1. law, govt and politics
2. government
3. government contracting and procurement

Duration : 90 Minutes
Max. Marks : 200
Please read the instructions carefully. You are allotted additional 5 minutes specifically for this purpose.
SAMPLE TEST PAPER
CLASS : XI
STREAM : SCIENCE - BIOLOGY
Write your Name and STaRT-2015 Student Registration No. in the space provided below.
Name
Reg. No. 1 5
GENERAL INSTRUCTIONS IN EXAMINATION HALL
A. General :
1. This Question Paper contains 50 questions. Please check before
starting to attempt. The question paper consists of 4 parts (Physics,
Chemistry, Biology & Mental Ability).
2. Space is provided within question paper for rough work hence no
additional sheets will be provided.
3. Blank paper, clipboard, log tables, slide rules, calculators, cellular
phones, pagers and electronic gadgets in any form are not allowed
inside the examinaiton hall.
4. The answer sheet, a machine-gradable Objective Response
Sheet (ORS), is provided separately.
5. Do not Tamper / mutilate the ORS or this booklet.
6. Do not break the seals of the question-paper booklet before
instructed to do so by the invigilators.
7. SUBMIT the ORS to the invigilator after completing the test &
take away the test paper with you.
8. Any student found/reported using unfair means to improve
his/her performance in the test, shall be disqualified from
STaRT-2015.
B. How to fill Objective Response Sheet (ORS) for filling details
marking answers:
9. Use only HB Pencil/Blue or Black ball point pen for filling the ORS.
Do not use Gel/Ink/Felt pen as it might smudge the ORS.
10. Write your STaRT-2015 Student Registration No. in the boxes given
at the top left corner of your ORS with blue/black ball point pen.
Also, darken the corresponding bubbles with HB Pencil/Blue or
Black ball point pen only.
11. If any student does not fill his/her STaRT-2015 Student Registration
No. correctly and properly, then his/her ORS will not be checked/
evaluated.
12. Since it is not possible to erase and correct pen filled bubble, you
are advised to be extremely careful while darken the bubble
corresponding to your answer.
13. Neither try to erase / rub / scratch the option nor make the Cross
(X) mark on the option once filled. Do not scribble, smudge, cut,
tear, or wrinkle the ORS. Do not put any stray marks or whitener
anywhere on the ORS.
14. If there is any discrepancy between the written data and the
bubbled data in your ORS, the bubbled data will be taken as final.
C. Question paper format and Marking scheme :
15. For each right answer you will be awarded 4 marks if you
darken the bubble corresponding to the correct answer and zero
marks if no bubble is darkened. In case of bubbling of incorrect
answer, minus one (–1) mark will be awarded.
v- lkekU; %
1- bl iz'u&i= esa 50 iz'u gSaA Ñi;k ijh{kk 'kq: djus ls igys tk¡p
ys a A bl iz ' u&i= k es a 4 Hkkx bl iz d kj gS a & HkkS f rd foKku]
jlk; u foKk u] tho f oKku ,oa eku fld ;k s X ;r k
2- jQ dk;Z djus ds fy, iz'u&i= esa gh LFkku fn;k x;k gS vr% vfrfjDr :i
ls dksbZ 'khV ;k isij ugha fn;k tk,xkA
3- [kkyh dkxt] r[rh] y?kqx.kd lkj.kh] LykbM :y] dsYdqy sVj] lsy
Qksu] ist j ,oa fdlh Hkh izdkj ds bysDVªkW fud xStsV ijh{kk gkWy esa
ykuk oftZr gSA
4- mÙkj iqfLrdk] vkWCtsfDVo jsLikWUl 'khV ¼vks-vkj-,l-½ tks fd e'khu }kjk
tk¡ph tk,xh] vyx ls iznku dh xbZ gSA
5- vks-vkj-,l- ;k iz'u&i= dks fdlh Hkh izdkj ls dkaVs&NkaVs ;k eksM+s ughaA
6- iz'u&i= dh lhy rc rd ugha [kksysa tc rd fd fujh{kd }kjk funsZ'k ugha
fn, tk,saA
7- ijh{kk lekIr gksus ds ckn vks-vkj-,l- 'khV fujh{kd dks lkSais rFkk iz'u&i=
vius lkFk ys tk,saA
8- ;fn dksbZ fo|kFkhZ ijh{kk esa vad c<+kus ds fy, vuqfpr lk/kuksa dk iz;ksx
