Name ________________________________________ Date ___________________ Class __________________ Chapter 5 Properties and Attributes of Triangles Cumulative Test 8. Where is the image of (−6, 2) reflected across the graph of y = −x? Choose the best answer. HJJG 1. Which of PQ and QR contains P? A PQ only HJJG B QR only D Neither G 8 J 13 JJJG 3. SU bisects ∠RST. If m∠RST = (8x + 15)� and m∠RSU = 5x�, what is m∠RST? C 50� B 37.5� D 75� H 112� G 78� J 158� C 16 m2 B 8 m2 D 64 m2 H 6π cm2 G 2.25π cm2 J 36π cm2 C (2.5, 0.5) B (4, 17) D (0.5, 5.5) B −3 D 9 J If the car will not start, then it is out of gas. 11. For which conditional statement (p → q) is its inverse (∼p → ∼q) false? A If a point is a midpoint of a segment, then it divides the segment into two congruent segments. B If Mike does not become an airplane pilot, then he will not learn how to fly a plane. C If you see a zebra, then you must be in a zoo. D If the biggest holiday of the month is Thanksgiving, then the month is November. 12. Which justifies the statement? If ∠1 ≅ ∠2 and ∠2 ≅ ∠3, then ∠1 ≅ ∠3. 7. The midpoint of a segment is (2, −5), and one of the endpoints is (3, 6). Where is the other endpoint? A (1, −16) C 3 H If the day is between Monday and Wednesday, then it is Tuesday. 6. What is the area of a circle whose diameter is 3 centimeters? F 1.5π cm2 A −9 G If Meg lives in Egypt, then she lives in Africa. 5. The perimeter of a square is 8 meters. What is its area? A 4 m2 J (−2, 6) F If a fruit has seeds inside, then it is an orange. 4. If the complement of an angle measures 22�, what is the measure of its supplement? F 68� G (−2, −6) 10. For which conditional statement (p → q) is its converse (q → p) false? H 9 A 25� H (2, 6) 9. What is the next term in the sequence? 729, −243, 81, −27, . . . C Both 2. K is between J and L. JK = 3x − 5, and KL = 2x + 1. If JL = 16, what is JK? F 7 F (2, −6) F Transitive Property of Congruence G Substitution H Symmetric Property of Congruence J Reflexive Property of Congruence Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 101 Holt McDougal Geometry Name ________________________________________ Date ___________________ Class __________________ Chapter 5 Properties and Attributes of Triangles Cumulative Test continued 13. Which is the most logical conclusion by the Law of Syllogism? If one of the angles of a triangle is obtuse, then the other two angles are acute. If a triangle is an obtuse triangle, then one of its angles is obtuse. A triangle has two acute angles. 16. Complete the statement. Two lines are parallel if the same-side interior angles are _______ angles. F complementary G supplementary H congruent J corresponding A The triangle is obtuse. 17. Which angles are alternate interior angles? B The other angle in the triangle is obtuse. C The triangle is not obtuse. D None of these are valid conclusions. 14. Which is a true biconditional statement? F Four points are coplanar if and only if they are noncollinear. G Two angles are complementary if and only if the sum of their measures is 90�. J A figure has an endpoint if and only if the figure is a segment. Reasons 1. Given 2. x + 5 = 0 2. Add. Prop. of = 3. 2(x � 5) = 0 3. B ∠1 and ∠5 D ∠3 and ∠7 Statements 15. Complete the proof. Given: x = −5 Prove: 2(x + 5) = 0 Proof: 1. x = −5 C ∠3 and ∠4 18. Complete the proof. Given: k � � Prove: ∠1 and ∠6 are supplementary. Proof: H A side of a triangle is a hypotenuse if and only if it is the longest side of a triangle. Statements A ∠1 and ∠4 ? A Multiplication Property of Equality B Transitive Property of Equality Reasons 1. k � � 1. Given 2. ∠1 ≅ ∠5 2. 3. m∠1 = m∠5 3. Def. of ≅ 4. ∠5 and ∠6 are supplementary. 4. Linear Pair Thm. 5. m∠5 + m∠6 = 180� 5. Def. of supp. � 6. m∠1 + m∠6 = 180� 6. Subst. 7. ∠1 and ∠6 are supplementary. 7. Def. of supp. � ? F Alternate Exterior Angle Theorem C Subtraction Property of Equality G Alternate Interior Angle Theorem D Reflexive Property of Equality H Same-Side Interior Angle Theorem J Corresponding Angle Theorem Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 102 Holt McDougal Geometry Name ________________________________________ Date ___________________ Class __________________ Chapter 5 Properties and Attributes of Triangles Cumulative Test continued 19. A line passes through the points (5, −8) and (6, 2). What is the slope? 