www.eenadupratibha.net IBPS CLERKS t e REASONING 1. h b i is the one that does not belong to that group? 2. n . a Four of the following five are alike in a certain way and so form a group. Which 1) Bat 2) Spider 4) Butterfly 5) Cockroach 3) Mosquito t a r p u d Akshay is 16th from the left end in the row of boys and Vijay is 18th from the right end. Avinash is 11th from Akshay towards the right end and 3rd from Vijay a n towards the right end. How many boys are there in the row? e e . w w 1) Data inadequate 2) 42 4) 48 3. 3) 43 5) None of these t e n How many such pairs of letters are there in the word 'CHILDREN' each of which w has as many letters between them in the word as there are between them in the . a h English alphabet? 4. 1) 3 2) 5 4) 2 5) None of these b i t 3) 4 a r p Pointing to the lady in the photograph, Mrinalini said "Her son's father is the only son-in-law of my mother." How is Mrinalini related to the lady? 1) Sister n e e . ww 4) Aunt 5. u d a 2) Mother 3) Cousin 5) None of these In a certain code 'MOTHER' is written as OMHURF. How will 'ANSWER' be written in that code? w 1) NBWRRF 2) MAVSPE 4) NBXSSE 5) None of these 3) NBWTRD Directions (Q. 6 - 10): Study the following information carefully and answer the questions given below: R-16-11-14 www.eenadupratibha.net www.eenadupratibha.net B, M, T, R, K, H and D are travelling in a train compartment with III-tier sleeper berth. Each of them has a different profession of Engineer, Doctor, Architect, Pharmacist, Lawyer, Journalist and Pathologist . They occupied two lower berths, t e three middle berths and two upper berths. B, the Engineer is not on the Upper berth. n . a The Architect is the only other-person who occupies the same type of berth as that of B. M and H are not on the middle berth and their professions are Pathologist and h b i Lawyer respectively. T is a Pharmacist. D is neither a Journalist nor an Architect. K occupies same type of berth as that of the Doctor. 6. 7. p u d 1) Doctor 2) Engineer 4) Pharmacist 5) Data inadequate a n 3) Lawyer Which of the following group occupies middle berth? e e . w w 1) DKR 4) DKT 8. t a r What is D's profession? 2) DHT 3) HKT Which of the following combinations of person - berth - profession is correct? w . a h 1) R - Lower - Journalist 2) R - Lower - Architect 3) D - Upper - Doctor 4) K - Upper - Lawyer b i t 5) All correct 9. t e n 5) None of these a r p Which of the following pairs occupy the lower berth? 1) BD 2) BR u d a 3) BT 4) Data inadequate 5) None of these n e e . ww 10. Who is the Architect? 1) D 2) H 3) R 4) Data inadequate 5) None of these w 11. If it is possible to make a meaningful word with the third, the fifth, the seventh and the tenth letters of the word 'OUTRAGEOUS', which of the following will be the second letter of that word? If more than one such word can be formed, give 'X' as the answer and if no such word can be formed, give 'Y' as the answer. www.eenadupratibha.net www.eenadupratibha.net 1) E 2) A 4) Y 5) X 3) S t e 12. The position of the first and the second digits in the number 7986032451 are interchanged. Similarly the positions of the third and fourth digits are interchanged and so on. Which of the following will be the fifth digit from the right end after the arrangement? 1) 3 2) 6 4) 0 5) None of these n . a h b i 3) 4 t a r 13. 'GROW' is written as '=@%#' and 'WITHIN' is written as '# ÷+@÷ ∆' in a certain code language. How would 'WING' be written in that code. p u d 1) # ÷ ∆= 2) # %∆= 3) %÷ ∆= a n 4) # ÷= 5) None of these e e . w w 14. If the letters of the word 'PRINCE' are rearranged as they appear in the English alphabet, the position of how many letters will remain unchanged after the rearrangement? w 1) None 2) One 3) Two 4) Three 5) None of these t e n . a h 15. If 'A★ B' means 'A is father of B'. 