Some inequalities involving multivalent functions

ANNALES
POLONICI MATHEMATICI
LX.2 (1994)
Some inequalities involving multivalent functions
by Shigeyoshi Owa (Osaka),
Mamoru Nunokawa (Gunma) and
Hitoshi Saitoh (Gunma)
Abstract. The object of the present paper is to derive some inequalities involving
multivalent functions in the unit disk. One of our results is an improvement and a generalization of a result due to R. M. Robinson [4].
1. Introduction. Let A(p) be the class of functions of the form
(1.1)
∞
X
p
f (z) = z +
an z n
(p ∈ N = {1, 2, 3, . . .})
n=p+1
which are analytic in the unit disk U = {z : |z| < 1}.
In 1947, Robinson [4] proved the following
Theorem A. Let S(z) and T (z) be analytic in U, and let
Re{zS 0 (z)/S(z)} > 0 (z ∈ U). If |T 0 (z)/S 0 (z)| < 1 (z ∈ U) and T (0) = 0,
then |T (z)/S(z)| < 1 (z ∈ U).
In the present paper, we derive an improvement and generalization of
Theorem A for functions belonging to A(p).
To establish our results, we have to recall the following lemmas.
Lemma 1 ([1], [2]). Let w(z) be analytic in U with w(0) = 0. If |w(z)|
attains its maximum value in the circle |z| = r < 1 at a point z0 ∈ U, then
we can write
(1.2)
z0 w0 (z0 ) = kw(z0 ),
where k is real and k ≥ 1.
Lemma 2 ([3]). Let p(z) be analytic in U with p(0) = 1. If there exists a
1991 Mathematics Subject Classification: Primary 30C45.
Key words and phrases: analytic function, unit disk, Jack’s lemma.
[159]
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S. Owa et al.
point z0 ∈ U such that
Re(p(z)) > 0
(|z| < |z0 |),
Re(p(z0 )) = 0,
and
p(z0 ) 6= 0,
then p(z0 ) = ia (a 6= 0) and
z0 p0 (z0 )
k
1
=i
a+
,
p(z0 )
2
a
(1.3)
where k is real and k ≥ 1.
2. Some counterparts of Theorem A. Our first result for functions
in the class A(p) is contained in
Theorem 1. Let S(z) ∈ A(m), T (z) ∈ A(n) with p = n − m ≥ 1. Let
S(z) satisfy Re{S(z)/zS 0 (z)} > α (0 ≤ α < 1/m). If
0 T (z) p−1
(z ∈ U),
(2.1)
S 0 (z) < (1 + pα)|z|
then
T (z) p−1
S(z) < |z|
(2.2)
(z ∈ U).
P r o o f. Since T (z)/S(z) = z p + . . . ∈ A(p), we define the function w(z)
by T (z) = z p−1 w(z)S(z). Then w(z) is analytic in U with w(0) = 0. It
follows from the definition of w(z) that
zw0 (z) S(z)
T 0 (z)
p−1
=z
w(z) 1 + p − 1 +
.
(2.3)
S 0 (z)
w(z) zS 0 (z)
If we suppose that there exists a point z0 ∈ U such that
max |w(z)| = |w(z0 )| = 1,
|z|≤|z0 |
then Lemma 1 gives w(z0 ) = eiθ and
z0 w0 (z0 ) = kw(z0 )
(k ≥ 1).
Therefore,
T 0 (z0 )
(2.4)
z p−1 S 0 (z
0
0
z
w
(z
)
S(z
)
0
0
0
= 1 + p − 1 +
0
w(z0 )
z0 S (z0 ) 0)
S(z0 )
≥ 1 + (p − 1 + k) Re
> 1 + pα.
z0 S 0 (z0 )
This contradicts our condition (2.1), so that |w(z)| < 1 for all z ∈ U. This
completes the proof of Theorem 1.
R e m a r k. If we take p = 1 and α = 0 in Theorem 1, then we recover
Theorem A due to Robinson [4].
