IIT JEE-Advanced 2011 Solved papers by Triumph Academy

Triumph Academy
IIT–JEE-11 / Paper I
[1]
CHEMISTRY
IIT JEE - 2011
Paper 1
Time: 3 hours
Max. Marks: 240
A. General:
1. This booklet is your Question Paper containing 60 questions. The booklet has 28 pages.
2. Blank papers, clipboards, log tables, slide rules, calculators, cellular phones, pagers, and electronic
gadgets in any form are not allowed to be carried inside the examination hall.
3. The answer sheet, Objective Response Sheet (ORS), is provided separately.
B. Question paper format and Marking Scheme:
4. The question paper consists of 3 parts (Mathematics, Chemistry and Physics). Each part has FOUR
sections.
5. For each question in Section I, you will be awarded 3 marks if you have darkened only the bubble
corresponding to the correct answer and zero mark if no bubble is darkened. In case of bubbling of
incorrect answer, minus one (–1) mark will be awarded.
6. For each question in Section II, you will be awarded 4 marks if you have darkened only the bubble
corresponding to the correct answer and zero mark if no bubble is darkened. In case of bubbling of
incorrect answer, zero (0) mark will be awarded.
7. For each question in Section III, you will be awarded 3 marks if you darken the bubble corresponding
to the correct answer, and zero mark if no bubble is darkened. In all other cases, minus one (–1) mark
will be awarded.
8. For each question in Section IV, you will be awarded 4 marks if you darken the bubble corresponding
to the correct answer, and zero mark if no bubble is darkened. In all other cases, minues one (–1)
mark will be awarded.
Name:
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Triumph Academy
IIT–JEE-11 / Paper I
[2]
CHEMISTRY
Part I
Section–I
Straight Objective Type
This section contains 7 multiple choice questions numbered 1 to 7. Each question has 4 choices (A), (B), (C) and
(D), out of which ONLY ONE is correct.
1.
Geometrical shapes of the complexes formed by the reaction of Ni 2 with Cl  , CN  and H 2 O,
respectively, are
(A) octahedral, tetrahedral and square planar
(B) tetrahedral, sqaure planar and octahedral
(C) square planar, tetrahedral and octahedral
(D) octahedral, square planar and octahedral
Ans. (B)
Sol.
NiCl 4
2
b g
Nib H Og
Ni CN
2
2.
 Tetrahedral
2
4
 Square planar
2
6
 Octahedral
AgNO3 (aq.) was added to an aqueous KCI solution gradually and the conductivity of the solution was
measured. The plot of conductance (  ) versus the volume of AgNO3 is
(A) (P)
Ans. (D)
(B) (Q)
(C) (R)
(D) (S)
Triumph Academy
3.
CHEMISTRY
Bombardment of aluminum by   particle leads to its artificial disintegration in two ways, (i) and (ii) as
shwon. Products X, Y and Z respectively are
(A) proton, neutron, positron
(C) proton, positron, neutron
Ans. (A)
Sol.
4.
IIT–JEE-11 / Paper I
[3]
4
2
He 
27
13
Al 

4
2
He 
27
13
Al 

30
15
Si 
4
2
He 
27
13
Al 

30
14
Si  e 
30
15
P
0
(B) neutron, positron, proton
(D) positron, proton, neutron
n1
b Y g  neutron
1
P1
b X g proton
b positron g
Extra pure N2 can be obtained by heating
(A) NH3 with CuO
(C) (NH4)2Cr2O7
(B) NH4NO3
(D) Ba(N3)2
Ans. (D)
Sol.
5.
b g
Ba N 3
2



 Ba  3N 2
Among the following compounds, the most acidic is
(A) p-nitrophenol
(B) p-hydroxybenzoic acid
(C) o-hydroxybenzoic aicd
(D) p-toluic acid
Ans. (C)
Triumph Academy
IIT–JEE-11 / Paper I
[4]
CHEMISTRY
O–H
O
OH
C
COOH
Sol.
because its carboxylate ion is stabilised due to intramolecular hydrogen bonding
O
and due to ortho effect.
6.
The major product of the following reaction is
(A)
(B)
(C)
(D)
Ans. (A)
O
O
C
NH
Sol.
(i) KOH
(ii) Br
N – CH 2
CH2Cl
Br
C
O
7.
O
Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The
molarity of the solution is
(A) 1.78 M
(B) 2.00 M
(C) 2.05 M
(D) 2.22 M
Triumph Academy
IIT–JEE-11 / Paper I
[5]
CHEMISTRY
Ans. (C)
Sol.
Total mass of the solution = 1000 + 120 = 1120 g
V
1120
 0.973 L
115
.
n urea 
M
120
 2 mol
60
2
 2.05 M
0.973
Section–II
Multiple Correct Answer Type
This section contains 5 multiple choice questions numbered 8 to 14. Each question has 4 choices (A), (B), (C)
and (D), out of which ONE OR MORE THAN ONE is / are correct.
8.
Extraction of metal from the ore cassiterite involves
(A) carbon reduction of an oxide ore
(B) self-reduction of a sulphide ore
(C) removal of copper impurity
(D) removal of iron
impurity
Ans. (A, D)
Sol.
Cassiterite contains impurity of FeWO4
bSnO g
2
SnO 2  2C 
 Sn  2CO
9.
Amongst the given options, the compound(s) in which all the atoms are in one plane in all the possible
conformations (if any), is (are)
(A)
(B)
(C) H 2 C  C  O
(D) H 2 C  C  CH 2
Ans. (B, C)
10.
The correct statement (s) pertaining to the adsorption of a gas on a solid surface is (are)
(A) Adsorption is always exothermic
(B) Physisorption maytransform into chemisorption at high temperature
(C) Physisorption increases with increasing temperature but chemisorption decreases with increasing
temperature
(D) Chemisorption is more exothermic than physisorption, however it is very slow due to higher energy of
activation.
Ans. (A, B, D)
Triumph Academy
IIT–JEE-11 / Paper I
[6]
CHEMISTRY
11.
According to kinetic theory of gases
(A) collision are always elastic
(B) heavier molecules transfer more momentum to the wall of the container
(C) only a small number of molecules have very high velocity
(D) between collision, the molecules move in straight lines with constant velocities.
Ans. (A, C, D)
Section–III
Paragraph Type
This section contains 2 paragraphs. Based upon each paragraph, 3 multiple choice questions have to be answered.
Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct.
Paragraph for Question Nos. 12 to 14
When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N, the solution
turns light blue. Addition of aqueous NaCl to the blue solution gives a white precipitate O. Addition of aqueous
NH3 dissolves O and gives an intense blue solution.
12.
The metal rod M is
(A) Fe
(B) Cu
(C) Ni
(D) CO
(B) Zn(NO3)2
(C) Al(NO3)3
(D) Pb(NO3)2
2
(B) Al NH 3
Ans. (B)
13.
The compound N is
(A) AgNO3
Ans. (A)
14.
The final solution contains
b g
Agb NH g
(A) Pb NH 3
(C)
Ans. (C)
2
4
3 2

and CoCl 4
b g
and Cu NH 3
2
4
(D)
b g
Agb NH g
3
4
3 2

b g
Nib NH g
and Cu NH 3
and
2
4
3 6
2
Triumph Academy
IIT–JEE-11 / Paper I
[7]
CHEMISTRY
Sol.
b g
2 AgNO 3  Cu 
 Cu NO 3 2  2 Ag
N
M
Light blue
AgNO 3  NaCl 
 AgCl  NaNO3
White ppt
O
b g

 AgbNH g
Cu 2   4 NH 3 
 Cu NH 3
AgCl  2 NH 3
2
4
3 2

Cl 
Paragraph for Question Nos. 15 to 16
An acyclic hydrocarbon P, having molecular formula C6H10 gave acetone as the only organic product through
the following sequence of reactions, in which Q is an intermediate organic compoud.
15
16.
The structure of compound P is
(A) CH 3CH 2 CH 2  C  C  H
(B) H 3CH 2 C  C  C  C  CH 2 CH 3
(C)
(D)
The structure of the compound Q is
(A) S
(B)
(C)
(D)
Ans. (D, B)
Triumph Academy
IIT–JEE-11 / Paper I
[8]
CHEMISTRY
CH 3
Sol.
CH 3
CH 3
CH 3
C–C CH
(D)
(1) H2SO4|HgSO4
CH 3– C – C – CH 3
CH 3 O
CH 3
CH 3
|
|

