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Some Homework Answers:
Section 3.5
Exercise 1:
Exercise 4: db/dt =
Section 4.1
Activity 4.1:
a) D is about 3.75 miles
b) D is about 3.875 miles
c) By some educated guessing and checking:
d) s(2) = s(0) = 4, this represents the EXACT distance traveled.
Activity 4.3:
a)
b)
c)
d)
Total distance traveled 2, total change in position 0.
The object is increasing for t in the intervals [0 , 1] and [4 , 8].
5 meters
the graph of s(t)
Exercise 1:
a) 12 miles at 1 hour
b) 2 miles north so one hour total change
c) 42 miles total but ending at starting point
Exercise 2:
a) 15.625 sec.
b) 3906.25 maximum height (or distance traveled up)
c)
d)
e) 1616 feet, between 1 and 5 seconds if it went up.
Exercise 3
a)
Exercise 4:
b) Because we multiply rate by day, which represents the sides of each square unit of area under the
curve.
c) LHS = 336 pollution units, RHS = 504 pollution units, Average = 470 pollution units