djrk ik;k x;k ;k ,slk lwfpr fd;k x;k rks og STaRT-2015 ds fy,
v;ksX; gksxkA
c - vkW C ts f DVo js L ikW U l 'khV ¼vks - vkj-,l-½ es a fMVs Y l rFkk mÙkj
vaf dr djus ds fy, fuEu izd kj Hkjs a %
9- vks-vkj-,l- Hkjus ds fy, dsoy HB isafly@uhyk ;k dkyk ckWy isu gh
iz;ksx djsaA tsy@L;kgh@QsYV isu iz;ksx ugha djsaA
10- viuk STaRT-2015 fo|kFkhZ jftLVªs'ku Øekad vks-vkj-,l- 'khV ds ck;sa
dksus esa fn, x, LFkku esa uhys ;k dkys ckWy isu ls HkjsaA lkFk gh Øekad ds
vuqlkj uhps fn, x;s xksyksa dks Hkh HB isafly@uhys ;k dkys ckWy isu ls
xgjk djsaA
11- ;fn dksbZ fo|kFkhZ viuk STaRT-2015 fo|kFkhZ jftLVªs'ku Øekad lgh ,oa
Bhd <ax ls ugha Hkjrk gS rks mldh vks-vkj-,l- dks pSd@ewY;kafdr ugha
fd;k tk,xkA
12- vks-vkj-,l- esa fn, x, xksyksa dks ;fn ,d ckj ckWy isu ls xgjk fd;k tkrk
gS rks mls feVkuk laHko ugha] blfy, fo|kFkhZ iwjh lrdZrk ls gh xksyksa dks
xgjk djsaA
13- ,d ckj fdlh fodYi ds xksys dks xgjk djus ds ckn feVkus ;k [kqjpus dk
iz;Ru ugha djsaA vks-vkj-,l- 'khV ij fdlh izdkj ds /kCcs] xUnxh ;k
flyoV u yxus nsa vkSj u gh bls eksM+sa ;k dkVsaA
14- ;fn fdlh lanHkZ esa fyf[kr ,oa xksyksa esa vafdr tkudkjh esa varj ik;k x;k
rks xksyksa esa vafdr tkudkjh dks gh izekf.kd ekuk tk,xkA
l - iz' u&i= izk :i ,oa va d izn ku fu;e %
15- izR;sd mÙkj ds fy, 4 vad fn, tk,xsa ;fn lgh xksys dks xgjk fd;k x;kA
;fn xyr xksys dks xgjk fd;k x;k rks ¼&1½ vad dkVk tk,xkA ;fn fdlh
xksys dks Hkh xgjk ugha fd;k x;k rks 'kwU; vad fn;k tk,xkA
Best of Luck
PART-I (PHYSICS)
Straight Objective Type
This section contains (1-15) questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out of
which ONLY ONE is correct.
lh/ksoLrqfu"B izd kj
bl [k.M esa(1-15) cgq& fod Yihiz'u gSaA izR;sd iz'u d s4 fod Yi (A), (B), (C) rFkk (D) gSa]ft uesalsfl Q Z,d l gh
gSA
3
1.
V(m )
Arc AB is half section of ellipse (with AB as the major axis). An ideal gas
is taken from A to B as shown in diagram. The work done by gas for A to
–3
B process is : [use  = 22/7]
5×10
pki AB nh?kZo`Ùkd kv/kZ& Hkkx (AB nh?kZv{k) gSA ,d vkn'kZxSl d ksfp=kkuql kj A
–3
A
lsB rd y st k;k x;kgSA bl çfØ ;kesaxSl }kjk A lsB rd fd ;k x;kd k;ZgS: 3×10
[ = 22/7]
0 2×103
(A) 11 J
2.
(C) –11 J
2
3
9×10
P(N/m )
(D) –22 J
A ball is thrown at different angles with same speed u and from the same point. It has the same range in both
the cases. If y1 and y2 be the maximum heights attained in the two cases, then y1 + y2 is :
,d xsan vy x&vy x d ks.klsijUrqleky pky u ls,d ghfcUnqlsQ s
ad ht krhgSA nksauksfLFkfr;ksaesaxsan d hijkl leku gSA ;fn
y1 rFkky2 nks
auksfLFkfr;ksaesaxsan }kjk çkIr v f/kd re Å pk¡bZ;kagksrksy1 + y2 gksxk
(A)
3.
(B) 22 J
B
u2
g
(B)
2u2
g
(C)
u2
2g
(D)
u2
4g
A simple pendulum is suspended from the ceiling of a car. Find the horizontal acceleration of the car in terms
of the angle  which the pendulum makes with the vertical.
,d d kj d h N r l s,d l jy y ksy d y Vd k gqv k gSA Å /okZ/kj l sy ksy d }kjk cuk;sx;s d ks.k d sinksaesad kj d k {kSfrt
Roj.k K kr d hft ,A
(A) g tan 
(B) g sin 
(C) g cos 
(D) g cot 
4.
A car is moving on a plane inclined at 30º to the horizontal with an acceleration of 9.8 m/s2 parallel to the plane
upward. A bob is suspended by a string from the roof. The angle in degrees which the string makes with the vertical
is : (Assume that the bob does not move relative to car) [g = 9.8 m/s2]
30º d ks
.k oky s,d ur ry ij ,d d kj ur ry d slekUrj Å ij d h vksj 9.8 m/s2 d sRoj.k lsxfr d j jgh gSA d kj d h Nr
lsMksjh}kjk,d y ksy d (bob) y Vd kgq
v kgSA Mksjh}kjkm/okZ/kj d slkFkcuk;kx;kd ks
.kgS
%(ekuky ksy d (bob)]d kj d slkis{k
xfr ughad jrk gS½ [g = 9.8 m/s2]
(A) 20º
(B) 30º
(C) 45º
(D) 60º
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 3
5.