H
4 / C 2 H 5OH
NaBH

 CH 3  C  CH  CH 3 
 CH 3  C  CH  CH 3 

dil . acid
|
|
|
|
CH 3 OH
CH 3 OH 2

CH 3
CH3
CH3 CH3
|
|
|
|
(i) O
CH 3  C  CH  CH 3 
 CH 3  C  CH  CH 3 
 CH3  C  C  CH3  3  CH 3COCH3
|

CH 3

a ii f Zu / H O
2
|
CH 3
Section – IV
Integer Answer Type
This section contains 8 questions. The answer to each of the questions is a single-digit integer, ranging from
0 to 9. The appropriate bubbles below the respective question numbers in the SORS have to be darkened.
17.
Reaction of Br2 with Na 2 CO 3 in aqueous solution gives sodium bromide and sodium bromatewith evolution
of CO2 gas. The number of sodium bromide molecules involved in the balanced chemical euqation is
Ans. (5)
Sol.
3Br2  3CO 32  
 5Br   BrO 3  3CO 2
18.
The difference in the oxidation numbers of the two types of sulphur atoms in Na 2S 4 O 6 is
Ans. (5 )
Sol.
O
O
+–
 
NaO – S – S – S – S – O Na
O
+5 0
0 +5
O
Triumph Academy
[9]
IIT–JEE-11 / Paper I
CHEMISTRY
19.
The maximum number of electrons that can have principal quantum number, n = 3, and spin quantum
1
number, ms   , is
2
Ans. (9)
Sol.
Number of orbital for n = 3 is = n2 = 9
Number of electron n = 3 and m s  
20.
1
=9
2
A decapeptide (Mol. Wt. 796) on complete hydrolysis gives glycine (Mol. Wt. 75), alanine and phenylanine.
Glycine contributes 47.0% to the total weight of the hydrolysed prdoucts. The number of glycine units
present in the decapeptide is
Ans. (6)
Sol.
Let number of glycine units = n
mass of decapeptide = 796
mass of H2O needed = 162 g
Total mass = 958 g
958 

n
47
 75  n
100
958  47
6
100  75
21.
To an evacuated vessel with movable piston under external pressure of 1 atm, 0.1 mol of He and 1.0 mol.
of an unknown compound (vapour pressure 0.68 atm. at 00C) are introduced. Considering the ideal gas
behaviour, the total volume (in litre) of the gases at 00C is close to
Ans. (7)
Sol.
Let unknown is X.
b
g
p He  p total  p x  1  0.68 atm
 0.32 atm
Now p He  n He

v
7
RT
V
RT 010
.  0.082  273

p He
0.32
Triumph Academy
IIT–JEE-11 / Paper I
[10]
CHEMISTRY
22.
The total number of alkenes possible bydehydromination of 3-bromo-3-cyclopentylhexane using alcoholic
KOH is
Ans. (5)
Sol.
(Cis + trans)
23.
(Cis + trans)
bg
The work function  of some metals is listed below. The number of metals which will show photoelectric
effect when light of 300 nm wavelength falls on the metal is
Metal
b g
 eV
Li
Na
K
Mg
Cu
Ag
Fe
Pt
W
2.4
2.3
2.2
3.7
4.8
4.3
4.7
6.3
4.75
Ans. (4)
Sol.
For photoelectric effect to occur
E      4.14 eV
 Li, Na, Ka, Mg will show photoelectronic effect when light g 300 nm wavelength falls on the metal is (4).
[11]
IIT 2011 / Paper I
PHYSICS
Part II
Section – I (Total Marks : 21)
Single Correct Answer Type
This section contains 7 multiple choice questions numbered 24 to 30. Each question has 4 choices (A), (B),
(C) and (D), out of which ONLY ONE is correct.
24.
A ball of mass (m) 0.5 kg is attached to the end of a string having length (L) 0.5 m. The ball is rotated on
a horizontal circular path about vertical axis. The maximum tension that the string can bear is 324 N. The
maximum possible vlaue of angular velocityof ball (in radian / s) is
(A) 9
Sol.: (D)

25.
(B) 18
(C) 27
(D) 36
m max 2 r  Tmax
 max 
Tmax

mr
324
 1296  36 rad / s
0.5  0.5
A meter bridge is set-up as shown, to determine an unknown resistance 'X' using a standard 10 ohm
resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-corrections are
1 cm and 2 cm respectively for the ends A and B. The determined value of 'X' is
(A) 10.2 ohm
(B) 10.6 ohm
(C) 10.8 ohm
(D) 11.1 ohm
[12]
IIT 2011 / Paper I
PHYSICS
Sol.: (B)
26.
X 53
53

X
 10  10.6  (include the end corrections as well in the calculated length)
10 50
50
A 2 F capacitor is charged as shown in figure. The percentage of its stored energy dissipated after the
switch S is turned to position 2 is
(A) 0%
(B) 20%
(C) 75%
(D) 80%
bg
1
2
Sol.: (D) U i   2 V 2
U loss 
 lost 
27.
U loss 4
  80%
Ui
5
A police car with a siren of frequency 8 kHz is moving with uniform velocity 36 km / hr towards a tall
building which reflects the sound waves. The speed of sound in air is 320 m / s. The frequencyof the siren
heard by the car driver is
(A) 8.50 kHz
(B) 8.25 kHz
(C) 7.75 kHz
(D) 7.50 kHz
Sol.: (A)
28.
bg bg
1 2  8

V 2
2
10
f final  8 
LM 320  10 OP  8  33  8.5 kHz
N 320  10 Q 31
5.6 liter of helium gas at STP is adiabatically compressed to 0.7 liter. Taking the initial temperature to be
T1 , the work done in the prcess is
(A)
Sol.: (A)
9
RT1
8
3
RT1
2
(C)
TV  1  constant
b g
T1 5.6

(B)
2/3
 T2 0.7
2/3
 T2  T1 8
2/ 3
FG IJ
H K
 4T1
 RT1
1
3R
Wad   U  nCv T   
3T1  
4
2
8
15
RT1
8
(D)
9
RT1
2
[13]
IIT 2011 / Paper I
PHYSICS
29.

Consider an electric field E  E0 x , where E 0 is a constant. The flux through the shaded area (as shown
in the figure) due to this field is
(A) 2 E0a 2
Sol.: (C)
(B)
2 E0a
2
(C) E0a 2
(D)
E 0a 2
2

A  ai  ak  aj  a 2 k  a 2i
j d i
e
 
  E  A  E 0i  a 2 k  a 2i  E 0 a 2
30.
The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelength
of the second spectral line in the Balmer series of singly-ionized helum atom is
(A) 1215 Å
(B) 1640 Å
(C) 2430 Å
(D) 4687 Å
Sol.: (A)
LM
N
OP
Q
1
1 1
5
R 

R
1
4 9
36
LM
N
OP
Q
1
1 1
3
 4R 
 R
2
4 9
4

2
5 4
5
5


 2 
 6561  1215 Å
 1 36  3 27
27
[14]
IIT 2011 / Paper I
PHYSICS
Section–II (Total Marks : 16)
Multiple Correct Answer Type
This section contains 4 multiple choice questions numbered 31 to 34. Each question has 4 choices (A), (B),
(C) and (D), out of which ONE OR MORE THAN ONE is / are correct.
31.
b g
A spherical metal shell A of radius R A and a solid metal sphere B of radius RB  R A are kept far apart
and each is given charge +Q. Now they are connected by a thin metal wire. Then
(A) E Ainside  0
Sol.: (A, B, C, D)

(B) QA  QB
 A RB
(C)   R
B
A
(D) E Aon surface  E Bon surface
On connecting V A  VB
kQ A kQB

