ?kVsxkA
(c) It shall first increase and then decrease
(c) og loZizFke c<+sxk rni”pkr~ ?kVsxkA
(d) It shall first decrease and then increase
(d) og loZizFke ?kVsxk fQj c<+sxkA
41. If a clock based on oscillating pendulum is taken
from earth to moon, it will :
41. ,d nksyu xfr ij vk/kkfjr ?kM+h dks ;fn i`Foh ls
pUnzek ij ys tk;k tk, rks og %
(a) become slow
(a) /kheh gks tk,xhA
(b) become fast
(b) rst gks tk,xkhA
(c) give same time as on earth
(c) i`Foh ij n”kkZ, x, le; dks iznf”kZr djsxkA
(d) stop working
(d) dk;Z djuk can djsxkA
42. What is the frequency of a wave whose time
period is 0.05 second?
42. 0-05 lsd.M dh le;kof/k okys rjax dh vko`fRr
fdruh gksxh\
(a) 5 Hz
(b) 10 Hz
(a) 5 Hz
(b) 10 Hz
(c) 20 Hz
(d) 40 Hz
(c) 20 Hz
(d) 40 Hz
MAJOR KALSHI CLASSES PVT. LTD.
Beware of Negative Marking
7
MKC FOUNDATION (SAMPLE PAPER)
43. The time period of seconds pendulum is 2 second, where g = 9.80 m/s2. The time period of
seconds pendulum where g = 4.90 m/s2 :
(a) is
2 per second
Class - 12th
43. lsd.M le; dh vko`fRr okys nksyu dh le;kof/k
2 lsd.M gS tgk¡ g = 9.80 m/s2. lsd.M dh nksyu
vko`fRr okys ml nksyu dh le;kof/k D;k gksxh
ftlds g dk eku 4.90 m/s2 gS :
2 izfr lsd.M
(a)
(b) is 2 2 per second
(c) is 2 second
(d) cannot be determined unless length is given
44. The frequency of simple pendulum is fHz. How
many times does kinetic energy assume its maximum value per second?
(a) f/2
(b) f
(c) 2f
(d) 4f
45. A lens, immersed in a liquid, becomes invisible
when :
(b) 2 2 izfr lsds.M
(c) 2 lsd.M
(d) Kkr ugha gks ldrk tc rd mldh yEckbZ
irk u gks
44. fdlh ljy nksyu dh vko`fRr fHz gSA ml nksyu
dh xfrt ÅtkZ] fdruh xquh izfrlsd.M viuk
vf/kdre eku izkIr djsxh\
(a) f/2
(c) 2f
(b) f
(d) 4f
45. ,d nzO; esa Mqcks, x;s ysUl vn`”; gks tkrk gS]
tc&
(a) the focal length of the lens is zero
(a) ysUl dh Qksdy nwjh “kwU; gks tk,A
(b) the focal length of the lens is infinite
(b) tc ysUl dh Qksdy nwjh vlhfer gksA
(c) the refractive index of the lens is less than
the refractive index of the liquid
(c) ysUl dk viorZukad nzO; ds viorZukad ls
(d) the refractive index of the lens is equal to
the refractive index of the liquid
(d) ysUl dk viorZukad nzO; ds viorZukad ds
46. The image formed on the retina of a human eye
is :
(a) virtual and inverted
de gksA
cjkcj gksA
46. ekuo us= ds jsfVuk ij cuh izfrfcEc&
(a) vkHkklh rFkk mYVh gksxh
(b) vkHkklh rFkk lh/kh gksxh
(b) virtual and erect
(c) okLrfod rFkk lh/kh
(c) real and erect
(d) okLrfod rFkk mYVh
(d) real and inverted
47. The focal length of the lens in a photographic
camera is 5cm. What is the power of the lens?
47. ,d QksVksxzkQh dSejk esa yxs ysUl dh Qksdy nwjh 5
lseh0 gSA ysUl dk ikWoj gksxk&
(a) + 5D
(b) + 10D
(a) + 5D
(b) + 10D
(c) + 15 D
(d) + 20D
(c) + 15 D
(d) + 20D
48. A virtual, erect and magnified image of an object
is to be produced with a concave mirror of focal
length 12 cm. Which one of the following object
distances should be chosen for this purpose?
48. 12 lseh0 dh Qksdy nwjh ds vory ysUl ls fdlh
oLrq dh vkHkklh] lh/kh rFkk foLr`r izfrfcEc cuuh
gSA blds fy, p;fur oLrq dh nwjh Qksdy dsUnz ls
fdruh gksuh pkfg,\
(a) 5 cm
(b) 12 cm
(a) 5 lseh0
(b) 12 lseh0
(c) 15 cm
(d) 20 cm
(c) 15 lseh0
(d) 20 lseh0
MAJOR KALSHI CLASSES PVT. LTD.
Beware of Negative Marking
8
MKC FOUNDATION (SAMPLE PAPER)
Class - 12th
49. When light waves travel from air to glass, which
variables are affected?
(a) Wavelength, frequency and velocity
(b) Velocity and frequency only
(c) Wavelength and frequency only
(d) Wavelength and velocity only
49. tc fo|qr dh rjaxs ok;q ls “kh”ks esa izos”k djrh gS
50. A long, straight conductor carries a steady
electric currect in the upward direction. The magnetic field due to this current at a point on the
east of the conductor is directed towards :
50. ,d yEch rFkk lh/kh fo|qr pkyd ds Hkhrj ,d
(a) west
(b) south
(c) north
(d) south-west
rks buesa ls dkSu ls vO;; dk eku izHkkfor gksxk\
(a) rjax nS/;Z] vko`fRr rFkk osx
(b) osx rFkk vko`fRr
(c) flQZ rjax nS/;Z rFkk vko`fRr
(d) flQZ rjax nS/;Z rFkk osx
fLFkj fo|qr /kkjk Å/okZ/kj fn”kk esa izokfgr gks jgh
gSA bl fo|qr /kkjk ds dkj.k pkyd ds iwohZ fn”kk esa
fLFkr fcUnq ij cuus okyk pqEcdh; {ks= dh fn”kk
gksxh %
(a) if”pe
(b) nf{k.k
(c) mRrj
(d) nf{k.k&if”pe
51. Moment of inertia of a body does not depend
upon its—
(a) shape
(b) mass
(c) angular velocity
(d) axis of rotation
51. fdlh fi.M dk tM+rk laosx buesa ls fdl ij fuHkZj