 1
Value of  is increased gradually from  = 0. At  = tan–1   both the blocks just start slipping. Then value of 2 is:
2
2
(g = 10 m/s )
 = 0 ls d k eku
 1
y xkrkj c<+jgk gSA  = tan–1  2  ij nksauksCy kWd xfr d juk çkjEHk d jrs
 
gSA rc 2 d k eku gS: (g = 10 m/s )
2
(A) 0.5
6.
(B) 0.4
(B) 20 N
(C) 30 N
(D) none of these bues
alsd ksbZugh

The potential energy for a force field F is given by U (x,y) = cos (x + y). The force acting on a particle at
 
position given by coordinates  0,  is
 4

,d cy {ks=k F d h fLFkfrt Å t kZU (x,y) = cos (x + y) gS] rksfunsZ'kkad  0,  
 4
1
(A) –
8.
(D) 0.3
A particle of mass 5 kg is moving on rough fixed inclined plane (making an angle 30 ° with horizontal) with
constant velocity of 5 m/s as shown in the figure. Find the friction force acting on the body by the incline
plane. ( take g = 10m/s 2)
5 kg nz
O;eku d k,d d .k,d fLFkj [kqjnjsur ry ¼t ks{kSfrt ls30 ° d kd ks.kcukrkgS
½ ij fn[kk;s
fp=kkuql kj 5 m/s d sfu;r osx lsxfr d jrk gSA ur ry }kjk d .k ij y xusoky k ?k"kZ.k cy Kkr
d hft ,A ( g = 10m/s2)
(A) 25 N
7.
(C) 0.6
2
1
( ˆi  ˆj )
(B)
2
( ˆi  ˆj )
1
3 ˆ 
 ˆ
(C)  2 i  2 j 


fLFkfr ij d .k ij y xusoky k cy gS
1
3 ˆ 
 ˆ
(D)  2 i  2 j 


The potential energy (in S units) of a particle of mass 2 kg in a conservative field is U = 6x – 8y. If the initial velocity

of the particle is u = – 1.5 ˆi + 2 ˆj then the total distance travelled by the particle in first two seconds is -
,d 2 kg nzO;eku oky sd .k d h laj{kh {ks=k esafLFkfrt Å t kZ(in S units) U = 6x – 8y gSA ;fn d .k d k izkjfEHkd osx

d .M esar; d h xbZd qy nwjh gksxh &
u = – 1.5 ˆi + 2 ˆj gSrksd .k }kjk igy snkslS
(A) 10 m
(B) 12 m
(C) 15 m
(D) 18 m
(SPACE FOR ROUGH WORK)
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 4
9.
An insect of mass m = 3 kg is inside a vertical drum of radius 2 m that is rotating with an
angular velocity of 5 rad/sec. If the insect does not fall off , then the minimum co-efficient
of friction required is (g = 10m/s 2) :
,d 3 kg nzO;eku d k d hM+k2 eh-f=kT;k d sm/okZ/kj Mªe d svUnj gSrFkkMªe 5 rad/sec d sd ks.kh; osx
ls?kwe jgk gSA ;fn d hM+k uhpsugh fxjrk rksU;wure vko';d ?k"kZ.k xq.kkad gS(g = 10m/s2) :
(A) 0.5
10.
(B) 0.4
(C) 0.2
(D) none of these bues
alsd ksbZugha
A mass M hangs stationary at the end of a light string that passes through a smooth
fixed tube to a small mass m that moves around in a horizontal circular path. If  is
the length of the string from m to the top end of the tube and  is angle between this
part and vertical part of the string as shown in the figure, then time taken by m to
complete one circle is equal to
,d nzO;eku M gYd h jLlh lsfLFkj : i lsy Vd jgk gSrFkk jLlh d k nwl jk fljk fpd uh t M+or~
V~;w
c lsxq
t kjusd sckn Nks
VsnzO;eku m lsca/kkgS
A t ks{kS
frt o`Ùkh; iFkesa?kwe jgkgSA ;fn m lsV~
;w
c
d sÅ ijhfljsrd jLlhd hy EckbZ vkSj jLlhd sbl Hkkx rFkkjLlhd sÅ /okZ/kj Hkkx d schp d ks.k
 gSrksm }kjk ,d pDd j y xkusesao`Ùk iwjk d jusesafy ;sx;sle; d k eku gksxk

(A) 2  g sin 
11.