RA
RB .
also R  constant

32.
 A RB

 B RA
An electron and a proton are moving on straight parallel paths with same velocity. They enter a semiinfinite region of uniform magnetic field perpendicular to the velocity. Which of the following statement(s0
is/are true?
(A) They will never come out of the magnetic field region.
(B) They will come out travelling along parallel paths.
(C) They will come out at the same time.
(D) They will come out at different times.
Sol.: (B, D) As shown in the figure they will come out after describing a semicircle along parallel paths.
Also time taken t 
m
which will be different for both.
qB
[15]
IIT 2011 / Paper I
PHYSICS
33.
b g
A metal rod of length L and mass m is pivoted at one end. A thin disk of mass M and radius R  L is
attached at its center to the free end of the rod. Consider two ways the disc is attached: (case A). The disc
is not free to rotate about its center and (case B) the disc is free to rotate about its center. The rod-disc
system performs SHM in vertical plane after being released from the same displaced position. Which of
the following statement(s) is/are true?
(A)
(B)
(C)
(D)
Restoring torque in case A = Restoring torque in case B
Restoring torque in case A < Restoring torque in case B
Angular frequency for case A > Angular frequency for case B
Angular frequency for case A < Angular frequency for case B
Sol.: (A, D) In both the situations, net restoring torque is same. In first case when the disk is not free to rotate about its
centre its moment of inertia is
mR 2
 mL2 about the axis where as in second case its moment of inertia is mL2 .
2
So from   I 2 , the angular frequency in case A is lesser than that in B.
34.
A composite block is made of slabs A, B, C, D and E of different thermal conductivities (given in terms of
a constant K) and sizes (given in terms of length, L) as shown in the figure. All slabs are of same width.
Heat Q flows only from left to right through the blocks. Then in steady state
(A)
(B)
(C)
(D)
heat flow through A and E slabs are same.
heat flow through slab E is maximum.
temperature difference across slab E is smallest.
heat flow through C = heat flow through B + heat flow through D.
Sol.: (A, C, D) Slabs A and E are in series and thus heat flow through them is same and maximum. Treating slabs B, C, D
as a joint block and since it is in series with A and E temperature difference across slab E is smallest as it has the least
resistance. Also for slabs B, C, D heat current H 
kA
and thus H C  H B  H D .
L
[16]
IIT 2011 / Paper I
PHYSICS
Section–III (Total Marks : 15)
Paragraph Type
This section contains 2 paragraphs. Based upon the first paragraph, 3 multiple choice questions and based
upon the second paragraph 2 multiple choice questions have to be answered. Each of these question has four
choices (A), (B), (C) and (D), out of which ONLY ONE is correct.
Paragraph for Question Nos. 35 to 37
Phase space diagrams are useful tools in analyzing all kinds of dynamical problems. They are especially useful in
studying the changes in motion as initial position and momentum are changed. Here we consider some simple
dynamical systems in one-dimension. For such systems, phase space is a plane in which position is plotted along
bg
bg
horizontal axis and momentum is plotted along vertical axis. The phase space diagram is x t vs. p t curve in
this plane. The arrow on the curve indicates the time flow. For example, the phase space diagram for a particle
moving with constant velocity is a straight line as shown in the figure. We use the sign convention in which
position or momentum upwards (or to right) is positive and downwards (or to left) is negative.
35.
The sphase space diagram for a ball thrown vertically up from ground is
(A)
(B)
[17]
IIT 2011 / Paper I
PHYSICS
(C)
36.
(D)
The phase space diagram for simple harmonic motion is a circle centered at the origin. In the figure, the two
circles represent the same oscillator but for different initial conditions, E1 and E 2 are the total mechanical
energies respectively. Then
(A) E1  2 E 2
(B) E1  2 E 2
(C) E1  4 E 2
(D) E1  16 E 2
[18]
IIT 2011 / Paper I
PHYSICS
37.
Consider the spring-mass system, with the mass submerged in water, as shown in the figure. The phase
space diagram for one cycle of this system is
(A)
(B)
(C)
(D)
Sol.: (D, C, B) For a ball thrown upward, the magnitude of position first increases and then decreases. The magnitude of
momentum for upward flight decreases and then for downward flight increases so correct option is B.
The amplitude of SHM for second case is double that of first and other factors (mass frequency) are same so from
1
m 2 a 2 , E 2  4 E1
2
During the downward motion (from upper extreme to lower extreme) of block, the momentum is negative and its
magnitude first increases then decreases. For upward motion (from lower extreme to upper extreme), the magnitude of momentum first increases and then decreases, the sign is +ve here.
Further due to the damping the upper extreme for the upward phase is lower from previous one.
So correct option is B.
E
[19]
IIT 2011 / Paper I
PHYSICS
Paragraph for Question Nos. 38 to 39
A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing
fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let N be the number density
of free electrons, each of mass m. When the electrons are subjected to an electric field, they are displaced
relatively away from the heavy positive ions. If the electric field becomes zero, the electrons being to oscillate
about the positive ions with a natural angular frequency  p , which is called the plasma frequency. To sustain the
oscillations, a time varying electric field needs to be applied that has an angular frequency  where a part of the
energy is absorbed and a part of it is reflected. As  approaches  p , all the free electrons are set to resonance
together and all the energy is reflected. This is the explanation of high reflectivityof metals.
38.
Taking the electronic charge as é and the permittivity as '  0 ' , use dimensional analysis to determine the
correct expression for  p .
(A)
39.
Ne
m 0
(B)
m 0
Ne
(C)
Ne 2
m 0
(D)
m 0
Ne 2
Estimate the wavelength at which plasma reflection will occur for a metal having the density of electrons
N  4  1027 m 3 . Take  0  1011 and m  10 30 , where these quantities are in proper SI units.
(A) 800 nm
(B) 600 nm
(C) 300 nm
Sol.: (C, B) By checking dimension of each option, the correct option is
p 
LM
MN
Ne 2
m 0
OP
PQ
The frequency of light reflected is

c
 P/ 2
 2  3  108 
P
so wavelength is
2
10 30  10 11
4  10 27  1.6  16
.  10 38
 600 nm
(D) 200 nm
[20]
IIT 2011 / Paper I
PHYSICS
Section – IV
Integer Answer Type
This section contains 7 questions. The answer to each of the questions is a single-digit integer, ranging from
0 to 9. The appropriate bubbles below the respective question numbers in the ORS have to be darkened.
40.
The activity of a freshly prepared radioacitve sample is 1010 disintegrations per second, whose mean life is
109 s. The mass of an atom of this radioisotope is 10–25 kg. The mass (in mg) of the radioactive sample is
Sol.: (1)
A  N
N
so
41.
A
 A

M  mN  mA  10 25  1010  109  10 6 kg  1 mg
Four point charges, each of +q, are rigidly fixed at the four corners of a square planar soap film of side 'a'.
The surface tension of the soap film is . The system of charges and planar film are in equilibrium, and
Lq O
a  kM P
N Q
2
Sol.: (3)
1/ N
, where 'k' is a constant. Then N is
b g
The force due to surface tension on any side is  2 and the force electrostatic force on any side is
2 kq 2
a2
. For
equlibrium,
q
q
q
q
F kq I  2b ga
GH a JK
LF q I O
a  k MG J P
MNH  K PQ
2
2
2
2
42.
1/ 3
Steel wire of length L at 40 oC is suspended from the ceiling and then a mass m is hung from its free end.
The wire is coolled down from 40 oC to 30 oC to regain its original length L. The coefficient of linear
thermal expansion of the steel is 10–5 / oC, Young's modulus of steel is 1011 N / m2 and radius of the wire
is 1 mm. Assume that L >> diameter of the wire. Then the value of m in kg is nearly
Sol.: (3)
mgL
 L T
AY
m
AY T
g

  10 6  1011  10 5  10

10
[21]
IIT 2011 / Paper I
PHYSICS
43.
Four solid spheres each of diameter 5 cm and mass 0.5 kg are placed with their centers atthe corners
of a square of side 4 cm. The moment of inertia of the system about the diagonal of the square is
N  10 4 kg m2 , then N is
Sol.: (9)
LM
MN
2
2
mR 2
T  2  mr 2  2 mr 2 
5
5
2
OP
PQ
R
r
LM
N
OP
Q
8 2
1 8 5
mr  mR 2     16  10 4  9  10 4
5
2 5 4
44.
A long circular tube of length 10 m radius 0.3 m carries a current I along its curved surface as shown. A
wrie-loop of resistance 0.005 ohm and of radius 0.1 m is placed inside the tube with its axis coinciding with
b g
the axis of the tube. The current varies as I  I 0 cos 300t where I 0 is constant. If the magnetic moment
b g
of the loop is N 0 I 0 sin 300t , then 'N' is
Sol.: (6)
The given tube is equivalent to a solenoid. The current per unit length of the solenoid is
is B   0
i
I
. The flux through the coil is   Br 2 so current induced is
L
FG IJ
H K
  r 2 dI
 1 d
1 d 0I

 Br 2 
r 2  0
R R dt
R dt L
RL dt
So magnetic moment of coil is
M  r 2i 
 0 2 r 4 dI  0  10  10 4

 300 I 0 sin 300t  6 0 I 0 sin 300t
RL dt
5  10 3  10
b g
I
. So field produced
L
[22]
IIT 2011 / Paper I
PHYSICS
45.
A boy is pushing a ring of mass 2 kg and radius 0.5 m with a stick as shown in the figure. The stick applies
a force of 2 N on the ring and rolls it without slipping with an acceleration of 0.3 m / s2. The coefficient of
friction between the ground and the ring is large enough that rolling always occurs and the coefficient of
friction between the stick and the ring is (P / 10). The value of P is
Sol.: (4)
Writing torque about instantaneous axis of rotation
a = 0.3 m / s2
2N
f
(2)P/10
FG P IJ R  I 
H 10 K
P
a
2 R  R  e2mR j
5
R
2R  2
or
46.
IAOR
2
b
g
or 2  2  2  0.3 
P
5
or P  4
A block is moving on an inclined plane making an angle 45o with the horizontal and the coefficient of
friction is . The force required to just push it up the inclined plane is 3 times the force required to just
prevent it from sliding down. If we defined N = 10 , then N is
Sol.: (5)
bmg sin  mg cos g  3 mg sin  mg cos
2mg sin   4 mg cos