52. What is the torque of force F  2ˆi  3 ˆj  4 kˆ

acting at a point r  3ˆi  2 ˆj  3kˆ about the
origin?
(a) 17ˆi  6 ˆj  13kˆ
(b) 17ˆi  6 ˆj  13kˆ
(c) 6ˆi  6 ˆj  12kˆ
(d) 6ˆi  6 ˆj  12kˆ

52. ewy fcUnq ds bnZ&fxnZ ,d fcUnq r  3ˆi  2 ˆj  3kˆ

ij yxus okys cy F  2ˆi  3 ˆj  4 kˆ dk cy&vk?kw.kZ
53. Which of the following options are correct?
(a) Acceleration due to gravity decreases with
increasing altitude.
(b) Acceleration due to gravity increases with
increasing depth (assume the earth to be a
sphere of uniform density).
(c) Acceleration due to gravity increases with
increasing latitude.
(d) Acceleration due to gravity is independent
of the mass of the earth.
53. fuEu esa ls dkSu&lk lgh gS\
(a) xq#Rokd’kZ.k ds dkj.k mRiUu Roj.k Å¡pkbZ ds c<+us
54. Which of the following graphs show the
variation of acceleration due to gravity g with
depth d from the surface of the earth?
54. uhps fn, x, xzkQ esa ls dkSu lk xzkQ i`Foh dh
lrg ds uhps d xgjkbZ ij xq#Rokd’kZ.k g ds
(a)
g
(b)
g
ugha gksrh\
(a) vkdkj
(c) dks.kh; osx
gksxk %
(a) 17ˆi  6 ˆj  13kˆ
(c) 6ˆi  6 ˆj  12kˆ
dkj.k Roj.k esa gksus okys ifjorZu dks n”kkZrk gS\
g
(b)
(d)
d
d
g
g
(c)
g
d
d
g
(b) 17ˆi  6 ˆj  13kˆ
(d) 6ˆi  6 ˆj  12kˆ
ij ?kVrh gSA
(b) xq#Ro ds dkj.k Roj.k xgjkbZ c<+us ds lkFk c<+rh
gSA ¼;fn i`Foh dks ,d leku ?kuRo dk xksyk eku
fy;k tk,½
(c) xq#Ro ds dkj.k mRiUu Roj.k v{kka”k ds c<+us ds
lkFk&lkFk c<+rh gSA
(d) xq#Ro ds dkj.k mRiUu Roj.k i`Foh ds nzO;eku ij
fuHkZj ugha djrkA
(a)
d
(b) nzO;eku
(d) ?kw.kZu /kqjh
g
(c)
d
MAJOR KALSHI CLASSES PVT. LTD.
(d)
d
Beware of Negative Marking
d
9
MKC FOUNDATION (SAMPLE PAPER)
55. If the distance between the earth and the sun were
half its present value, the number of days in a
year would have been
Class - 12th
55. ;fn i`Foh rFkk lwjt ds chp dh nwjh vk/kh gksrh gS]
,d o’kZ esa fnolksa dh la[;k gksxh %
(a) 64.5
(b) 129
(a) 64.5
(b) 129
(c) 182.5
(d) 730
(c) 182.5
(d) 730
56. The number of significant figures in 0.06900
is :
56. 0-06900 bl vk¡dM+sa esa egRoiw.kZ vad gS %
(a) 5
(b) 4
(a) 5
(b) 4
(c) 2
(d) 3
(c) 2
(d) 3
57. Pressure exerted by a liquid is :
(a) directly proportional to the height of liquid
column
(b) inversely proportional to height of liquid
column
(c) independent of the height of liquid column
(d) None of these
57. fdlh nzO; }kjk yxk;k x;k ncko&
(a) ikjs dh uyh esa ikjs dh Å¡pkbZ ds lekuqikrh
gksrk gSA
(b) ikjs dh uyh esa ikjs dh Å¡pkbZ ds O;qRØekuqikrh
gksrk gSA
(c) ikjs dh uyh esa ikjs dh Å¡pkbZ ij fuHkZj ugha
gksrkA
(d) buesa ls dksbZ Hkh ughaA
58. The Reynold’s number for fluid flow in a pipe
depends on :
(a) viscosity of the fluid
(b) velocity of the fluid
(c) diameter of the pipe
(d) All (a), (b) and (c)
58. fdlh ikbZi ds Hkhrj nzO; ds cgko dh jsukYM la[;k
59. Angle of contact between water and mercury is
1400. The shape of meniscus of mercury in a
tube is
59. ty rFkk ikjs ds e/; lEidZ dks.k 1400 gSA fdlh
(a) concave upward
(b) plane
(c) convex upward
(d) None of these
60. Surface tension is defined as the force per unit
length, dimensional formula for surface tension
is :
fuHkZj djrh gS&
(a) nzO; dh “;kurk ij
(b) nzO; ds osx ij
(c) ikbZi ds O;kl ij
(d) (a), (b) rFkk (c) lHkh
V~;wc esa ikjs dh lrg dk vkdkj gksxk&
(a) ckg~; vory
(b) lery
(c) ckg~; mRry
(d) buesa ls dksbZ ugha
60. i`’B ruko dh ifjHkk’kk i`’B dh izfr yEc bdkbZ ij
yxus okyk cy] i`’B ruko dk foeh; lw =
gS %
(a) MLT–2
(b) ML0T–2
(a) MLT–2
(b) ML0T–2
(c) ML2T–2
(d) ML–1T–2
(c) ML2T–2
(d) ML–1T–2
61. Maximum number of electrons in a subshell l = 3
61. mid{kk l = 3 rFkk n = 4 esa bysDVªku dh vf/kdre
la[;k gksxh %
and n = 4 is :
(a) 10
(b) 12
(a) 10
(b) 12
(c) 14
(d) 16
(c) 14
(d) 16
MAJOR KALSHI CLASSES PVT. LTD.
Beware of Negative Marking
10
MKC FOUNDATION (SAMPLE PAPER)
62. The correct set of four quantum numbers for the
valence electron of rubidium atom (z = 37)
is :
Class - 12th
62. #fcfM;e ijek.kq (z = 37) ds lcls ckg~; d{kk esa
jgus okys osysUl bysDVªkuksa ds pkj vyx&vyx
DokaVe la[;kvksa dk lgh lkeqP; ¼lsV½ gS %
(a) 5, 0, 0, +
1
2
(b) 5, 1, 0, +
1
2
(a) 5, 0, 0, +
1
2
(b) 5, 1, 0, +
1
2
(c) 5, 1, 1, +
1
2
(d) 6, 0, 0, +
1
2
(c) 5, 1, 1, +
1
2
(d) 6, 0, 0, +
1
2
63. A gas absorbs a photon of 355 nm and emits at
two wavelengths. If one of the emissions is at
680 nm the other is at :
(a) 518 nm
(b) 1035 nm
(c) 325 nm
(d) 743 nm