'A×B' means 'A is mother of B' and 'A# B' means 'A is husband of B' then which of the following means 'P is grandson of Q'? b i t 1) Q # R × S ★ P 2) Q ★ N × P # R a r p 3) Q ★ L # N × P 4) P # N × M ★ Q u d a 5) None of these Directions (Q. 16 - 20): In each of the questions below are given three statements followed by three conclusions numbered I, II and III. You have to take the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts. n e e . ww w 16. Statements: Some flowers are bins. Some bins are handles. All handles are sticks. www.eenadupratibha.net www.eenadupratibha.net Conclusions: I) Some sticks are bins. II) Some handles are flowers. t e III) Some sticks are flowers. n . a 1) Only II follows 2) Only III follows 3) Only I and II follow 4) Only I and III follow h b i 5) None of these 17. Statements: Some towers are windows. t a r All windows are houses. p u d Some houses are temples. Conclusions: I) Some towers are temples. a n II) Some houses are towers. e e . w w III) Some temples are windows. 1) Only I follows t e n 2) Only II follows w 3) Only III follows 4) Only I and II follow . a h 5) None of these 18. Statements: Some walls are doors. b i t Some doors are cots. a r p Some cots are chairs. Conclusions: I) Some chairs are doors. u d a II) Some cots are walls. n e e . ww III) No chair is door. 1) Only II follows 2) Only III follows 3) Only either I or III follows 4) Only I follows w 5) None of these 19. Statements: All trees are gardens. All gardens are stones. All stones are fences. www.eenadupratibha.net www.eenadupratibha.net Conclusions: I) Some fences are gardens. II) All gardens are fences. t e III) Some stones are trees. n . a 1) Only I and II follow 2) Only I and III follow 3) Only II and III follow 4) All follow h b i 5) None of these 20. Statements: All books are leaves. t a r Some leaves are jungles. No jungle is box. p u d Conclusions: I) Some jungles are books. a n II) No book is box. e e . w w III) Some leaves are boxes. 1) None follows 2) Only I follows 3) Only II follows 4) Only III follows w 5) Only I and II follow KEY . a h t e n b i t 1-1; 2-1; 3-3; 4-5; 5-5; 6-1; 7-4; 8-2; 9-2; 10-3; 11-5; 12-4; 13-1; 14-3; 15-2; 16-5; 17-2; 18-3; 19-4; 20-1. a r p EXPLANATIONS 1-1: Bat is a mammal 2-1 n e e . ww C H I L D R E < u d a 3-3: N < < Such pairs are ⇒ HI, EI, HN and IN. 4-5: Photograph of Mrinalini T H < < < M E O M H U +1 < R R +1 < O < w 5-5: F www.eenadupratibha.net www.eenadupratibha.net S W < < N A W E < T R F +1 6-10: Persons Profession t e +1 n . a Berth B Engineer Lower M Pathologist Upper T Pharmacist Middle R Architect Lower K Journalist Middle H Lawyer D Doctor h b i t a r p u d a n e e . w w 6-1: D is doctor R < A < N < Similarly, Upper Middle 7-4: DKT 9-2: BK 10-3: w . a h 11-5: O U T R A G E O U S 1 2 3 4 5 6 7 8 9 10 b i t Meaningful words are SEAT and EAST. 12-4: a r p > 7986032451 ⇒ 9 7 6 8 3 0 4 2 1 5 u d a 5th from right 13-1: G R O W and W I T H I N ↓ ↓ ↓ e↓ en ↓ ↓ ↓ ↓ ↓ ↓ . w w # ÷ + ÷ ∆ = @ % # w Similarly, W I N G ↓↓↓↓ # ÷ t e n 8-2: ∆ = www.eenadupratibha.net www.eenadupratibha.net 14-3: Arrangement according to English Alphabet C E I N P R Only two letters I and N are unchanged. t e 15-2: 1) Q # R × S ★ P: ⇔ Q (+) S (+) n . a R (−) h b i ⇔ t a r P The gender of P is unknown, therefore ‘P is grandson of Q’ is not true. p u d 2) Q ★ N × P # R: Q a n ⇔ e e . w w (+) ⇔ N t e n (−) w P (+) ⇔ R . a h (−) Here, the gender of P is known, therefore 'P is grandson of Q'. b i t 16-5: Some bins are handles. (I-Type) All handles are sticks. (A-Type) a r p u d a I + A = I - type Conclusion. "Some bins are sticks." Conclusion I is converse of this conclusion. n e e . ww 17-2: Some towers are windows. (I-Type) w All windows are houses. (A-Type) I + A = I - type conclusion. "Some towers are houses." Conclusion (II) is converse of the above conclusion. www.eenadupratibha.net www.eenadupratibha.net 18-3: All the three Premises are Particular Affirmative (I-type). No conclusion follows from, Particular Premises. t e Conclusions I and III form Complementary pair. Therefore either I or III follows. n . a 19-4: All trees are gardens. (A-Type) h b i t a r All gardens are stones. (A-Type) A + A = A - type conclusion. p u d "All trees are stones." Conclusion III is converse of this conclusion. All trees are stones. (A-Type) a n e e . w w t e n All stones are fences. (A-Type) w "All trees are fences." . a h All gardens are stones. (A-Type) b i t a r p All stones are fences. (A-Type) "All gardens are fences." u d a This is conclusion II. Conclusion I is converse of this conclusions. n e e . ww 20-1: Some leaves are jungles. w No jungle is box. I + E = O - type conclusion. "Some leaves are not boxes." Writer: S. Arun Mohan www.eenadupratibha.net
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