1
1
tan  
2
2
N  10  10 
1
5
2
Triumph Academy
IIT–JEE-11 / Paper I
[23]
MATHEMATICS
PART III
Section–I
Straight Objective Type
This section contains 7 multiple choice questions numbered 47 to 53. Each question has 4 choices (A), (B), (C)
and (D), out of which ONLY ONE is correct.
47.
Let  and  be the roots of x 2  6x  2  0 , with    . If a n   n   n for n  1 , then the value of
a 10  2a 8
is
2a 9
(A) 1
(B) 2
(C) 3
(D) 4
 is a roots of of equation  2  6  2  0 ;  2  6B  2  0
Sol: (C)
 2  6  2  0   2  2  6
e
j e
 10  10  2  8  8
a 10  2a 8

2a 9
2  9  9
e
j e
2 e   j
6 e   j

3

e
 8  2  2  8  2  2
9
9
j
j

9
j
b g b g
2 e   j
 8  6  8 6
9
9
9
2(  9   9 )
48.
A Straight line L through the point (3,  2) is inclined at an angle 60o to the line 3x  y  1 . If L also
intersects the x  axis , then the equation of L is
(A) y  3x  2  3 3  0
(B) y  3x  2  3 3  0
(C) 3y  x  3  2 3  0
(D)
Sol: (B)
Inclination of line
3x  y  1 is 150o
Inclination of line L = 150o  60o
 210o , 90o
Slope of line L = tan 210 o  tan 30 o 
Equation of = Line L
y2 

1
3
bx  3g
3y  x  3  2 3  0
1
3
3y  x  3  2 3  0
Triumph Academy
IIT–JEE-11 / Paper I
[24]
MATHEMATICS
49.
Let ( x 0 , y 0 ) be the solution of the following equations
b g
(2 x) ln 2  3y
ln 3
3ln x  2 ln y
Then x 0 is
(A)
Sol: (C)
1
6
(B)
1
3
(C)
1
2
(D) 6
Let ln x  p, ln y  q
ln 2  a, ln 3  b
 (3y) ln 3
Now, (2 x) ln 2

a (a  p)  b( b  q ) . . . (1)

3ln x  2 ln y  (ln x) (ln 3)  (ln y) (ln 2)
pb  qa . . . (2)
From (1) a 2  b 2  bq  pa
 b.
pb
 pa
a
e
j

p 2
b  a2
a
p  a

ln x   ln 2  x 

1
2
z
ln 3
50.
x sin x 2
dx is
The value of
2
2
sin
x

sin(ln
6

x
)
ln 2
(A)
1 3
ln
4 2
(B)
z
ln 3
Ans: (A)
I
x sin x 2
sin x 2  sin(ln 6  x 2 )
ln 2
z
ln 3

I
ln 2

I
1
2
1 3
ln
2 2
z
ln 2
3
2
dx
sin t
dt
sin t  sin(ln 6  t ) 2
ln 3
(C) ln
sin(ln 6  t )
dt
sin(ln 6  t )  sin t
Put x 2  t
(D)
1 3
ln
6 2
Triumph Academy
IIT–JEE-11 / Paper I
[25]
MATHEMATICS
Adding

51.
 I
1
2I 
2
z
ln 3
dt 
1 3
ln
2 2
ln 2
1 3
ln
4 2




Let a  i  j  k , b  i  j  k and c  i  j  k be three vectors. A vector v in the plane of a and b ,
1
whose projection on c is
, is given by
3
(A) i  3j  3k
Sol: (C)



52.
(B) 3i  3j  k
(D) i  3j  3k
(C) 3i  j  3k
  
v  a  b
 
vc
1
 
c
3


 
c
 
a . c   ( b . c) 
3
   1 
(a  b) . c 
c
3
1   
c  a. c
1  ( 1)
3

2
 

1
b.c
  
v  a  2b  2i  j  3i
o
t
o
t
Let P   : sin   cos   2 cos  and Q   : sin   cos   2 sin  be two sets. Then
(A) P  Q and Q  P  
(C) P  Q
Ans: (D) sin   cos   2 cos 
 sin   ( 2  1) cos 
 tan  
1
2 1
 2 1
 sin   cos   2 sin 
 ( 2  1) sin   cos 
 tan   2  1
(B) Q  P
(D) P  Q
Triumph Academy
53.
IIT–JEE-11 / Paper I
[26]
MATHEMATICS
Let the straight line x  b divide the area enclosed by y  (1  x) , y  0 and x  0 into two parts
2
R1 (0  x  b) and R 2 ( b  x  1) such that R 1  R 2 
(A)
Ans: (B)
3
4
R1  R 2 
z
z
z
z
1
(1  x) 2 dx  (1  x) 2 dx 
0
b
b

1
2 (1  x) 2 dx  (1  x) 2 dx 
0




0
2

(1  x ) 3
3
e
(C)
1
4
b

1
2
(B)
b

0
(1  x) 3
3
j FGH
1

0
1
4
1
4
1
4
IJ
K
2
1
1
(1  b) 3  1  0 

3
3
4
2
2 1 1 1 1 1
(1  b) 3      
3
3 3 4 3 4 12
(1  b) 3 
1
1
1
 1 b   b 
8
2
2
1
. Then b equals
4
1
3
(D)
1
4
Triumph Academy
IIT–JEE-11 / Paper I
[27]
MATHEMATICS
Section–II
Straight Objective Type
This section contains 4 multiple choice questions numbered 54 to 57. Each question has 4 choices (A), (B), (C)
and (D), out of which ONE OR MORE THAN ONE is / are correct.
54.
Let M and N be two 3  3 non-singular skew-symmetric matrices such that MN  NM . If p T denotes
the transpose of P, then M 2 N 2 ( M T N ) 1 ( MN 1 ) T is equal to
(C) M 2
(B) N 2
(A) M 2
(D) MN
Ans: (Bouns) M 2 N 2 ( M T N ) 1 ( MN 1 ) T

e
M 2 N 2 ( N 1 ( M T ) 1 ) ( N 1 ) T M T
j
2
2
1
T
T 1
 M N N (  M ) ( N ) (  M)
55.

M 2 N ( N N 1 ) (  M) 1 (  N ) 1 (  M)

M 2 N ( I) (  N ) (  M )

M 2 N ( NM) 1 (  M)

M ( MN ) ( MN ) 1 (  M)

M (I) (  M)

 M2
b
g
1
(  M)
The vectors(s) which is/are coplanar with vectors i  j  2 k and i  2 j  k , and perpendicular to the
vectors i  j  k is/are
j  k

SOL: ( A, D) a  i  j  2k

b  i  2j  k

c  i  j  k
(A)
(B)  i  j


(C) i  j

vector coplanar with a and b and perpendicular to c is given by
  
c  (a  b)



     
(c . b) a  ( c . a) b
 
4 a  4b
 
 
4(a  b)  4(  j  k)
(D)  j  k
Triumph Academy
56.
[28]
IIT–JEE-11 / Paper I
MATHEMATICS
x2 y2
Let the eccentricity of the hyperbola 2  2  1 be reciprocal to that of the ellipse x 2  4 y 2  4 . If the
a
b
hyperbola passes through a focus of the ellipse, then
x2 y2

1
(A) the equation of the hyperbola
3
2
(C) the eccentricity of the hyperbola is
SOL: ( B, D) Equation of ellipse
x2 y2

1
4
1
eccentricity of ellipse  1 
1
3

4
2
eccentricity of hyperbola 
2
3
Foci of ellipse (  3 , 0) .



3
a
2
3
a2

0
b2
1
 1  a2  3
b2 
a2
1
3
Equation of Hyperbola :

x2 y2

1
3
1
x 2  3y 2  3
Foci of hyperbola : (  2, 0)
5
3
(B) a focus of the hyperbola is (2, 0)
(D) the equation of the hyperbola is x 2  3y 2  3
Triumph Academy
IIT–JEE-11 / Paper I
[29]
MATHEMATICS
57.
Let f : R  R be a function such that
f ( x  y)  f ( x)  f ( y), x, y  R
If f ( x) is differentiable at x  0 , then
(A) f ( x) is differentiable only in a finite interval containing zero
(B) f ( x) is continuous x  R
(C) f ' ( x) is constant x  R
(D) f ( x) is differentiable except at finitely many points
Ans: (B, C or B, C, D ) f ( x)  lim
h0
f ( x  h)  f ( x)
f ( x)  f ( h)  f ( x)
 lim
h 0
h
h
f ( h)
f ( h)  f (0)
 lim
 lim
h 0 h
h0
h
 f  (0) = A const = k (say)

f ( 0)  kx  c but f (0)  0  k  0  f ( x)  kx
f ( x  0)
 f ( x)  f (0)
 f (0)  0
Triumph Academy
IIT–JEE-11 / Paper I
[30]
MATHEMATICS
Section–III
Linked Comprehension Type
This section contains 2 paragraphs. Based upon each paragraph, 3 multiple choice questions have to be
answered. Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct.
Paragraph for Question Nos. 58 to 59
Let U1 and U 2 be two urns such that U1 contains 3 white and 2 red balls, and U 2 contains only 1 white ball.
A fair coin is tossed. If head appears then 1 ball is dawn at random from U1 and put into U 2 . However , if tail
appears then 2 balls are drawn at random from U1 and put into U 2 . Now 1 ball is drawn at random from U 2 .
58.
The probability of the drawn ball from U 2 being white is
(A)
13
30
23
30
(B)
(C)
W
19
30
(2 W)
(D)
W
1
3/ 5
H
2/5
1/ 2
SOL: ( B)
3/10
Coin
1/ 2
T
6 /10
1/10
P(W) 