(B) 2  g cos 
m
(C) 2  g M sin 

m
M
m
(D) 2  g M
A uniform thin rod of mass ‘m’ and length L is held horizontally by two vertical strings attached to the two ends. One
of the string is cut. Find the angular acceleration soon after it is cut :
,d m nz
O;eku rFkkL y EckbZd hNM+d ksnksy Ecor~Mksjh;ks
a}kjk{kS
frt y Vd k;kx;kgSMksjhfd ukjks
alsca
/khgS
A ;fn ,d Mksjhd ks
rksM +fn;k t k;srksMksjh VwVusd srqjUr ckn d ks.kh; Roj.k gksxk:
(A)
12.
g
2L
(B)
g
L
(C)
3g
2L
(D)
2g
L
A uniform cylinder of mass m can rotate freely about its own axis which is horizontal. A particle of mass m 0
hangs from the end of a light string wound round the cylinder which does not slip over it. When the system is
allowed to move, the acceleration of the descending mass m 0 will be:
m nz
O;eku d k ,d le: i csy u mld h Loa; v{k t ks{kSfrt gSd slkis{k ?kw.kZu d sfy , LorU=k gSA m o nzO;eku d k ,d d .k ,d
Mks
jhd sfljslsyVd kgq
v kgSrFkkMks
jhcsy u ij fyiVhgq
bZgSt ksbl ij fQ lyrhughagSA t c fud k; d ksxfr d sfy, NksM+
kt krk
gS]nzO;eku m 0 d k uhpsd h vksj Roj.k gksxk &
(A)
2mo g
m  2m o
(B)
mo g
m  mo
(C)
2m o g
m  mo
(D)
mog
2m  mo
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 5
13.
In the figure shown the initial velocity of boat (30 kg) + person (15 kg )
is 2 m/s. Find velocity v of person with respect to boat so that velocity of
boat will be 1 m/s towards right (Neglect friction between boat and water)
fp=kkuq
l kj "uko + euq
";" d kiz
kjfEHkd os
x 2 eh0@lS
0 gS
A euq
"; d kos
x v uko d slkis
{k
Kkr d jksft llsuko d kos
x 1 eh0@ls
0 nk;havks
j gkst k;s¼uko vkS
j ikuhd schp ?k"kZ
.k
ux.; gS½
nkW
;hvkS
j 3 m/s
ck¡
;hvkS
j 3 m/s
nk¡
;hvkS
j 4 m/s
ck¡
;hvkS
j 4 m/s
(A) 3 m/s towards right
(B) 3 m/s towards left
(C) 4 m/s towards right
(D) 4 m/s towards left
14.
The spacecraft of mass M moving with a velocity v in free space explodes and breaks up into two pieces. If after
explosion a piece of mass m comes to rest, the other piece of spacecraft will have velocity.
M nz
O;eku d kvUrfj{k;ku eq
Dr {ks=kesav os
x lsxfr'khy gSrFkkfoLQ ks
V d sd kj.knksHkkxksaes
aVwV t krkgSA ;fn foLQ ksV d si'pkr~
m nz
O;eku d k ,d Vqd M+k fojkekoLFkk esavk t krk gS]vUrfj{k;ku d svU; Vqd M+sd k osx gksxk &
(A)
15.
ls
ls
ls
ls
Mv
M  m
(B)
Mv
M  m
(C) mv / (M–m)
(D)
mv
M  m
A projectile is launched at an angle  with the horizontal from point A, and finally falls at point B. A and B are
on a horizontal line. During the course of the motion from point A to point B, for the projectile :
,d iz{ksI; fcUnqA ls{kSfrt d slkFk d ks.k ij NksM +k t krk gS]var esa;g /kjkry d sfd lh fcUnqB ij igq¡p rk gSA A o B ,d gh
{ksfrt js[kk ij fLFkr gSaA fcUnqA lsB rd xfr d snkSjku iz{ksI; d sfy ;s:

A
B
(A) magnitude of normal acceleration first increases then decreases.
(B) magnitude of tangential acceleration first increases then decreases.
(C) radius of curvature first increases then decreases.
(D) external force acting on it first increases then decreases.
(A) vfHky Ecor~¼vfHkd s
Unzh;½ Roj.kd kifjek.kigy sc<+rkgSfQ j ?kVrkgS
(B) Li'kZ
js[kh; Roj.k d k ifjek.k igy sc<+rk gSfQ j ?kVrk gS
(C) oØ rk f=kT;k igy sc<+
rh gSvkSj fQ j ?kVrh gSA
(D) vkjks
fir cká cy igy sc<+rk gSvkSj fQ j ?kVrk gSA
(SPACE FOR ROUGH WORK)
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 6
PART-II (CHEMISTRY)
Straight Objective Type
This section contains ( 16-25) questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out of
which ONLY ONE is correct.
lh/ksoLrqfu"B izd kj
bl [k.M esa(16-25) cgq& fod Yihiz'u gSaA izR;sd iz'u d s4 fod Yi (A), (B), (C) rFkk(D) gSa]ft uesalsfl Q Z,d l gh
gSA
16.