(c) O22 , B2
(d) O , NO

(c) O2
64. jklk;fud rRoksa dk og tksM+k ftuds cU/k vkMZj
(a) NO, CO

65. Bond order of 1.5 is shown by :
(a) O22
(b) 1035 nm
(d) 743 nm
leku gSa %
(b) N2, O2

2
xzg.k djus ds i”pkr~ nks vyx&vyx rjax nS/;Z
okyh jsfM;ks/kehZ fofdj.k mRiUu djrk gSA ;fn
buesa ls ,d fofdj.k rjaxnS/;Z 680 nm gS rks nwljs
dh rjax nS/;Z gksxh %
(a) 518 nm
(c) 325 nm
64. The pair of species with the same bond order is :
(a) NO, CO
63. ,d xSlh; rRo 355 nm vkdkj okys QksVku dks

(c) O22 , B2

(a) O22
(d) O2
(c) O2
(a) 27.2 eV
(b) 40.8 eV
(c) 54.4 eV
(d) 108.8 eV
67. In allene (C3H4) the type (s) of hybridisation of
the carbon atoms is (are) :
(d) O2 , NO 
65. buesa ls fdldk cU/k vkMZj 1-5 gS\
(b) O2
66. If the first ionization energy of H atom is
13.6 eV, then the 2nd ionization energy of the
atom is :
(b) N2, O2
(b) O2
(d) O2
66. ;fn gkbMªkstu ijek.kq (H) dh izFke vk;uhdj.k
ÅtkZ (I. E1) 13.6 eV gS rks bldh f}rh; vk;uhdj.k
ÅtkZ (I–E2) fdruh gksxh\
(a) 27.2 eV
(b) 40.8 eV
(c) 54.4 eV
(d) 108.8 eV
67. ,fyu (C3H4) esa dkcZu ijek.kq }kjk iznf”kZr ladj.k
gksrk gS %
(a) sp and sp3
(b) sp and sp2
(a) sp rFkk sp3
(b) sp rFkk sp2
(c) Only sp2
(d) sp2 and sp3
(c) dsoy sp2
(d) sp2 rFkk sp3
68. The sp3d2 hybridization of central atom of a
molecule would lead to :
(a) square planar geometry
(b) tetrahedral geometry
(c) trigonal bipyramidal geometry
(d) octahedral geometry
MAJOR KALSHI CLASSES PVT. LTD.
68. fdlh v.kq ds dsUnzh; ijek.kq }kjk iznf”kZr sp3d2
ladj.k ls cuus okys vk.kfod <k¡pksa dk foU;kl
gksxk %
(a) square planar foU;kl
(b) prq’dh; foU;kl
(c) Vªkbxksuy ckbZ fijkfeMy (Trigonal Bipyramidal)
(d) octahedral foU;kl
Beware of Negative Marking
11
MKC FOUNDATION (SAMPLE PAPER)
Class - 12th
69. Hybridication of C2 and C3 of
H3C – CH = C = CH = CH3 are :
(a) sp, sp3
(b) sp2, sp
(c) sp2, sp2
(d) sp, sp
69. H3C – CH = C = CH = CH3 esa C2 rFkk C3 dkcZu
70. Which one of the following is paramagnetic?
(a) N2
(b) NO
(c) CO
(d) O3
70. buesa ls dkSu&lh xSl iSjkeSXusfVd gS\
(a) N2
(b) NO
(c) CO
(d) O3
71. The maximum number of hydrogen bonds that a
molecule of water can have is :
(a) 1
(b) 2
(c) 3
(d) 4
71. ty ds v.kq esa cuus okys gkbMªkstu cU/kksa dh
72. Based on the first law of thermodynamics, which
one of the following is correct?
(a) For an isothermal process, q = + w
(b) For an isochoric process, u = – q
(c) For an adiabatic process, u = – w
(d) For an cyclic process, q = – w
72. Å’ekxfrdh; ds izFke fu;e ds vk/kkj ij fuEu esa
73. The amount of heat evolved when 500 cm3 of
0.1M HCl is mixed with 200 cm3 of 0.2 M NaOH
is :
(a) 1.292 KJ
(b) 2.292 KJ
(c) 3.392 KJ
(d) 0.292 KJ
73. 0-1 eksyyrk ds 500 cm3 HCl vEy dks 0-2 eksyyrk
ds 200 CC NaOH ¼dkfLVd vEy½ esa feykus ij
74. Which of the following is an intensive property?
(a) temperature
(b) surface tension
(c) viscosity
(d) all of these
74. buesa ls dkSu&lh iz—fr ,d baVsuflo iz—fr gS\
