MATH 895-4 Fall 2010 Course Schedule f a cu lty of science d epa r tm ent of m athema tic s Week Date Sections from FS2009 1 Sept 7 I.1, I.2, I.3 2 14 I.4, I.5, I.6 3 21 II.1, II.2, II.3 4 28 II.4, II.5, II.6 5 Oct 5 III.1, III.2 6 12 IV.1, IV.2 L ECTURE 26 Part/ References Topic/Sections Combinatorial Structures FS: Part A.1, A.2 Comtet74 Handout #1 (self study) Symbolic methods Combinatorial parameters FS A.III (self-study) Combinatorial Parameters T HE B EST C ARD T RICK Notes/Speaker Lecture 26: The Best Card Trick Contents 7 8 9 Unlabelled structures Labelled structures I Labelled structures II Asst #1 Due Multivariable GFs 19 Analytic 26.1 HowIV.3, toIV.4 Perform theMethods Best CardComplex TrickAnalysis . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 26 IV.5 V.1 26.2 Exercises . . Nov 2 10 11 VI.1 12 A.3/ C Singularity Analysis . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Asymptotic methods Asst #2 Due 1 4 Sophie Introduction to Prob. Mariolys 18 Limit Laws and Comb You areIX.1about to pull off the most amazing card Marni trick... The audience draws 5 cards from the deck and gives them to the volunteer who, in turn, shows you four of the five cards, say: Random Structures 20 IX.2 Discrete Limit Laws Sophie 23 12 13 9 FS: Part B: IV, V, VI Appendix B4 . . . . . . . Stanley 99: Ch. 6 Handout #1 (self-study) IX.3 and Limit Laws FS: Part C (rotating presentations) Combinatorial Mariolys 4♠, K♦, 4♥, 5♣. instances of discrete 25 Continuous Limit Laws Marni After aIX.4 dramatic moment of “reading” the volunteers mind, and the minds of the audience members, Quasi-Powers and was hidden from you, must be the 9♠. The audience you reveal that the fifth card, the one that 30 IX.5 Sophie Gaussian limit laws gasps... How could this be?1 14 Dec 10 Presentations Asst #3 Due How to Perform the Best Card Trick 26.1 You could come up with some story about how the first four cards were shown to you in order to allow you to tune into your volunteers mind, thus allowing you to read the fifth card. Or explain that you are having trouble reading his/her mind so you need the entire audience to concentrate on the fifth card. Of course all this is all just for show. The fact is, your volunteer is actually your accomplice and he/she passed you enough information to determine the final card. There is no element of chance here, your accomplice simply “encoded” theMarni value of the last ofcard in the firstFRASER four UNIVERSITY cards. This begs the question: How did they do this? Dr. MISHNA, Department Mathematics, SIMON Version of: 11-Dec-09 Let’s first describe the standard deck of playing cards. There are four suits: clubs ♣, diamonds ♦, hearts ♥, and spades ♠. Within each suit there are 13 ranks: (A)ce, 2, 3, 4, 5, 6, 7, 8, 9, 10, (J)ack, (Q)ueen, (K)ing. It will be convenient for us to think of Ace = 1, Jack = 11, Queen = 12, and King = 13. In card jargon we are considering “Aces to be low”, by which we mean the Ace is the lowest ranking card. There are 4 · 13 = 52 cards in all. See Figure 1 for some examples. (a) 5 Hearts. of (b) Jack of clubs. (c) Queen of Diamonds. (d) King of Spades. Figure 1: Examples of names of playing cards. 