LM
N
1/ 2
R
2W
OP  23
Q 30
(3W)
1R) (2W, 1R)
2(1W
W,1R
2R
1 3 1 2 1 1 3 1 6 2 1 1 1
           
2 5 2 5 2 2 10 2 10 3 2 10 3
1
9
1
9  3   6
30
2
2
(1W 1R)
(1W, 2R)
W
1
W
2/ 3
1/ 3
W
W
11
30
Triumph Academy
IIT–JEE-11 / Paper I
[31]
MATHEMATICS
59.
Given that the drawn ball from U 2 is white, the probability that head appeared on the coin is
(A)
17
23
11
23
(B)
(C)
15
23
(D)
12
23
SOL: ( D)
F Head appear on coin I
PG
H ball drawn from U is white JK
=
2
1 3 1 2 1
   
12
2 5 2 5 2

1 3 1 6 2 1 1 1
23
      
2 10 2 10 3 2 10 3
FG IJ
H K
Paragraph for Question Nos. 60 to 62
Let a, b and c be three numbers satisfying
a
60.
b
LM1
c 8
MN7
OP
PQ
9
2
3
7
7  0
7
0
0 . . . (E)
If the point P (a , b, c) , with reference to (E), lies on the plane 2 x  y  z  1 , then the value of 7a  b  c
is
(A) 0
(B) 12
(C) 7
(D) 6
a  8b  7c  0
UV
W
SOL: ( D) 9a  2 b  3c  0 . . . (E)
7a  7 b  7c  0
1
8
7
Now, D  9
2
3 0
7
7
7
 system (E) has infinite solutions
a b
c
 
 k (say)
1 6 7


2a  b  c  1
2 k  6k  7 k  1

k 1

7a  b  c  7 k  6k  7 k  6k  6
Triumph Academy
IIT–JEE-11 / Paper I
[32]
MATHEMATICS
61.
Let  be a solution of x 3  1  0 with Im( )  0 . If a  2 with b and c satisfying (E), then the value of
3
1
3
 b c
a



is equal to
(A) 2
(B) 2
(C) 3
(D) 3
a  2, k  2 , b  12, c  14
Sol: (A)
3

2

1
 12

3
 4
 3  1  3 2
3 (   2 )  1

 3( 1)  1  2
62.
Let b  6 , with a and c satisfying (E). If  and  are the roots of the quadratic equation ax 2  bx  c  0 ,
then
F 1 1I
 GH    JK

n
n0
is
(A) 6
(B) 7
(C)
6
7
b  6  k  1  a  1, c  7
Sol: (B)
quadratic Equation is x 2  6x  7  0  ( x  7) ( x  1)  0  x  7, 1
F 1 1I F 1 1 I
 GH    JK  GH 1  (7) JK
F 6I 1  7
 G J 
H 7K 1 6

n
n0

n0

n 0
n
7
n
(D) 
Triumph Academy
IIT–JEE-11 / Paper I
[33]
MATHEMATICS
Section – IV
Integer Answer Type
This section contains 10 questions. The answer to each of the questions is a single-digit integer, ranging from
0 to 9. The appropriate bubbles below the respective question numbers in the ORS have to be darkened.
63.
The minimum value of the sum of real numbers a 5 , a 4 , 3a 3 , 1, a 8 and a10 with a  0 is
e j
a 5  a 4  3 a 3  1  a 8  a 10
Sol : [8]

64.
1 1 3  1 1 1
F
H
e j b1gea jea jIK
 a 5a 4 a 3
3
8
10
1/ 8
1
(using AM  GM )
a 5  a 4  3a 3  1  a 8  a 10  8
FG
H
bg
1
Let f   sin tan
FG
H
IJ IJ ,where       . Then the value of
KK
4
4
d
b f ( ) g
db tan g
sin 
cos 2
is
FG
H
bg
1
Sol: [1] f   sin tan
IJ  sinFG sin
cos 2 K
H
sin 
sin 

e
sin 2   cos2   sin 2 
j

I
J
  cos 2 K
sin 
1
sin 2
sin 
sin 

 tan 
cos  cos 
b g
b
g
b g
b g
d tan 
d
f  
1
d tan 
d tan 
65.
If z is any complex number satisfying z  3  2i  2 , then the minimum value of 2 z  6  5i is
FG
H
Sol: [5] 2 z  6  5i  2 z  3 
FG
H
 2 3 3
=2
FG 5 IJ  5
H 2K
IJ
K
5
i
2
5
2
IJ
K
(corresponding Pt A)
Triumph Academy
66.
IIT–JEE-11 / Paper I
[34]
g
MATHEMATICS
g
Let f : 1,   2,  be a differentiable function such that f (1)  2 . If
z
x
6 f ( t )dt  3x f ( x)  x 3
1
for all x  1 , then the value of f ( 2) is
z bg
x
bg
3
SOL [6] 6 f t dt  3  f x  x
1
differenciating both sides
bg bg bg
xf ' b xg  f b xg  x
F 1I
f ' b xg  f b xgG  J  x
H xK
6f x  3f x  3xf ' x  3x 2


2
integration factor
bg
f x e
1
 dx
x

1
x
solution is given by
z
b g FGH IJK
f b xg  x  cx
f b1g  2  c  1
f b xg  x  x
f b2g  6
1
1
f x  x
dx  c  x  c
x
x

Now

67.
2
2
The positive integer value of n  3 satisfying the equation
1
sin
is
FG  IJ
H nK

1
1

2
3
sin
sin
n
n
FG IJ
H K
FG IJ
H K
Triumph Academy
IIT–JEE-11 / Paper I
[35]
MATHEMATICS
SoL [7]
1
sin

n

1
1

2
3
sin
sin
n
n

1
1
1


sin  sin 2 sin 3

sin 3  sin  

sin 4  sin 3

7 

 
2
2
7
sin   sin 3
sin 2
(Let

 )
n

1
1
1
sin 3  sin 



sin 2 sin  sin 3
sin .sin 3

2 cos 2  sin  


7
2 sin cos
0
2
2
sin   sin 3
sin 2
sin   0

cos
7
0
2
p
68.
Let a1 , a 2 , a 3 , ..., a100 be an arithmetic progression with a1  3 and S p   a i , 1  p  100 . For any
i 1
Sm
integer n with 1  n  20 , let m  5n . If S does not depend on n, then a 2 is
n
b g
b g
m
2a 1  m  1 d
m 6  md  d
5 6  d  5nd
Sm
5n 6  5nd  d
 2



SoL [3, 9 or 3 and 9 ] S n
n
n
6

nd

d
n
6

nd

d
6  d  nd is free from n
2a 1  n  1 d
2
g
g
b
b
g b
g b
g
g
d6

6d  0

a 2  a1  d  3  6  9
69.
b
b
Consider the parabola y 2  8x . Let 1 be the area of the triangle formed by the end points of its latus
rectum and the point P
FG 1 , 2IJ on the parabola, and 
H2 K
2
be the area of the triangle formed by drawning
tangents at P and at the end points of the latus rectum. Then
1
is
2
SoL [2] Area of  formed by three pts to to parabola is twice the area of  formed by tangents at these pts.
Triumph Academy
IIT–JEE-11 / Paper-II
[7]
PHYSICS
Part II
Section–I (Total Marks : 24)
(Single Correct Answer Type)
This section contains 8 multiple choice questions numbered 21 to 28. Each question has 4 choices (A), (B),
(C) and (D), out of which ONLY ONE is correct.
21.
A light ray traveling in glass medium is incident on glass-air interface at an angle of incidence . The
reflected (R) and transmitted (T) intensities, both as function of , are plotted. The correct sketch is
(A)
(B)
(C)
(D)
Triumph Academy
IIT–JEE-11 / Paper-II
[8]
PHYSICS
22.
A wooden block performs SHM on a frictionless surface with frequency, v0 . The block carries a charge