(a) rki
(b) i`’B ruko
(c) “;kurk
(d) buesa lHkh
75. 0.023g of sodium metal is reacted with 100 cm3
of water. The pH of the resulting solution is :
(a) 10
(b) 8
(c) 9
(d) 12
75. 0.023 xzke lksfM;e /kkrq dk 100 cm3 ty ls fØ;k
dh tkrh gSA ifj.kkeh ?kksy dk pH gksxk %
(a) 10
(b) 8
(c) 9
(d) 12
76. Amines behave as :
(a) lewis acids
(b) lewis base
(c) aprotic acid
(d) neutral compound
76. ,ehUl crkZo djrs gSa %
(a) yqbl vEy dh Hkkafr
(b) yqbl {kkj dh Hkkafr
(c) ,izksfVd vEy dh Hkkafr
(d) mnklhu la;qXe dh Hkkafr
77. Percentage of free space in a body centred cubic
unit cell is :
(a) 32%
(b) 34%
(c) 28%
(d) 20%
77. BCC ¼ckMh lsaVMZ D;wfcd½ ;wfuV lsy esa ekStwn
MAJOR KALSHI CLASSES PVT. LTD.
ijek.kq }kjk iznf”kZr ladj.k gksxk&
(a) sp, sp3
(c) sp2, sp2
(b) sp2, sp
(d) sp, sp
vf/kdre la[;k gS %
(a) 1
(c) 3
(b) 2
(d) 4
ls dkSu&lk fu’d’kZ lgh gS\
(a) lerkih; izfØ;k gsr,q q = + w
(b) Isochoric izfØ;k gsrq, u = – q
(c) ,d Adiabatic izfØ;k gsrq, u = – w
(d) pØh; izfØ;k gsr,q q = – w
mRiUu Å’ek dh ek=k gksxh %
(a) 1.292 KJ
(c) 3.392 KJ
(b) 2.292 KJ
(d) 0.292 KJ
fjDr LFkku dk izfr”kr gksrk gS %
(a) 32%
(c) 28%
(b) 34%
(d) 20%
Beware of Negative Marking
12
MKC FOUNDATION (SAMPLE PAPER)
78. The appearance of colour in solid alkali metal
halides is generally due to :
(a) Schottky defect
(b) Frenkel defect
(c) Interstitial position
(d) F-centres
79. 2-Acetoxy benzoic acid is used as :
Class - 12th
78. Bksl {kkjh; /kkrq ds gsykbZM~l ds jaxhu ut+j vkus
dh lkekU;r% dkj.k gS\
(a) Schottky fodkj
(b) ÝsUdy fodkj
(c) var% vkf.od fLFkfrdh
(d) F-dsUnzksa dh mRifRr
79. 2-Acetoxy benzoic dk iz;ksx fd;k tkrk gS\
(a) Antiseptic
(a) Antiseptic ds :i esa
(b) Antidepressant
(b) rukojks/kh vkS’kf/k ds :i esa
(c) Antimalarial
(c) eysfj;kjks/kh vkS’kf/k
(d) Antipyretic
(d) Tojjks/kh vkS’kf/k
80. The oxidant which is used as an antiseptic is :
(a) KBrO3
(b) KMnO4
(c) CrO3
(d) KNO3
81. When Cl2 gas reacts with hot and concentrated
sodium hydroxide solution, the oxidation number of chlorine changes from :
(a) zero to – 1 and zero to + 3
(b) zero to + 1 and zero to – 3
(c) zero to + 1 and zero to – 5
(d) zero to – 1 and zero to + 5
80. ,slk vkDlhdkjd ftldk iz;ksx laØe.kjks/kh jlk;u
ds :i esa Hkh gksrk gS %
(a) KBrO3
(c) CrO3
(b) KMnO4
(d) KNO3
81. tc Dyksjhu xSl (Cl2) dh fØ;k xeZ rFkk lkU/kz
dkfLVd lksMk (NaOH) foy;u ¼?kksy½ ls dh tkrh
gS] rks Dyksjhu dh vkDlhdj.k la[;k cnyrh gS&
(a) “kwU; ls &1 rFkk “kwU; ls $3
(b) “kwU; ls $1 rFkk “kwU; ls &3
(c) “kwU; ls $1 rFkk “kwU; ls &5
(d) “kwU; ls &1 rFkk “kwU; ls $5
82. In which of the following compounds, nitrogen
exhibit is highest oxidation state?
(a) N3H
(b) NH2OH
(c) N2H4
(d) NH3
82. buesa ls fdl ;qXed esa ukbVªkstu v.kq lcls mPp
83. Three reactions involving H2PO4– are given
below :
83. H2PO4– ls lEc) rhu jlk;fud fØ;k,¡ uhps nh
vkDlhdj.k voLFkk n”kkZrk gS\
(a) N3H
(c) N2H4
(b) NH2OH
(d) NH3
xbZ gS %