7.5 ml of a gaseous hydrocarbon was exploded with 36 ml of oxygen. The volume of gases on cooling was found
to be 28.5 ml, 15 ml of which was absorbed by KOH and the rest was absorbed in a solution of alkaline pyrogallol. If all volumes are measured under same conditions, the formula of hydrocarbon is
,d xSl h; gkbMªksd kcZu d s7.5 ml d ksvkWDlht u d s36 ml d slkFkfoLQ ksfVr fd ;kx;kA B.Mkd jusij xSl d kvk;ru 28.5 ml
ik;kx;k]ft les
als15 ml d ksKOH d s}kjkvo'kks
f"kr fd ;kx;krFkkcpsgq
, vk;ru d ks{kkjh; ik;jks
xyS ks
y d sfoy;u es
avo'kkfs"kr
fd ;k x;kA ;fn lHkh vk;ru leku ifjfLFkfr ij ekisx;srksgkbMªksd kcZu d k lw=k gS\
(A) C3H4
17.
18.
(B) C2H4
(C) C2H6
(D) C3H6
The correct set of four quantum numbers for the valence electron of Rubidium (Z = 37) is :
: fcfM;e (Z = 37) d sla;kst h by sDVªkWu d sfy , pkj Dok.Ve la[;k d k lgh leqPp; crkvks
(A) n = 5,  = 0, m = 0, s = +
1
2
(B) n = 5,  = 1, m = 0, s = +
1
2
(C) n = 5,  = 1, m = 1, s = +
1
2
(D) n = 6,  = 0, m = 0, s = +
1
2
Fluorine has the highest electronegativity among the ns2 np5 group on the Pauling scale, but the electron affinity of
fluorine is less than that of chlorine because :
(A) the atomic number of fluorine is less than that of chlorine.
(B) fluorine being the first member of the family behaves in an unusual manner.
(C) chlorine can accommodate an electron better than fluorine by utilising its vacant 3d–orbital.
(D) small size, high electron density and an increased electron repulsion makes addition of an electron to fluorine
less favourable than that in the case of chlorine in isolated stage.
ikWfy x ekiØ e d svuql kj ns2 np5 oxZesa¶Ykksjhu lclsT;knkfo|qr_ .khgSaA y sfd u ¶Ykksjhu d hby sDVªkWu ca/kqrk]Dy ksjhu lsd e
gksrh gSa]D;ksafd %
(A) ¶y ks
jhu d k ijek.kqØ ekad Dy ksjhu lsd e gksrk gSaA
(B) ¶y ks
jhu oxZd k igy k lnL; gSa] blfy ;s;svy x O;ogkj d jrk gSaA
(C) Dy ks
jhu fjDr 3d–d {kd d k mi;ksx ¶y ksjhu lsvPNh rjg d jd s,d by sDVªkWu j[k ld rk gSaA
(D) Nks
Vkvkd kj mPp by sDVªkWu ?kuRo vkSj by sDVªkWu çfrd "kZ.kesao`f) d sd kj.kfoy fxr voLFkkesaDy ksjhu d hrqy ukes¶y ksjhu
esa,d e– t ksM +uk d e vuqd qy gksrk gSA
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 7
19.
S1 : Always cyclic part is main chain and acyclic is substituent in alicyclic molecules.
S1 : ,fy lkbfDy d v.kqes
ages'kk pØ h; Hkkx eq[; J`a[ky k gksrk gSrFkk vpØ h; Hkkx izfrLFkkihA
S2 : Correct IUPAC name of the following is 3-Bromo-2-Chlorohepta-2,4-diene.
S2 : fuEu d klghIUPAC uke 3-cz
ks
eks-2-Dy ksjks
gs
IVk-2,4-MkbZbZu
S3 : DU of the following compounds is 6.
S3 : fuEu ;kS
fxd d k DU = 6 gSA
S4 : Di, tri., tetra of complex radical are considered for alphabetization.
S4 : la
d qy ewy d d k MkbZ]VªkbZ]VsVªk vxzst h o.kZeky k esalfEefy r fd ;k t krk gSA
(A) F T T F
(B) F T F T
(C) F F T T
20.
(D) T T F F
A 5.2 molal aqueous solution of methyl alcohol (CH3OH), is supplied. What is the mole fraction of methyl alcohol in
the solution ?
esfFky ,sYd ksgkWy ]CH3OH d k,d 5.2 eksy y t y h; foy ;u fn;k t krk gSA bl foy ;u esaesfFky ,sYd ksgkWy d keksy izHkka'k D;k
gS\
(A) 0.100
21.
22.
(B) 0.190
(C) 0.086
(D) 0.050
2K + 2 + 22 HNO3  2HO3 + 2KO3 + 22NO2 + 10H2O
If 3 moles of K & 2 moles 2 are reacted with excess of HNO3. Volume of NO2 gas evolved at NTP is
;fn K d s3 eksy rFkk 2 d s2 eksy HNO3 d svkf/kD; lsfØ ;k d jrsgSA ekud rki o nkc ij NO2 d k izkIr vk;ru
(A) 739.2 Lt
(B) 1075.2 Lt
(C) 44.8 Lt
(D) 67.2 Lt
gSµ
Identify the incorrect statement
(A) Formal charge do not indicate real charge separation with in the molecule.
(B) A pair of +1 and –1 formal charges on the adjacent atoms is considered as coordinate bond in lewis dot
structures.
(C) The lowest energy lewis dot structure is the one with minimum formal charge on the atoms.
