MATHS
1.Simplify using Identities
(i) (a2– b2)2
(ii) (2x + 5)2 – (2x – 5)2
(iii) (7m – 8n)2+ (7m + 8n)2
(iv) (4m + 5n)2 + (5m + 4n)2
(vi) (ab + bc)2– 2ab²c
(vii) (m2 – n2m)2 + 2m3n2
(viii) 5x-2(2x-7)= 2(3x – 1)=7/2
(ix) 113 × 87
(x) 207 x 193
2 . Show that
(i)
(ii)
(iii)
(3x + 7)2 – 84x = (3x – 7)2
(9p – 5q)2+ 180pq = (9p + 5q)2
(a – b) (a + b) + (b – c) (b + c) + (c – a) (c + a) = 0
3. Factorise:
2
i) 4x – 8x + 4
2
2
ii) 49 - x – y + 2xy
iii)
iv) 15xy – 6x + 5y -2.
v) x2 – 7x +10
4. Plot the points (0, 1), (2, 2) and (4, 3) on the graph. Join these points in
pairs. Do they all lie on the line passing through the origin?
5.A bus is going on a long journey starting at 4:00 hour. The speed of the
bus at different hours is given below :
Draw speed - time graph for the above data.
6. The sides of a triangular plot are in the ratio of 3 : 5 : 7 and its perimeter is 900 m. Find its area.
7. Find area of equilateral triangle of side 4a using Heron.s formula. Using this formula find area of
an equilateral triangle whose perimeter is 540cm.
8. The sides of a quadrilateral are 5cm, 12cm, 15cm and 20cm. The angle between first two sides is
90˚ Find the area of quadrilateral.
9. The perimeter of a rhombus is 240cm and one of its diagonals is 80cm. Find its area using Heron.s
formula.
10. The sides of a triangular field are 600m, 640m and 700m.
(a) Find the cost of fencing at the rate of Rs. 50 per metre leaving doors of 2m on each side
(b) Find cost of leveling the field at Rs. 50 per square metre .
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