(i) H 3 PO4  H 2O  H 3O  H 2 PO4


(i) H 3 PO4  H 2O  H 3O  H 2 PO4

2

(ii) H 2 PO4  H 2O  HPO4  H 3O

2

(ii) H 2 PO4  H 2O  HPO4  H 3O


2
(iii) H 2 PO4  OH  H 3 PO4  O


2
(iii) H 2 PO4  OH  H 3 PO4  O
In which of the above does H2PO4– act as an
acide?
mijksDr vfHkfØ;kvksa esa ls fdl vfHkfØ;k esa H2PO4–
,d vEy dh rjg O;ogkj djrk gS\
(a) dsoy (i) esa
(b) dsoy (ii) esa
(c) dsoy (iii) esa
(d) (i) rFkk (ii) esa
(a) (i) only
(b) (ii) only
(c) (iii) only
(d) (i) and (ii)
MAJOR KALSHI CLASSES PVT. LTD.
Beware of Negative Marking
13
MKC FOUNDATION (SAMPLE PAPER)
84. The tendency of BF3, BCl3 and BBr3 to behave
as lewis acid decreases in the sequence :
(a) BCl3 > BF3 > BBr3 (b) BF3 > BCl3 > BBr3
Class - 12th
84. BF3, BCl3 rFkk BBr3 dh yqbl vEy ds :i esa
crkZo djus dh izo`fRr buesa ls fdl Øe esa ?kVrh
gS\
(a) BCl3 > BF3 > BBr3 (b) BF3 > BCl3 > BBr3
(c) BBr3 > BF3 > BCl3 (d) BBR3 > BCl3 > BF3
(c) BBr3 > BF3 > BCl3 (d) BBR3 > BCl3 > BF3
85. Which of these changes with time for a firstorder reaction?
(A) Rate of reaction,
(B) Rate Constant,
(C) Half life
(a) A only
(b) C only
(c) A & B only
(d) B & C only
85. buesa ls dkSu lk ?kVd izFke&Øe okyh jklk;fud
86. Time requiredfor 100 percent completion of a
zero order reaction is :
(a) 2k/a
(b) a/2k
(c) a/k
(d) ak
86. thjks vkMZj fØ;k dks 100 izfr”kr laiUu ¼”kr
87. Which of the following is a molecular crystal?
(a) Dry ice
(b) Quartz
(c) Rock salt
(d) Diamond
87. buesa ls dkSu&lk vkf.od fØLVy gS\
(a) Dry ice
(b) DokVZ~t
(c) Rock salt
(d) ghjk
88. An ionic compound is expected to have tetrahedral structure if r+/r– lies in the range of :
(a) 0.414 to 0.732
(b) 0.732 to 1
(c) 0.155 to 0.225
(d) 0.225 to 0.414
88. r+/r– ds fdl range esa ,d vk;fud mRikn ¼;qXed½
dk Lo:i prq’Qydh; (Tetrahedra) gksxk\
(a) 0.414 ls 0.732
(b) 0.732 ls 1
(c) 0.155 ls 0.225
(d) 0.225 ls 0.414
89. Which one of the following is an example for
homogenous catalysis?
89. buesa ls dkSu&lh izfØ;k ,d le:ih; vfHkdkfeZd
(a) Hydrogenation of oil
(b) Manufacture of ammonia by Haber’s process
(c) Manufacture of sulphuric acid by contact
process
fØ;k gsrq le; ds lkFk cnyrh gS\
(A) jklk;fud fØ;k dh nj
(B) nj fLFkjkad
(C) v/kZ vk;q
(a) dsoy A
(b) dsoy C
(c) dsoy A rFkk B
(d) dsoy B rFkk C
izfr”kr½ djus gsrq vko”;d le; gS %
(a) 2k/a
(c) a/k
(b) a/2k
(d) ak
(homogenous catalysis) dk mnkgj.k gS\
(a) vkW;y dk gkbMªksftuhdj.k
(b) veksfu;k dk Habers fØ;k ls fuekZ.k
(c) lY¶;wfjd vEy dk contact izfØ;k }kjk mRikn
(d) Hydrolysis of sucrose in presence of dilute
hydrochloric acid
(d) dil HCl dh mifLFkfr esa lqdjkst dk gkbMªkfs yfll
90. The protecting power of lyophilic colloidal sol
is expressed in terms of :
90. tyizseh dksyk;M foy;u dh izfrj{kd {kerk dks
(Hydrolysis)
(a) critical miscelle concentration
buesa ls fdl vo;; }kjk iznf”kZr fd;k tkrk gS\
(a) fØfVdy Miscelle lkU/kzrk
(b) cougulation value
(b) cougulation value
(c) oxidation number
(c) vkDlhdj.k la[;k
(d) gold number
(d) xksYM uacj
MAJOR KALSHI CLASSES PVT. LTD.
Beware of Negative Marking
14
MKC FOUNDATION (SAMPLE PAPER)
Class - 12th
91. Number of chromosomes in a normal body cell
is :
(a) 43
(b) 44
(c) 45
(d) 46
91. ,d lkekU; vax dksf”kdk (body cell) esa ØksekslksEl
92. Which is the most stable ecosystem?