(D) Formal charge is the factor based upon electronegativity of bonded atom.
v l R; d Fku d ksigpkfu;sA
(A) ,d v.kqes
avkS
ipkfjd vkos'k(formal charge) okLrfod vkos'ki`
FkDd j.kd ksughn'kkZrkA
(B) ys
fol fcUnqla
jpukesafud VorhZ(adjacent) ijek.kqij +1 rFkk– 1 vkSipkfjd vkos
'kd ksmilgla;ks
t d ca
/kd s: i es
aekurs
gS
Aa
(C) U;w
ure Å t kZoky h y sfol fcUnqlajpuk esaijek.kqv ksaij U;wure vkSipkfjd vkos'k gksrk gSA
(D) vkS
ipkfjd vkos'k,d ,sl kd kjd gSt kscfU/kr ijek.kqv ksad hfo|qr _ .krkij vk/kkfjr gSA
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 8
23.
24.
Decreasing –I effect of given groups is :
fn;sx;slewgksd s–I izHkko d k ?kVrk gqv k Ø e gSA
(i) CN
(ii) NO2
(A) iii > ii > i > iv
(B) ii > iii > iv > i
(iii) NH2
(C) iii > ii > iv > i
(iv) F
(D) ii > i > iv > iii
Which of the following compound will not give positive iodoform test.
fuEu esalsd kSulk;kSfxd /kukRed vkW;ksM ksQ kWeZijh{k.kughansrkgSA
(A)
25.
(B)
(C)
(D) CH3 – CHO
(C)
(D)
The most stable anion is :
lclsvf/kd LFkk;h ,uk;u ¼_ .kk;u½ gS%
(A)
(B)
PART - III (BIOLOGY)
Straight Objective Type
This section contains ( 26-40) questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out of
which ONLY ONE is correct.
lh/ksoLrqfu"B izd kj
bl [k.M esa(26-40) cgq& fod Yihiz'u gSaA izR;sd iz'u d s4 fod Yi (A), (B), (C) rFkk(D) gSa]ft uesalsfl Q Z,d l gh
gSA
26.
On stimulation, the parasympathetic nerve fibres secrete a chemical called
(A) acetylecholine
(B) Lysin
(C) ADH
(D) vasopressin
mRizsj.k fey usij ijkuqd Eih rfU=kd k rU=k }kjk ,d jlk;u d k lzo.k fd ;k t krk gSft lsd gk t krk gS
(A) ,lhVkbZ
y d ksfyu
(B) ykbflu
(C) ADH
(D) oklki
sfszlu
27.
Which proteolytic enzyme induces lysis of fibrin during fibrinolysis ?
(A) fibrin
(B) plasmin
(C) thrombin
(D) All of these
d kSulkizksVh;ksy kbfVd ,Ut kbe Q kbfczuksy kbfll d snkSjku Q kbfczu d sVqVus¼y kbfll½ d ksizsfjr d jrkgS
(A) Q kbfcz
u
(B) Iy kfTeu
(C) Fkk
zs
fEcu
(D) mijks
Dr lHkh
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 9
28.
29.
30.
Which of the following digestive juices have the maximum pH ?
(A) gastric juice
(B) pancreatic juice
(C) bile
fuEu esalsd kSulsikpd ,Ut kbe d h pH lokZf/kd gS
(D) Saliva
(A) t Bj jl
(C) fiRr
(D) ykj
(C) African man
(D) Peking man
(B) vXuk'k;hjl
The cranial capacity was least among the
(A) Neanderthal man
(B) Java apeman
fuEu esalsfd lesalclsd e d iky h; lkeF;Zrk ik;h t krh gS
(A) fu,UMjFky ekuo
(B) t kok,iekuo
(C) vÝ hd u ekuo
(D) iS
fd ax
Last molars in human being are called
(A) milk teeth
(B) wisdom teeth
(D) none of these
(C) thecodont
ekuo esaik, t kusoky svfUre eksy j nkar d ksD;k d gk t krk gS
(A) nw
/k d snkar
(B) vDd y nk<+
(C) xrZ
nUr
ekuo
(D) bues
alsd ksbZugh
31.
Which of the following organelle is associated with synthesis of lipid and lipid like steroidal hormones?
(A) Mitochondria
(B) Lysosomes
(C) SER
(D) Chloroplast
fuEu esad kSu lk d ksf'kd kax fy fiM o fy fiM d h rjg LVhjkW;My gkWeksZu d sla'y s"k.k lslacaf/kr gS(A) ekbVks
d kW
f.Mª
;k
(B) ykblks
l kEsl
(C) SER
(D) gfjryod
32.
Malpighian tubules are present in
(A) rabbit and are excretory organs
(C) frog and are part of circulatory system
(B) cockroach and are respiratory organs
(D) cockroach and are excretory organs
eSYih?kh;u ufy d k,¡fd lesaik;ht krhgS
(A) [kjxks
'k esarFkk ;smRlt hZvax gksrh gS
(B) d kW
d jksp esarFkk 'olu vax gksrh gS
(C) es
a<+d esarFkk ifjlap j.k rU=k d k ,d Hkkx gksrh gS (D) d kWd jksp esarFkkmRlt hZvax gksrhgS
33.