1 See original article by Michael Kleber in Mathematical Intelligencer 24 #1, 2002 Jamie Mulholland, Spring 2011 Math 302 26-1 f a cu lty of science d epa r tm ent of m athema tic s Week Date Sections Part/ References MATH 895-4 Fall 2010 Course Schedule L ECTURE 26 Topic/Sections T HE B EST C ARD T RICK Notes/Speaker FS2009necessary for the trick? Given a collection of five cards from the deck there must be two Why are fivefrom cards of 1the Sept same suit (this is known in mathematics as the pigeonhole principle). Let A and B be two cards of the 7 I.1, I.2, I.3 Symbolic methods Combinatorial same suit. One of these cards will be taken as the fifth card, i.e. the hidden card. The other card will be shown Structures 2 14 I.4, I.5, I.6 Unlabelled structures FS: Partthe A.1, A.2 first, thus communicating suit of the hidden card. All that remains now is to communicate the rank of the Comtet74 3 21 Labelled structures I hidden card.II.1, II.2, II.3 Handout #1 (self study) 4 28 II.4, II.5, II.6 Labelled structures II 7 19 IV.3, IV.4 9 VI.1 12 A.3/ C Introduction to Prob. Mariolys 18 IX.1 Limit Laws and Comb Marni 20 IX.2 Discrete Limit Laws Sophie 23 IX.3 Combinatorial instances of discrete Mariolys 25 IX.4 Continuous Limit Laws Marni 30 IX.5 Quasi-Powers and Gaussian limit laws Sophie Once the suit is known there are 12 possibilities for the rank (since the hidden card is certainly not the one Combinatorial Combinatorial that to you). How can the remainingAsst 3 #1 cards 5 was Oct 5 just III.1,shown III.2 Due be arranged to communicate the rank? Since parameters Parameters FS A.III there are 6 ways to arrange 3 objects we can communicate a number from 1 to 6 with the remaining 3 cards. 6 12 IV.1, IV.2 Multivariable GFs (self-study) This doesn’t seem to be enough information. Complex Analysis Analytic Methods Does it matter which of two A and B, of the same suit, is shown and which is hidden? Yes, it does (to FS:the Part B: IV, V,cards, VI 8 26 Singularity Analysis B4 do the trick IV.5 in V.1 the wayAppendix we describe). Let’s define the distance, dist, between two cards of the same suit using Stanley 99: Ch. 6 Nov 2 Asst #2 Due the9 following diagram:Handout #1 Asymptotic methods 10 11 12 13 (self-study) Random Structures and Limit Laws FS: Part C (rotating presentations) Sophie Figure 2: The distance between card ranks is the number of steps it takes to move from one rank to the next in the 14 Dec 10 Presentations Asst #3 Due clockwise direction. For example, dist(3, 6) = 3, dist(8, J) = 3, dist(Q, 5) = 6, dist(A, 8) = 7. Notice that dist(6, 3) = 10, which is not the same as dist(3, 6) = 3. So the distance function is not symmetric in its arguments. However, we do have dist(a, b) = 13 − dist(b, a), for any two ranks a, b. It follows that for any two ranks a, b (i.e. two cards of the same suit) that either dist(a, b) or dist(b, a) is less than or equal to 6. If dist(a, b) ≤ 6 then we say a is smaller than b. So,Marni back to the two cards A, B.SIMON We FRASER will show the performer the smaller Dr. MISHNA, Department of Mathematics, UNIVERSITY Version of: 11-Dec-09 The larger card (i.e. the hidden card) will be at distance at most 6 from of the two cards and hide the larger. the smaller card and we can use the remaining 3 cards to communicate this distance. All that remains now is to assign numbers 1 through 6 to arrangements of three objects. We will use the playing cards natural ordering (from smallest to largest): A♣ < A♦ < A♥ < A♠ < 2♣ < 2♦ < 2♥ < 2♠ < 3♣ < 3♦ < 3♥ < 3♠ < 4♣ < 4♦ < 4♥ < 4♠ < . . . . . . < 10♣ < 10♦ < 10♥ < 10♠ < J♣ < J♦ < J♥ < J♠ < Q♣ < Q♦ < Q♥ < Q♠ < K♣ < K♦ < K♥ < K♠. That is, cards are first ordered by rank: A, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, and ties are broken using the suit ordering: ♣ < ♦ < ♥ < ♠ (i.e. alphabetic in first letter of name: (C)lub, (D)iamond, (H)eart, (S)pade). Given three cards, say a, b, c, where a < b < c, we can list the six arrangements lexicographically (dictionary order) and assign numbers as follows: abc = 1 acb = 2 bac = 3 bca = 4 cab = 5 cba = 6. Jamie Mulholland, Spring 2011 Math 302 26-2 MATH 895-4 Fall 2010 Course Schedule f a cu lty of science d epa r tm ent of m athema tic s Week Date Sections 1 Sept 7 I.1, I.2, I.3 2 14 I.4, I.5, I.6 Part/ References L ECTURE 26 Topic/Sections T HE B EST C ARD T RICK Notes/Speaker FS2009 For example,from the three cards 4♦, 5♣, K♦, have the following arrangements numbers (since 4♥ < 5♣ < K♦). 