+Q on its surface. If now a uniform electric field E is switched-on as shown, then the SHM of the block
will be
(A) on the same frequency and with shifted mean position.
(B) of the same frequency and with the same mean position.
(C) of changed frequency and with shifted mean position.
(D) of changed frequency and with the same mean position.
23.
The density of a solid ball is to be determined in an experiment. The diameter of the ball is measured with
a screw gauge, whose pitch is 0.5 mm and there are 50 divisions on the circular scale. The reading on the
main scale is 2.5 mm and that on the circular scale is 20 divisions. If the measured mass of the ball has a
relative error of 2%, the relative percentage error in the density is
(A) 0.9%
(B) 2.4%
(C) 3.1%
(D) 4.2%
24.
A ball of mass 0.2 kgrests on a vertical post of height 5 m. A bullet of mass 0.01 kg, traveling with a
velocity V m / s in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet
ravel independently. The ball hits the ground at a distance of 20 m and the bullet at a distance of 100 m
from the foot of the post. The intial velocity V of the bullet is
(A) 250 m / s
(B) 250 2 m / s
(C) 400 m / s
(D) 500 m / s
Triumph Academy
IIT–JEE-11 / Paper-II
[9]
PHYSICS
25.
26.
Which of the file patterns given below is valid for electric field as well as for magnetic field?
(A)
(B)
(C)
(D)
bg
F 2 I
x bt g  A sinG t  J . Adding a third sinusoidal displacement x bt g  B sinbt   g brings the mass
H 3K
A point mass is subjected to two simultaneous sinusoidal displacements in x-direction, x1 t  A sin t and
3
2
to a complete rest. The values of B and  are
(A) 2 A,
3
4
(B) A,
4
3
(C)
3 A,
5
6
(D) A,

3
Triumph Academy
IIT–JEE-11 / Paper-II
[10]
PHYSICS
27.
A long insulated copper wire is closely wound as a spiral of 'N' turns. The spiral has inner radius 'a' and
outer radius 'b'. The sprial lies in the X-Y plane and a steady current 'I ' flows through the wire. The Zcomponent of the magnetic field at the center of the sprial is
(A)
28.
FG IJ
b g HK
0N I
b
ln
2 ba
a
(B)
FG
b g H
0 N I
ba
ln
2 ba
ba
IJ
K
(C)
FG IJ
HK
0 N I
b
ln
2b
a
(D)
FG
H
0N I
ba
ln
2b
ba
IJ
K
A satellite is moving with a constant speed 'V'in a circular orbit about the earth. An object of mass 'm' is
ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its
ejection, the kinetic energy of the object is
(A)
1
mV 2
2
(B) mV 2
(C)
3
mV 2
2
2
(D) 2mV
Triumph Academy
IIT–JEE-11 / Paper-II
[11]
PHYSICS
Section–II
Multiple Correct Answer Type
This section contains 4 multiple choice questions numbered 29 to 32. Each question has 4 choices (A), (B),
(C) and (D), out of which ONE OR MORE THAN ONE is / are correct.
29.
Two solid spheres A and B of equal volumes but of different densities d A and d B are connected by a
string. They are fully immersed in a fluid of density d F . They get arranged into an equilibrium state as
shown in the figure with a tension in the string. The arrangement is possible only if
(A) d A  d F
30.
(B) d B  d F
(C) d A  d F
(D) d A  d B  2 d F
Which of the following statement(s) is/are correct?
(A) If the electric field due to a point charge varies as r 2.5 instead of r 2 , then the Gauss law will still be
valid.
(B) The Gauss law can be used to calculate the field distribution around an electric dipole.
(C) If the electric field between two point charges is zero somewhere, then the sign of the two charges is
the same.
(D) The work done by the external force in moving a unit positive charge from point A at potential V A to
b
point B at potential V B is VB  V A
g
Triumph Academy
IIT–JEE-11 / Paper-II
[12]
PHYSICS
31.
A series R-C circuit is connected to AC voltage source. Consider two cases; (A) when C is without a
dielectric medium and (B) when C is filled with dielectric of constant 4. The current I R through the resistor
and voltage VC across the capacitor are compared in the two cases. Which of the following is/are true?
(A) I RA  I RB
32.
(B) I RA  I RB
(C) VCA  VCB
(D) VCA  VCB
A thin ring of mass 2 kg and radius 0.5 m is rolling without slipping on a horizontal plane with velocity
1 m / s. A small ball of mass 0.1 kg, moving with velocity 20 m / s in the opposite direction, hits the ring at
a height of 0.75 m and goes vertically up with velocity 10 m / s. Immediately after the collision
(A)
(B)
(C)
(D)
the ring has pure rotation about its sitationary CM.
the ring comes to a complete stop.
friction between the ring and the ground is to the left.
there is no friction between the ring and the ground.
Triumph Academy
[13]
IIT–JEE-11 / Paper-II
PHYSICS
Section–III
Integer Type
This section contains 6 questions. The answer to each of the questions is a single digit integer, ranging from
0 to 9. The correct digit below the question number in the ORS is to be bubbled.
33.
Two batteries of different emfs and different internal resistances are connected as shown. The voltage
across AB in volts is
34.
A series R-C combination is connected to an AC voltage of angular frequency   500 rad / s. If the
impedance of the R-C circuit is R 1.25 , the time constant (in millisecond) of the circuit is
35.
A train is moving along a straight line with a constant acceleration 'a'. A body standing in the train throws
a ball forward with a speed of 10 m / s, at an angle of 60o to the horizontal. The body has to move forward
by 1.15 m inside the train to catch the ball back at the initial height. The acceleration of the train, in m / s2,
is
36.
Water (with refractive index 
4
7
) in a tank is 18 cm deep. Oil of refractive index lies on water making
3
4
a convex surface of radius of curvature 'R = 6 cm' as shown. Consider oil to act as a thin lens. An object
'S' is placed 24 cm above water surface. The location of its image is at 'x' cm above the bottom of the tank.
Then 'x' is
Triumph Academy
[14]
IIT–JEE-11 / Paper-II
PHYSICS
37.
A block of mass 0.18 kg is attached to a spring of force-constant 2 N / m. The coefficient of friction
between the block and the floor is 0.1. Initially the block is at rest and the spring is un-stretched. An
impulse is given to the block as shown in the figure. The block slides a distance of 0.06 m and comes to
rest for the first time. The initial velocity of the block in m / s is V = N / 10. Then N is
38.
A silver sphere of radius 1 cm and work function 4.7 eV is suspended from an insulating thread in freespace. It is under continuous illumination of 200 nm wavelength light. As photoelectrons are emitted, the
sphere gets charged and acquires a potential. The maximum number of photelectrons emitted from the
sphere is A  10 z (where 1  A  10 ). The value of 'Z' is
Triumph Academy
[15]
IIT–JEE-11 / Paper-II
PHYSICS
Section – IV
Matrix-Match Type
This section contains 2 questions. Each question has four statements (A, B, C and D) given in Column I and
five statements (p, q, r, s and t) in Column II. Any given statement in Column I can have correct mathcing
with ONE or MORE statement(s) given in Column II. For example, if for a given question, statement B
matches with the statements given in q and r, then for that particular question, against statement B, darken the
bubbles corresponding to q and r in the ORS.
39.
One mole of a monatomic ideal gas is taken through a cycle ABCDA as shown in the p-V diagram.
Column II gives the characteristic involved in the cycle. Match them with each of the processes given in
Column I.
Column I
Column II
(A) Process A  B
(p)
Internal energy decreases.
(B) Process B  C
(q)
Internal energy increases.
(C) Process C  D
(r)
heat is lost.
(D) Process D  A
(s)
Heat is gained.
(t)
Work is done on the gas.
Triumph Academy
IIT–JEE-11 / Paper-II
[16]
PHYSICS
40.
Column I shows four systems, each of the same length L, for producing standing waves. The lowest
possible natural frequencyof a system is called its fundamental frequency, whose wavelength is denoted as
 f . Match each system with statements given in Column II describing the nature and wavelength of the
standing waves.
Column I
Column II
(A) Pipe closed at one end
(p)
Longitudinal waves
(B) Pipe open at both ends
(q)
Transverse waves
(C) Stretched wire clamped at both ends
(r)
f  L
(D) Stretched wire clamped at both ends and at mid-point
(s)
 f  2L
(t)
 f  4L
Triumph Academy
IIT–JEE-11 / Paper II
[1]
CHEMISTRY
IIT JEE - 2011
Paper 2
Time: 3 hours
Max. Marks: 240
A. General:
1. This booklet is your Question Paper containing 60 questions. The booklet has 28 pages.
2. Blank papers, clipboards, log tables, slide rules, calculators, cellular phones, pagers, and electronic
gadgets in any form are not allowed to be carried inside the examination hall.
3. The answer sheet, Objective Response Sheet (ORS), is provided separately.
B. Question paper format and Marking Scheme:
4. The question paper consists of 3 parts (Mathematics, Chemistry and Physics). Each part has FOUR
sections.
5. For each question in Section I, you will be awarded 3 marks if you have darkened only the bubble
corresponding to the correct answer and zero mark if no bubble is darkened. In case of bubbling of
incorrect answer, minus one (–1) mark will be awarded.
6. For each question in Section II, you will be awarded 4 marks if you have darkened only the bubble
corresponding to the correct answer and zero mark if no bubble is darkened. In case of bubbling of
incorrect answer, zero (0) mark will be awarded.
7. For each question in Section III, you will be awarded 4 marks if you darken the bubble corresponding
to the correct answer, and zero mark if no bubble is darkened. In all other cases, minues one (–1)
mark will be awarded.
8. For each question in Section IV, you will be awarded 2 marks for each row in which you have
darkened the bubble(s) corresponding to the correct answer. Thus, the question in this section carries
a maximum of 8 makrs. There is no negative marking for incorrect answer(s) for this section.
Name:
81-B/3, Lohagal Road, Ajmer-305 001 Telefax: 0145-2628805, 2628178
Reg. No.: 1 2 J E E
e-mail: [email protected] website: www.triumphacademy.com
Triumph Academy
IIT–JEE-11 / Paper II
[2]
CHEMISTRY
Part I
Section–I
Straight Objective Type
This section contains 6 multiple choice questions numbered 1 to 6. Each question has 4 choices (A), (B), (C) and
(D), out of which ONLY ONE is correct.
1.
Oxidation states of the metal in the minerals haematite and magnetite, respectively, are
(A) II, III in haematite and III in magnetite
(B) II, III in haematite and II in magnetitie
(C) II in haematite and II, III in magnetite
(D) III in haematite and II, III in magnetitie
2.
Among the following complexes (K - P),
b g b Kg, CobNH g Cl bLg, Na Coboxalateg bM g, NibH Og
Pt b CN g bQ g and Znb H O g b NO g b P g
K 3 Fe CN
6
3 6
K2
4
2
3
6
3
b g
Cl 2 N ,
(B) K, M, O, P
(D) L, M, N, O
Passing H2S gas into a mixture of Mn 2  , Ni 2  , Cu2  and Hg 2 ions in an acidified aqueous solution
precipitates
(A)
(B) MnS and CuS
CuS and HgS
(C) MnS and NiS
4.
6
3 2
the diamagnetic complexes are
(A) K, L, M, N
(C) L, M, O, P
3.
2
3
(D) NiS and HgS
Consider the following cell reaction
bg
2 Fe b sg  O 2 b g g  4 H baq g 
 2 Fe b2aq g  2 H 2 O l
E 0  167
. V
b g
. atm pH = 3, the cell potential at 250C is
At Fe 2   103 M, P O 2  01
(A) 1.47 V
5.
(B) 1.77 V
(C) 1.87 V
(D) 1.57 V
b g bMol. Wt. 329g in 100 g of
The freezing point (in 0C) of a solution containing 0.1 g of K 3 Fe CN
c
6
h
. kg mol 1 is
water K f  186
(A) 2.3  102
(B) 5.7  102
(C) 5.7  103
(D) 12
.  102
Triumph Academy
IIT–JEE-11 / Paper II
[3]
CHEMISTRY
6.
7.
Amongst the compounds given, the one that would form a brilliant colored dye on treatment with NaNO2
in dil. HCl followed by addition to an alkaline solution of   naphtol is
(A)
(B)
(C)
(D)
The major product of the following reaction is
(A) a hemiacetal
8.
(B) an acetal
(C) an ether
(D) an ester
(C) an   furanose
(D) an   pyranose
The following carbohydrate is
(A) a ketohexose
(B) an aldohexose
Triumph Academy
IIT–JEE-11 / Paper II
[4]
CHEMISTRY
Section–II
Multiple Correct Answer Type
This section contains 5 multiple choice questions numbered 8 to 14. Each question has 4 choices (A), (B), (C)
and (D), out of which ONE OR MORE THAN ONE is / are correct.
9.
Reduction of the metal centre in aqueous permagnetic ion involves
(A) 3 electron in neutral medium
(B) 5 electrons in neutral medium
(C) 3 electron in alkaline medium
(D) 5 electrons in acidic medium
10.
Theequilibrium
2Cu I
Cu 0  Cu II
in aqueous medium at 25 0C shifts towards the left in the presence of
(A) NO 3
11.
(B) Cl 
For the first order reaction
bg
bg
(C) SCN 
(D) CN 
bg
2 N 2 O5 g 
 4 NO 2 g  O 2 g
(A) the concentration of the reactant decreases exponentially with time
(B) the half-life of the reaction decreases with increasing temperature
(C) the half-life of the reaction depends on the initial concentration of the reaction
(D) the reaction proceeds to 99.6% completion in eight half-life duration.
12.
The correct functional group X and the reagent/reaction conditions Y in the following scheme are
(A) X  COOCH 3 , Y  H 2 / Ni / heat
(B) X  CONH 2 , Y  H 2 / Ni / heat
(C) X  CONH 2 , Y  Br2 / NaOH
(D) X  CN , Y  H 2 / Ni / heat
Triumph Academy
[5]
IIT–JEE-11 / Paper II
CHEMISTRY
Section–III
Integer Answer Type
This section contains 5 questions. The answer to each of the questions is a single-digit integer, ranging from
0 to 9. The appropriate bubbles below the respective question numbers in the SORS have to be darkened.
13.
Among the following, the number of compounds than can react with PCl5 to give POCl3 is
O 2 , CO 2 , SO 2 , H 2 O, H 2SO 4 , P4 O 10
14.
The volume (in mL) of 0.1 M AgNO3 required for complete precitation of chloride ions present in 30 mL
b g
of 0.01 M solution of Cr H 2 O 5 Cl Cl 2 , as silver chloride is close to
15.
b
g
.  1010 , 0.1 mol of CuCl
In 1L saturated solution of AgCl K sp AgCl  16
b
g
K sp CuCl  1.0  106 is added. The resultant concentration of Ag+ in the solution is 16
.  10 x . The
value of 'x' is
16.
The number of hexagonal faces that are present in a truncated octahedron is
17.
The maximum number of isomers (including stereoisomers) that are possible on monochlorination of the
following compounds is
18.
The total number of contributing structures showing hyperconjugation (involving C - H bonds) for the
following carbocation is
Triumph Academy
IIT–JEE-11 / Paper II
[6]
CHEMISTRY
Section–IV
Matrix-Match Type
This section contains 2 questions. The question contains statements given in two columns, which have to be
matched. The Statements in Column I are labelled A, B, C and D, while the statements in Column II are
labelled p, q, r, s and t. Any given statement in Column I can have correct matching with ONE OR MORE
statement(s) in Column II.
19.
Match the transformations in Column I with appropriate options in Column II
Column I
Column II
(C)
bg
bg
CaCO bsg 
 CaObsg  CO bg g
2H 
 H bg g
(D)
Pb white , solid g 
 Pb red , solid g
(A)
(B)
CO 2 s 
 CO 2 g
3
2