Universal pigments present in all the algae are
(A) Chl a, Chl b
(B) Chl a, b, c
(C) Chl a, carotenoid
(D) Chl a, b carotenoid
,sl klkoZf=kd o.kZd t kslHkh'kSoky ksaesaik;kt krkgS(A) Dy ks
jksfQ y a, b
(B) Dy ks
jksfQ y a, b, c
(C) Dy ks
jksfQ y a, d SjksfVukW;M
(D) Dy ks
jksfQ y a, b, d SjksfVukW;M
34.
Which hormone is responsible in delaying senesence
(A) GA
(B) ABA
(C) Cytokinin
fuEu esad kSu lk gkWeksZu t h.kZrk d ksfoy Ec d jrk gS(A) GA
(B) ABA
(C) lkbVkd
s kbfuu
(D) Ethylene
(D) bFkkbZ
y hu
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 10
35.
In EMP pathway which occurs in both aerobic and anaerobic cell, non enzymatic step is
(A) Glucose  glucose 6 phosphate
(B) Fructose 1.6 diphosphate  3 PGA
(C) 3 PGAL  1,3di PGAL
(D) PEP  PA
EMP ikFkost ksvkW
Dlhd kjho
vukWDlhd kjhnksuksaizd kj d h d ksf'kd kvksaesaik;k t krkgS]esa,Ut kbe jfgr in gS(A) Xy w
d kst  Xy wd kst 6 Q kWLQ sV
(B) Ý DVks
t 1.6 MkbQ kWLQ sV  3 PGA
(C) 3 PGAL  1,3di PGAL
36.
(D) PEP  PA
In chromosome when centromere is subterminal in position, it is said to be
(A) Metacentric
(B) Acrocentric
(C) Sub-metacentric
(D) Telocentric
xq.klw=k esat c lSUVªksfe;j d h fLFkfr mifljh; gksrh gSrksblsd grsgSa(A) eS
VklS
fUVª
d
(B) ,Ø ks
lS
fUVª
d
(C) lc&eS
VklS
fUVª
d
37.
(D) Vhyks
lS
fUVª
d
In photosynthetic carbon oxidative (PCO) cycle which organelle is involved releasing of ammonia and CO2?
(A) Chloroplast
(B) Peroxisome
(C) Mitochondria
(D) All of these
izd k'kla'y s"kh vkWDlhd kjh (PCO) pØ esad kSulk d ksf'kd kax veksfu;ko CO2 eqDr d jusd sfy ;smÙkjnk;hgS?
(A) gfjryod
(B) ijvkW
Dlhlks
e
(C) ekbVks
d kW
f.Mª
;k
(D) lHkh
38.
39.
40.
Peristomes for spore dispersal are present in
(A) Riccia
(B) Marchantia
(C) Equisetum
(D) Funaria
cht k.kqv ksad sizd h.kZu gsrqiSfjLVkse fd lesaik;kt krkgS(A) fjfDl;k
(B) ekd s
fU'k;k
Z
(C) bDohlhVe
(D) ¶;w
usfj;k
Microsporophyll of Cycas has the same nature as
(A) Sepal
(B) Stamen
(C) Petal
(D) Carpel
lkbd l d sy ?kqcht k.kqd h izÑ fr fuEu esafd ld sleku gS\
(A) cká ny
(B) iq
ds
a
lj
(C) ny
(D) v.Mi
When filament is attached to the back of the anther and the anther can freely swing is called
(A) Dorsifixed
(B) Basifixed
(C) Adnate
(D) Versatile
;fn ijkxd ks"k d si`"B Hkkx lsiqrUrqbl izd kj lay Xu gksfd ijkxd ks"k eqDr: i lsiqrUrqij nksy u d j ld sog iqad sl j
d gy krkgS
(A) i`
"By Xu
(B) vk/kkj y Xu
(C) la
y Xu
(D) eq
Drnksy h
(SPACE FOR ROUGH WORK)
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 11
PART-IV (MENTAL ABILITY)
Straight Objective Type
This section contains ( 41-50) questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out of
which ONLY ONE is correct.
lh/ksoLrqfu"B izd kj
bl [k.M esa(41-50) cgq& fod Yihiz'u gSaA izR;sd iz'u d s4 fod Yi (A), (B), (C) rFkk(D) gSa]ft uesalsfl Q Z,d l gh
gSA
Direction (41 to 43) : Find the missing terms –
funsZ'k ¼41 l s43½’v K kr in K kr d jksA
41.
42.
94, 166, 258, ?, 4912
(A) 3610
(B) 1644
(C) 1026
(D) 516
AD
17
BP
258
GN
?
(A) 203, 181
CF
HJ
LM
(B) 179, 239
(C) 18, 210
(D) 9, 29
(B) 64
(C) 4
(D) 16
39
108
?
43.
(A) 38
44.