3 21 II.1, II.2, II.3 4 28 II.4, II.5, II.6 Combinatorial Structures 4♥ 5♣ K♦ FS: Part A.1, A.2 5♣ Comtet74 K♦ 4♥ Handout #1 (self study) Symbolic methods = 1, structures 4♥ K♦ Unlabelled = 4, 5♠ = 2, K♦ 4♥ 5♣ = 5, Labelled structures I 5♠ 4♥ K♦ = 3, K♦ 5♣ 4♥ = 6. Labelled structures II Since the three cards had distinct ranks we don’t need to look at the suit to break ties, since there will be no Combinatorial Combinatorial 5 toOct 5 III.1, III.2 an example with ties see Exercise 2(c). Asst #1 Due ties break. For parameters Parameters FS A.III 6 we 12 can IV.1, Multivariable GFs the trick. We use the term Accomplice to refer to the one who Now layIV.2out the(self-study) procedure for performing knows all five cards, and Performer for the one attempting to guess the hidden card. 7 19 IV.3, IV.4 Complex Analysis 8 26 Procedure: 9 Nov 2 Accomplice: IV.5 V.1 9 VI.1 18 IX.1 23 IX.3 Analytic Methods FS: Part B: IV, V, VI Appendix B4 Stanley 99: Ch. 6 Handout #1 (self-study) Singularity Analysis Asymptotic methods Asst #2 Due Sophie 10 The audience select five cards at random. Let s1 , s2 , r1 , r2 , r3 be the five cards drawn from the deck, (1) 12 A.3/ C Introduction to Prob. Mariolys where s1 and s2 have the same suit. Limit Laws and Comb Marni 11 Picks two of the same suit: s , s . (Note: there could be more than two cards of the same suit, just pick (2) 2 Random Structures1 20 IX.2 Discrete Limit Laws Sophie any two for s1 and andsLimit 2 .) Laws FS: Part C Combinatorial Mariolys (rotating of discrete 12 Picks one as the hidden card: instances (3) after re-labeling if necessary assume that s1 is smaller than s2 (i.e. presentations) 25 IX.4 Continuous Limit Laws Marni dist(s , s ) ≤ 6). The hidden card will then be s . 1 2 2 Quasi-Powers and 13 Arrange 30 IX.5the remaining 3 cards r , r , r to correspond Sophie to the number dist(s , s ). (4) 1Gaussian 2 limit 3 laws 1 2 14 Dec 10 #3 Due (5) Reveal cards one at a Presentations time. Reveal card s1 first,Asst then reveal the remaining cards in the order found in Step (4). Performer: (1) Determines the hidden card: The first card s1 gives the suit of the hidden card and a place to start counting (namely its rank). Determine the number (between 1 and 6) to which the arrangement of the last 3 cards corresponds and add this to the rank of s1 , thus determining the hidden card s2 . (2) Reveals the hidden card and waits for applause. Dr. Marni MISHNA, Department of Mathematics, SIMON FRASER UNIVERSITY Version of: 11-Dec-09 The Accomplice needs to be able to think fast since they need to arrange the cards rather quickly in order to start revealing them one at a time. The Performer, however, can stall for time by drawing large copies of the cards on the blackboard as they are revealed. This extra time will allow the Performer to work out the number corresponding to the arrangement of the final three cards. Warning: If the trick is performed a few times as outlined above the audience will pick up, rather quickly, that the first card is the same suit as the hidden one. So you may want to mix up the position of the