2
(p)
phase transition
(q)
allotropic change
(r)
H is positive
(s)
S is positive
S is negative
(t)
20.
Match the reactions in Column I with appropriate types of steps/reactive intermediante involved in these
reactions as given in Column II.
Column I
Column II
(A)
(p)
Nucleophilic substitution
(B)
(q)
Electrophilic substitution
(C)
(r)
Dehydration
(D)
(s)
Nucleophilc addition
(t)
Carbanion
Triumph Academy
IIT–JEE-11 / Paper II
[17]
MATHEMATICS
Section–I
Straight Objective Type
This section contains 6 multiple choice questions numbered 20 to 23. Each question has 4 choices (A), (B), (C)
and (D), out of which ONLY ONE is correct.
41.
Let f :[ 1, 2]  [0, ) be a continuous function such that f ( x)  f (1  x) for x [ 1, 2] . Let
z
2
R1  x f ( x) dx , and R be the area of the region bounded by y  f ( x) , x  1 , x  2 , and the x2
1
axis. Then
(A) R1  2 R 2
42.
(B) R1  3R 2
(D) 3R1  R 2
Let f ( x)  x 2 and g( x)  sin x for all x  R . Then the set of all x satisfying
( f og og of ) ( x)  ( g og of ) ( x) , where ( f og)( x)  f ( g( x)) is
(A)  n , n {0, 1, 2,...}
(C)
43.
(C) 2 R1  R 2
(B)  n , n {1, 2,...}

 2 n , n {...,2,  1, 0, 1, 2,...}
2
(D) 2 n, n {...,2,  1, 0, 1, 2,...}
Let ( x, y) be any point on the parabola y 2  4 x . Let P be the point that divides the line segment from
(0, 0) to ( x, y) in the ratio 1 :3 . Then the locus of P is
(A) x 2  y
44.
(B) y 2  2 x
(C) y 2  x
(D) x 2  2 y
x2 y2

 1 . If the normal at the point P intersects the x  axis
a 2 b2
at (9, 0), then the eccentricity of the hyperbola is
Let P(6, 3) be a point on the hyperbola
(A)
5
2
(B)
3
2
(C) 2
(D)
3
Triumph Academy
IIT–JEE-11 / Paper II
[18]
MATHEMATICS
45.
A value of b for which the equations
x 2  bx  1  0
x2  x  b  0
have one root in common is
(A)  2
46.
(B) i 3
(C) i 5
(D)
2
Let   1 be a cube root of unity and S be the set of all non singular matrices of the form
LM 1
MM
N
a
1