(a) Desert
(b) Ocean
(c) Mountain
(d) Forest
92. buesa ls dkSu lcls fLFkj ifjfLFkfrdh ra= gS\
(a) e#LFky
(b) egklkxjh;
(c) ioZrh;
(d) ou
93. In a nuclear reactor, one of the following
animals, is skin a respiratory organ?
(a) Coakroach
(b) Frog
(c) Spark
(d) Whale
93. buesa ls dkSu&ls tho esa Ropk ,d “olu vax gS\
94. Which is the earliest of the Indian Institute of
Technologies established?
(a) ITT, Delhi
(b) IIT, Mumbai
(c) IIT Khragpur
(d) IIT, Kanpur
94. buesa ls dkSu&lk Hkkjrh; izkS|ksfxdh laLFkku lcls
95. Which broadcasting major in India has launched
High Definition (HD) versions of its channels in
the country and unveiled its new corporate logo?
95. buesa ls fdl fnXxt izlkj.k daiuh us vius pSuyksa
dks mPp ifjHkkf’kr (HD) izl kj.k fdLeks a dks
(a) Star TV
(b) Sony TV
(c) Zee TV
(d) ESPN Star
dh la[;k gksrh gS\
(a) 43
(c) 45
(b) 44
(d) 46
(a) dkdjksp ¼frypV~Vk½ (b) esa<+d
(c) LikdZ
igys LFkkfir gqvk\
(a) ITT, fnYyh
(c) IIT, [kM+xiqj
(d) Ogsy
(b) IIT, eqEcbZ
(d) IIT, dkuiqj
izfrLFkkfir dj vius u, dkjiksjsV izrhd fpUg dk
vukoj.k fd;k\
(a) Star TV
(c) Zee TV
(b) Sony TV
(d) ESPN Star
96. Humayun Nama was written by :
(a) Humanyun
(b) Akbar
(c) Abul Fazal
(d) Gulbadan Begum
96. gqek;q¡ukek fdlds }kjk fy[kk x;k\
(a) gqek;q¡ }kjk
(b) vdcj }kjk
(c) vcqy Qt+y
(d) xqycnu csxe
97. The voting age in India was lowered from 21
years to 18 years through :
(a) President Ordinance
(b) Constitutional Amendment
(c) Executive Order
(d) Parliamentary Legislation
97. Hkkjr esa oksV Mkyus dh mez dks 21 o’kZ ls 18 o’kZ
98. Which one of the following is a green house gas?
(a) Oxygen
(b) Nitrogen
(c) Carbon-di-oxide
(d) Ozone
98. buesa ls dkSu ,d xzhu gkml xSl gS\
(a) vkWDlhtu
(b) ukbVªkstu
(c) dkcZuMkbZ vkWDlkbM (d) vkstksu
99. At Sindri in Bihar, the fertilize produced is :
99. flUnjh] fcgkj esa dkSu ls moZjd dk mRiknu gksrk
(a) Urea
(b) Ammonium Phosphate
(c) Calcium Super Phosphate
(d) Ammonium Sulphate
MAJOR KALSHI CLASSES PVT. LTD.
fd;k x;k fdl la”kks/ku] dkuwu ;k v/;kns”k }kjk\
(a) jk’Vªifr v/;kns”k }kjk
(b) laoS/kkfud la”kks/ku }kjk
(c) dk;Zdkjh vkns”k }kjk
(d) lalnh; fo/ks;d }kjk
gS\
(a) ;wfj;k
(b) ,eksfu;e QkLQsV
(c) dSfY”k;e lqij QkLQsV
(d) ,eksfu;e lYQsV
Beware of Negative Marking
15
MKC FOUNDATION (SAMPLE PAPER)
Class - 12th
100. Which one of the following is a coastal district
in Kerala?
(a) Palghat
(b) Wayanand
(c) Kollam
(d) Idukki
100. buesa ls dkSu&lk ftyk dsjy dk rVh; ftyk gS\
101. Which of the following is not a desert of
Rajasthan?
(a) Kota
(b) Barmer
(c) Jaisalmer
(d) Churu
101. buesa ls dkSu&lk “kgj ;k tuin jktLFkku ds
102. A day is added when on crosses :
102. buesa ls dkSu&lk v{kka”k ;k js[kk yka?kus ij ,d
(a) The equator from south to north
(b) 180 0 degree lo ngitude from east to
west
(c) the equator from north to south
(d) 180 0 degree lo ngitude from west to
east
(a) iky?kkV
(b) os;ukZn
(c) dksye
(d) bMqdh
e#LFkyh; {ks= dk fgLlk ugha gS\
(a) dksVk
(b) ckM+esj
(c) tSlyesj
(d) pq#
u;k fnu “kq: gks tkrk gS\
(a) nf{k.k ls mRrj fn”kk esa fo’kqor js[kk yka/kus ij
(b) iwohZ fn”kk ls if”pe fn”kk dh vksj 1800 v{kka”k
ikj djus ij
(c) fo’kqor js[kk dks mRrj ls nf{k.k fn”kk esa yka?kus
ij
(d) if”pe ls iwjc fn”kk dh vksj 1800 v{kka”k dks
yka/kus ij