1 A −10 C 10 6 B − D 10 11 24. Three sides of a triangle are shown. Which triangle is acute? F 3, 4, 5 H 4, 5, 6 G 5, 12, 13 J 4, 7, 10 25. Find y. 20. Complete the paragraph proof. Given: ∠2 ≅ ∠5 Prove: ∠1 ≅ ∠4 F m∠2 + m∠3 = 180� G m∠4 + m∠7 = 180� J m∠6 + m∠7 = 180� 21. Find all values for x. B 0 < x < 11 D x > −3 B 82� D 134� F (–10, 1) H (–0.4, 1) G (–10, 5) J (–0.4, 0.2) 27. Complete the statement. If ∠U ≅ ∠P, ∠S ≅ ∠Q, ∠T ≅ ∠R, UT ≅ PR, US ≅ PQ, and ST ≅ QR , then �PQR ≅ _______. H m∠4 + m∠5 = 180� C 4 < x < 11 C 128� 26. Point R in ∆QRS has coordinates (–2, 1). ∆QRS underwent a dilation with scale factor 5 centered at the origin. What are the coordinates of the image of R? Proof: It is given that ∠2 ≅ ∠5. By the Linear Pair Theorem, m∠2 + m∠1 = 180� and _______. By the Congruent Supplements Theorem, ∠1 ≅ ∠4. A x < 11 A 36� A �RQP C �TUS B �STU D �UST 28. What is the least information needed to prove the triangles congruent by SSS? 22. What is the slope of the line 3 perpendicular to y = − x + 9? 2 3 2 F H − 2 3 3 2 J − G 2 3 F ∠M ≅ ∠Q H LN ≅ PR and MN ≅ QR G LN ≅ PR 23. What is the equation of the line that passes through (0, −2) and (4, 6)? A y = 2x − 2 C y=x−2 1 B y = x −2 D y = −2x + 2 2 J LN ≅ QR and MN ≅ PR Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 103 Holt McDougal Geometry Name ________________________________________ Date ___________________ Class __________________ Chapter 5 Properties and Attributes of Triangles Cumulative Test continued JJJG 33. QS bisects ∠PQR. What is QR? 29. Why is �PQS ≅ �RQS? A SAS B ASA A 65 B 50 C AAA D HL 30. Complete the proof. Given: �ABC is equilateral, and BD is an altitude. C 40 D 15 34. XL, XM, and XN are perpendicular bisectors. The perimeter of ΔFGH is 54. What is FG? Prove: BD bisects AC. F 36 G 27 Proof: 35. SV and RT are medians. What is JS − JT? By definition of equilateral, AB ≅ CB, and by the Reflexive Property of Congruence, BD ≅ BD . Since BD is an altitude, ∠BDA and ∠BDC are right angles. So �BDA and �BDC are right � and �BDA ≅ �BDC by HL. Therefore, AD ≅ CD by ? . By definition of bisector, BD bisects AC. F HL H ASA G SAS J CPCTC G right J equiangular C 2y − B 2x − 3y D 1 x 2 1 x − 2y 2 37. Two sides of a 30�-60�-90� triangle are 9 and 18. What is the length of the third side? A 9 2 C 18 2 B 9 3 D 18 3 38. PQ is a midsegment. What is PQ? 32. One of the base angles of an isosceles triangle is 40�. Which is the triangle classification according to its angles? H obtuse A x−y 36. In ΔJKL, JK > JL > KL. Which is the correct order of the angles from smallest measure to largest? F ∠J , ∠L , ∠K H ∠K, ∠L, ∠J G ∠J, ∠K, ∠L J ∠L, ∠K, ∠J 31. Given: TUVW is a rectangle. Prove: TV = UW For an analytic proof, which is the best placement of the rectangle in the coordinate plane? A T(0, 0), U(a, b), V(0, c), W(−a, c − b) B T(0, 0), U(a, 0), V(a, b), W(0, b) C T(a, b), U(a + b, 0), V(a + b, c), W(0, c) D T(0, 0), U(a, 0), V(a, a), W(0, a) F acute H 18 J 9 F 16 G 17 H 32 J 34 Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 104 Holt McDougal Geometry 11. False Performance Assessment 12. KM, KL, LM 1. Perpendicular Bisector Theorem 13. 6 < x < 10 2. B is the midpoint of AC since BE is a midsegment. 14. 24 3. 90°; Def. of perpendicular bisector 15. The lengths do not form a Pythagorean triple because the hypotenuse ( 34 ) is not a whole number. 4. ∠BDC, ∠DBE, ∠EDB, ∠ABE, ∠A 5. AE < AB; ∠AEB = 90°, ∠ABE = 45°, and, if two angles in a triangle are not congruent, then the longer side is opposite the larger angle. 16. obtuse 17. 6 18. 10 6. The triangles are not congruent. The reasoning in the answer for question 5 can be used to show that AB > AE and AB > EB and likewise that DC > BC. But since AB = BC, it follows that DC is longer than each side of �ABE. Therefore �ABE cannot be congruent to �CDB. Chapter Test Form C: Free Response 1. 56° 2. y − 3 = 2(x − 4) 3. 72° or 8° ⎛ 1⎞ 4. ⎜ 4, ⎟ ⎝ 2⎠ 5. m∠VGT = 108°; the distance from G to UV = 19.5 7. a. 14 b. 14 2, or about 19.8 c. 28 d. 28 2, or about 39.6 6. (1, 1) 7. (4, 4) Cumulative Test 8. 4 or −3 9. 132° 10. Let �ABC be an obtuse triangle with ∠A as its obtuse angle. Suppose �ABC has a right angle, say ∠B. Since m∠A > 90° and m∠B = 90°, and since it must be true that m∠C > 0°, it follows that m∠A + m∠B + m∠C > 180°. This last inequality contradicts the Triangle Sum Theorem. The assumption that m∠B = 90° is therefore false. Hence the obtuse triangle cannot have a right angle. 11. 5 < s < 19 12. ∠M, ∠L, ∠K 13. 3 < x < 10 14. 9, 12, and 15 15. True 16. 2 < x < 4 3 17. 24 cm 2 2 18. 288 3 in or about 498.8 in 1. C 20. H 2. F 21. C 3. D 22. G 4. H 23. A 5. A 24. H 6. G 25. B 7. A 26. G 8. J 27. D 9. D 28. H 10. G 29. B 11. C 30. J 12. F 31. B 13. D 32. H 14. G 33. A 15. A 34. H 16. G 35. C 17. D 36. G 18. F 37. B 19. D 38. G Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 254 Holt McDougal Geometry
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