MATH 245: Differential Equations and Linear Algebra SAMPLE MIDTERM I Fatl'2009 NAME , hNSv/ER ReY NO{E: There a.re 5 problems on this midterm (totat of 6 pages). Use of calculators to ctreck your work is permitted; however, in order to receive full credit for any problem, you must show work leading to your answer. You have 50 minutes to complete this test. Problem Possible points 1 20 2 20 3 20 4 20 5 20 Total 100 Score I MATH 245 - MIDTERM Page 2 Problem 1. (20pts) At noon a ca,r starts from rest at point A and proceeds at constant acceleration along a straight road toward point B. If the car reaches B at 12:50 PM. with a velocity of 60 mph, what is the distance from AtoB. L-t ( d.,tt"^." +,--"lUt ) X(t) = Pos,l6^ I M;\p4 cI Giv.rn X(ta) - O Xt(rz1 =- o tr ttzf) = 60 tt' = F\I (")rt6A,^L r x(rz{1 Xt= of t ga{ J V" = a (t- lr) X =- Itt = a- - s,uc-e I a tt- t'\" t d" z-'- e\'\\-cA a (rz\*- o ' t 6o = ^- ( E) x!zl) -t : c') 1'(rz)--o. &c 72 *ip,S 8-)(E)25 r;lL> MATH 245 _ MIDTERM I Problem 2. (20pts) A pitcher of buttermilk initally at 25C is to be cooled by setting it on the front porch, where the temperature is 0'C. Suppose that the temperature of the buttermilk has dropped to 15"C after 20 min. When will it be at 5'C? -f: bo"p"*"t^r" \ , t' Lw',r - dt,: -ktfT-o)- -kT dta lr- [rtt.*"ltL-.) ln -LHg =) l^ T: -Lt )r ... e, ) [: C e-bt_ T(") = 25 C: Z€ fzo)= ti 15 = zS e- ?sV ;\= E Y-53 D;t *.-L -tt";5 g'l t e,+t* S=ZS1* *=s r-3* u--/ ^zntE1") .,)rZ = Lf I L* = JJ*(s) = ry -!^ 5 JnS - 'lq3 L = 2-/)J"5 €n^irr,(rr) MATH 245,- MIDTEF.M Problem 3. (20pts) I Solve the following rg' + 3u J'o F")u ' ,, u(2) :, L^t f UIAt )' -- 2x7 i rys / dx-= +t I v = t + Z-+v il 4r Pace 4 initial value problem. - 2x1, = , (3 J* Le = <u'' = xo Z=+'-C ) ,l--f II4$TH245-MIPTERJvII ,, . P+ee5 (20pts) Appty Euler's method with a step size h : 0-1 to approximate the solution to the following initial value problem on the interval [0,.5]. Problem 4. A':U-r-1, Xn*, tl= )tt+( 0-0 t.o 0-I t_o ' g(0):1 Tr^, '), t/ n .lt- J^ 0- z,1"1 L) I g^ ln 9_ , 117 1557 "881+7 (-a) - 7-o4 {-o t o-t (t- e-r -1) .?1 +o-l(^11 *0-Z-1-):'1'1 -"0z-1 ='1L"1/ 7.0+ o-t( t 0-t (-ttT- -3- L)= -161 ,1ts1 * o.t (.1ts7--+-L) .1[7 , -1js7" = e, 691+1 vvrrr o"t (-TG+() - 033 I - .13fT MAIH 245 - MIDTERM I Pase 6 Problem 5. (20pts) Find the general solution to the following difierential equation. u"'+4u':5e2' *3r- 1 -c =o)lzi (ft 't) : o Jn^**U^r^", g-\,*'. 7^, @ ZA ,sM2*d Yeo4c< l- ftl^+'.-l-. +& V\ t( Yu JT Js : +A? + Yfrf rr t, At* * Bxor Cx LB + + +(A;" =) 'tc: => -( * z6x, c) : t;. t3x* ) /- t/,lr l6A=5 gh=3 G-- '= ZAt" * Zf) Xr-C = ,,{ "' Yfr u :, B = yg/r C = -t/rr 9nl,n Ju, = cr + tzL'?u t Qstalx r Et-r ?i- 17
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