103. Which of the following states does not have a
railway station?
(a) Sikkim
(b) Mizoram
(c) Nagaland
(d) Tripura
103. buesa ls fdl jkT; esa dksbZ jsyos LVs”ku ugha gS\
104. The deepest ocean is :
(a) Arctic
(b) Pacific
(c) Atlantic
(d) Indian
104. lcls xgjk egklkxj gS %
(a) vkdZfVd
(b) iz”kkar
(c) vVykafVd
(d) fgUn
105. Which of the following is an example of credit
investment?
(a) A share (of stock)
(b) A draft
(c) A banker’s acceptance
(d) A bond
105. buesa ls dksZu ,d ØsfMV bUosLVes.V gS\
106. From the given alternative words, select the word
which cannot be formed using the letters of the
given word TRANQUILITY
(a) QUANTITY
(b) QUALITY
(c) ANTIQUITY
(d) LIQUIDITY
106. fuEufyf[kr oSdfYid “kCnksa esa ls ml “kCn dk
p;u djsa ftldk fuekZ.k TRANQUILITY “kCn
107. In a certain code, ORDER is written as  
$ #  and BOARD is written as *  %  $.
How is ABODE written in that code?
107. fdlh fo”ks ’ k dks M es a ] ORDER dks  
$ #  dh rjg rFkk BOARD dks *  %  $. dh
rjg fy[kk tkrk gSA blh dksM ¼dwV½ esa ABODE
(a) % *  $ #
(b) *  $ # 
(c) % *  $ 
(d)  *  $ #
MAJOR KALSHI CLASSES PVT. LTD.
(a) flfDde
(b) fetksje
(c) ukxkyS.M
(d) f=iqjk
(a) LVkd ds “ks;j
(b) Mªk¶V
(c) cSadj }kjk tkjh Loh—fr i=
(d) ,d ckW.M
ds v{kjksa ls laHko ugha gS %
(a) QUANTITY
(c) ANTIQUITY
(b) QUALITY
(d) LIQUIDITY
fdl izdkj ls fy[kk tk,xk\
(a) % *  $ #
(c) % *  $ 
(b) *  $ # 
(d)  *  $ #
Beware of Negative Marking
16
MKC FOUNDATION (SAMPLE PAPER)
108. Ramakant walks Northwards. After a while, he
turns to his right and a little further to his left.
Finally after walking a distance of one kilometre,
he turns to his left again. In which direction is he
moving now?
Class - 12th
108. jkekdkar mRrjh fn”kk esa iSny pyrk gSA dqN le;
ckn og nk¡;h vksj eqM+ tkrk gS rFkk rRi”pkr~ fQj
ck¡;ha vksj eqM+rk gSA var esa 1 fdyksehVj iSny pyus
ij og nksckjk ck¡;h vksj eqM+ tkrk gSA vc og fdl
fn”kk esa py jgk gS\
(a) North
(b) South
(a) mRrj
(b) nf{k.k
(c) East
(d) West
(c) iwjc
(d) if”pe
109. Find out the missing number :
4
109. foyqIr la[;k dks Kkr djsa %
5
4
41
?
6
7
(a) 9
(c) 85
5
41
2
5
?
6
1
7
(b) 16
(d) 112
2
5
1
(a) 9
(c) 85
(b) 16
(d) 112
110. A man walks 1 km towards East and then he
turns to South and walks 5 km. Again he turns
to East and walks 2 km, after this he turns to
North and walks 9 km. Now, how far is he from
his starting point?
(a) 3 km
(b) 4 km
(c) 5 km
(d) 7 km
110. ,d O;fDr iwjc fn”kkesa 1 fdeh0 pyrk gS rRi”pkr~
Direction (111-112) : Which one set of letter, when
sequentially placed at the gaps in the given letter
series shall complete it.
111. C – ac – aa – aa – bc – bcc
(a) cabba
(b) ccbbb
(c) bbbbb
(d) decdb
funsZ”k (111-112) : fuEufyf[kr v{kj J`a[kyk ds fjDr
LFkkuksa dks fdl v{kj lkeqP; dks Øeokj Hkjus ij
og laiw.kZ gks tk,xk %
112. abc – d – bc – d – b – cda
(a) bacde
(b) cdabe
(c) dacab
(d) decdb
112. abc – d – bc – d – b – cda
(a) bacde
(b) cdabe
(c) dacab
(d) decdb
113. ‘Teacher’ is related to ‘school’ in the same way
as ‘cook’ is related to :
(a) Food
(b) Kitchen
(c) Hostel
(d) House
113. ‘Teacher’ dk lEcU/k ‘school’ ls mlh izdkj ls gS
tSls ‘cook’ dk lEca/k gS %
(a) Food ls
(b) Kitchen ls
(c) Hostel ls
(d) House ls
114. What will come in place of question mark (?) in
the following series?