suit card when performing the trick. It has been suggested to play the suit card in position i (mod 4) when performing for the ith time. Jamie Mulholland, Spring 2011 Math 302 26-3 MATH 895-4 Fall 2010 Course Schedule f a cu lty of science d epa r tm ent of m athema tic s Week Date 1 Sept 7 I.1, I.2, I.3 3 21 II.1, II.2, II.3 4 28 II.4, II.5, II.6 5 Oct (a)5 III.1, III.2 6 12 IV.1, IV.2 7 19 IV.3, IV.4 8 26 9 Nov (b)2 26.2 Sections Part/ References from FS2009 Exercises Combinatorial L ECTURE 26 Topic/Sections T HE B EST C ARD T RICK Notes/Speaker Symbolic methods 1. In each scenario Structures below, five cards, which the audience has drawn, are given. Pick a card to hide and find 2 14 I.4, I.5, I.6 Unlabelled structures A.2 an arrangement FS: of Part theA.1, remaining four cards which determines the hidden card. 10 11 Labelled structures I Labelled structures II Combinatorial parameters FS A.III (self-study) Combinatorial Parameters Analytic Methods FS: Part B: IV, V, VI Appendix B4 Stanley 99: Ch. 6 Handout #1 (self-study) Complex Analysis Asst #1 Due Multivariable GFs Singularity Analysis Asymptotic methods Asst #2 Due 9 VI.1 12 A.3/ C Introduction to Prob. Mariolys 18 IX.1 Limit Laws and Comb Marni 20 IX.2 Discrete Limit Laws Sophie 23 IX.3 Combinatorial instances of discrete Mariolys 25 IX.4 Continuous Limit Laws Marni (c) 12 IV.5 V.1 Comtet74 Handout #1 (self study) Random Structures and Limit Laws FS: Part C (rotating presentations) Sophie 2. Your accomplice has presented you with the Quasi-Powers and following arrangements of four cards. Determine the fifth 30 IX.5 Sophie Gaussian limit laws card. You may assume the first card is the suit card. 13 14 Dec 10 Presentations Asst #3 Due (a) (b) Dr. Marni MISHNA, Department of Mathematics, SIMON FRASER UNIVERSITY Version of: 11-Dec-09 (c) Jamie Mulholland, Spring 2011 Math 302 26-4 MATH 895-4 Fall 2010 Course Schedule f a cu lty of science d epa r tm ent of m athema tic s Week Date Sections 1 Sept 7 I.1, I.2, I.3 2 14 I.4, I.5, I.6 3 21 II.1, II.2, II.3 4 28 II.4, II.5, II.6 5 Oct 5 III.1, III.2 Part/ References from FS2009 Solutions to Exercises: 1. (b) Hide the 12 IV.1, IV.2 7 19 IV.3, IV.4 8 26 9 Nov 2 11 12 Topic/Sections T HE B EST C ARD T RICK Notes/Speaker Symbolic methods Combinatorial (a) Hide the 9♣ and present the arrangement: Structures 6 10 L ECTURE 26 9 (c) 12 Labelled structures I Labelled structures II IX.1 20 IX.2 23 IX.3 13 30 14 Dec 10 Asst #1 Due Multivariable GFs Complex Analysis Analytic Methods FS: Part B: IV, V, VI Singularity Analysis Appendix B4 Stanley 99: Ch. 6 Asymptotic methods Handout #1 (self-study) three possible choices here: (ii) hide the IX.4 Combinatorial Parameters the arrangement: There VI.1 are (i)A.3/ hide the 5♦ and present: C 18 25 Combinatorial parameters A.IIIpresent K♥ FS and (self-study) IV.5 V.1 Unlabelled structures FS: Part A.1, A.2 Comtet74 Handout #1 (self study) Random Structures and Limit Laws FS: Part C (rotating presentations) J♦ and present: IX.5 Asst #2 Due Sophie Introduction to Prob. Mariolys Limit Laws and Comb Marni Discrete Limit Laws Sophie Combinatorial instances of discrete Mariolys Continuous Limit Laws Marni Quasi-Powers and Gaussian limit laws Sophie Presentations Asst #3 Due (i) hide the 3♦ and present: In this last case we need to use the suit ordering to break the tie between the two 5’s: recall ♦ < ♠. Dr. Marni MISHNA, Department of Mathematics, SIMON FRASER UNIVERSITY Version of: 11-Dec-09 2. (a) (b) Jamie Mulholland, Spring 2011 Math 302 (c) 26-5
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