Next, applying Lemma 2, we prove
Multivalent functions
161
Theorem 2. Let S(z) ∈ A(m), T (z) ∈ A(n) with p = n−m ≥ 1. Let S(z)
satisfy Re{S(z)/zS 0 (z)} > α (0 ≤ α < 1/m) and −α/p ≤ Im{S(z)/(zS 0 (z))}
≤ α/p (0 ≤ α < 1/m). If
0
T (z)
> 0 (z ∈ U),
(2.5)
Re
z p S 0 (z)
then
T (z)
> 0 (z ∈ U).
(2.6)
Re
z p S(z)
P r o o f. Defining the function q(z) by T (z) = z p q(z)S(z), we see that
q(z) is analytic in U with q(0) = 1. Note that
T 0 (z)
zq 0 (z) S(z)
p
(2.7)
= z q(z) 1 + p +
.
S 0 (z)
q(z) zS 0 (z)
Suppose that there exists a point z0 ∈ U such that
Re(q(z)) > 0
(|z| < |z0 |),
Re(q(z0 )) = 0,
and q(z0 ) 6= 0.
Then, applying Lemma 2, we have q(z0 ) = ia (a 6= 0) and
k
1
z0 q 0 (z0 )
=i
a+
(k ≥ 1).
q(z0 )
2
a
Therefore, writing S(z0 )/(z0 S 0 (z0 )) = α0 + iβ0 , we obtain
0
T (z0 )
akα0
1
(2.8) Re
= −apβ0 −
a+
z0p S 0 (z0 )
2
a
kα0
(1 + a2 )
= −apβ0 −
2
α0
α
≤ −apβ0 −
(1 + a2 ) ≤ −apβ0 − (1 + a2 ).
2
2
Since −α/p ≤ β0 ≤ α/p, if a > 0, then
α
α
−apβ0 − (1 + a2 ) ≤ aα − (1 + a2 )
(2.9)
2
2
α
= − (1 − a)2 ≤ 0,
2
and if a < 0, then
α
α
(2.10)
−apβ0 − (1 + a2 ) ≤ −aα − (1 + a2 )
2
2
α
= − (1 + a)2 ≤ 0.
2
This contradicts our condition (2.5). Consequently, Re(q(z)) > 0 for all
z ∈ U, so that Re{T (z)/(z p S(z))} > 0 (z0 ∈ U).
Further, using the same technique as in the proof of Theorem 2, we
obtain
162
S. Owa et al.
Theorem 3. Let S(z) ∈ A(m), T (z) ∈ A(n) with p = m − n
≥ 0. Let S(z) satisfy Re{S(z)/(zS 0 (z))} > α (0 ≤ α < 1/m) and −α/p ≤
Im{S(z)/(zS 0 (z))} ≤ α/p (0 ≤ α < 1/m). If
p 0 z T (z)
> 0 (z ∈ U),
(2.11)
Re
S 0 (z)
then
p
z T (z)
> 0 (z ∈ U),
(2.12)
Re
S(z)
Acknowledgements. This research was supported in part by the Japanese Ministry of Education, Science and Culture under Grant-in-Aid for
General Scientific Research.
References
[1]
[2]
[3]
[4]
I. S. J a c k, Functions starlike and convex of order α, J. London Math. Soc. 3 (1971),
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S. S. M i l l e r and P. T. M o c a n u, Second order differential inequalities in the complex
plane, J. Math. Anal. Appl. 65 (1978), 289–305.
M. N u n o k a w a, On properties of non-Carath´eodory functions, Proc. Japan Acad.
68 (1992), 152–153.
R. M. R o b i n s o n, Univalent majorants, Trans. Amer. Math. Soc. 61 (1947), 1–35.
S. Owa
H. Saitoh
DEPARTMENT OF MATHEMATICS
KINKI UNIVERSITY
DEPARTMENT OF MATHEMATICS
GUNMA COLLEGE OF TECHNOLOGY
HIGASHI-OSAKA, OSAKA 577
TORIBA, MAEBASHI, GUNMA 371
JAPAN
JAPAN
M. Nunokawa
DEPARTMENT OF MATHEMATICS
UNIVERSITY OF GUNMA
ARAMAKI, MAEBASHI, GUNMA 371
JAPAN
Re¸cu par la R´edaction le 4.10.1993
R´evis´e le 28.2.1994