91.304 Foundations of Computer Science Fall 2010 Computer Science Department University of Massachusetts Lowell Lowell MA, 01854 Sample Midterm Quiz Hint 1. (10pts) DFA (1) Describe the formal definition of DFA in brief. (2) Give a DFA accepting the language L: { 2. (15pts) NFA to DFA (1) Describe briefly the differences between NFA and DFA (2) Convert this ε-NFA to DFA. ε a b c → p {q, r} Ø {q} {r} q Ø {p} {r} {p, q} *r Ø Ø Ø Ø a,c P,q,r b q,r b r a,c Page 1 of 4 }. 3. (15pts) Regular Expression and NFA (1) Write the regular expression for the language L: the set of strings of 0’s and 1’s with at most one pair of consecutive 0’s. (2) Convert your regular expression to NFA 4. (15pts) CFG and PDA (1) Describe the formal definition of CFG in brief. (2) Design CFG for the language . (3) Design PDA for the same language in (2). (Not the PDA converted from CFG, you do not need the result of (2) to design the PDA) (2) SXC | AY XaXb | ε CcC | ε AaA | ε YbYc | ε (3) a, ε/a b, a/ε c, ε/ε ε, ε/ε ε, ε/ε ε, ε/ε ε, ε/ε a, ε/ε b, ε/b c, b/ε Page 2 of 4 5. (15pts) CFG SAB | C AaAb | ab BcBd | cd CaCd | aDd DbDc | bc (1) Is this grammar ambiguous? (2) What is left-most derivation? (3) Write two different left-most derivations or parsing trees for aabbccdd. (1) Yes (3) SABaAbBaabbBaabbcBdaabbccdd SCaCdaaDddaabDcddaabbccdd 6. (15pts) Pumping Lemma Given the language L: { (1) Is L regular? (2) If not, using pumping lemma to prove it. } Assume that L is regular, according to pumping lemma, there exists a positive integer s so that we can pick a string and break w into such that for all . Choose since , , should only contains 1. For some , thus , this is a contradiction. So L is not regular. Page 3 of 4 7. (15pts) Pumping Lemma Given the language L: { }. (1) Is L context-free? (2) If not, using pumping lemma to prove it. Let L’={ } Assume L’ is CFL, by pumping lemma, there exists a constant integer n such that for any string z in L’, if |z| ≥ p, z can be decomposed into z=uvwxy, where |vwx| ≤ p, vx ≠ ε, for all i ≥ 0, uviwxiy in also in L’. Choose z = 0n where n ≥ p + 2. |z| > p. z = uvwxy. Let |vx| = t, |uwy| = n – t. Let z’ = uvn-twxn-ty = 0(n - t) * t + n – t = 0(n – t)(1 + t). Since both (n – t) and (1 + t) > 1, z’ is not in L’, contradiction. Therefore, L’ is not CFL. Then use complement property. (Extra Credit) 8. (10pts) Algebraic Laws for Regular Expression Prove or disprove the following statement about regular expression. Prove: Page 4 of 4
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