2
b
c
1
OP
PP
Q
where each of a, b, and c is either  or  2 . Then the number of distinct matrices in the set S is
(A) 2
(B) 6
(C) 4
(D) 8
47.
The circle passing through the point (-1, 0) and touching the y-axis at (0, 2) also passes through the point
FG
H
IJ
K
FG
H
3
(A)  , 0
2
48.
1  x ln(1  b 2 )
If lim
x0
(A) 

4
IJ
K
5
(B)  , 2
2
1/ x
FG
H
3 5
(C)  ,
2 2
IJ
K
b
g
(D) 4, 0
b
 2 b sin 2  , b  0 and    ,  , then the value of  is
(B) 

3
(C) 

6
(D) 

2
Triumph Academy
IIT–JEE-11 / Paper II
[19]
MATHEMATICS
Section–II
Straight Objective Type
This section contains 4 multiple choice questions numbered 54 to 57. Each question has 4 choices (A), (B), (C)
and (D), out of which ONE OR MORE THAN ONE is / are correct.
49.
Let E and F be two independent events. The probability that exactly one of them occurs is
probability of none of them occuring is
11
and the
25
2
. If P(T) denotes the probability of occurrence of the event T,
25
then
(A) P( E ) 
50.
4
3
1
2
2
1
3
4
, P( F)  (B) P( E )  , P( F)  (C) P( E )  , P( F)  (D) P( E )  , P( F) 
5
5
5
5
5
5
5
5
If
R| x   ,
| 2
f b xg  S  cos x,
|| x  1,
T ln x,
x

2

 x  0,
2
0 x 1
x 1

then
(A) f ( x) is continuous at x  

2
(D) f (x) is differentiable at x  
3
2
(A) f is not invertiable on (0, 1)
(B) f  f 1 on (0, 1) and f ( b) 
1
f (0)
1
(C) f  f 1 on (0, 1) and f ( b) 
f (0)
(D) f 1 is differentiable on (0, 1)
(C) f(x) is differentiable at x  1
51.
(B) f (x) is not differentiable at x  0
f : ( 0, 1)  R be defined by
f ( x) 
bx
1  bx
where b is a constant such that 0  b  1 . Then
52.
Let L be a normal to the parabola y 2  4 x . If L passes through the point (9, 6) , then L is given by
(A) y  x  3  0
(C) y  x  15  0
(B) y  3x  33  0
(D) y  2 x  12  0
Triumph Academy
[20]
IIT–JEE-11 / Paper II
MATHEMATICS
Part II
Section–III
Integer Answer Type
This section contains 5 questions. The answer to each of the questions is a single-digit integer, ranging from
0 to 9. The appropriate bubbles below the respective question numbers in the SORS have to be darkened.
53.
The straight line 2 x  3y  1 divides the circular region x 2  y 2  6 into two parts. If
S
RSFG 2, 3IJ , FG 5 , 3IJ , FG 1 ,  1 IJ , FG 1 , 1 IJ UV
TH 4 K H 2 4 K H 4 4 K H 8 4 K W
then the number of point(s) in S lying inside the smaller part is
54.
Let   e i / e and a , b, c, x, y, z be non zero complex numbers such that
abc x
a  b  c 2  y
a  b 2  c  z
x y z
2
a b c
2
2
Then value of
2
2
2
is
55.
The number of distinct real roots of x 4  4 x 3  12 x 2  x  1  0
56.
Let y ( x)  y( x)g ( x)  g x g ( x) , y(0)  0, x R where f  ( x) denotes
57.
Let M be a 3  3 matrix satisfying
bg
d f ( x)
and g( x) is a given
dx
non-constant differentiable function on R with g(0)  g(2)  0 . Then the value of y(2) is
LM0OP LM1OP L 1 O L 1 O
LM1OP LM 0 OP
M
P
M
P
M M1P  M 2 P , M M1P  M 1 P and M M1P  M 0 P
MN0PQ MN 3 PQ MN 0 PQ MN1PQ
MN1PQ MN12PQ
The the sum of the diagonal entries of M is
58.



Let a   i  k , b   i  j and c  i  2 j  3k be three given vectors. If r is a vector such that
 
   

r  b  c  b and r  a  0 then the value of r  b is
Triumph Academy
IIT–JEE-11 / Paper II
[21]
MATHEMATICS
Section–IV
Matrix-Match Type
This section contains 2 questions. The question contains statements given in two columns, which have to be
matched. The Statements in Column I are labelled A, B, C and D, while the statements in Column II are
labelled p, q, r, s and t. Any given statement in Column I can have correct matching with ONE OR MORE
statement(s) in Column II. The appropriate bubbles corresponding to the answers to the question have to be
darkened as illustrated in the following example:
59.
Match the statements in Column I with those in Column II.
[Note: Here z takes values in the complex plane and Im z and Re z denote, respectively, the imaginary
part and the real part of z.]
Column I
Column II
(A) The set
(p)
( ,  1)  (1, )
(q)
( , 0)  (0, )
(r)
2, 
RSReFG 2iz IJ: z is a complex number, z  1, z  1UV
T H 1 z K
W
2
is
(B) The domain of the function
f ( x)  sin 1
FG 8(3) IJ is
H 1 3 K
x 2
2 ( x 1)
1
tan 
1
(C) If f ()   tan 
1
tan  , then
1
 tan  1
RS
T
the set f () : 0   
(s)
b,  1  1, g
(t)
b, 0  2, g
UV
W

is
2
(D) If f ( x)  x 3/ 2 (3x  10) , x  0 , then
f ( x) is increasing in
g
Triumph Academy
[22]
IIT–JEE-11 / Paper II
MATHEMATICS
38.
Match the statements in Column I with the values in Column II.
Column I
Column II



(A) If a  j  3 k , b   j  3 k and c  2 3 k form
(p)

6
(q)
2
3
(r)

3
(s)

(t)

2
a triangle, then the internal angle of the

triangle between a and b is
z
b
(B)
If ( f ( x)  3x)dx  a 2  b 2 , then the value of
a
f
FG  IJ is
H 6K
(C) The value of
z
5
 6
sec( x) dx is.
ln 3 7
6
(D) The maximum value of Arg
z  1 , z  1 is given by
FG 1 IJ for
H 1 z K
IIT JEE - 2011
(Paper I)
CHEMISTRY
1. (B)
8. (A, D)
12. (B)
17. 5
2. (D)
9. (B, C)
13. (A)
18. 5
3. (A)
4. (D)
5. (C)
10. (A, B, D)
11. (A, C, D)
14. (C)
19. 9
20. 6
21. 7
6. (A)
7. (C)
15. (D)
22. 5
16. (B)
23. 4
PHYSICS
24. (D)
25. (B)
31. (A, B, C, D)
35. (D)
36. (C)
40. 1
41. 3
26. (D)
27. (A)
28. (A)
32. (B, D)
33. (A, D)
37. (B)
42. 3
43. 9
44. 6
29. (C)
30. (A)
34. (A, B, C, D)
38. (C)
39. (B)
45. 4
46. 5
MATHEMATICS
47. (C)
48. (B)
54. (Marks to all)
58. (B)
59. (D)
63. 8
64. 1
49. (C)
50. (A)
51. (C)
52. (D)
53. (B)
55. (A, D) 56. (B, D)
57. (B, C OR B, C, D)
60. (D)
61. (A)
62. (B)
65. 5
66. Marks to all
67. 7
68. 3, 9 OR 3 & 9
(Paper II)
CHEMISTRY
1. (D)
2. (C)
3. (A)
4. (D)
5. (A)
6. (C)
9. (A, C, D)
10. (B, C, D)
11. (A, B, D)
12. (C, D)
13. 4
14. 6
15. 7
16. 8
17. 8
18. 6
19. [A]  p, r, s ; [B]  r, s ; [C]  t ; [D]  p, q, t
20. [A]  r, s, t ; [B]  p, s ; [C]  r, s ; [D]  q, r
7. (B)
8. (B)
27. (A)
28. (B)
PHYSICS
21. (C)
22. (A)
23. (C)
24. (D)
25. (D)
26. (B)
29. (A, B, D)
30. (C, D)
31. (B, C)
32. (A, C)
33. 5
34. 4
35. 5
36. 2
37. 4
38. 7
39. [A]  p, r, t ; [B]  p, r ; [C]  q, s ; [D]  r, t
40. [A]  p, t ; [B]  p, s ; [C]  q, s ; [D]  q, r
MATHEMATICS
41. (C)
42. (A)
43. (C)
44. (B)
45. (B)
46. (A)
47. (D)
48. (D)
49. (A, D)
50. (A, B, C, D)
51. (A)
52. (A, B, D)
53. 2
54. Marks to all
55. 2
56. 0
57. 9
58. 9
59. [A]  s ; [B]  t ; [C]  r ; [D]  r
60. [A]  q ; [B]  p OR p, q, r, s, t ; [C]  s ; [D]  t
69. 2