If AJAY is written as 1117, then in same code NAMA would be written as :
;fn AJAY d ks1117 fy [kk t k;srks]mlh d ksM +esa NAMA d ksD;k fy [kk t k;sxk \
(A) 5114
(B) 5411
(C) 5141
(D) 4511
45.
Arrange the following group such that when arranged in a specific order, meaningful word is formed.
fuEu v{kjksd slewg d ksbl izd kj O;ofLFkr d jksrkfd buls,d vFkZiw.kZ'kCn cu t k;s\
V A H Y
1 2 3
4
(A) 2, 3, 4, 5, 1
46.
E
5
(B) 3, 2, 5, 1, 4
(C) 3, 5, 2, 1, 4
(D) 1, 5, 2, 3, 4
If + is x,– is +, x is  and  is –, then what is the value of given equation
;fn + d k ery c ×] – d k ery c +, × d k ery c ÷ rFkk ÷ d k ery c – ekusrksbl
lwp uk d svk/kkj ij fuEu lehd j.k d k
eku gks
xkA
21 ÷ 8 + 2 – 12 × 3 = ?
(A) 14
(B) 9
47.
(C) 13.5
What is the product of all the numbers in the dial of a telephone ?
Vsfy Q ksu d sMk;y ij fLFkr vad ksad k xq.kuQ y D;k gksxk?
(A) 1,58,480
(B) 1,59,450
(C) 1,59,480
(D) 11
(D) None of these
(SPACE FOR ROUGH WORK)
RESONANCE
STaRT2015 XI_(BIO) - 12
Directions (48) : In the following questions, there is a diagram marked (X), with one or more dots placed in it. The
diagram is followed by four other figures, marked (A), (B), (C) and (D) only one of which is such as to make
possible the placement of the alternative in each case.
funsZ'k (48) : fuEufy f[kr iz'u esa] ,d v kd `fr (X) nh xbZgSft l l s,d ;k v f/kd fcUnqy xsgq, gSA ;g v kd `fr v U; pkj v kd `fr;ksa
d k v uql j.k d jrh gSft ud ksfd (A), (B), (C) rFkk (D) esafpfUgr fd ;k x;k gSA buesal sfl Q Z,d v kd `fr esabu fcUnqv ksa d s
l gh fpfUgr d h l EHkkouk gSA ml fod Yi d kspqfu;s?
48.
(X)
(A)
(B)
(C)
(D)
Directions : (49) Figures 1 and 2 are related in a particular manner. Establish the same relationship between figures 3 and
4 by choosing a figure from amongst the four alternatives, which would replace the question mark in figure (4).
funsZ'k : (49) iz'u v kd `fr d sizFke Hkkx esafn;sx;snwl jsfp=k d k ft l izd kj igy sfp=k l sl EcU/k gSogh l EcU/k nwl jsHkkx d srhl js
fp=k d k mÙkj v kd `fr esafn;sx;spkj fod Yiksaesal sfd l l sl EcU/k gksxkA
¼iz'u v kÑ fr½
Problem Figures
........
......
............
......
:
... ...
...............
49.
Answer Figures
::
............
..........
.................
..
....
..
. ...
...
... ....
: ?
¼mÙkj v kÑ fr½
................
.....
..
...... ....
.....................
...
...........
..
.....
...
.. ..
..................
(A)
(B)
(C)
(D)
Directions : (50) Out of the four figures (A), (B), (C) and (D), given in each problem, three are similar in a certain way.
However, one figure is not like the other four. Choose the figure which is different from the rest.
funsZ'k : (50) uhpsfn;sx;s4 fp=kksa(A), (B), (C) rFkk (D) esarhu fd l h rjhd sl sl eku gSv kSj ,d mu rhuksal sv y x gSv FkkZr~
l ewg esal srhu fp=k l eku izÑ fr ij v k/kkfjr gSml fp=k d kscrkb, ft l d h izd `fr ckfd rhuksal sv y x gSaA
50.
(A)
(B)
(C)
(D)
ANSWER KEY
CLASS : XI
|
STREAM : SCIENCE-BIOLOGY
(SPACE FOR ROUGH WORK)
1.
6.
11.
(C)
(A)
(C)
2.
7.
12.
(C)
(B)
(A)
3.
8.
13.
(A)
(C)
(A)
4.
9.
14.
(B)
(C)
(A)
5.
10.
15.
(C)
(D)
(A)
16.
21.
(B)
(A)
17.
22.
(A)
(D)
18.
23.
(D)
(D)
19.
24.
(B)
(C)
20.
25.
(C)
(A)
26.
31.
36.
(A)
(C)
(B)
27.
32.
37.
(B)
(D)
(C)
28.
33.
38.
(C)
(C)
(D)
29.
34.
39.
(C)
(C)
(B)
30.
35.
40.
(B)
(C)
(D)
41.
46.
(A)
(B)
42.
47.
(A)
(D)
43.
48.
(C)
(A)
44.
49.
(C)
(B)
45.
50.
(C)
(B)
RESONANCE
STaRT2015 XI_(BIO) - 13