TG HU
VI
JW ?
(a) KY
(b) KX
(c) YK
(d) XK
114. fuEufyf[kr J`a[kyk esa iz”u fpUg ¼\½ ds LFkku ij
MAJOR KALSHI CLASSES PVT. LTD.
nf{k.k fn”kk esa eqM+dj 5 fdeh0 pyrk gSA nksckjk
og iwjc fn”kk esa eqM+dj 2 fdeh0 pyrk gSA blds
ckn og mRrj fn”kk esa eqM+dj 9 fdeh0 iSny pyrk
gSA vius izkjfEHkd fcUnq ls og fdruh nwjh ij gS\
(a) 3 km
(c) 5 km
(b) 4 km
(d) 7 km
111. C – ac – aa – aa – bc – bcc
(a) cabba
(b) ccbbb
(c) bbbbb
(d) decdb
dkSu&lk fuEufyf[kr tksM+k iz;qDr gksxk\
TG HU
(a) KY
(c) YK
VI
JW ?
(b) KX
(d) XK
Beware of Negative Marking
17
MKC FOUNDATION (SAMPLE PAPER)
115. In a certain code ‘GIVE’ is written as ‘VIEG’
and ‘OVER’ is written as ‘EVRO’. How will
‘DISK’ be written in that code?
(a) SIDK
(b) KISD
(c) KDSI
(d) SIKD
Class - 12th
115. ,d fo”ks’k dwV Hkk’kk esa ‘GIVE’ dks ‘VIEG’ dh
rjg rFkk ‘OVER’ dks ‘EVRO’ dh rjg fy[kk
tkrk gSA ml dwV Hkk’kk esa ‘DISK’ fdl izdkj ls
fy[kk tk,xk\
(a) SIDK
(c) KDS
(b) KISD
(d) SIKD
116. In how many different ways can the letters of the
world ‘CLOUD’ be arranged?
(a) 24
(b) 240
(c) 120
(d) 60
116. ‘CLOUD’ “kCn ds v{kjksa dks fdrus vyx&vyx
Direction (117-118) : Out of the four alternatives
choose the one which best expresses the meaning of the given word.
117. Lethargy
(a) Excitement
(b) Vigour
(c) Laziness
(d) Vivaciousness
funsZ”k (117-118) : fuEufyf[kr pkj fodYiksa esa ls ml
fodYi dks pqus] tks uhps fn, x, “kCn dk mi;qDr
vFkZ O;Dr djrk gS&
117. Lethargy
(a) Excitement
(c) Haziness
(b) Vigour
(d) Vivaciousness
118. Placid
(a) Calm
(c) Worried
118. Placid
(a) Calm
(c) Worried
(b) Agitated
(d) Passionate
(b) Agitated
(d) Passionate
rjhdksa ls O;ofLFkr fd;k tk ldrk gS\
(a) 24
(c) 120
(b) 240
(d) 60
Direction (119-120) : Choose the word opposite in
meaning to the given word
119. Minor
(a) Big
(b) Major
(c) Tall
(d) Heavy
funsZ”k (119-120) : fuEufyf[kr “kCn ds foyksekFkZd “kCn
dk p;u djsa %
119. Minor
(a) Big
(c) Tall
(b) Major
(d) Heavy
120. Revealed
120. Revealed
(a) Denied
(c) Ignored
(b) Concealed
(d) Overlooked
(a) Denied
(b) Concealed
(c) Ignored
(d) Overlooked
____________
MAJOR KALSHI CLASSES PVT. LTD.
Beware of Negative Marking
18
MKC FOUNDATION (SAMPLE PAPER)
Class - 12th
ANSWERSHEET
1. (d)
2. (b)
3. (d)
4. (c)
5. (b)
6. (a)
7. (a)
8. (b)
9. (d)
10. (a)
11. (c)
12. (a)
13. (c)
14. (c)
15. (b)
16. (c)
17. (b)
18. (c)
19. (a)
20. (b)
21. (b)
22. (a)
23. (d)
24. (c)
25. (c)
26. (a)
27. (c)
28. (c)
29. (b)
30. (d)
31. (c)
32. (a)
33. (c)
34. (d)
35. (b)
36. (d)
37. (a)
38. (c)
39. (b)
40. (d)
41. (a)
42. (c)
43. (b)
44. (c)
45. (b)
46. (d)
47. (d)
48. (a)
49. (d)
50. (c)
51. (c)
52. (b) 53. (a) (c)
54. (a)
55. (b)
56. (b)
57. (a)
58. (d)
59. (a)
60. (b)
61. (c)
62. (a)
63. (d)
64. (c)
65. (d)
66. (c)
67. (b)
68. (d)
69. (b)
70. (b)
71. (d)
72. (d)
73. (b)
74. (d)
75. (d)
76. (b)
77. (a)
78. (d)
79. (d)
80. (b)
81. (d)
82. (a)
83. (b)
84. (d)
85. (a)
86. (c)
87. (a)
88. (c)
89. (d)
90. (d)
91. (d)
92. (b)
93. (b)
94. (c)
95. (a)
96. (d)
97. (d)
98 (c)
99. (a) 100. (c)
101. (a)
102. (d)
103. (a)
104. (b)
105. (d)
106. (d)
107. (a) 108. (d)
109. (c)
111. (b)
112. (c)
113. (b)
114. (d)
115. (d)
116. (c)
117. (c)
119. (b) 120. (b)
118. (a)
110. (c)
*****
MAJOR KALSHI CLASSES PVT. LTD.
Beware of Negative Marking
19